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Arizona - CHEM - 103B
Exam I masterPage 1Chemistry 103B Exam 1 Answer Key Form B1. (2) When a chemical reaction has reached equilibrium (a) the reaction quotient Q has reached a minimum (b) the concentrations of the reactants have become equal to the concentrations o
Arizona - CHEM - 103B
Exam I masterPage 1Chemistry 103B Exam 1 Answer Key Form A1. (2) A reaction has just one elementary step , C + C C2 [slow]. The rate constant k has the value 7.1 x 10 L/mols. At the start of the reaction (t = 0) the concentrations of C and C2
Arizona - PHYS - 141
Homework 5 solutions page 186 In these 8 problems, the roots associated to the forcing term are indicated in the answer in those cases where the answer was yes. 1) No , the t-1 is not a polynomial 2) Yes , the roots 4i are repeated 4 times (polynomia
Arizona - CHEM - 103B
Exam I masterPage 1Chemistry 103B Exam 2 Form D Answer Key1. (2) Which acid/conjugate base pair would be best for making a buffer solution with pH = 3.00? (a) H3 PO4 / H2 PO4-(b) HCO3 /CO32-(c) H2 CO3 /HCO3-(d) HCN/CN-(e) CH3 OH/C
Arizona - CHEM - 103B
Exam I masterPage 1Chemistry 103B Exam 2 Answer Key Form A1. (2) What is [OH ] for a solution that has pH = 14.85? (a) 7.1 M (b) 2.3 x 10 M-4 -(c) 0.14 M(d) 4.4 x 10 M-9(e) 4.3 x 10-11MDefinitions of pOH and pH. pOH = 14.00 14.85
Arizona - CHEM - 103B
Exam I masterPage 1Chemistry 103B Exam 1 Answer Key Form C1. (2) A reaction has just one elementary step , C2 2 C [slow]. The rate constant k has the value 7.1 x 10 s . At the start of the reaction (t = 0) the concentrations of C2 and C were 0
Washington - E E - 341 and 23
EE341, Autumn 2007 Problem Set 1 SOLUTION (updated 8th October)Reading for this problem set: Chapter 9 of Signals, Systems, and Transforms. 1. The following is the graph of a signal x[n].4 3 2 1-11 03-4-3-2 -1 -22456-1Assum
Washington - E E - 341 and 23
Washington - E E - 341 and 23
EE341, Autumn 2007 Problem Set 3 SOLUTIONReading for this problem set: Chapter 10 of Signals, Systems, and Transforms. 1. Show that, for any function g[n], g[n] [n] = g[n] solution From the definition of the convolution sum,g[n] [n] =k=-g[k]
Washington - E E - 341 and 23
Note: X()=4 when =0Cannot Recover the original x[n] in this caseoriginal x[n] is recovered in this caseoriginal x[n] is recovered in this caseThe 8 point DFT provides the best spectral representation overall. However the 4 point DFT would suf
Washington - E E - 341 and 23
= (z-1)/(z-1) + 1/(z-1)+11()
Washington - E E - 341 and 23
EE341, Autumn 2007 Problem Set 5 SOLUTIONReading for this problem set: Sections 12.1 - 12.3 of Signals, Systems, and Transforms. 1. Prove that: DT F{nx[n]} = j solution By definition,dX() dX() =n=-x[n]e-jnd d x[n]e-jn X() = d d n=- Becaus
Washington - E E - 341 and 23
EE341, Autumn 2007 Problem Set 7 SOLUTIONReading for this problem set: Chapter 12 of Signals, Systems, and Transforms. 1. The signal x(t) = 5 cos(8t) is sampled eight times with T = 0.1s, starting at t = 0. solution(a) Compute the DFT of this sequ
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #8 SolutionAutumn 20076.71 I DD =0.20mW = 60.1A VTNL = -1+ 0.5 3.3 + 0.6 - 0.6 = -0.400V VH = 3.3V 3.3V W W 1.16 0.20 | For VO = VL = 0.2V , 60.1A = 100A 3.3 - 0.6 - 0.20 = 2 1 L S L S W
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #7 SolutionAutumn 20076.4vO VH (3.3 V)vI VL (0V) 1.1 V (V REF) 3.3V V+6.5v V H (3.3 V)Ov V L (0V) 1.1 V (V REF) 3.3V V+IZ= A =A()6.9 VOH = 5 V VOL = 0 VVIH = VREF = 2 V VIL = VREF = 2
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #2 SolutionAutumn 20072.18 Since Ge is from column IV, acceptors come from column III and donors come from column V. (a) Acceptors: B, Al, Ga, In, Tl (b) Donors: N, P, As, Sb, Bi2.23 N A > N D : N A -
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #3 SolutionAutumn 20073.22 V I VD = nVT ln1+ D | I D = I S exp D -1 IS nVT 7x10-5 A 5x10-6 A (a) VD = 1.05(0.025V )ln1+ = 0.837V | (b) VD = 1.05(0.025V )ln1+ = 0.768V 10-18 A 10-18 A
