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Course: BUAD 306, Fall 2007
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14 CHAPTER OPTIONS AND CORPORATE FINANCE Answers to Concepts Review and Critical Thinking Questions 1. A call option confers the right, without the obligation, to buy an asset at a given price on or before a given date. A put option confers the right, without the obligation, to sell an asset at a given price on or before a given date. You would buy a call option if you expect the price of the asset to increase....

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14 CHAPTER OPTIONS AND CORPORATE FINANCE Answers to Concepts Review and Critical Thinking Questions 1. A call option confers the right, without the obligation, to buy an asset at a given price on or before a given date. A put option confers the right, without the obligation, to sell an asset at a given price on or before a given date. You would buy a call option if you expect the price of the asset to increase. You would buy a put option if you expect the price of the asset to decrease. A call option has unlimited potential profit, while a put option has limited potential profit; the underlying asset's price cannot be less than zero. 2. a. b. c. d. The buyer of a call option pays money for the right to buy.... The buyer of a put option pays money for the right to sell.... The seller of a call option receives money for the obligation to sell.... The seller of a put option receives money for the obligation to buy.... 3. 4. The intrinsic value of a call option is Max [S E,0]. It is the value of the option at expiration. The value of a put option at expiration is Max[E S,0]. By definition, the intrinsic value of an option is its value at expiration, so Max[E S,0] is the intrinsic value of a put option. The call is selling for less than its intrinsic value; an arbitrage opportunity exists. Buy the call for $10, exercise the call by paying $35 in return for a share of stock, and sell the stock for $50. You've made a riskless $5 profit. The prices of both the call and the put option should increase. The higher level of downside risk still results in an option price of zero, but the upside potential is greater since there is a higher probability that the asset will finish in the money. False. The value of a call option depends on the total variance of the underlying asset, not just the systematic variance. The call option will sell for more since it provides an unlimited profit opportunity, while the potential profit from the put is limited (the stock price cannot fall below zero). The value of a call option will increase, and the value of a put option will decrease. 5. 6. 7. 8. 9. 10. The reason they don't show up is that the U.S. government uses cash accounting; i.e., only actual cash inflows and outflows are counted, not contingent cash flows. From a political perspective, they would make the deficit larger, so that is another reason not to count them! Whether they should be included depends on whether we feel cash accounting is appropriate or not, but these contingent liabilities should be measured and reported. They currently are not, at least not in a systematic fashion. 11. The option to abandon reflects our ability to shut down a project if it is losing money. Since this option acts to limit losses, we will underestimate NPV if we ignore it. B-246 SOLUTIONS 12. The option to expand reflects our ability to increase production if the new product sells more than we initially expected. Since this option increases the potential future cash flows beyond our initial estimate, we will underestimate NPV if we ignore it. 13. This is a good example of the option to expand. 14. With oil, for example, we can simply stop pumping if prices drop too far, and we can do so quickly. The oil itself is not affected; it just sits in the ground until prices rise to a point where pumping is profitable. Given the volatility of natural resource prices, the option to suspend output is very valuable. 