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L12

Course: CHEM 111, Spring 2008
School: Colorado State
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Which of these metals has the most negative electron affinity? A. B. C. D. E. calcium cadmium chromium copper cobalt [Ar]4s2 [Kr]5s24d10 [Ar]4s13d5 [Ar]4s13d10 [Ar]4s23d7 Atomic radius measures how strongly the outer shell valence electrons of an atom are attracted to the nucleus. The bigger the atomic radius, the further the valence electrons are from the nucleus, the less...

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Which of these metals has the most negative electron affinity? A. B. C. D. E. calcium cadmium chromium copper cobalt [Ar]4s2 [Kr]5s24d10 [Ar]4s13d5 [Ar]4s13d10 [Ar]4s23d7 Atomic radius measures how strongly the outer shell valence electrons of an atom are attracted to the nucleus. The bigger the atomic radius, the further the valence electrons are from the nucleus, the less attraction they experience. Electron Affinity measures how readily a neutral atom can gain an electron. As the electron affinity becomes more negative, the tendency to gain an electron gets bigger. Ionization Energy measures how readily an atom or ion releases an electron. As the ionization energy gets bigger, the tendency to release an electron gets smaller. Which of these metals has the most negative electron affinity? A. B. C. D. E. calcium cadmium chromium copper cobalt [Ar]4s2 [Kr]5s24d10 [Ar]4s13d5 [Ar]4s13d10 [Ar]4s23d7 Atoms can lose or gain electrons to become ions. Atoms can lose or gain electrons to become ions. For cations, electrons are taken away from the outermost subshell, making cations smaller than their parent atoms. Na: [Ne]3s1 Na+: [Ne] Mg: [Ne]3s2 Mg2+: [Ne] Al: [Ne]3s23p1 Al3+: [Ne] Atoms can lose or gain electrons to become ions. For cations, electrons are taken away from the outermost subshell, making cations smaller than their parent atoms. Na: [Ne]3s1 Na+: [Ne] Mg: [Ne]3s2 Mg2+: [Ne] Al: [Ne]3s23p1 Al3+: [Ne] These ions are all isoelectronic with Ne (1s22s22p6). In general, for maingroup elements the most stable ions are the ones that are isoelectronic with a noble gas. Atoms can lose or gain electrons to become ions. For anions, electrons are added to the outermost subshell. The electron electron repulsion makes the anions bigger than their parent atoms. S: [Ne]3s23p4 S2: [Ne] 3s23p6 = [Ar] Cl: [Ne]3s23p5 Cl: [Ne] 3s23p6 = [Ar] Atoms can lose or gain electrons to become ions. For anions, electrons are added to the outermost subshell. The increase in electronelectron repulsion makes the anions bigger than their parent atoms. Cl: [Ne]3s23p5 Cl: [Ne] 3s23p6 = [Ar] These ions are isoelectronic with Ar (1s22s22p63s23p6). In general, for maingroup elements the most stable ions are the ones that are isoelectronic with a noble gas. S: [Ne]3s23p4 S2: [Ne] 3s23p6 = [Ar] In general, metals lose electrons to become cations. gain Nonmetals electrons to become anions. Figure 8.29 Ionic vs. atomic radius. SAMPLE PROBLEM 8.8 PROBLEM: Ranking Ions by Size Rank each set of ions in order of decreasing size, and explain your ranking: (a) Ca2+, Sr2+, Mg2+ (b) K+, S2, Cl (c) Au+, Au3+ PLAN: Compare positions in the periodic table, formation of positive and negative ions and changes in size due to gain or loss of electrons. SOLUTION: (a) Sr2+ > Ca2+ > Mg2+ These are members of the same Group (2A/2) and therefore decrease in size going up the group. The ions are isoelectronic; S2 has the smallest Zeff and therefore is the largest while K+ is a cation with a large Zeff and is the smallest. (c) Au+ > Au3+ (b) S2 > Cl > K+ The higher the + charge, the smaller the ion. Maingroup ions and the noble gas configurations. Figure 2.19 Some common monatomic ions of the elements. Can you see any patterns? The Period 4 crossover in sublevel energies. The 4s subshell is lower in energy than the 3d subshell. Electrons fill the 4s subshell first. Once electrons are placed inside the 3d subshell, those electrons become more stable. When transition metals lose electrons to become cations, electrons are lost from the 4s subshell first. "First in, first out" SAMPLE PROBLEM 8.6 PROBLEM: Writing Electron Configurations of MainGroup Ions Using condensed electron configurations, write reactions for the formation of the common ions of the following elements: (b) Potassium (Z = 19) (c) Indium (Z = 49) (a) Iodine (Z = 53) PLAN: Ions of elements in Groups 1A(1), 2A(2), 6A(16), and 7A(17) are usually isoelectronic with the nearest noble gas. Metals in Groups 3A(13) to 5A(15) can lose their np or ns and np electrons. SOLUTION: (a) Iodine (Z = 53) is in Group 7A(17) and will gain one electron to be isoelectronic with Xe: I ([Kr]5s24d105p5) + e I ([Kr]5s24d105p6) K ([Ar]4s1) K+ ([Ar]) + e (c) Indium (Z = 49) is in Group 3A(13) and can lose either one electron or three electrons: In ([Kr]5s24d105p1) In+ ([Kr]5s24d10) + e+ In ([Kr]5s24d105p1) In3+([Kr] 4d10) + 3e (b) Potassium (Z = 19) is in Group 1A(1) and will lose one electron to be isoelectronic with Ar: Figure 8.27 Apparatus for measuring the magnetic behavior of a sample.