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #4 SolutionAutumn 20073.73 Diodes are labeled from left to right(a) D1 on, D2 off, D3 on : I D2 = 0 | I D1 = I D3 + 0.990mA = 0 - (-5)10 - 0 = 0.990mA 3.3k + 6.8k I D3 = 1.09mA | VD2 = 5 - ( - 3300
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #5 SolutionAutumn 20074.4 (a)' n " ox-14 cm 2 3.9 8.854x10 F / cm 3.9o = n = 500 K = nC = n Tox Tox V - sec 50x10-9 m( 100cm / m) ox()F A A = 34.5 x 10-6 2 = 34.5 2 V - sec V V (b) & (c)
Washington - EE - 331
EE 331Devices and Circuits I Problem Set #6 SolutionAutumn 20074.85(a)100k 12V = 3.75V | Assume saturation 100k + 220k 100x10-6 5 2 3.75 = VGS + 24 x10 3 ID = VGS + 24 x10 3 (VGS -1) 2 1 VGG =2 6VGS -11VGS + 2.25 = 0 VGS = 1.599V
Washington - EE - 331
EE 331Devices and Circuits I Solution Set #1Autumn 2007Answer the following problems from Jaeger (3rd Ed.). Each problem has 20 points (100 points total) 2.2 Based upon Table 2.1, a resistivity of 1015 -cm > 105 -cm, and silicon dioxide is an i
GWU - CHEM - 004
Chem 004 - Spring 2006SteroidsSteroidsCholesterol Sex Hormones The Pill Pregnancy TestBlackboard: http:/blackboard.gwu.eduOffice Hours: MW 3:10-3:55 PM, 1957 E Street, room 213, or by appointmentThe steroid nucleusFunction Regulation of sec
GWU - CHEM - 004
Nucleic AcidsThe Genetic CodeTranscription, Translation and ReplicationDeoxyribonucleic acid (DNA) - Mainly found in the cell nucleus - Very large molecules - Double stranded - Store genetic informationChem 004 - Spring 2006Chemical units of D
GWU - CHEM - 004
Chem 004 - Spring 2006Background- 1900 - Less than 10% of people who developed invasive cancers survived. + 2000 - Over 50% are cured. - 1970 - 5 year survival rate of children with leukemia: less than 10%. + 2000 - 60-70% alive after 5 years.Ca
Kansas - WS - 396
Rebecca J Tolman/ 2331360 Ws 396 Project Description 2/20/2007 Topic: I would Like to explore the topic, of Openly LGBTIQ Clergy People in Kansas/ the Midwest. A listing, description, and discussion of the specific evidence: I would like to explore t
UCLA - CHEM - 153A
Seat # _ Last initial _ Chemistry and Biochemistry 153A Fall 2003 Midterm Examination _ Print your full name (last name first) Question # 1 2 3 4 5 6 7 TOTAL Value 28 30 18 16 22 18 20 152 __ SignatureINSTRUCTIONS READ EACH QUESTION CAREFULLY! SHOW
UCLA - CHEM - 153A
Seat # _ Last initial _ Chemistry and Biochemistry 153A Winter 2004 Midterm Examination KEY _KEY_ Print your full name (last name first) Question # 1 2 3 4 5 TOTAL Value 31 34 33 28 26 152 __ SignatureINSTRUCTIONS READ EACH QUESTION CAREFULLY! SHOW
UCLA - CHEM - 153A
Seat # _ Chemistry 153A Section 2 Fall 98 Final ExamQuestion # 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 TOTALValue 20 6 6 10 4 15 15 16 5 18 15 25 25 20 20 15 15 250ScoreFINAL COURSE GRADE Gas constant: R=1.98 x 10-3 kcal/oK/mole R= 8.31 x 1
UCLA - CHEM - 153A
Seat # _ Last initial _ Chemistry and Biochemistry 153A Winter 2002 Midterm Examination _KEY_ Print your full name (last name first) Question # 1 2 3 4 5 6 7 8 TOTAL Value 23 23 20 10 11 25 10 30 152 __ SignatureINSTRUCTIONS READ EACH QUESTION CAREF
UCLA - CHEM - 153A
Seat # _ Last initial _ Practice Exam KEY Chemistry and Biochemistry 153A Midterm Examination KEY _KEY_ Print your full name (last name first) Question # 1 2 3 4 5 6 7 8 TOTAL Value 20 32 10 12 18 13 23 24 152 Score __ Student ID Number _ Print your
UCLA - CHEM - 153A
Name _KEY_64. (25) a. (2) In the monosaccharide derivatives known as alditols (sugar alcohols), the aldehyde group is reduced to CH2OH. Give the appropriate common name of the sugar alcohol derived from D-glyceraldehyde. _glycerol__ b. (1) The nu
UCLA - CHEM - 153A
Seat # _ Last initial _ Chemistry and Biochemistry 153A Fall 2006 Midterm Examination_KEY_ Print your full name (last name first) Question # 1 2 3 4 5 6 TOTAL Value 21 22 31 27 20 31 152 __ Print your TA's name _ Discussion section # [or time & day