15. There are two possible benefits. First, awarding employee stock options may better align the interests of the employees with the interests of the stockholders, lowering agency costs. Secondly, if the company has little cash available to pay top employees, employee stock options may help attract qualified employees for less pay. Solutions to Questions and Problems NOTE: All end of chapter problems were solved using a spreadsheet. Many problems require multiple steps. Due to space and readability constraints, when these intermediate steps are included in this solutions manual, rounding may appear to have occurred. However, the final answer for each problem is found without rounding during any step in the problem. Basic 1. a. The value of the call is the stock price minus the present value of the exercise price, so: C0 = $55 [$45/1.062] = $12.63 The intrinsic value is the amount by which the stock price exceeds the exercise price of the call, so the intrinsic value is $10. b. The value of the call is the stock price minus the present value of the exercise price, so: C0 = $55 [$35/1.062] = $22.04 The intrinsic value is the amount by which the stock price exceeds the exercise price of the call, so the intrinsic value is $20. c. The value of the put option is $0 since there is no possibility that the put will finish in the money. The intrinsic value is also $0. The calls are in the money. The intrinsic value of the calls is $4. The puts are out of the money. The intrinsic value of the puts is $0. 2. a. b. CHAPTER 14 B-247 c. The Mar call and the Oct put are mispriced. The call is mispriced because it is selling for less than its intrinsic value. If the option expired today, the arbitrage strategy would be to buy the call for $2.80, exercise it and pay $90 for a share of stock, and sell the stock for $94. A riskless profit of $1.20 results. The October put is mispriced because it sells for less than the July put. To take advantage of this, sell the July put for $3.90 and buy the October put for $3.65, for a cash inflow of $0.25. The exposure of the short position is completely covered by the long position in the October put, with a positive cash inflow today. Each contract is for 100 shares, so the total cost is: Cost = 10(100 shares/contract)($8.05) Cost = $8,050 3. a. b. If the stock price at expiration is $130, the payoff is: Payoff = 10(100)($130 110) Payoff = $20,000 If the stock price at expiration is $118, the payoff is: Payoff = 10(100)($118 110) Payoff = $8,000 c. Remembering that each contract is for 100 shares of stock, the cost is: Cost = 10(100)($5.15) Cost = $5,150 The maximum gain on the put option would occur if the stock price goes to $0. We also need to subtract the initial cost, so: Maximum gain = 10(100)($110) $5,150 Maximum gain = $104,850 If the stock price at expiration is $104, the position will be worth: Position value = 10(100)($110 104) Position value = $6,000 And your profit will be: Profit = $6,000 5,150 Profit = $850 d. At a stock price of $103 the put is in the money. As the writer you will make: Net gain(loss) = $5,150 10(100)($110 103) Net gain(loss) = $1,850 B-248 SOLUTIONS At a stock price of $132 the put is out of the money, so the writer will make the initial cost: Net gain = $5,150 At the breakeven, you would recover the initial cost of $5,150, so: $5,150 = 10(100)($110 ST) ST = $104.85 For terminal stock prices above $104.85, the writer of the put option makes a net profit (ignoring transaction costs and the effects of the time value of money). 4. a. The value of the call is the stock price minus the present value of the exercise price, so: C0 = $80 75/1.06 C0 = $9.25 b. Using the equation presented in the text to prevent arbitrage, we find the value of the call is: $80 = [($93 77)/($93 85)]C0 + $77/1.06 C0 = $3.68 5. a. The value of the call is the stock price minus the present value of the exercise price, so: C0 = $75 $45/1.05 C0 = $32.14 b. Using the equation presented in the text to prevent arbitrage, we find the value of the call is: $75 = [($96 65)/($85 70)]C0 + $65/1.05 C0 = $9.82 6. Each option contract is for 100 shares of stock, so the price of a call on one share is: C0 = $1,200/100 shares per contract C0 = $12 Using the no arbitrage model, we find that the price of the stock is: S0 = $12[($65 45)/($65 60)] + $45/1.09 S0 = $89.28 7. a. The equity can be valued as a call option on the firm with an exercise price equal to the value of the debt, so: E0 = $1,040 [$1,000/1.06] E0 = $96.60 CHAPTER 14 B-249 b. The current value of debt is the value of the firm's assets minus the value of the equity, so: D0 = $1,040 96.60 D0 = $943.40 We can use the face value of the debt and the current market value of the debt to find the interest rate, so: Interest rate = [$1,000/$943.40] 1 Interest rate = .06 or 6% c. The value of the equity will increase. The debt then requires a higher return; therefore the present value of the debt is less while the value of the firm does not change. Using the no arbitrage valuation model, we can use the current market value of the firm as the stock price, and the par value of the bond as the strike price to value the equity. Doing so, we get: $1,200 = [($1,500 900)/($1,500 1,000)]E0 + [$900/1.06] E0 = $299.07 The current value of the debt is the value of the firm's assets minus the value of the equity, so: D0 = $1,200 299.07 D0 = $900.93 8. a. b. Using the no arbitrage model as in part a, we get: $1,200 = [($1,700 700)/($1,700 1,000)]E0 + [$700/1.06] E0 = $382.06 The stockholders will prefer the new asset structure because their potential gain increases while their maximum potential loss remains unchanged. 