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### 19induction2s

Course: PH 102, Fall 2009
School: Augustana
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Word Count: 561

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102 Induction Physics Professor Lee Carkner Lecture 19 Rail Gun F For each rail B = 0I/2r B = (4X107)(100000) / 2(0.005) B = 4 T so sum of B = 8 T Force on conductor: X I B field from each rail I F = BIL sin F = (8)(100000)(0.01) sin 90 F = 8000 N Magnetic Fields and Current We have already seen that: There should be a parallel effect where magnetic fields can produce currents Constant...

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102 Induction Physics Professor Lee Carkner Lecture 19 Rail Gun F For each rail B = 0I/2r B = (4X107)(100000) / 2(0.005) B = 4 T so sum of B = 8 T Force on conductor: X I B field from each rail I F = BIL sin F = (8)(100000)(0.01) sin 90 F = 8000 N Magnetic Fields and Current We have already seen that: There should be a parallel effect where magnetic fields can produce currents Constant magnetic fields do not produce currents For the area of interest there must either more or less magnetic field with time Magnetic Flux Consider a region with a magnetic field We will define the magnetic flux as the component of the B field that passes through a region times the area of the region, or: = BA cos Unit of flux is the Weber (Wb), 1 Wb = 1 T m2 = 0 means face on = 90 means edge on Magnetic Flux Flux Through a Loop =BA cos 0 =BA What is force on particle? aligned with B, F= 0 Same is true for flux = BA cos 90 = 0 if = 0, = BA = maximum flux if = 90, = 0 Induction What happens if you change the flux through a loop of wire? Connect a loop to an ammeter and move a magnet through it Current stops when the movement stops Usually means something (either the loop or the magnet) must be moving Faraday's Law We can find the emf from Faraday's Law: = N(/t) To find the emf, we don't want , but rather how fast changes Can write as: /t = (fi)/(tfti) Lenz's Law The induced current produces a magnetic field of its own Lenz's Law: The induced current will be in a direction such that the magnetic field it produces will counteract the changes in the original B Induced Current Consider a in loop a B field The induced current flows such that the induced B is in the same direction as the original field Changing B If you increase the flux: The induced current flows such that the induced B is opposite the original field Applied Induction Induction is useful because it links physical motion to electric currents The moving magnet produces a changing flux The current thus preserves a record of the motion Many applications in music Microphone Electric Guitar Induction Devices Microphone Speaker Electric guitar Pickup magnet magnetizes string, the motion of which induces current The tape is magnetized such that when it passes the tape heads it induces a current Tape recorders and players How Does Induction Work? If we move the wire through a B field the electrons now have a velocity This deflection produces an imbalance of charge Next Time Read 21.321.6 Homework, Ch 21, P 7, 9, 11, 13 A wire is carrying a current straight towards you....

