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...Ch MAE130B 11 (4) Compressible Flow Changzheng Huang Compressible Flow Non-isentropic adiabatic flow (Fanno flow) Non-isentropic frictionless flow (Rayleigh flow) Ch 11 (4) Changzheng Huang 2 2. Non-isentropic adiabatic flow (Fanno flow) V1 p1A Mass Momentum Energy D w l V pA 1V1 A = VA = m p1 A pA w Dl = m (V V1 ) V 2 V12 m h + + gz h1 + + gz1 = Q + W 2 2 Since flow is adiabatic (Q=0),...
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.../* MAE 9: Homework #2, Fall 2008 Due on Monday, October 13, Turnin from 9:00am - 9:00pm Compute the area (A) and the volume (V) of a sphere with radius R=0.1, R=0.2, R=0.3, . , R=1.5 . Compute also the total area (TA) and the total volume (TV) of all...
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Ch MAE130B 11 (4) Compressible Flow Changzheng Huang Compressible Flow Non-isentropic adiabatic flow (Fanno flow) Non-isentropic frictionless flow (Rayleigh flow) Ch 11 (4) Changzheng Huang 2 2. Non-isentropic adiabatic flow (Fanno flow) V1 p1A Mass Momentum Energy D w l V pA 1V1 A = VA = m p1 A pA w Dl = m (V V1 ) V 2 V12 m h + + gz h1 + + gz1 = Q + W 2 2 Since flow is adiabatic (Q=0), steady (W=0) and horizontal (gz=0), Mass Energy Ch 11 (4) V = Constant V h+ = h0 = constant 2 Changzheng Huang 2 Note the conditions of validity of this. 3 Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T M<1 pa V V+dV D w M=1 Ta pA (p+dp)A Fanno line M>1 dx s Second law of thermodynamics states that entropy must be constant or increasing for adiabatic flow. Three typical Fanno flow cases, T 1 M<1 T 2 a M>1 1 s (i) Subsonic Fanno flow Ch 11 (4) T a 2 s (ii) Supersonic Fanno flow Changzheng Huang 2 Shock 1 s (iii) Normal shock Fanno flow 4 a Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* Question, for a given flow condition (say M), how far can the flow extend before it reaches the chocked condition (l*-l)? d dV Mass d ( V ) = 0 + =0 V Momentum Adp w Ddx = VAdV Energy Entropy Ch 11 (4) V2 d h+ = 0 2 c p dT + VdV = 0 Tds = c p dT Changzheng Huang Tds = dh vdp dp = c p dT 5 dp p p Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* Momentum Adp w Ddx = VAdV From pipe flow, p 2 2 = =w l r R l V 2 p = f D2 w = f V 2 8 dx 2dp 2dV f = + 2 D V V 6 D2 4 dp f V 2 8 Ddx = V D2 4 dV Ch 11 (4) Changzheng Huang Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* f dx 2dp 2dV = + 2 D V V dx dp kp 2 2dV d dT 2c 2 2dV f = + = + 2 kV 2 + V D p kV V T 2 dV + dT 2 + 2dV = kM 1 2dV + 2 dT = T kM 2 V kM 2 V kM 2 T V dx kM 2 1 dV 2 2 dT f = + D kM 2 V 2 kM 2 T Ch 11 (4) Changzheng Huang 7 Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* Momentum Energy dx kM 2 1 dV 2 2 dT f = + D kM 2 V 2 kM 2 T V2 d h+ = 0 2 kR T dT dV 2 + 2 =0 2 k 1 V T 2V 2 22 dV 2 c p dT + =0 2 dT k 1 2 dV 2 M + =0 2 T 2 V 2 Definition V = Mc Ch 11 (4) V = M c = M kRT Changzheng Huang dV 2 dM 2 dT = + 2 2 V M T 8 Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* Momentum dx kM 2 1 dV 2 2 dT f = + D kM 2 V 2 kM 2 T k 1 dM 2 dT = 2 k 1 2 T M 1+ 2 dV 2 dM 2 1 = 2 k 1 2 M 2 V 1+ M 2 9 Energy dT k 1 2 dV 2 + M =0 2 T V 2 dT dV 2 dM 2 Definition + 2= T V M2 Ch 11 (4) Changzheng Huang Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* 1 M 2 dM 2 dx kM 4 =f k 1 2 D 1+ M 2 M * =1 M l* 1 M 2 dM 2 dx = f k 1 2 kM 4 l D 1+ M 2 [( k + 1) 2] M 2 = f ( l * l ) 1 1 M 2 k +1 + ln 2 kM 2k 1 + [( k + 1) 2] M 2 D Ch 11 (4) Changzheng Huang 10 Temperature-entropy diagram 2. Non-isentropic adiabatic flow (Fanno flow) T 1 pa V V+dV D w Ta pA (p+dp)A dx s 0 l l* T ( k + 1) 2 = * T 1 + [( k 1) 2] M 2 V [( k + 1) 2] M = = * 2 V 1 + [( k 1) 2] M * 2 1/ 2 1/ 2 p 1 T ( k + 1) 2 = * *= * 2 p M 1 + [( k 1) 2] M T * p0 p0 p p 1 2 k 1 2 M = = 1 + * * * 2 p0 p p p0 M k + 1 Ch 11 (4) Changzheng Huang +1 k 2( k 1) 11 Compressible Flow Non-isentropic adiabatic flow (Fanno flow) Non-isentropic frictionless flow (Rayleigh flow) Ch 11 (4) Changzheng Huang 12 3. Non-isentropic frictionless flow (Rayleigh flow) T V1 V D q pA pA 1 b a s l Mass Momentum Energy Mass Momentum Entropy Ch 11 (4) 1V1 A = VA = m p1 A pA = m (V V1 ) Rayleigh line V 2 V12 m h + + gz h1 + + gz1 = Q + W 2 2 V = 1V1 p + V = p1 + V 2 2 11 ( V ) RT = p + V 2 p+ 1 11 2 p s s1 = c p ln T p R ln T1 p1 13 Changzheng Huang 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx Differential analysis Mass d ( V ) = 0 b a s c p dT + VdV = Tds dp + VdV = 0 d dV + =0 V Momentum dp = VdV Energy Entropy dh + VdV = q Tds = dh vdp Tds = c p dT Ch 11 (4) dp dp d dT =0 p T Changzheng Huang 14 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx 1 dT 1 dV ds +2 = c p dT + VdV = Tds k 1 T M V kR dp + VdV = 0 d dV + =0 V dp 2 dV + kM =0 p V d dV + =0 V b a s dT = T (1 kM 2 ) dp d dT =0 p T Ch 11 (4) dp d dT =0 p T Changzheng Huang 1 M 2 ) ( kM 2 + k 1) kR ( ( k 1) M 2 ds 15 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx dT (1 kM ) ( k 1) M ds = T (1 M ) ( kM + k 1) kR 2 2 2 2 b M<1 M>1 a s ds kR (1 M ) ( kM + k 1) = dT T (1 kM ) ( k 1) M 2 2 2 2 2 2 dT (1 kM ) ( k 1) M T = ds (1 M 2 ) ( kM 2 + k 1) kR Ma =1 1 Mb = k Ch 11 (4) Changzheng Huang 16 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx b M<1 M>1 a s dh + VdV = q Energy Second law of thermodynamics also states that entropy increases with heating and decreases with cooling. T T T b b cooling b heating cooling a a a heating shock heating heating cooling s s s (i) Subsonic (ii) Supersonic (iii) Normal shock Rayleigh flow Rayleigh flow Rayleigh flow Ch 11 (4) Changzheng Huang 17 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx Momentum dp = VdV p + V 2 = pa + aVa2 b M<1 M>1 a s p 1 + kM 1+ k = = pa 1 + kM 1 + kM 2 2 a 2 aVa2 p V 2 p + = 1+ pa p pa pa kV 2 p kVa2 1 + c 2 p = 1 + c 2 a a Ch 11 (4) T p a pV p Mc = = = Ta pa pa Va pa M a ca p kRT M = pa kRTa 1/ 2 T p M = pa Ta 2 1/ 2 T 2 p =M Ta pa Changzheng Huang 18 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A dx 2 p 1 + kM a 1+ k = = pa 1 + kM 2 1 + kM 2 b M<1 M>1 a s T0 T0 T Ta = T0,a T Ta T0,a T 1+ k =M2 2 Ta 1 + kM 2 T a V Mc == =M Va M a ca Ta Ch 11 (4) 1/ 2 2 T0 2 ( k + 1) M k 1 2 M = 1 + 22 2 T0,a (1 + kM ) p0 T0 p pa = p0,a p pa p0,a p0 1 + k 2 k 1 2 = M 1 + 2 p0,a 1 + kM k + 1 2 Changzheng Huang 19 