9. The conversion ratio is the par value divided by the conversion price, so: Conversion ratio = $1,000/$40 Conversion ratio = 25.00 The conversion value is the conversion ratio times the stock price, so: Conversion value = 25.00($55) Conversion value = $1,375.00 B-250 SOLUTIONS 10. a. The minimum bond price is the greater of the straight bond value or the conversion price. The straight bond value is: Straight bond value = $32.50(PVIFA4%,40) + $1,000/1.0440 Straight bond value = $851.55 The conversion ratio is the par value divided by the conversion price, so: Conversion ratio = $1,000/$50 Conversion ratio = 20 The conversion value is the conversion ratio times the stock price, so: Conversion value = 20($38) Conversion value = $760.00 The minimum value for this bond is the straight bond value of $851.55. b. 11. a. The option embedded in the bond adds the extra value. The minimum bond price is the greater of the straight bond value or the conversion value. The straight bond value is: Straight bond value = $70(PVIFA9%,30) + $1,000/1.0930 Straight bond value = $794.53 The conversion ratio is the par value divided by the conversion price, so: Conversion ratio = $1,000/$60 Conversion ratio = 16.67 The conversion price is the conversion ratio times the stock price, so: Conversion value = 16.67($50) Conversion value = $833.33 The minimum value for this bond is the convertible floor value of $833.33. b. The conversion premium is the difference between the current stock price and conversion price, divided by the current stock price, so: Conversion premium = ($60 50)/$50 = .20 or 20% CHAPTER 14 B-251 12. The value of the bond without warrants is: Straight bond value = $105(PVIFA12%,15) + $1,000/1.1215 Straight bond value = $897.84 The value of the warrants is the selling price of the bond minus the value of the bond without warrants, so: Total warrant value = $1,000 897.84 Total warrant value = $102.16 Since the bond has 20 warrants attached, the price of each warrant is: Price of one warrant = $102.16/20 Price of one warrant = $5.11 13. If we purchase the machine today, the NPV is the cost plus the present value of the increased cash flows, so: NPV0 = $2,000,000 + $350,000(PVIFA12%,10) NPV0 = $22,421.94 We should not purchase the machine today. We would want to purchase the machine when the NPV is the highest. So, we need to calculate the NPV each year. The NPV each year will be the cost the plus present value of the increased cash savings. We must be careful however. In order to make the correct decision, the NPV for each year must be taken to a common date. We will discount all of the NPVs to today. Doing so, we get: Year 1: NPV1 = [$1,840,000 + $350,000(PVIFA12%,9)] / 1.12 NPV1 = $22,220.92 Year 2: NPV2 = [$1,680,000 + $350,000(PVIFA12%,8)] / 1.122 NPV2 = $46,774.49 Year 3: NPV3 = [$1,520,000 + $350,000(PVIFA12%,7)] / 1.123 NPV3 = $55,031.14 Year 4: NPV4 = [$1,360,000 + $350,000(PVIFA12%,6)] / 1.124 NPV4 = $50,201.20 Year 5: NPV5 = [$1,200,000 + $350,000(PVIFA12%,5)] / 1.125 NPV5 = $34,994.16 Year 6: NPV6 = [$1,200,000 + $350,000(PVIFA12%,4)] / 1.126 NPV6 = $69,371.85 The company should purchase the machine three years from now when the NPV is the highest. B-252 SOLUTIONS Intermediate 14. a. The base-case NPV is: NPV = $1,800,000 + $455,000(PVIFA16%,10) NPV = $399,118.50 b. We would abandon the project if the cash flow from selling the equipment is greater than the present value of the future cash flows. We need to find the sale quantity where the two are equal, so: $1,400,000 = ($65)Q(PVIFA16%,9) Q = $1,400,000/[$65(4.6065)] Q = 4,676 Abandon the project if Q < 4,676 units, because the NPV of abandoning the project is greater than the NPV of the future cash flows. c. The $1,400,000 is the market value of the project. If you continue with the project in one year, you forego the $1,400,000 that could have been used for something else. If the project is a success, present value of the future cash flows will be: PV future CFs = $65(9,000)(PVIFA16%,9) PV future CFs = $2,694,828.17 From the previous question, if the quantity sold is 4,000, we would abandon the project, and the cash flow would be $1,400,000. Since the project has an equal likelihood of success or failure in one year, the expected value of the project in one year