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Alfred University - ENGR - 103
Justin Zeh Dr. Leigh 1/30/2008 Problem #4RectangleSide Length 1 Side Length 2 Area Perimeter 7 4 28 22CircleRadius Area PerimeterRight TriangleSide Length 1 Side Length 2 Side Length 3 Area Perimeter
Alfred University - ENGR - 103
Justin Zeh Dr. Leigh 1/31/2008 Initial Tempature Heated Tempature Percentage Increase 20 21 0.39
Alfred University - ENGR - 103
Alfred University - ENGR - 103
1 2 34 345 67 123 23 3451 2 23 34 67 123 345
Alfred University - ENGR - 103
1 2 3 4 5 6 7 8 9 10
Alfred University - ENGR - 103
A 0.01B 0.02C 0.03D 0.04E 0.05F 0.06G 0.07H 0.08I 0.09J 0.1K 0.11L 0.12M 0.13N 0.14O 0.15P 0.16Q 0.17R 0.18S 0.19T 0.2U 0.21V 0.22W 0.23X 0.24Y 0.25Z 0.26[ 0.27\ 0.28] 0.29^ 0.3_ 0.31` 0.3
Alfred University - ENGR - 103
Helicopter Design Matrix Hel Split wing hole add 2 punch in paper each clips wing cut wing to pointDrop Times (seconds) 1 2 3Height (m) 5.9436 A 5.9436 B 5.9436 C 5.9436 D 5.9436 E 6.7056 F 5.9436 G 5.9436 H 5.9436 I 5.9436 J 5.9436 K 5.9436 L4
S. Connecticut - ECO - 221
2-Liter BottleSoft Drinks Filled at 95 % Level of Confidence Data Sample Standard Deviation Sample Mean Sample Size Confidence Level0.0446 2.00 50 95%Intermediate Calculations Standard Error of the Mean 0.006307392 Degrees of Freedom 49 t Value 2
S. Connecticut - ECO - 221
Utility Charge 82 90 95 96 102 108 109 111 114 116 119 123 127 128 129 130 130 135 137 139 141 143 144 147 148 149 149 150 151 153 154 157 158 163 165 166 167 168 171 172 175 178 183 185 187 191 197ClassesFreqRFDCRFMdptsRF*M79 up to 99
S. Connecticut - ECO - 221
Waiting Time 0.38 2.34 3.02 3.20 3.54 3.79 4.21 4.50 4.77 5.12 5.13 5.55 6.10 6.19 6.461 1 1 1 1 1 1 1 1 1 -2 1 1 1 1 1 0.975 0.975Mean 4.286667 0.95 4.286667 0.7 Median 4.5 0.95 4.5 0.7 1st Quartile 3.2 0.95 3.2 0.7 3rd Quartile 5.55 0.95 0 2 5.
S. Connecticut - ECO - 221
Reason for Job Interview Mistakes Survey of 150 PeopleUnprepared to discuss skills/experience3%Lack of eye contact5%Other reasons9%Limited enthusiasm16%Unprepared to discuss career plans23%Little or no knowledge of company44%
Marquette - CHEM - 102
Experiment#2 Student A Wavelength Jolyn M1P1 0 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60546 0.552 0.534 0.518 0.504 0.493 0.48 0.469 0.46 0.452 0.444 0.437 0.43 0.424 0.418 0.413 0.408 0.403 0.399 0.395 0.391 0.387Experiment#3 Stud
Marquette - CHEM - 101
90% Salicylic Acid vs. A/Mass8070y = 0.744x + 2.944 60A/mass (g)50403020100 0 20 40 60% Salicylic Acid80100120Standardization of NaOH Trial 1 2 3KHP mass (grams) 0.276 g 0.277 g 0.309 gNaOH Volume (mL) 14.00 mL 14.15
S. Connecticut - ECO - 221
Column1 Mean Standard Error Median Mode Standard Deviation Sample Variance Kurtosis Skewness Range Minimum Maximum Sum Count Largest(1) Smallest(1) Confidence Level(95.0%) 2.00072 0.006302254 2.004 2.012 0.044563662 0.00198592 0.080400572 0.008832396