UCLA - CHEM - 153A
Chemistry 153A Practice Final Exam KEY First letter of your last name _ Question # 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 TOTAL TOTAL COURSE SCORE FINAL COURSE GRADE Value 25 5 10 10 7 I have read the instructions below. 14 18 15 18 20 20 16 25 17 15 __
UCLA - CHEM - 153A
Seat # _ Last initial _ Chemistry and Biochemistry 153A Fall 2002 Midterm Examination _KEY_ Print your full name (last name first) Question # 1 2 3 4 5 6 7 8 9 10 TOTAL Value 10 22 8 5 6 24 11 8 32 19 145WRITE YOUR LAST NAME IN THE SPACE PROVIDED ON
Virginia Tech - MATH - 1206
In the trig section we neededh0lim0 sin h =" "=1 h 00 cos h - 1 =" "=1 h 0 We used a geometrical argument to solve it, but there are a lot of those functions with an indeterminant form " 0 " or " " like 0 h0limx1limln x 0 =" " x-1 0
Virginia Tech - MATH - 1206
In the trig section we neededh0lim0 sin h =" "=1 h 00 cos h - 1 =" "=1 h 0 We used a geometrical argument to solve it, but there are a lot of those functions with an indeterminant form " 0 " or " " like 0 h0limx1limln x 0 =" " x-1 0
Virginia Tech - MATH - 1206
In the trig section we neededh0lim0 sin h =" "=1 h 00 cos h - 1 =" "=1 h 0 We used a geometrical argument to solve it, but there are a lot of those functions with an indeterminant form " 0 " or " " like 0 h0limx1limln x 0 =" " x-1 0
University of Florida - CHM - 2046
University of Florida - CHM - 2046
University of Florida - CHM - 2046
University of Florida - CHM - 2046
UPenn - MEAM - 203
MEAM 203FALL 2002THERMO FINAL EXAM Closed books. Answer all four questions. Write clearly! Explain all steps. Answers without clear explanation will be discounted. GOOD LUCK. (30%) 1. An adiabatic compressor compresses vapor water from a saturat
UPenn - MEAM - 203
MEAM 203SPRING 2007THERMO - MIDTERM IIClosed books. One sheet with formulas is allowed. Answer all three questions. Write clearly! Explain all steps! GOOD LUCK.diffuser(45%) 1. A new aircraft is designed to fly with steady state velocity of
UPenn - MEAM - 203
MEAM 203FALL 2002THERMO - MIDTERM II Closed books. Answer all three questions. Write clearly! Explain all steps. Answers without clear explanation will be discounted. GOOD LUCK. (30%) 1. In a counter flow heat exchanger air is used to heat up wat
UPenn - MEAM - 203
MEAM 203FALL 2002THERMO - MIDTERM IClosed books. Write clearly! Explain all steps! GOOD LUCK.(50%) 1. An ideal gas undergoes a cycle consisting of the following three processes: (i) Process 1-2: Isothermal compression from pressure p1=100kPa,
UPenn - MEAM - 203
MEAM 203SPRING 2007THERMO - MIDTERM IClosed books. One sheet with formulas is allowed. Answer all questions. Write clearly! Explain all steps! GOOD LUCK. 1. (35%) A cylinder (B), capped with a frictionless,Afree-floating piston, is connected
UCSD - CHEM - 140A
Chemistry 140A Whitesell Fall Quarter, 2004 Second Midterm Exam, Monday November 15first namemiddle initiallast nameStudent ID NumberRegradeQuest 1 2 3 4 5 6 7 8 9 10 11 totalPoints 15 8 6 5 5 10 8 10 15 8 10 100scoreYour answers to
Brandeis - ECON - 2a
BRANDEIS UNIVERSITY Department of Economics Economics 2a Intro to Econ Answers to Problem Set 5 1. a) The cost to Acme to cut back by 3 tons is $3 + $6 + $9 = $18. The cost to Bloated to cut back by 3 tons is $1 + $2 + $3 = $6. The total cost for bot
Michigan - EECS - 314
EECS 314Winter 2007 Exam 3= FinalSample solutionTuesday April 24, 2006, 1:30 3:30 PMStudents will take the exam in the following rooms, according to the first letter of their last names: 220 Chrysler Auditorium (our lecture room) A through O
Michigan - EECS - 314
Sample solutionsEECS 314 Winter 2007 Exam 2Thursday March 15, 2006, 10:00 11:30 AMStudents will take the exam in the following rooms, according to the first letter of their last names: 220 Chrysler Auditorium (our lecture room) A through O 1504