is the average of the success and failure cash flows, plus the cash flow in one year, so: Expected value of project at year 1 = [($2,694,828.17 + $1,400,000)/2] + $455,000 Expected value of project at year 1 = $2,502,414.08 The NPV is the present value of the expected value in one year plus the cost of the equipment, so: NPV = $1,800,000 + ($2,502,414.08)/1.16 NPV = $357,253.52 15. a. b. If we couldn't abandon the project, the present value of the future cash flows when the quantity is 4,000 will be: PV future CFs = $65(4,000)(PVIFA16%,9) PV future CFs = $1,197,701.41 The gain from the option to abandon is the abandonment value minus the present value of the cash flows if we cannot abandon the project, so: Gain from option to abandon = $1,400,000 1,197,701.41 Gain from option to abandon = $202,298.59 CHAPTER 14 B-253 We need to find the value of the option to abandon times the likelihood of abandonment. So, the value of the option to abandon today is: Option value = (.50)($202,298.59)/1.16 Option value = $87,197.67 16. If the project is a success, present value of the future cash flows will be: PV future CFs = $65(18,000)(PVIFA16%,9) PV future CFs = $5,389,656.33 If the sales are only 4,000 units, from Problem #14, we know we will abandon the project, with a value of $1,400,000. Since the project has an equal likelihood of success or failure in one year, the expected value of the project in one year is the average of the success and failure cash flows, plus the cash flow in one year, so: Expected value of project at year 1 = [($5,389,656.33 + $1,400,000)/2] + $455,000 Expected value of project at year 1 = $3,849,828.17 The NPV is the present value of the expected value in one year plus the cost of the equipment, so: NPV = $1,800,000 + $3,849,828.17/1.16 NPV = $1,518,817.39 The gain from the option to expand is the present value of the cash flows from the additional units sold, so: Gain from option to expand = $65(9,000)(PVIFA16%,9) Gain from option to expand = $2,694,828.17 We need to find the value of the option to expand times the likelihood of expansion. We also need to find the value of the option to expand today, so: Option value = (.50)($2,694,828.17)/1.16 Option value = $1,161,563.87 17. a. The value of the call is the maximum of the stock price minus the present value of the exercise price, or zero, so: C0 = Max[$75 ($85/1.05),0] C0 = $0 The option isn't worth anything. b. The stock price is too low for the option to finish in the money. The minimum return on the stock required to get the option in the money is: Minimum stock return = ($85 75)/$75 Minimum stock return = .1333 or 13.33% which is much higher than the risk-free rate of interest. B-254 SOLUTIONS 18. B is the more typical case; A presents an arbitrage opportunity. You could buy the bond for $800 and immediately convert it into stock that can be sold for $1,000. A riskless $200 profit results. 19. a. The conversion ratio is given at 25. The conversion price is the par value divided by the conversion ratio, so: Conversion price = $1,000/25 Conversion price = $40 The conversion premium is the percent increase in stock price that results in no profit when the bond is converted, so: Conversion premium = ($40 36)/$36 Conversion premium = .1111 or 11.11% b. The straight bond value is: Straight bond value = $35(PVIFA5%,20) + $1,000/1.0520 Straight bond value = $813.07 And the conversion value is the conversion ratio times the stock price, so: Conversion value = 25($36) Conversion value = $900.00 c. We simply need to set the straight bond value equal to the conversion ratio times the stock price, and solve for the stock price, so: $813.07 = 25S S = $32.52 d. There are actually two option values to consider with a convertible bond. The conversion option value, defined as the market value less the floor value, and the speculative option value, defined as the floor value less the straight bond value. When the conversion value is less than the straight-bond value, the speculative option is worth zero. Conversion option value = $950 900 = $50 Speculative option value = $900 813.07 = $86.93 Total option value = $50.00 + 86.93 = $136.93 20. a. The NPV of the project is the sum of the present value of the cash flows generated by the project. The cash flows from this project are an annuity, so the NPV is: NPV = $100,000,000 + $25,000,000(PVIFA20%,10) NPV = $4,811,802.14 CHAPTER 14 B-255 b. The company should abandon the project if the PV of the revised cash flows for the next nine years is less than the project's aftertax salvage value. Since the option to abandon the project occurs in year 1, discount the revised cash flows to year 