14 Pages

# Chapter 44

Course Number: PHYS 2306, Fall 2007

College/University: Virginia Tech

Word Count: 2990

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44.1: m a) K 9 . 109 mc 2 1 1 v 2 1 c 2 0 . 1547 mc 2 10 31 kg, so K 1 . 27 10 14 J b) The total energy of each electron or positron is E K mc 2 1 .1547 mc 2 14 9 . 46 10 J. The total energy of the electron and positron is converted into the total energy of the two photons. The initial momentum of the system in the lab frame is zero (since the equal-mass particles have equal speeds in opposite...

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SUNY Buffalo - PHY - 107-207
1. The speed (assumed constant) is (90 km/h)(1000 m/km) / (3600 s/h) = 25 m/s. Thus, during 0.50 s, the car travels (0.50)(25) 13 m.2. Huber's speed is v0=(200 m)/(6.509 s)=30.72 m/s = 110.6 km/h, where we have used the conversion factor 1 m/s = 3
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SUNY Buffalo - PHY - 107-207
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SUNY Buffalo - PHY - 107-207
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SUNY Buffalo - PHY - 107-207
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SUNY Buffalo - PHY - 107-207
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SUNY Buffalo - PHY - 107-207
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SUNY Buffalo - PHY - 107-207
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