k k 1 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A heating dx dh + VdV = q > 0 b M<1 M>1 s a M T0 T cooling p p0 b T a M T0 p p0 b T cooling a b shock heating a heating heating s (i) Subsonic Rayleigh flow Ch 11 (4) heating cooling s s (ii) Supersonic (iii) Normal shock Rayleigh flow Rayleigh flow Changzheng Huang 20 3. Non-isentropic frictionless flow (Rayleigh flow) T V V+dV D q pA (p+dp)A cooling dx dh + VdV = q < 0 b M<1 M>1 s a M T0 T cooling p p0 b T a M T0 p p0 b T cooling a b shock heating a heating heating s (i) Subsonic Rayleigh flow Ch 11 (4) heating cooling s s (ii) Supersonic (iii) Normal shock Rayleigh flow Rayleigh flow Changzheng Huang 21
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UC Irvine >> MAE >> 130B (Spring, 2009)
MAE130B Ch 11 (5) Normal Shock Wave Changzheng Huang Compressible Flow 1. Normal shock wave 2. Examples Ch 11 (5) Changzheng Huang 2 (1) Normal shock wave Fanno flow Mass Momentum Energy M>1 (x) Rayleigh flow (y) M<1 Normal shock V = const p ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Discussion solution #7 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Discussion solution #8 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Discussion solution #9 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
MAE130B Final Review Changzheng Huang Final Review 1. Ch 9. External Flow 2. Ch 11. Compressible Flow Final review Changzheng Huang 2 (1) Ch 9. External Flow: lift and drag L U D y U dFx = ( pdA ) cos + ( w dA ) sin dFy = ( pdA ) sin + ( w ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Homework solution #6 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Homework solution #7 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
Homework solution #8 ...
UC Irvine >> MAE >> 130B (Spring, 2009)
University of California, Irvine MAE130B Design Project Winter Quarter, 2009 You may have seen the spectacular show of the dancing fountain in front of the casino hotel Bellagio in Las Vegas. While this fantastic music fountain show has entertained ...
UC Irvine >> MAE >> 130B (Spring, 2009)
UNIVERSITY OF CALIFORNIA, IRVINE Department of Mechanical and Aerospace Engineering MAE130B INTRODUCTION TO VISCOUS AND COMPRESSIBLE FLOWS Dr. Changzheng Huang Winter Quarter, 2009 Required Text: Fundamentals of Fluid Mechanics Munson, Young, and O...
UC Irvine >> MAE >> 130B (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
Homework set #1, due on January, 15, 4:00 pm Chapter 1, problems 5, 6, 7, 9, 13, 18, 20, 23, 24, 25 ...
UC Irvine >> MAE >> 180 (Spring, 2009)
Homework set #2, due on January, 22, 4:00 pm Chapter 2, problems 1, 2, 3, 7, 8, 9 AND The voltage drop across the 1 k resistor should track as close as possible the voltage supply output, but should not exceed 4 V. The amplitude of the sinusoidal vol...
UC Irvine >> MAE >> 180 (Spring, 2009)
Homework set #3, due on January, 29, 4:00 pm Chapter 5, problems 12 and 13 (do not do the first circuit in figure D). AND For a rectangular wave input signal with a frequency of 1 Hz and amplitude 5 V, a current limiting resistor R = 1 , and a forwar...
