Register now to access 7 million high quality study materials (What's Course Hero?) Course Hero is the premier provider of high quality online educational resources. With millions of study documents, online tutors, digital flashcards and free courseware, Course Hero is helping students learn more efficiently and effectively. Whether you're interested in exploring new subjects or mastering key topics for your next exam, Course Hero has the tools you need to achieve your goals.
2 Pages
Logarithmic Decrement
Course: CIVIL ENGI CE 573, Fall 2005School: Purdue
Rating:
Word Count: 101
Document Preview
573: CE Structural Dynamics Logarithmic Decrement Matlab Example >> u1 = udata(2) u1 = 96.5749 >> u2 = udata(10) u2 = 83.9971 (Located from the plot.) (Located from the plot.) >> delta = log(u1/u2) delta = 0.1395 u = log k , k = 1. uk +1 >> xi = delta/sqrt(delta^2 + 4*pi^2) xi = 0.0222 >> Td = (10-2)*0.25 Td = 2 >> w =...
Unformatted Document Excerpt
Coursehero >> Indiana >> Purdue >> CIVIL ENGI CE 573Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
573: CE Structural Dynamics Logarithmic Decrement Matlab Example
>> u1 = udata(2) u1 = 96.5749 >> u2 = udata(10) u2 = 83.9971
(Located from the plot.)
(Located from the plot.)
>> delta = log(u1/u2) delta = 0.1395
u = log k , k = 1. uk +1
>> xi = delta/sqrt(delta^2 + 4*pi^2) xi = 0.0222 >> Td = (10-2)*0.25 Td = 2 >> w = (2*pi)/(Td*sqrt(1-xi^2)) w = 3.1424 (About 5% error in .) >> = u7 udata(52) u7 = 38.4136 >> delta = 1/(7-1)*log(u1/u7) delta = 0.1537 >> xi = delta/sqrt(delta^2 + 4*pi^2) xi = 0.0244 >> Td = (52-2)*0.25/6 Td = 2.0833 >> w = (2*pi)/(Td*sqrt(1-xi^2)) w = 3.0168 (About 0.5% error in .) >> approxxi = delta/(2*pi) approxxi = 0.0245 (Not much change in value of .)
u 1 = log k , k = 1& n = 6. n uk + n
(Recall that t for each sample is 0.25.)
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more.
Course Hero has millions of course specific materials providing students with the best way to expand
their education.
Below is a small sample set of documents:
Below is a small sample set of documents:
Berkeley - CIV ENG - CE 227
CE 227 Homework #2 SolutionsAdpated from: Troy MorganProblem 4 Conceptual DesignIn this problem, we investigate various structural configurations for our building. I've presented a sketch of possible solutions here, but obviously yours may (and
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Numerical Evaluation of Dynamic Response Newmark Methods ExampleGiven: Mass of tank m = 0.2533 kip-sec2 / in , stiffness k = 10 kips/in, undamped natural period T = 1.0 sec ( = 6.283 rad/sec ), and = 0.05 . Tank star
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#5 Supplemental ProblemGiven: Another common model used for buildings is the portal frame model, which tries to account forflexibility of both horizontal and vertical members by allowing for rotations at connections.
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Solution to HW#1Problem #1Given: A concrete slab (mass = 20,000 kg) forms the floor of a manufacturing facility. To preventexcessive vibrations from reaching the equipment placed on this floor, the slab is supported by
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics MDOF Earthquake Response Spectrum ExampleGiven: A three story building is modeled using shear frames. The mass and stiffness properties are as indicated. Assume = 0.02 for all modes. Each story has a height of 14 ft. Re
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example on Orthogonality and Modal MatricesGiven: A three-story building is modeled as shown. The dead load per unit length for each horizontal girder varies with each floor; you may assume that the weight of each column
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example: MDOF Damped Forced VibrationGiven: A six story shear frame model building has the following mass and stiffness properties: m = 66 lb-sec 2 / in , E = 30 106 psi and I = 882 in 4 for each column. The property ma
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example: Rayleigh QuotientGiven: A six-story building is modeled as a shear-frame structure. Parameters are m = 66 lb-sec 2 / in , E = 30 106 psi, and I = 882 in 4 . Required: Estimate the fundamental natural frequency
Purdue - CIVIL ENGI - CE 573
Berkeley - CIV ENG - CE 227
Characterizing Near Fault Ground Motion For The Design And Evaluation Of BridgesPaul SomervilleABSTRACT Near-fault ground motions are different from ordinary ground motions in that they often contain strong coherent dynamic long period pulses and p
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#6 Supplemental ProblemsProblem #1Given: A popular method for limiting the effects of earthquakes on structures is to base isolate them; that is, to put in supports underneath the structure that isolate the main part
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#1 Supplemental ProblemsProblem #1Given: A concrete slab (mass = 20,000 kg) forms the floor of a manufacturing facility. To preventexcessive vibrations from reaching the equipment placed on this floor, the slab is su
Auckland - CIVIL ENGI - Civil 416
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#5 SolutionsGiven: Another common model used for buildings is the portal frame model, which tries to account forflexibility of both horizontal and vertical members by allowing for rotations at connections. In this pro
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example on Natural Frequencies and ModesGiven: A two-story building is modeled as a shear-frame structure. Parameters are m = 35 103 kg and k = 17.5 106 N/m. Required: Determine the natural frequencies and natural vibr