S. Connecticut - ECO - 221
EMV EMV Probability of Fav R.R MKT Research No MKT Research 0.1 0 10000 0.2 5000 10000 0.3 10000 10000 0.4 15000 10000 0.5 20000 10000 0.6 25000 10000 0.7 30000 10000 0.8 35000 10000 0.9 40000 10000 1.0 45000 1000045000 40000 35000 EMV of MKT Resear
Marquette - CHEM - 101
X-values Y-values 1.1 6.3 1.4 8.7 1.6 10.2 1.9 12.1 2.2 15SUMMARY OUTPUT Regression Statistics Multiple R 0.997794 R Square 0.995593 Adjusted R Square 0.994124 Standard Error 0.253572 Observations 5 ANOVA df Regression Residual Total SS MS 1 43.579
Marquette - CHEM - 101
Test Tube 1 2 3 4 5 6*Color Intensity 10 6 1 0 0 0Personal Observations on Color Brightest Green Light, almost lime green Clear, with barely a hint of green No Color No Color No ColorSolvent HexaneTest Tube 1 2 3 4 5 6Number of Drops 20 14
S. Connecticut - ECO - 221
Scatter Diagram3.532.52 Y1.510.50 0 5 10 15 20 25XRegression Analysis Regression Statistics Multiple R 0.82700064 R Square 0.683930058 Adjusted R Square 0.652323064 Standard Error 0.308058436 Observations 12 ANOVA df Regression Res
Marquette - CHEM - 102
30Trial One of Unknown2520Conductivity15 y = -0.886x + 28.80y = 0.203x - 0.310 1050 0.00 5.00 10.00 15.00 20.00 25.00Volume (mL)30.0035.0040.0045.0050.0030Trial Two of Unknown2520Conductivity15 y = -0.833x + 30.
S. Connecticut - ECO - 221
Scatter Plot: Cell Phone Battery Capacity vs Talk Time5.04.54.03.53.0Talk Time2.52.01.51.00.50.0 0 200 400 600 800 1000 1200 1400 1600 1800Battery CapacityPg 69 # 22 Name Samsung SPH-N200 Nokia 6185 Sanyo SCP-4500 Kyocera
Marquette - CHEM - 102
Density Determination40 y = 1.1x - 0.5 353025 Mass, g20151050 0 5 10 15 20 25 30 35 40Volume, mLPart III Volume, mL 10.1 20 6.9 26.1 34.9 29 23.9 17.9Mass, g 10.366 21.119 7.066 27.705 37.396 31.001 25.389 18.87 40 35Density De
Marquette - CHEM - 102
16.00pH Titration of Unknown Acid14.0012.0010.00pH8.006.004.002.000.00 0 5 10 15 20 25Volume (mL)3035404550Determination of pKa of Unknown Acid3.0002.000y = 0.736x - 2.586 1.0000.000 -1.00 pH 0.00 1.00 2.00 3.0
Marquette - CHEM - 102
Part 1 Concentration of SCN- vs. Absorbance0.50.450.40.350.3Absorbance (nm) 0.25 y = 2993x + 0.022 0.2 Series1 Linear (Series1)0.150.10.050 0 0.00002 0.00004 0.00006 0.00008 0.0001 0.00012 0.00014 0.00016Concentration (M)Part 2
Marquette - CHEM - 102
Part One Metal Cu Zn Pb Ag Part Two Cathode Cu Zn Pb Ag Zn Mg Cu Pb Anode Volts -0.873 -0.852 0.488 -0.933 Solution Zn (NO3)2 MgSO4 Cu(NO3)2 Pb(NO3)2 Observations Nothing Nothing Solution turned green/turquoise Nothing
Marquette - CHEM - 102
Enthalpy of NaOH and HCl45.0 y = -0.007x + 40.26 40.035.0Temperature in Celsius30.0 y = -0.000x + 25.04 25.020.015.010.05.00.0 0 30 60 90 120 150 180 210 240 270 300 330 360 390 420 450 480Time in SecondsEnthalpy of Dilution of 2
Marquette - CHEM - 102