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Augustana - PH - 102
Electric PotentialPhysics 102 Professor Lee Carkner Lecture 11Find E1 and E2E1 = 8.99X109(2X106)/(32) = 1124 N /C r22 = 32 + 42 r2 = 5 m E2 = 8.99X109(4X106)/(52) = 1438 N /C 1 = 0 (right on xaxis) Can get 2 from triangle tan 2 = , 2 = 37
Augustana - PH - 102
MotorsPhysics102 ProfessorLeeCarkner Lecture20RinginSolenoidIfthecurrentflowsclockwisethroughthe solenoid,theBfieldinsideisstraightdown Togetmaximumflux,theringshouldfaceup (samedirectionassolenoid) Weneedtofindthefluxthroughtheloop beforeandaft
Augustana - PH - 102
Magnetic ForcePhysics 102 Professor Lee Carkner Lecture 17PAL #17 Magnetic FieldDirection electron is fired into magnetic field that points north if it is deflected up Force equation: F = qvB sin = sin1 (F/qvB) = sin1 [(1.7X1014)/(1.6X1019)(
Augustana - AS - 311
TheTerrestrialPlanetsAstronomy311 ProfessorLeeCarkner Lecture9WheredidtheEarthcomefrom?a) a) b) c) d) Itaccretedfromrockyplanetesimals Itaccretedfromrockyandicyplanetesimals Itrapidlycondensedoutofthesolarnebula ItwascapturedbytheSunsgravity Itw
Augustana - PH - 102
HeatPhysics 102 Professor Lee Carkner Lecture 2PAL #2 Galileo ThermometerHow does it work?Water heats up and expands, becomes less dense, as the density of the water decreases it can't support heavier balls which drop, balls have different de
Augustana - PH - 102
The Second Law of ThermodynamicsPhysics 102 Professor Lee Carkner Lecture 6PAL #6 First LawWork of 2 step process Step 1: 1 mole of gas at 300 K and 1 m3 expands to 2 m3, constant pressure W = PV, PV = nRT P = nRT/V = (1)(8.31)(300)/(1) = 2493
Augustana - PH - 102
Kirchhoff's RulesPhysics 102 Professor Lee Carkner Lecture 14PAL #13 Ohm's Law1.5 V battery, 167 A current in 1 m long, 2 mm thick wireR = V/I = 1.5/167 = 0.00898 R = (L/A) = RA/L = (0.00898)(p)(0.001)2/1 = 2.8X108 ( m)wire is aluminum3
Augustana - PH - 102
PhaseChangesPhysics102 ProfessorLeeCarkner Lecture4 Session:104884PAL#4KineticTheory50litersofagasat20Cand2atm Howmanymoles?PV=nRT,n=PV/RTConverttoSIunitsVi=50L/1000L/m3=0.05m3 Ti=20C+273.15=293.15K P=(2atm)(101300Pa/atm)=202600Pa n=(202600)
Augustana - AS - 311
Observing Template Telescope ObservationsObject: Date and Time: Notes:Object: Date and Time: Notes:Object: Date and Time: Notes:Object: Date and Time: Notes:
Augustana - PH - 102
Equations and Constants: Circuits and MagnetismC = Q/V C = 0 A/d Ceq = C1 + C2 + C3 . (parallel) 1/Ceq = 1/C1 + 1/C2 + 1/C3 . (series) Energy = 1/2QV = 1/2C(V)2 =Q2/2C I = Q/t V = IR R = L/A P = IV = I2R = (V)2/R Req = R1 + R2 + R3 . (series) 1/Re
Augustana - PH - 102
Equations and Constants: ElectricityF = ke q1 q2/r2 E = F/q0 = keq/r2 PE = -W = -Fd = qV V = Vf-Vi = PE/q V = ke q/r PE = ke q1 q2/r K.E. = mv2 W = -qV C = Q/V C = 0 A/d Ceq = C1 + C2 + C3 . (parallel) 1/Ceq = 1/C1 + 1/C2 + 1/C3 . (series) Energy
Augustana - PH - 102
Equations and Constants: Magnetism and LightB = ( 0I)/(2r) F = ( 0I1I2L)/(2d) B = 0nI =BAcos =N/t =BLv =2f = maxsin t = maxsin2ft max=NBA =LI/t L=N/I L= 0n2Al(lastsymbolislowercaseell) PEL=(1/2)LI2 (VP/VS)=(NP/NS) Irms=0.707Imax Vrms=0.707Vm
Augustana - PH - 102
Equations and Constants: Exam 1TC = TK -273.15 TF = 9/5 TC +32 L = L T = M/V V = V T = 3 P = F/A KE = (1/2) mv2rms = (3/2)kBT PV = nRT Q =mcT Q = mL Q/t = [kA(T1-T2)]/L Pr = AeT4 Pnet = Ae(T4-T42) U = Q W U = (3/2)nRT W = P V W = nRTln(Vf/Vi)
Augustana - AS - 315