1 as well. To determine the level of expected cash flows below which the company should abandon the project, calculate the equivalent annual cash flows the project must earn to equal the aftertax salvage value. We will solve for C2, the revised cash flow beginning in year 2. So, the revised annual cash flow below which it makes sense to abandon the project is: Aftertax salvage value = C2(PVIFA20%,9) $50,000,000 = C2(PVIFA20%,9) C2 = $50,000,000 / PVIFA20%,9 C2 = $12,403,973.08 Challenge 21. The straight bond value today is: Straight bond value = $72(PVIFA10%,25) + $1,000/1.1025 Straight bond value = $745.84 And the conversion value of the bond today is: Conversion value = $38.50($1,000/$160) Conversion value = $240.63 We expect the bond to be called when the conversion value increases to $1,300, so we need to find the number of periods it will take for the current conversion value to reach the expected value at which the bond will be converted. Doing so, we find: $240.63(1.11)t = $1,300 t = 16.16 years The bond will be called in 16.16 years. The bond value is the present value of the expected cash flows. The cash flows will be the annual coupon payments plus the conversion price. The present value of these cash flows is: Bond value = $72(PVIFA10%,16.16) + $1,300/1.1016.16 = $844.27 B-256 SOLUTIONS 22. We will use the bottom up approach to calculate the operating cash flow. Assuming we operate the project for all four years, the cash flows are: Year Sales Operating costs Depreciation EBT Tax Net income +Depreciation Operating CF Change in NWC Capital spending Total cash flow 0 1 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 2 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 3 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 4 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 $750,000 0 $4,643,000 $750,000 $9,000,000 $9,750,000 There is no salvage value for the equipment. The NPV is: NPV = $9,750,000 + $3,893,000(PVIFA16%,3) + $4,643,000/1.164 NPV = $1,557,535.55 b. The cash flows if we abandon the project after one year are: Year Sales Operating costs Depreciation EBT Tax Net income +Depreciation Operating CF Change in NWC Capital spending Total cash flow 0 1 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 $750,000 $6,595,000 $11,238,000 $750,000 $9,000,000 $9,750,000 The book value of the equipment is: Book value = $9,000,000 (1)($9,000,000/4) Book value = $6,750,000 CHAPTER 14 B-257 So, the taxes on the salvage value will be: Taxes = ($6,750,000 6,500,000)(.38) Taxes = $95,000 This makes the aftertax salvage value: Aftertax salvage value = $6,500,000 + 95,000 Aftertax salvage value = $6,595,000 The NPV if we abandon the project after one year is: NPV = $9,750,000 + $11,238,000/1.16 NPV = $62,068.97 If we abandon the project after two years, the cash flows are: Year Sales Operating costs Depreciation EBT Tax Net income +Depreciation Operating CF Change in NWC Capital spending Total cash flow 0 1 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 2 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 $750,000 $5,430,000 $10,073,000 $750,000 $9,000,000 $9,750,000 The book value of the equipment is: Book value = $9,000,000 (2)($9,000,000/4) Book value = $4,500,000 So the taxes on the salvage value will be: Taxes = ($4,500,000 6,000,000)(.38) Taxes = $570,000 This makes the aftertax salvage value: Aftertax salvage value = $6,000,000 570,000 Aftertax salvage value = $5,430,000 B-258 SOLUTIONS The NPV if we abandon the project after two years is: NPV = $9,750,000 + $3,893,000/1.16 + $10,073,000/1.162 NPV = $1,091,914.39 If we abandon the project after three years, the cash flows are: Year Sales Operating costs Depreciation EBT Tax Net income +Depreciation Operating CF Change in NWC Capital spending Total cash flow 0 1 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 2 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 0 0 $3,893,000 3 $8,500,000 3,600,000 2,250,000 $2,650,000 1,007,000 $1,643,000 2,250,000 $3,893,000 $750,000 $3,645,000 $8,288,000 $750,000 $9,000,000 $9,750,000 The book value of the equipment is: Book value = $9,000,000 (3)($9,000,000/4) Book value = $2,250,000 So the taxes on the salvage value will be: Taxes = ($2,250,000 4,500,000)(.38) Taxes = $855,000 This makes the aftertax salvage value: Aftertax salvage value = $4,500,000 855,000 Aftertax salvage value = $3,645,000 The NPV if we abandon the project after three years is: NPV = $9,750,000 + $3,893,000(PVIFA16%,2) + $8,288,000/1.163 NPV = $1,808,978.46 We should abandon the equipment after three years since the NPV of abandoning the project after three years has the highest NPV.