30.0Temperature Readings for Trial Oney = 29.529.529.028.528.0 Temperature (Celcius)27.527.026.5 y = -0.010x + 27.37 26.025.525.024.5 0 50 100Time (seconds)15020025030.0Temperature Readings for Trial Twoy = 29.529
Marquette - CHEM - 102
Trial 1400.0300.0200.0 y = 1.497x - 54.71 Volume (mL) 100.00.0 -150.0 -100.0 -50.0 0.0 50.0 100.0 150.0 200.0 250.0 300.0 350.0-100.0-200.0-300.0Temperature (Kelvins)Trial 2350.0300.0250.0200.0 Volume (mL) y = 0.709x + 22.51
Marquette - CHEM - 102
Job's Method1.600 1.400 Absorbancy 1.200 1.000 0.800 0.600 0.400 y = 5000x + 1.2090.200 0.000 0.000000y = -24636x + 1.550 0.000020 0.000040 0.000060 0.000080Moles of Reagent 2# Moles of Reagent 2 Absorbancy 0.000000 1.200 0.000005 1.254 0.000
Marquette - CHEM - 102
Part Well and Reactants I A1 + thymol blue A2 + thymol blue A3 + thymol blue A4 + thymol blue A5 + thymol blue A1 + 5 drops Na2SO4 A3 + NaHSO4 crystals A4 + hot water bath A4 + cold water bath A5 + cold water bath A5 + hot water bath II B1 + 10 drops
Marquette - CHEM - 102
Trial # 1 3 2Volume Drop(mL) Diameter of film(cm) Area(cm^3)Volume film(mL) Diameter of object(cm) Volume object(mL) 0.276 33.25 867.9 1.07E-04 1.23E-07 9.76E-22 0.276 31.75 791.3 1.07E-04 1.35E-07 1.29E-21 0.276 28.25 626.5 1.07E-04 1.70E-07 2.59E
Marquette - CHEM - 102
90.0Trial One Stearic Acidy = -0.074x + 78.93 y = -0.005x + 70.0280.070.060.0 Temperature (Celcius)50.040.030.020.010.00.0 0 100 200 300Time (seconds)40050060070090.0Trial 2 Stearic Acidy = -0.065x + 77.81 y = -0.00
Marquette - CHEM - 102
#3Name of Acid Paltimic AcidMolar Mass (g/mol) Pure Density(g/mL) Actual Density(g/mL) 256.4 0.852 0.808Name of Object Glass BeadsMolar Mass(g/mol) 5.02E+22Density(g/mL) 2.47(v/v)% concentration 0.0387% Mass (g) M water 126.187 M water+oi
Marquette - CHEM - 102
Pipet 1 2 3Trial #1 Number of #2 Trial Drops (drops per mL) Average Number of Drops/ mL Trial #3 Volume of One Drop (mL) 23 25 23 23.67 0.04225 28 28 30 28.67 0.03488 21 22 23 22 0.04545Well # # drops of 0.20 Ni(NO3)2 # drops of 0.10 NaOH Moles N
Marquette - CHEM - 102
First Titration Mass of KHP Initial Buret Reading Final Buret Reading Volume NaOH Used Molarity of NaOH Average Molarity of NaOH Standard Deviation Relative Standard Deviation Second Titration Volume of Vinegar Initial Buret Reading Final Buret Readi
UWO - MOS - 398
T0 0.00Ti 0.10Change in T 0.10Risk-Free Rate So 0.05100Volatility Exercise Price 0.15 1050123109.95141 4.9514072 104.858 1.8596 100 1.954944353 95.3673 0 90.949268 0 100 0115.292535 10.29253496 1 1 104.8577166 0 1 1 95.36732562
UWO - MOS - 398
T0 0.00Ti 0.10Change in T 0.10Risk-Free Rate So 0.05100Volatility Exercise Price 0.15 1050123109.95141 4.9514072 104.858 1.8156 100 1.908685777 95.3673 0 90.949268 0 100 0115.292535 10.29253496 1 1 104.8577166 0 1 1 95.36732562
UWO - MOS - 398
T 1 55.70 0#TimeSteps Change in T 10 0.10r 0.05So 100.00Volatility 0.15K 105.00123456132.92 30.00 126.77 24.46 120.89 19.44 115.29 15.08 1.00 1.00 104.86 7.24 1.00 1.00 95.37 2.58 115.29 13.75 109.95 10.10 1.00 100.00 3.95 1.0
