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Course: EGM 2511, Spring 2008
School: University of Florida
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Word Count: 202

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Complete COSMOS: Online Solutions Manual Organization System Chapter 7, Solution 78. (a) Note: The 2 kip force at E has been replaced by the equivalent force and couple at C. M A = 0: - ( 6 ft )(1 kip/ft )(12 ft ) + 8 kip ft - (12 ft )( 2 kips ) + ( 24 ft ) Dy - ( 32 ft )(1 kip ) = 0 Fy = 0: D y = 5 kips Ay - (1 kip/ft )(12 ft ) - 2 kips + 5 kips - 1 kip = 0 A y = 10 kips Shear Diag: From 10 kips at A, V...

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Complete COSMOS: Online Solutions Manual Organization System Chapter 7, Solution 78. (a) Note: The 2 kip force at E has been replaced by the equivalent force and couple at C. M A = 0: - ( 6 ft )(1 kip/ft )(12 ft ) + 8 kip ft - (12 ft )( 2 kips ) + ( 24 ft ) Dy - ( 32 ft )(1 kip ) = 0 Fy = 0: D y = 5 kips Ay - (1 kip/ft )(12 ft ) - 2 kips + 5 kips - 1 kip = 0 A y = 10 kips Shear Diag: From 10 kips at A, V decreases with slope -1 kip/ft to - 2 kips at C, drops 2 kips, is constant at - 4 kips to D, jumps 5 kips, and is constant at 1 kip to B. V = 0 at E, where 10 kips - (1 kip/ft x ) = 0, x = 10 ft. Moment Diag: From zero at A, M increases with decreasing slope to = 50 kip ft at F , decreases by 1 (10 kips)(10 ft ) 2 1 ( 2 kips )( 2 ft ) to 48 kip ft at C, drops 2 8 kip ft to 40 kip ft, then decreases with slope - 4 kips to - 8 kip ft at D. Finally M increases with slope 1 kip to zero at B. (b) M max = 50 kip ft at F (10.00 ft from A ) Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell 2007 The McGraw-Hill Companies.
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