UC Irvine >> MAE >> 180 (Spring, 2009)
Homework set #4, due on February 5, 4:00 pm Chapter 3, problems 1, 6, 7, 8, 9, 10, 12, 16, 17, 24, 26 AND Chapter 5, problem 12, figure C: solve the problem by writing down the characteristic equations for the capacitor and the diode, similarly to wh...
UC Irvine >> MAE >> 180 (Spring, 2009)
Homework set #7, due on March, 6, 4:00 pm Chapter 9, problems 4, 5, 6, 12, 20. ...
UC Irvine >> MAE >> 180 (Spring, 2009)
DUE ON MARCH 13th, FRIDAY 1] Compute Vo as a function of Vi, for a) R1 = 10k, R2 = 0; b) R1 = 0, R2 = 10k; c) R1 = 7.5k, R2 = 2.5k; d) R1 = 5k, R2 = 5k; e) R1 = 2.5k, R2 = 7.5k. R2 Vi + R1 10k 10k Vo 2] The input voltage is Vi = 8sin(2t). Plot...
UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
1] Find the amplitude of the current I for sinusoidal input signals having a amplitude of 4 V, and the following frequencies: 0.1 Hz, 1 Hz, 10 Hz, and 100 Hz. (Hint: the op-amp can be approximated by our ideal, Golden Rules model). (25 points) I 0....
UC Irvine >> MAE >> 180 (Spring, 2009)
1] This circuit is called difference amplifier. What is Vout in terms of Va, Vb, R1 and R2? (Hint: the op-amp can be approximated by our ideal, Golden Rules model). (25 points) 2] This is an instrumentation amplifier. Compute Vout in terms of Va, Vb...
UC Irvine >> MAE >> 180 (Spring, 2009)
MAE180- ELECTRIC CIRCUIT AND INTERFACES Winter 2009 Catalog Data: The design of analog circuits based on lumped circuit elements. Analog circuits for interfaces of mechanical systems and data acquisition. Emphasis on operational amplifier circuit des...
UC Irvine >> MAE >> 180 (Spring, 2009)
MAE180 Laboratory Project 1 DAQ analog input, half wave rectifier and bandpass filter EXPERIMENT #1: using a DAQ card for recording voltage signals. Differential versus SingleEnded Analog Inputs. DESCRIPTION A voltage signal is transferred to the A/...
UC Irvine >> MAE >> 180 (Spring, 2009)
MAE180 Laboratory Project 2 Basic operational amplifier circuits EXPERIMENT #1: open loop test circuit. DESCRIPTION The physical package of an op-amp has more terminals than the 3-terminal symbol used in class to represent it. The figures below show...
UC Irvine >> MAE >> 180 (Spring, 2009)
MAE180 Laboratory Project 3 Departure from ideal op-amp performance. Peak detector. EXPERIMENT #1: input bias current. DESCRIPTION An important departure from the ideal op-amp model is the very small, but finite current that the inverting and non-in...
UC Irvine >> MAE >> 180 (Spring, 2009)
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UC Irvine >> MAE >> 180 (Spring, 2009)
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U. Houston >> BCHS >> 3304 (Spring, 2009)
University of Houston BCHS 3304 Exam I. Instructor: Dr. Briggs, Feb. 9, 2006 Printed Name_ANSWER KEY_ Answer all questions; show all work. Multiple choice Circle the single letter (i.e. a., b., c., d., or e.) of the most correct answer, then mark it...
U. Houston >> BCHS >> 3304 (Spring, 2009)
University of Houston BCHS 3304 Exam III Instructor Dr. Briggs Apr. 06, 2006 Printed Name_ANSWER KEY_ LAST, FIRST Student ID#: Multiple choice, 2 pts each (100 pts) Circle letter (i.e. a., b., c., d., or e.) of the most correct answer, then mark it ...
U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> SPAN >> 3341 (Spring, 2009)
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U. Houston >> SPAN >> 3341 (Spring, 2009)
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U. Houston >> SPAN >> 3341 (Spring, 2009)
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U. Houston >> SPAN >> 3341 (Spring, 2009)
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U. Houston >> SPAN >> 3341 (Spring, 2009)
Chapter 14 Proposito de cierre- determinar la condicion financiera de la empresa durante el periodo contable. Hay perdida or ganancia? Cuales son los activos y pasivos que tiene la empresa al final del periodo? Cuatro Pasos del Cierre: Hacer el balan...