UWO - MOS - 398
T 1 55.70 0#TimeSteps Change in T 10 0.10r 0.05So 100.00Volatility 0.15K 105.00123456132.92 30.00 126.77 24.46 120.89 19.44 115.29 15.08 1.00 1.00 104.86 7.24 1.00 1.00 95.37 2.58 115.29 13.75 109.95 10.10 1.00 100.00 3.95 1.0
UWO - MOS - 398
Question One Maturity (years) Zero Rate (%) (Cont. Comp.) 1 5.00% 2 5.25% 3 5.50% 4 5.75% 5 6.00% (used formula on page 83)Forward rate for nth year 5.00% 5.50% 6.00% 6.50% 7.00%Question 2 Date 1 2 3 4 5 LIBOR (1 year) 5.00% 5.50% 6.00% 6.50% 7.0
United States Merchant Marine Academy - NAVSCIENCE - hs101
DATA SHEET - EXPERIMENT 9 (Ver 4th Ed.) INTERFERENCE AND DIFFRACTION OF LIGHT Date: 27-Mar-08 Mid'n 1: Mid'n 2: Mid'n 3: Mid'n 4: Nick Aswad Nick Chester Judd Connell John Fieldsl LASER [ nm ] =D [ cm ] =632.8 50 dl LASER dD0.05 0.5 0.005 0
Winthrop - CHEM - 303
E strain of E strain of E strain of E strain of E strain of E strain of E strain of E strain ofkJ/mol Eclipsed Ethane Staggered Ethane Gauche Butane Anti Butane Chair Cyclohexane Boat Cyclohexane Diaxial trans -1,4-dimethylcyclohexane Diequitorial
Cincinnati - RE - RE Finance
Real Estate Finance Homework #6 SolutionsProblem #1 a.Assumptions: NOI Years 1-8 Resale Cap Rate Discount Rate (Required Rate of Return) Holding Period = See below 10% on Year 8 NOI 12% 7 yearsYearNOI Resale Value Total Cash Flow NPV =01$ 1
Cincinnati - RE - RE Finance
Real Estate Finance Homework #7 - Land Development Financing Schedule 1 - Summary of Assumptions Acreage Timing Construction period Absorption period Sales Assumtions Average sales price per acre Selling cost Land Absorption Schedule: Acres Sold Year
Cincinnati - RE - RE Finance
Real Estate Finance Homework #4 SolutionsQuestion #1House Price Loan to Value Ratio Loan Amount Terms Rate Amortization Payment Monthly Annual Salary Mr. Midwest Mrs. Midwest Total Qualified Income Housing Expenses Principal & Interest RE Taxes Pr
Cincinnati - RE - RE Finance
Real Estate Finance Homework #2 SolutionsProblem #1: ARM A PV = I= N= PMT Yr 1 = ARM B PV = I= N= PMT Yr 1 = ARM C PV = I= N= PMT Yr 1 = $ 150,000 6.00% 300 ($966.45) PMT Yr 1 = ($966.45) I= 6.00% N= 288 PV = $147,329.94 balance EOY 1 PV = I= N= PMT
Cincinnati - RE - RE Finance
Real Estate Finance Homework #1 Solutions Fall 2007Problem #1 a P/Yr = PV = I= N= PMT = 12 $ 350,000 7.0% 300 (2,473.73)Problem #1 b PMT = $2,473.73 Annual Debt Service = $ 29,685 Loan Amt = $ 350,000 ADS/Loan Amt = 0.0848 K Problem #1 c Interest
Cincinnati - RE - RE Finance
Real Estate Finance Homework #3 SolutionsFall 2007 Problem 1 (a) House price = Loan A $ $ 120,000 80% 96,000 9.00% 25 ($805.63) 12,000 ($137.96) 300 13.29%loan loan amount rate year amort Monthly pmtLoan B $90% 108,000 9.50% 25 ($943.59)loan
WVU - LDR - 201
Do You Have What It Takes?Group 7 Leadership 201Have a dream and make it a reality.