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Degrees of Freedom Modeling Options Examples
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Numerical Evaluation of Dynamic Response Elastoplastic Behavior ExampleGiven: Mass of frame m = 0.5 kip-sec2 / in , stiffness k = 20 kips/in, and = 0.02 . Tank starts at rest and is subjected to pulse F(t) as shown. A
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#2 Supplemental ProblemsProblem #1Given: A viscously damped structure is set into free vibration with an initial velocity. The resultingdamped oscillations are shown above.Required: (a) Determine the logarithmic de
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Solutions to HW#3Problem #1m Y(t) y(t)v = constantCenter of MasskcFramegh yo y (x)RWheelxGiven: A car can be (crudely) modeled as a single degree of freedom system having the entire car's mass m lumpe
Purdue - CIVIL ENGI - CE 573
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#4 Supplemental ProblemGiven: A response spectrum is a plot of the maximum dynamic load factor (DLF) as a function of the(nondimensional) duration of the loading. See Figures 4.4 and 4.5 in the text for examples. We w
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics General Periodic Response Theorymu + cu + ku = F ( t ) ao + an cos ( n t ) + bn sin ( n t )n =1 n =1 N NComplementary Solution: uc (t ) = e - t [ A cos D t + B sin D t ]. Particular Solution:For constant term: u
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#3 Supplemental Problemv = constantm Y(t) y(t)Center of MasskcFramegh yo y (x)RWheelxGiven: A car can be (crudely) modeled as a single degree of freedom system having the entire car's massm lumped a
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example: Inverse Vector Iteration for Higher ModesGiven: A six-story building is modeled as shown. Parameters are m = 66 lb-sec 2 / in , E = 30 106 psi, and I = 882 in 4 . Required: Use inverse vector iteration to find
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Damped Free Vibration Case #1: Overdamped Vibration c > ccr > 1: Case #2: Critically Damped Vibration c = ccr = 1: Case #3: Underdamped Vibration c < ccr < 1:
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Example: Inverse Vector IterationGiven: A two-story building is modeled as a shear-frame structure. Parameters are m = 35 103 kg and k = 17.5 106 N/m. mode shape {a}1 for this building. Solution: 1. Property matrices
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics HW#7 Supplemental ProblemProblem #1Given: Illustrative Example 13.2 in the textbook (pages 418 426) describes the evaluation of the dynamic response of a three dimensional space frame using SAP 2000. A careful reading o
Purdue - CIVIL ENGI - CE 573
CE 573: Structural Dynamics Generalized SDOF Systems TheoryAssume dynamic equilibrium for displacement v( x, t ) : beam FI (t ) + FD (t ) + FS (t ) + FE (t ) = 0,beam beam beamwith each force dependent on v( x, t ) except for the external
Auckland - CIVIL ENGI - Civil 416
Pittsburgh - ECON - 0100
ECON 0100Place: G23 PH Days: MW Time: 3:004:15 PM TA: Kristin Harnett Recitation: noneProfessor: Frank Giarratani Office: 4926 WWPH Office hours: MW 1:002:30 PM or by appointmentTen principles of economicsChapter 1Course web page: http:/blackb
Pittsburgh - ECON - 0100
The circular-flow modelThe market forces of supply and demandChapter 4Market for Goods and ServicesRevenueGoods and services sold Goods and services boughtSpendingFirmsHouseholdsWages, rent, and profitInputs for productionLabor, la
Pittsburgh - ECON - 0100
Interdependence and tradeInterdependence and the gains from tradeChapter 3Economic interdependence is a predominant characteristic of our country and our world.People dependent on other people. Countries dependent on other countries.Economist
Pittsburgh - ECON - 0100
Science is used to explain how systems workThinking like an economistChapter 2Physical systems Chemical systems Biological systems Economic systemsIn each case, people have defined a set of phenomena that are linked. In each case, people have
Pittsburgh - ECON - 0100
What we observePriceAt any moment in time, this is what we observe.Elasticity and its applicationChapter 5Point A P00Q0QuantityWhat we observePriceMarket equilibriumBut, this can change at any time! Price of Ice-Cream Cone Suppl
Cornell - PHYS - 2207
P207 - Fall 2007 Solutions Assignment 41 Chapter 5, Problem 13 (a) The net force on the salami is Fnet = Fgravity + Tcord-to-scale where Fgravity is the force of gravity and Tcord-to-scale is the force of the scale. Since Fnet = ma and a = 0, then
Cornell - PHYS - 2207
P207 - Fall 2007 Solutions Assignment 21 (a) For a constant acceleration a, and initial position and velocity zero, v(t) = at 1 x(t) = at2 2 Solve Equation 1 for time to get t = v/a Then substitution of Equation 3 into Equation 2 gives 1 v x= a 2 a
Cornell - PHYS - 2207
P207 - Fall 2007 Solutions Assignment 31 (a) Horizontal and vertical components of velocity are shown below.0 -1 vy [m/s] -2 -3 -4 -5 0 50 40 vx [m/s] 30 20 10 0 0 0.05 0.1 0.15 0.2 0.25 time [seconds] 0.3 0.35 0.4 0.05 0.1 0.15 0.2 0.25 0.3 0.35
Cornell - PHYS - 2207
P207 - Fall 2007 Solutions Assignment 11 The apparent size of the elevator is proportional to the angle subtended . We see from the diagram that tan = h/d where h is the height of the elevator and d is the distance. Since the height is always much
Valencia - EGS - 2310
Seventh EditionCHAPTER4VECTOR MECHANICS FOR ENGINEERS: STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityEquilibrium of Rigid Bodies 2002 The McGraw-Hill Companies, Inc. All rights reserved.