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yp968 Homework 8 Radin (58415) This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 If the points3 1 (0, 1), ( 2 , 5), (1, 2), ( 2 , 2), (2, 5)1Use
University of Texas - M - 408L
yp968 Homework 4 Radin (58415) This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points 5. V = 6. V = 7 cu. units 15 5 cu. units 12 003 10.0 poi
University of Texas - M - 408L
yp968 Homework 7 Radin (58415) This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points keywords: 3x2 dx . 4 - x2 002 10.0 points Consequently, I
University of Texas - M - 408L
Version 106 Homework 01 Radin (58415) This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. Welcome to Quest Learning and Assessment. Best of luck this semest
University of Texas - M - 408L
yp968 Homework 6 Radin (58415) This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Determine the integral I = x(ln x)2 dx .11. I = 2. I
University of Texas - M - 408L
Version PREVIEW EXAM 2 Zheng (58355) This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. CalC7g49b 001 10.0 points Determine if (ln x)2 lim x 3x + 6 ln x
University of Texas - M - 408L
yp968 Homework 9 Radin (58415) This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points 2. fx = -2 sin(3y - x) - x cos(3y - x) 3. fx = x cos(3y -
University of Texas - M - 408L
yp968 Homework 5 Radin (58415) This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points 1 dx . 1 + 4(x - 1)2 x-1 +C 2 1. I = 2. I = 3 2 9 81
University of Texas - M - M408L
Version 120 EXAM 2 Radin (58415) This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 Determine ifx1Consequently, the limit exists and lim (ln x)2 =
CUNY Queens - ENGL - 110H
Erica Rodriguez Aids in New York City10/23/07Formatted: JustifiedAn epidemic developed in the 1980's in the United States that has had no end. This epidemic is AIDS (Acquired Immune Deficiency Syndrome): an untreatable, untraceable disease, whi
CUNY Queens - HNRS - 126
10/17/2007 1:54:00 PM Catharsis is anything that brings about an extreme emotional reaction or peace. And you should have fear because it might happen to you. Cyrsanthium and electra are character foils Look up Martha Gram and Pascal Dance 19th centu
CUNY Queens - HNRS - 126
Overture -At the beginning. -Summarizes themes of the opera. -All instrumental -when they sing at the same time its called a &quot;tutti&quot; -richititivo- conversation + singing -Piano- 19th century instrument, felt covered hammers that hits the string -Harp
CUNY Queens - PSYCH - 101
Psych 1011/30/2008 1:36:00 PMGestalt Psychology Interested in consciousness as it arises in perception Looking at the whole; not how it comes together or individual parts Behaviorism Early 1900s Founded by John B. Watson Psychology should study o
Sewanee - BIO - 132
39.4 Explain how the neuron develops and maintains a resting potential. Neurons use electrical signals to transmit information. In a resting neuron, one that is not transmitting an impulse, the inner surface of the plasma membrane is negatively charg
Elon - JCM - 200
Media &amp; Politics &amp; Books(Ch. 6 &amp; 7)3/7/2008 8:51:00 AM THE ROLE OF THE MEDIA (&quot;THE FOURTH ESTATE&quot;) The Role of the Media:To survey a socio-political environment (p.88 in the book) The Watchdog Function The role of the media has changed as the main
Elon - JCM - 200
Magazines (March 12, 2008)3/12/2008 7:53:00 AMMagazines have to broker to the newsstands in order to get their magazines sold WHAT IS A MAGAZINE? It's an Arabic word, that was first used by the British and would publish literary works, government
Elon - JCM - 200
Advertising3/17/2008 7:55:00 AMN.C Ayers (sp?) said you can judge a company by looking at its advertising WHAT IS ADVERTISING? Smoking is an example of the success of advertising Public Relations is more broad than advertising Advertising is more
Baylor - ENG - 1304
Eubanks 1 Bailey Eubanks English 1304 Mr. Reiter February 26, 2008 A Step Toward the Future: Cloning All throughout Hollywood cloning has played a major role in numerous films; from The Island all the way to Multiplicity this invigorating idea of clo
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Fall 2002 Second MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and
Blue Mountain College - AD - 220
Henry Ford and the Model T: A Case Study in Productivity People often credit Henry Ford with inventing the automobile and the assembly line. In fact, he did neither! What Mr. Ford actually did was change the way manufacturers operate. Henry Ford brou