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Colorado State - CHEM - 111
Figure 8.27Apparatus for measuring the magnetic behavior of a sample. FOLLOWUP PROBLEM 8.7 PROBLEM:Writing Electron Configurations and Predicting Magnetic Behavior of Transition Metal IonsWrite the condensed electron configuration of ea
Colorado State - CHEM - 111
Covalent Bonding involves sharing of electrons between two or more nuclei. Covalent Bonding in H2(g) Lewis Structure of H2(g). Also represented as HH. The line represents a pair of shared electrons, or a bonding electron pair.H + H H:H
Colorado State - CHEM - 111
Types of Chemical FormulasA chemical formula is comprised of element symbols and numerical subscripts that show the type and number of each atom present in the smallest unit of the substance. An empirical formula indicates the relative number of a
Colorado State - CHEM - 111
Lewis structuresFirst, species that obey the octet rule: eight valence electrons for each atom (except H).Place all the atoms relative to each other. Atom with lowest group # is usually in the center (i.e. it is the central atom). This atom is
Colorado State - CHEM - 111
Lewis structuresFirst, species that obey the octet rule: eight valence electrons for each atom (except H).Place all the atoms relative to each other. Atom with lowest group # is usually in the center (i.e. it is the central atom). This atom is
Colorado State - CHEM - 111
VSEPR Valence Shell Electron Pair Repulsion TheoryAn electron group can be a nonbonding electron pair, a single bond, or a multiple bond around the central atom. H C Hsingle bondsOdouble bondtrigonal planarEach group of valence electrons
Colorado State - CHEM - 111
Paul Adrien Maurice Dirac (19021984)The underlying physical laws necessary for the mathematical theory of a large part of physics and the whole of chemistry are thus completely known, and the difficulty is only that the exact application of these
Colorado State - CHEM - 111
The Central Themes of VB Theory Basic PrincipleA covalent bond forms when the orbitals of two atoms overlap and the overlap region, which is between the nuclei, is occupied by a pair of electrons with opposite spins. The two wave functions are in
Colorado State - CHEM - 111
Today's Topic: PolarityBond Polarity Molecular PolarityChemQuizFor the ketene molecule, what is the hybridization of the atom labeled C1? (A) sp (B) sp2 (C) sp3 (D) sp3d (E) sp3d2ChemQuizFor the ketene molecule, what is the hybridization of th
Colorado State - CHEM - 111
Colorado State - CHEM - 111
Today's Topic: Intermolecular ForcesObservation of PolarityH2O, waterCCl4, carbon tetrachloridepolarnonpolarWhich is/are polar?acetoneethanolhexaneWhich is/are polar?acetoneethanolhexaneMolecular Comparison of States of Ma
University of Florida - MAC - 2313
Colorado State - CHEM - 111
Dipoledipole forces tend to be stronger than London dispersion forces for similar sized molecules. Dipoledipole forces tend to be stronger than London dispersion forces for similar sized molecules.What's so special about H2O? H2O can exhib
Colorado State - CHEM - 111
mole(mol) the amount of a substance that contains the same number of entities as there are atoms in exactly 12 g of carbon12. This amount is 6.022x1023. The number is called Avogadro's number and is abbreviated as N. One mole (1 mol) contains 6.