Study Guide for Quiz #2 Astronomy 315In studying for the quiz you should concentrate on your notes and exercises. I would suggest that you do not just read them over, but test yourself on your mastery of the material. You can use the questions below
Augustana - AS - 311
Observing Template Naked Eye ObservationsObject: Location: Date and Time: Notes:Object: Location: Date and Time: Notes:
Augustana - PH - 203
Equations and Constants: Circuits and Magnetismi = q/t i0 = i1 + i2 J = i/A vd = i/(neA) R = (L/A) 0 = 0(T T0) V = iR P = iV P = i2R P = V2/R V = ir Req = R1 + R2 + R3 . 1/Req = 1/R1 + 1/R2 + 1/R3 . Q = C V C = 0A/d = RC QC = CVC VC= [1-
Augustana - PH - 203
Equations and Constants: ElectricityF = (k q1 q2 )/r2 F2 = Fx2 + Fy2 Fy = F sin Fx = F cos tan = (Fy/Fx) E = F/q0 E = k q/r2 p = qd E = (1/(2 0) (p/z3) = pE sin U = -pE cos W = Uf - Ui dE = (1/(4 0) ( ds/r2) E = qz / (4 0(z2+R2)3/2) E = (/2 0)
Augustana - PH - 202
Equations and Constants: Fluids and Waves=m/V P=F/A P=p0+gh W=mg W=Vg R=Av=constant p1+1/2v12+gy1=p2+1/2v22+gy2 L= 1/2A(vt2vb2) Fo=Fi(Ao/Ai) do=di(Ai/Ao) W =Fd x=xmcos( t+ ) v= xmsin( t+ ) a= 2xmcos( t+ ) =2/T=2f F=kx =(k/m) T=2(m/k) U=kx2
Augustana - PH - 202
Equations and Constants: Opticsc=3X108m/s I=Ps/4r2 F=L/4d2 pr=I/c pr=2I/c E=Emsin(kx t) B=Bmsin(kx t) c=E/B 0=8.85X1012F/m 0=1.26X106H/m c=1/( 0 0) S=(1/ 0)EB I=(1/c 0)Erms2 I=I0 I=I0cos2 1= 1 n2sin 2=n1sin 1 c=sin1(n2/n1) B=tan1n i=p f=r 1/p+1
Augustana - PH - 202
Equations and Constants: Sound and Thermodynamicsf=nv/2L v=(B/) s=smcos(kx t) p=pmsin(kx t) pm=(v )sm L=m L=(m+) I=Ps/4r2 I=v 2sm2 =(10dB)log(I/I0) f=nv/2L f=nv/4L fbeat=f1f2 f=f(vvD/vvS) u=(/)c TC = TK -273.15 TF = 9/5 TC +32 L = L T V = V T =3
Augustana - AS - 311
Study Guide for Quiz #1 Astronomy 311: The Solar SystemIn studying for the quiz you should concentrate on your notes and exercises. I would suggest that you do not just read them over, but test yourself on your mastery of the material. You can use t
Augustana - EXPERIMENT - 2003
PHOTOELECTRIC EFFECTTHEORY When light of sufficiently high frequency falls on the surface of a metal, electrons (called photoelectrons) are emitted. It is observed that the maximum kinetic energy that may be attained by a photoelectron, KEmax, depen
Augustana - EXPERIMENT - 351
PHOTOELECTRIC EFFECTTHEORY When light of sufficiently high frequency falls on the surface of a metal, electrons (called photoelectrons) are emitted. It is observed that the maximum kinetic energy that may be attained by a photoelectron, KEmax, depen
Augustana - EXPERIMENT - 2003
The Michelson InterferometerIntroduction An interferometer is a device that can be used to measure lengths or changes in length with great accuracy by means of interference fringes. In this experiment, it will be used to measure the wavelength of a
Augustana - EXPERIMENT - 351
The Michelson InterferometerIntroduction An interferometer is a device that can be used to measure lengths or changes in length with great accuracy by means of interference fringes. In this experiment, it will be used to measure the wavelength of a
Augustana - PH - 102
EntropyPhysics 102 Professor Lee Carkner Lecture 7If an automobile engine outputs 149200 W to the drive shaft and outputs 596800 W to the radiator, what is the efficiency?W = 149200 W QC = 596800 W W = QH QC, QH = W + QC QH = 149200 + 596800 =
Augustana - PH - 313
Vapor Power CyclesThermodynamics Professor Lee Carkner Lecture 19PAL # 18 TurbinesV Power of Brayton Turbine V If the specific heats are constant (k = 1.4) can find T from (T2/T1) = (P2/P1)(k-1)/kV T2 = T1(P2/P1)(k-1)/k = (290)(8)0.4/1.4 = V