U. Houston >> SPAN >> 3341 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> SPAN >> 3304 (Spring, 2009)
Totatzi Lpez Tres Generaciones- Rough Draft Forma y Sentido de Tres Generaciones de Rosaura Snchez El Cuento Tres Generaciones trata de una abuela, madre e hija quienes viven juntas en la misma casa, pero cuyas emociones son vividas por separado. Hay...
U. Houston >> SPAN >> 3304 (Spring, 2009)
La Inhabilidad de Escapar el Destino en Las Medias Rojas de Emilia Pardo Bazn En Las Medias Rojas de Los Pasos de Ulloa y La Madre Naturaleza, Emilia Pardo Bazn nos muestra la realidad cruel de la vida en la clase baja en Espaa en la poca de expansin...
U. Houston >> SPAN >> 3384 (Spring, 2009)
La Fuerza de Casilda en La mujer del juez de Isabel Allende Casilda es la protagonista en La mujer del juez, que lleg un da a un pueblo para casarse con el Juez Hidalgo. Ese da el narrador omnisciente relata que dudaba que la mujer, plida y delicada...
U. Houston >> SPAN >> 3384 (Spring, 2009)
La Inhabilidad de Escapar el Destino en Las Medias Rojas de Emilia Pardo Bazn En Las Medias Rojas de Los Pasos de Ulloa y La Madre Naturaleza, Emilia Pardo Bazn nos muestra la realidad cruel de la vida en la clase baja en Espaa en la poca de expansin...
U. Houston >> SPAN >> 3384 (Spring, 2009)
Las Salamandras La Lucha Contra Las Salamandras Las Salamandras de Tomas Rivera En Las Salamandras, el uso de primera persona protagonista en el cuento es importante para la profundidad emocional del cuento. Esto es importante para sentir la alienaci...
U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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U. Houston >> CHEM >> 3331 (Spring, 2009)
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UC Davis >> CHEM >> 2B (Winter, 2008)
Chem 2B: last worksheet and its only 2 problems! 1. Consider the following reaction: 2 SO2 (g) + O2 (g) 2 SO3 (g) Kp = 10 a) is the reaction spontaneous at 900K when PSO2 = 1.0x10-3 atm, PO2 = 0.20 atm, and PSO3 = 1.0x10-4 atm? CH3OH (g), 2. Calc...
Drexel >> ADF >> asdf (Spring, 2009)
MULTIPLE CHOICE QUESTIONS 1. a. b. c. The activation temperature of most ice-forming nuclei is _ 0 oC. above about well below *c. well below 2. a. b. c. Hygroscopic nuclei _ water molecules. repel attract vaporize *b. attract 3. a. b. c. d. e. Hygros...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #2 Due Friday, Jan. 16 at 8:00 pm (Late submissions will be accepted until Monday, Jan. 19 at 8 pm, for a ma...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #3 Due Friday, January 23 at 8:00 pm (Late submissions will be accepted until Monday, Jan. 26, at 8 pm, for ...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #4 Due Friday, January 30 at 8:00 pm (Late submissions will be accepted until Monday, Feb. 1 at 8 pm, for a ...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #5 Due Friday, Feb. 6 at 8:00 pm (NO LATE SUBMISSIONS ACCEPTED FOR THIS ASSIGNMENT, so that the solutions ca...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #6 Due TUESDAY, Feb. 17 at 8:00 pm (No late submissions accepted.) For the following problems you are to cr...
UC Davis >> ENG >> ENG6 (Winter, 2009)
UNIVERSITY OF CALIFORNIA, DAVIS Department of Electrical and Computer Engineering ENG 6, Engineering Problem Solving Winter 2009 Problem Set #7 Due MONDAY, February 23 at 8:00 pm (No late submissions accepted.) For the following problems you are to...
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