Colorado State - CHEM - 111
Empirical and Molecular Formulas Empirical Formula The simplest formula for a compound that agrees with the elemental analysis and gives rise to the smallest set of whole numbers of atoms. Molecular Formula The formula of the compound as it exist
Colorado State - CHEM - 111
Limiting Reactants2H2(g) + O2(g) 2H2O(g)There is not enough H2 to react with all the O2 initially present. Some O2 is left over after the completion of the reaction. H2 is referred to as the limiting reactant or limiting reagent. O2 is ref
Colorado State - CHEM - 111
The effect of side reactions on yield.A + B(reactants)C(main product)D(side products) Actual Yield vs. Theoretical YieldTheoretical Yield: The amount of product that is calculated to form when all of the limiting reagent has reacte
Colorado State - CHEM - 111
Solutions A solution is a homogeneous mixture. It consists of two `parts': Solute the smaller amount of substance Solvent the larger amount of substanceIn this class we talk almost exclusively about aqueous solutions (i.e. solvent = water)
Colorado State - CHEM - 111
The Unusual Properties of WaterWater Molecular Weight (g/mol) State at Standard T and P Melting Point (C) Boiling Point (C) Methane 16 Gas 182 164 Carbon Dioxide 44 Gas 78.5 (subl) 56.6 (5.2 atm)18 Liquid 0 100Figure 4.1Electron distr
Colorado State - CHEM - 111
Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display.Sample Problem 4.1 Determining Moles of Ions in Aqueous Ionic Solutions PROBLEM: How many moles of each ion are in the following solutions? (a) 5.0 mol of amm
Colorado State - CHEM - 111
Acids are molecular compounds that dissociate in water to form an electrolyte solution containing anions and H+ cations. Bases are ionic or molecular compounds that generate OH ions in aqueous solution.Acidbase reaction (a.k.a. neutralization rea
Colorado State - CHEM - 111
4.29 Complete the following precipitation reactions with balanced molecular, total ionic, and net ionic equations. (b) FeSO4(aq) + Ba(OH)2(aq) > ? 4.29 Complete the following precipitation reactions with balanced molecular, total ionic
Colorado State - CHEM - 111
Colorado State - CHEM - 111
CHEM 111 Recitation Week #3 February 5th & 7th, 2008 (10 points) Some possibly useful informationName: ANSWER KEY Section:average atomic mass = [(isotope mass) x (fractional isotope abundance)] E = h = c En = 2.18 x 10-18J $" Z2 % 2' #n &h =
Colorado State - CHEM - 111
CHEM 111 Recitation Week 6 February 26th & 28th, 2008 (10 points)Name: Answer Key Section:1a. What is the general rule for determining whether a compound is ionic or covalent? (0.5 points) Ionic: between metals and nonmetals Covalent: between non
Colorado State - CHEM - 111
CHEM 111 Recitation Week 9 March 25th & 27th, 2008 (10 points)Name:KEYSection:Some possibly useful information Selected electronegativity values: B: 2.0; N: 3.0; O: 3.5; P: 2.1; S: 2.5; Cl: 3.0 1.000 lb = 453.6 g; Avogadro's number (NA): 6.022
Colorado State - CHEM - 111
Use the picture to answer questions 1-3. 1. This wave has the longest wavelength. 2. This wave has the lowest frequency. 3. This wave has the highest energy.4. Which atomic depiction below correctly represents the isotope 50Ti?22e 22p+ 28n022p+
Colorado State - CHEM - 111
CHEM 111 - Practice Test # 1 - Answer key 1. A 2. A 3. C 4. A 5. B 6. D 7. E 8. D 9. C 10. A 11. C 12. B 13. D 14. D 15. A 16. A 17. E 18. C 19. C 20. E 21. B 22. B 23. C 24. D 25. A
Colorado State - CHEM - 111
Additional Exam 1 Practice Problems (from textbook sections 8.0-8.4) (Answers are on the next page, don't peek!) 1. Select the correct ground-state electron configuration of sulfur (S). (A) (B) (C) (D) (E) 1s22s22p83s23p2 1s22s22p63s23p4 1s22s22p83s2
Colorado State - CHEM - 111
CHEM 111 - Practice Exam 2 March 4 & 6, 2008 PLEASE DO NOT WRITE ON THIS EXAM! SCRATCH PAPER IS AVAILABLE UPON REQEUST. For this exam, you will need a pencil, a TI-30Xa calculator and your CSU ID card. NO OTHER MATERIALS are allowed on your desk duri
University of Florida - MAC - 2313
Colorado State - CHEM - 111
Additional Exam 2 Practice Problems (from textbook sections 10.2, 11.0-11.2) (Answers are on the last page, don't peek!) Consider the following species in answering questions 1 4: i) H3O+ ii) SeF4 iii) CS2 iv) SiCl4v)ICl51. Which species use(s)
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SUNY Rockland - ENG - 102
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SUNY Rockland - ENG - 102
SUNY Rockland - ENG - 102