Temple - CHEM - 1034
0.9 1.2 1.4 1.6 1.9 2.1 2.3 2.6 2.8 3 3.2 3.5 3.7 4 4.4 4.7 4.9 5.2 5.4 5.7 5.9 6.1 6.5 6.7 6.81.92 1.91 1.91 1.93 1.98 2.03 2.06 2.17 2.21 2.32 2.42 2.66 3.07 5.19 6.13 6.35 6.49 6.74 6.84 6.99 7.16 7.34 7.62 7.9 8.239 8 7 6 5 4 3 2 1 0H3PO4 T
Luther - ECON - 242
Robert Garrett Pretest 32 31 29 10 30 33 22 25 32 20 30 20 24 24 31 30 15 32 23 23 Posttest Differences t-Test: Paired Two Sample for Means 34 2 31 0 Posttest Pretest 35 6 Mean 28.3 25.8 16 6 Variance 35.37895 39.74737 33 3 Observations 20 20 36 3 Pe
Luther - ACCTG - 250
Assumptions Direct materials cost per unit Direct manufacturing labor per unit Variable manufacturing overhead per unit Total Inspection, setup materials handling Total Machine lease Total Allocated fixed plant admin. Units produced Analysis Variable
Luther - ECON - 242
Robert Garrett Econ 242 Excel Charts Moral values Economy/jobs Terrorism Iraq Health care Taxes Eductaion Other 22 20 19 15 8 5 4 7Voter Issues2520151050Voter IssuesEductaion 4% Taxes 5% Health care 8% Economy/jobs 20% Other 7% Moral val
Luther - ECON - 242
Robert Garrett Econ 242 Discrete Probability Distributions PORTFOLIO SELECTION Event P(Event) A B C Economy Declines 0.3 500 -2000 -7000 No Change 0.5 1000 2000 -1000 Economy Expands 0.2 2000 5000 20000 E(X) 1050 1400 1400 VAR(X) 272500 6240000 93240
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 2B-3AP2-39 1 The company is now using a differentiation strategy. They are now participating in high end markets where technological sophistication and high quality materials are necessary. 2 Activity Produce or acquire pu
Luther - ECON - 242
SUMMARY OUTPUT Regression Statistics Multiple R 0.816421 R Square 0.666542 Adjusted R Square 0.629492 Standard Error 1.236603 Observations 11 ANOVA df Regression Residual Total SS MS F Significance F 1 27.51 27.51 17.98994 0.00217 9 13.76269 1.529188
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 6BP6-38 Month January February March April May June July August September October November December Temp 31 41 43 44 46 50 53 60 50 40 30 20 Cost 760 629 543 410 275 233 220 210 305 530 750 870High pointLow pointAnte
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 6AE6-26 1 2 3 4 5 6 7 8 9 10 11 12 E6-31B F E I E H L A J K C or D G I would choose Regression 1. It has a reasonably high R-square and low SE compared to the other two options has better t-value scores.E6-32 Month 1 2
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 5DP5-62 1 Pool Purchasing Materials handling Quality control Roasting Blending Packaging Cost 579,000 720,000 144,000 961,000 336,000 260,000Units of Driver 1,400 2,400 1,200 100,000 36,000 30,000Rate 413.57 300.00 120
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 5CE5-41 a b c d e f g h I Activity Report for duty and review patient charts Visit each patient and take her/his temperature Update patients' records Coordinate lab and radiology works Wait for the attending physician to a
Luther - ACCTG - 250
ACCT 250 HOMEWORK CHAPTER 6CP6-52 Complexes 1 2 4 8 Learning rate Average Time 17.0 13.6 10.9 8.7 80% 26.1 4 6.5 Total Time 17.0 27.2 43.5 69.6 Incremental Time N/A 10.2 16.3 26.1Time for last four complexes Divide by number of complexes Time per
Luther - ACCTG - 250
ACCT 250 EXCEL EXAMPLE CHAPTER 6B EXAMPLEMonth 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 Analyses 2 4 2 1 2 1 1 2 2 1 2 2 4 4 30 Accounts Paychecks 325 1,029 310 993 302 1,268 213 1,028 222 984 214 712 131 762 123 739 115 708 296 1,232 213 978 222 929