Valencia - EGS - 2310
Seventh EditionCHAPTER3VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityRigid Bodies: Equivalent Systems of Forces 2002 The McGraw-Hill Companies, Inc. All
Valencia - EGS - 2310
Seventh EditionCHAPTER6VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityAnalysis of Structures 2002 The McGraw-Hill Companies, Inc. All rights reserved.Se
Valencia - EGS - 2310
Seventh EditionCHAPTER7VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityForces in Beams and Cables 2002 The McGraw-Hill Companies, Inc. All rights reserved.
Valencia - EGS - 2310
Seventh EditionCHAPTER8VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityFriction 2002 The McGraw-Hill Companies, Inc. All rights reserved.Seventh Edition
Valencia - EGS - 2310
Valencia - EGS - 2310
Seventh EditionCHAPTER5VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityDistributed Forces: Centroids and Centers of Gravity 2002 The McGraw-Hill Companies,
Valencia - EGS - 2310
Seventh EditionCHAPTER2VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityStatics of Particles 2002 The McGraw-Hill Companies, Inc. All rights reserved.Seve
Valencia - EGS - 2310
Seventh EditionCHAPTER1VECTOR MECHANICS FOR ENGINEERS:STATICSFerdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech UniversityIntroduction 2002 The McGraw-Hill Companies, Inc. All rights reserved.Seventh Edit
ASU - MAT - 272
Mat 272 Test 2Dr. Firozx + y -1 x-21. Find and sketch the domain of f ( x, y ) =Solution: x + y - 1 0, x 22. Draw the rough sketch of the function f ( x, y ) = 81 - x 2 - y 2 and draw minimum six level curves.Solution:3. Evaluate( x ,
ASU - MAT - 272
Mat 272 Test 1Dr. Firoz1. Find the center and radius of the sphere 4 x 2 + 4 y 2 + 4 z 2 - 8 x + 16 y - 1 = 0 . Solution: Center at (1, -2, 0) and radius (3 / 2) 2 2. Given a vector u =< 4, 4,3 > . Find a vector of magnitude 10 in the direction o
ASU - MAT - 272
Mat 272 Project # 3 Project 3 for all students due on or before April 3, 2008Dr. Firoz Your name: . 1. Consider the circular plate of radius a bounded by the circle r = a whose mass a2 density is given by (r , ) = 2 2 . We will find its mass and i
ASU - MAT - 272
Mat 272 Project # 4 Project 4 for all students due on or before April 10, 2008Dr. Firoz Your name: . 1. Use the transformation 2u = x + y, 2v = x - y to evaluate the double integral x+ y x- y sin 2 cos 2 dA R over triangular region R with
ASU - MAT - 272
Mat 272 Test 3Dr. FirozA1. Evaluate the double integralwork.1 4 eRxy + e x dxdy, R = [0,1] [0, 4] . Show completeSol:x x x x e y + e dxdy = e y + e dxdy = 13.3 R 0 02. Let R be the region shown in the accompanying figure. Fill
ASU - MAT - 272
Mat 272 Project 2 Project 2 for all students due on or before March 27, 2008Dr. Firoz Your name: . 1. Attach this page with your complete work. The figure shows a sector of a circle with central angle x, let A( x) be the area of the segment between
ASU - MAT - 272
Mat 272 Test 1Dr. Firoz1. Find the center and radius of the sphere 4 x 2 + 4 y 2 + 4 z 2 - 8 x + 16 y - 1 = 0 . Solution:4( x 2 + y 2 + z 2 - 2 x + 8 y ) - 1 = 0 ( x - 1) 2 + ( y + 4) 2 + z 2 = 21/ 4The center is at (1, -4, 0) and radius21
ASU - MAT - 272
Mat 272 Calculus III Final Exam on May 3, 2008 Saturday at 7:40 in EDC 117 Test Concept 1. Distance formula D = P1 P2 = ( x1 - x 2 ) 2 + ( y1 - y 2 ) 2 + ( z1 - z 2 ) 2Dr. Firoz2. Equation of a sphere ( x - a ) 2 + ( y - b) 2 + ( z - c) 2 = r 2 c
ASU - MAT - 272
Department of Mathematics and Statistics Arizona State University Project 1 for all students due on or before March 6, 2008Dr. Firoz Your name: . Attach this page with your complete work. 1. Find the parametric equations of the tangent line to the c