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Fall 2004 First MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Fall 2003 Final ExamThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and the
Blue Mountain College - MATH - 201
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Spring 2004 Second MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions a
Blue Mountain College - MATH - 201
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Fall 2005 First MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Spring 2002 Final ExamThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and t
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Spring 2004 Second MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions a
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Fall 2004 Second MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Spring 2004 Final ExamThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions and t
Blue Mountain College - MATH - 201
B U Department of MathematicsMath 201 Matrix Theory Spring 2005 Second MidtermThis archive is a property of Boazii University Mathematics Department. The purpose of this archive is to organise and centralise the distribution of the exam questions a
Mercyhurst - BUS - 101
Types of Checks Check- A draft drawn by a depositor ordering a bank to pay a sum certain of money. Cashier's Check- A check drawn by the bank on itself, rather than on a drawer's account, which constitutes the bank's promise to pay the payee on prese
Mercyhurst - BUS - 101
Warrants of Title Good Title- Except where disclaimed, sellers warrant that they have good and valid title that can be transferred to the buyer. Quiet Possession- Lessees warrant that they are the only ones with title to the property. No Liens- Selle
Mercyhurst - BUS - 101
April 9, 2008 NotesTypes of monetary damages -A breach of contract entitles the non-breaching party to sure for money damages including: Compensatory Damages- Damages that compensate the non-breaching party for the injury or losses substantiated. I
Mercyhurst - BUS - 101
Tender of Delivery requires that the seller/lessor 1) Have and hold conforming goods at the disposal of the buyer/lessee, and 2) Give the buyer/lessee reasonable notice to enable the buyer/lessee to take delivery Unless the parties have agreed otherw
Mercyhurst - BUS - 101
Negotiable Instruments- A written document signed by the marker or drawer of the instrument, setting forth the signers unconditional promise or order to pay a fixed amount of money (with or without interest in a specified amount or at a specified rat
UIllinois - BA - 310
A 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
UIllinois - BA - 310
Global Management Regional Trading Alliances: Agreements among groups of partner countries to facilitate interpartner trade. Used to. - Increase market size - Reduce trade barriers. Trends in importance for trade of national borders and regional trad
UIllinois - BA - 310
Paul Aquino SPCM 112 Mrs. Filter Reflection Paper April 29, 2008 Before I took SPCM 111-112, I expected that it would be just like any other high school speech class. However, after completing both classes I realize how much I actually learned. In hi
UIllinois - BA - 310
CASE 1 PART1 1)Capital Structure D= P= E= V= 2)cost 3)cost 4)cost 5)cost 31.5 16.1 111 158.6 w.d= w.p= w.e= w.e= 9.13% 3.612% 7.609% 10.920% 10.925% w.d= 0.19861286 w.p= 0.10151324 w.e= 0.6998739debt pref. stock equity(CAPM) equity (Dividends)6)W
UIllinois - BA - 310
Ryan McCoy 4/23/2008 CHLH 199 Final Journal Over the course of my semester in this class I have learned so many things that will impact my life everyday. At first I came to see the class as basically an attack on men. There were many reasons for this
UCLA - GE CLUST - 70B
Seema Ullal GE Cluster 70A Dis A Reading Assignment 2 1. 19th century physicists believed that the universe was filled with a &quot;luminiferous ether&quot; because the ether explained how light traveled across the emptiness of space. In the 1800s, light and e
UCLA - GE CLUST - 70B
Seema Ullal GE Cluster 70A Dis 1AReading Assignment 31. Radiocarbon dating can not be used to find the decay rate of an individual carbon atom. The formula for exponential decay can be used to give the half-life of the substance or the average-lif
UCLA - GE CLUST - 70B
Seema Ullal GE Cluster 70A Dis A Reading Assignment 1 1. Sagan argues that even though it is fairly likely that extraterrestrial beings would exist in a universe as large as our own, there is no concrete physical evidence that this is true. There is