Augustana - PH - 202
Kinetic Theory of GasesPhysics 202 Professor Lee Carkner Lecture 15 Through which material will there be the most heat transfer via conduction? a) solid iron b) wood c) liquid water d) air e) vacuum Through which 2 materials will the
Augustana - PH - 202
Archimedes' Principle&quot;Got to write a book, see, to prove you're a philosopher. Then you get your . free official philosopher's loofah.&quot; Terry Pratchett, Small GodsPhysics 202 Professor Lee Carkner Lecture 2 Which of the following would d
Augustana - PH - 102
FirstLawofThermodynamicsPhysics102 ProfessorLeeCarkner Lecture5 (Session:104884)PAL#5PhaseChangeFinaltemperatureofmeltedFrosty Fourheats:WarmupFrostyto0C:micecice(0(5) MeltFrosty:miceLice WarmupmeltedFrosty:mwatercwater(Tf0) Cooldownair:maircai
Augustana - PH - 102
Ampere's LawPhysics 102 Professor Lee Carkner Lecture 18Currents and Magnetism It is also true that moving charged particles produce magnetic fields Serious magnetic fields are produced by currentsWhat is the magnitude and direction of
Augustana - PH - 102
Ohm's LawPhysics 102 Professor Lee Carkner Lecture 13Potential difference (V or V): in volts (joules per coulomb)Circuit TheoryCurrent (I): in amperes (amps, coulombs per second)I = Q/ tResistance (R):how hard it is to get current t
Augustana - PH - 313
Pure SubstancesThermodynamics Professor Lee Carkner Lecture 5PAL # 4 First LawP Pumping water uphill and then running it back to produce energy P But the pump and the turbine are only 75% efficientP Rate of power imparted to water = P Wwater =
Augustana - PH - 202
DoubleSlitDiffractionPhysics202 ProfessorLeeCarkner Lecture27Singleslitdiffraction,howbrightisspot5cm fromcenter?=680nm,a=0.25mm,D=5.5m Converty=5cmto tan=y/D,=arctan(y/D)=0.52deg NeedtofindtofindI =(a/)sin=10.5rad I=Im(sin/)2=0.007ImPAL#26D
Augustana - AS - 311
TelescopesandSpacecraftAstronomy311 ProfessorLeeCarkner Lecture7Ifitislowtidewhereyouarestanding rightnow,howmanytotalplaceson Earthareatlowtiderightnow?How manytotalplacesonEarthareathigh tiderightnow?a) b) c) a) a) 1and0 1and1 1and2 2and2 4and
Augustana - PH - 102
RCCircuitsPhysics102 ProfessorLeeCarkner Lecture15KirchhoffsRules+ I1 V=6V I2 6 I3 6 4Leftloop:66I2=0 6=6I2soI2=1A Rightloop:6I26I34I3=0 SinceI2=1,610I3=0,or6=10I3orI3=0.6A I1=I2+I3 I1=1+0.6orI1=1.6A Voltage:ForbatteryV=6V,for6,V=6I2=6V,for2
Augustana - PH - 102
Coulomb's LawPhysics 102 Professor Lee Carkner Lecture 93 m +5eForce on 2 from 1: F12 = kq1q2/r2PAL #8F12 2eF232.1 m +7eF12 = (8.99X109)(5)(1.6X1019)(2)(1.6X1019)/(32) = 2.56X1028 N Force is to left, make negative Force on 2 from 3: F23
Penn State - PHYS - 213
Physic 214 Laboratory Diffraction of Light Theory: Light that is incident upon a more slit will be diffracted and produce a diffraction pattern on a distant screen. If light with wavelength is incident upon a slit of width a, the light will interfer
Penn State - PHYS - 213
Interference of LightRefraction (a review) Character of the wave in different (transparent) media wave travels slower Index of refraction n = c/v frequency is constant (wavelength changes) Law of Refraction (Snells Law) n1 sin 1 = n2 sin 2
Penn State - PHYS - 213
Chapter 33-7 PolarizationThe Beginning of Optical Physics (Light and Optics)Transverse Wave Property (Electric Field Considered) Ancient ideaHistorical attempts to characterize light light emanates from eye to illuminate object Newton (18t
