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Phys4W09MT330Solutions

Course: PHYS 4, Winter 2009
School: UCSB
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UCSB - ECE - 2B
UCSB - ECE - 2B
ECE 2B Final Exam Review Diode Circuits I-V characteristics Load-line analysis Approximate DC modeling (constant voltage drop model) DC circuit calculations Basic circuit applications (rectifiers, limiters, doublers) LEDs Laplace Transform Met
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124d
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework #2Problem 1:Hspice Netlist; *Full adder HSPICE netlist* .include '180nm.txt' *netlist-VDD Vdd 0 1.8VIN A0 0 PULSE 0 1.8 0NS 0NS 0NS 30NS 60NS * input line: square wave, amp. rise t, fall t, on t, pe
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework #1Problem 1:Quite amazingly Moores predictions for the advancement of integrated circuits are still valid after more than four decades. He was able to foresee the problems associated with decreasing co
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework #3Problem 1:(b) Potential Barrier : 4.05 0.95 = 3.1 eV.Problem 2:Problem 3:F=KT/q ln(ni/Na)=0.37 We have given = -1.13= 0.125So , Vt = - 0.25(b)VT= - 0.25 + 0.0627=-0.1873 Body biasing
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework # 4Problem 1:Problem 2: 3.45 X 10-17 2.7 X 10-16 1.8 X 10-16Please attach graph using XL, Matlab, Tecplot etc.Problem 3:Problem 4: Delay in case A < Case B < Case C Pavg in case A > Case B > Cas
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework # 5Problem 1:Problem 3:Problem 4:Problem 5:Problem 6:Problem 7:Problem 8:Problem 9:(70+70+40+10+120+120+20) + 150 (70+40+10+120+120+20)=0.125ns TB C=260(120+120+20)+260(120+20)=0.104ns T
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework # 6Problem 1:(c) Pass transistor logic :A B C D E F666666 A Out1 Bp = (6+6 ) /3 = 4 g = 7/3 h=3 D = 111 C1 D1 E1 F1Problem 2: (a)A C B D(b)A C BOutDOutA BDC
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework # 7Problem 1:Problem 2: (a)Problem 3:Problem 4:
UCSB - ECE - 124A
ECE124A VLSI PrinciplesSolutions to Homework # 8Problem 1:Problem 2:Problem 3:Problem 4:End of solutions to Homework # 8
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Name: Solutions Perm No. _ECE 124AFall 2008UNIVERSITY OF CALIFORNIA, SANTA BARBARADepartment of Electrical and Computer EngineeringMIDTERM EXAMINATION-ECE124ARoom: ESB-Cooper Lab, November 7, 4:10-6:10 PMREAD CAREFULLY: This is a CLOSED BOO
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UCSB - ECE - 137a
HW2 Solution1. IS = 2.27 9 9V = 1.20mA I L < 1.20 mA | RL > = 7.50 k 15k 1.2mAIZ =1 VS VZ VZ VS 1 = VZ + RS RL RS RS RL | |PZ = VZ I Z PZnom = 15V ( 150mA) = 2.25 Wnom IZ =max IZPZmax = 15V (0.90)(266mA)= 3.59 Wmin IZ =100
UCSB - ECE - 137a
HW3 Solution4.1 (a) VG > VTN corresponds to the inversion region (b) VG < VTN corresponds to the accumulation region (c) VG < VTN corresponds to the depletion region 4.2 (a)" ox14 3.9o 3.9 8.854x10 F / cm F nF C= = = = 6.91x108 2 = 69.1 2 9 Tox T
UCSB - ECE - 137a
Problem Set 4Additional Problems1.2. (a)The drain and gate of M1 and M3 are connected. So you can think of the two transistors as nonlinear resistors. Then Ib is determined by the three resistors (M1, Rb, and M3). Now we have M1 and M2 current
UCSB - ECE - 137a
ECE 137A Winter 2009Homework 4 Solutions4.33 (a) Since VDS = VGS and VTN > 0 for both transistors, both devices are saturated. ThereforeID1 =' Kn W K' W 2 2 (VGS1 VTN ) and ID 2 = n (VGS 2 VTN ) . 2L 2LFrom the circuit, however, ID2 must e
UCSB - ECE - 137a
UCSB - ECE - 137a
ECE 137A Quiz #1 Solution Luis Chen Given doping profileNd(x) 10181015 x 0 1mAssuming that n(x) = Nd(x). Initially, because of the charge gradient, carriers diffuse from right to left, leaving behind positively charged ions. This in turn establ
UCSB - ECE - 137a