Penn State - PHYS - 212
Chapter 24 Electric PotentialRelationship between Work done by a force and ENERGY If you accelerate an object to a greater speed by applying a force you increase its kinetic energy These changes in KE are due to energy transfers: you transfer ene
Penn State - PHYS - 2
Chapter 9 Static Equilibrium; Elasticity and FractureEx. 9-7Units of Chapter 9The Conditions for Equilibrium Solving Statics Problems Applications to Muscles and Joints Stability and Balance Elasticity; Stress and Strain Fracture Spanning a Spac
Penn State - PHYS - 250
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Penn State - PHYS - 2
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Penn State - PHYS - 250
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Penn State - PHYS - 211
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Penn State - PHYS - 2
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Penn State - PHYS - 250
Chapter 4 Dynamics: Newtons Laws of MotionProb. 6 (#35 in book)Units of Chapter 4 Force Newtons First Law of Motion Mass Newtons Second Law of Motion Newtons Third Law of Motion Weight the Force of Gravity; and the Normal ForceUnits of C
Penn State - PHYS - 211
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Penn State - PHYS - 213
Physics 213 Spring 2009Dr. Leonard GambergAssociate Professor email: lpg10@psu.edu Office Luerssen-122-B Hrs. Tues, Wed 5-6pm or by appointment Phone: 610-396-6124 Fax: 610-396-6024 Course Web-stite: http:/hadron2.bk.psu.edu/ Class Schedule Mon, We
Penn State - PHYS - 211
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Penn State - PHYS - 213
Optical Instruments Telescopes Compound lens problem1 1 1 = + f ob iob pob 1 1 1 = + f eye ieye peyeObject at focal point of converging lens puts a virtual image at infinityOptics of TelescopeNewtonian Reflectorf ob m = - f eyeReflectors
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EXPERIMENTS 1 &amp; 2: ELECTRIC FIELD MAPPINGNOTE: The procedure for Exp. 1 begins on page 2 and the procedure for Exp. 2 begins on page 5.Object: To determine the nature of the electric field and equipotentials of a dipole and the relationship between
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StatisticalMechanicsPart1Physics313 ProfessorLeeCarkner Lecture251KineticTheory Thermodynamicpropertiesofagasaredue tomotionsoflargenumbersofgas molecules Thebehavioroftheensembleisgoverned bystatistics Theparticlesbehaveinarandomfashion
Augustana - PH - 316
PH316AUGUSTANA COLLEGEWINTER 2006-2007Deep Impact: How much time would we have to prepare? T. S. Grimes &amp; R. S. Kruidenier INTRODUCTION When considering the scenario of a possible earth impact, our eyes automatically turn to the moon. If such a
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#6 Uniform Circular MotionOBJECTIVE: To study the motion of an object undergoing uniform circular motion. DISCUSSION: An object undergoing uniform circular motion (moving with constant speed along the circumference of a circle) experiences a centrip
Penn State - PHYS - 250
#6 Uniform Circular MotionOBJECTIVE: To study the motion of an object undergoing uniform circular motion. DISCUSSION: An object undergoing uniform circular motion (moving with constant speed along the circumference of a circle) experiences a centrip
Augustana - PH - 316
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