ECE137A Quiz#2Solution LuisChen t=0+Na=1017 Nd=1015 Losslessswitch C Vo(t)=0fort<0 1.Calculatetotalenergybeforeswitchcloses 2.Calculatetotalenergyafterswitchcloses 3.IsEi=Ef,ifnot,whynot Here,weassumeidealdiode,i.e.Noreversecurrent.Initially, 1 2 E
UCSB - ECE - 144
UCSB - ECE - 144
UCSB - ECE - 144
Homework 3 solutions
UCSB - ECE - 144
d'rh #4 Horne?*tCalS*oootolt+ tn-p- Waua|/Lt'rrn,'J>efi<k: 0-k,ftu-.tt's ftAox,ue-teqvahls-'ns ,Vx d :VrF : Jr'rnc- fjut,ufrjwzFa ,)C. ): 6,. F, ctr,y) dU;. & y F rt r , Y )e * ) P tJ \:li& H r [F,fi e * i Pi' td
UCSB - ECE - 144
Hovnetctt[I5?-r, a"\CrL; t" cu+h? c*l.Ltu+luI tl coi,inh I t a+ ) b) L)r"'5i*-tBL) c"rt\ldL) costBt) tisi*'t'tsLL)'d-L .' ]. <l*[' tcf[ = U'L6ra, t,nu-Lo:l liutn-, (ol C"sh' L) = Ia^lL -. +.".r si-.(g0 Ji.,^ (+i N L ' ?
UCSB - ECE - 144
ru = rD?b \Art(a)s: 4Z= f . f osIrl O ,* J6TL,*7 IC'@7t)<e. +i,-L f e^lra'[r 5:6eY?ta-94;or'\s "f*t"^A E- ,J=4s,t'I t*tV2Ib:)sr -I['.,ro)4rt r c o*7'64,&tr ^ ,l rzPhas{UptIry uelory)rz5 s.?^u
UCSB - ECE - 147b
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UCSB - ECE - 147b
University of California, Santa BarbaraDepartment of Electrical & Computer EngineeringECE 147b: Digital Control Winter 2009Homework 1. Due 5.00pm Friday, 30th January, 2009 in the homework boxes on the 3rd oor of Harold Frank Hall.Problem 1. Co
UCSB - ECE - 147b
C=4*(1+2*s)/s Integrator insures no steady state error. Has rise time of 0.125 seconds, which is slightly less than 1/10th the rise time of the plant in closed loop (1.5 seconds).Root Locus:Root Locus Editor for Open Loop 1 (OL1) 0.50.40.30.
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University of California, Santa BarbaraDepartment of Electrical & Computer EngineeringECE 147b: Digital Control Winter 2009Homework 3. Due 5.00pm Friday, 20th February, 2009 in the homework boxes on the 3rd. oor of Harold Frank Hall. If you use M
UCSB - ECE - 147b
UCSB - ECE - 147b
University of California, Santa BarbaraDepartment of Electrical & Computer EngineeringECE 147b: Digital Control Winter 2009Homework 4. Due 5.00pm Friday, 6th March, 2009 in the homework boxes on the 3rd. oor of Harold Frank Hall. If you use Matla
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UCSB - ECE - 147b
University of California, Santa BarbaraDepartment of Electrical & Computer EngineeringECE 147b: Digital Control Winter 2009Homework 1. Due 5.00pm Friday, 16th January, 2009 in the homework boxes on the 3rd oor of Harold Frank Hall.Problem 1. Fo
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Homework Assignment 6 ECE 155A Winter 2009 Due Monday, March 2This network programming assignment involves not only BSD socket programming but also multithreaded programming in C / C+. This assignment builds on the previous program you wrote for As
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Homework Assignment 7 ECE 155A Winter 2009 Due Monday, March 9This network programming assignment involves a three-tier application, where there is a front-end tier containing "pure" clients, a middle tier containing a master that acts as both a cl
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Homework Assignment 1 ECE 155A - Winter 2009 Due Friday, January 161. Use the World Wide Web, including Google, Wikipedia, etc to search for information about the following IEEE standards: 802.3 (Ethernet), 802.11 (WiFi), 802.15 (Bluetooth) and 802.
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Homework Assignment 2 ECE 155A - Winter 2009 Due Friday, January 231. The Nyquist theorem and the Shannon theorem are fundamental results that relate the maximum data rate of a communication channel to its bandwidth, in the case of a noiseless chann
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Homework Assignment 3 ECE 155A - Winter 2009 Due Friday, January 301. A data link layer protocol uses the following character encoding: E: 01000101; FLAG: 01111110; ESC: 00011011C: 01000011;Show the bit sequence transmitted in binary for the eig
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