22 Pages

153A_Lec18

Course: CHEM 153A, Winter 2008
School: UCLA
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Catalytic Enzymes: Mechanisms Feb. 6, 2008 1 Overview Double-Reciprocal Plots of Enzyme Inhibition Enzyme Catalytic Mechanisms 2 Double-Reciprocal Plot of Competitive Inhibition = 1 + [I]/KI 3 Double-Reciprocal Plot of Uncompetitive Inhibition ' = 1 + [I]/K'I 4 Double-Reciprocal Plot of Mixed Inhibition = 1 + [I]/KI ' = 1 + [I]/K'I 5 6 Irreversible Inhibition Competitive, uncompetitive, and...

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Catalytic Enzymes: Mechanisms Feb. 6, 2008 1 Overview Double-Reciprocal Plots of Enzyme Inhibition Enzyme Catalytic Mechanisms 2 Double-Reciprocal Plot of Competitive Inhibition = 1 + [I]/KI 3 Double-Reciprocal Plot of Uncompetitive Inhibition ' = 1 + [I]/K'I 4 Double-Reciprocal Plot of Mixed Inhibition = 1 + [I]/KI ' = 1 + [I]/K'I 5 6 Irreversible Inhibition Competitive, uncompetitive, and mixed inhibition are reversible Irreversible inhibitors permanently inhibit enzyme activity May bind an essential functional group May damage an essential functional group May form a stable noncovalent complex Suicide inhibitors are a special type of irreversible inhibitor 7 Specific Catalytic Groups Contribute to Catalysis Catalysis provides a new, lower-energy rxn pathway Catalytic functional groups aid in the cleavage and formation of bonds by several mechanisms: Acid-base cat. Covalent cat. Metal ion cat. 8 General Acid-Base Catalysis 1 2 3 9 1 10 2 11 3 12 Covalent Catalysis Transient covalent bond E between and S is involved Transient covalent complex undergoes further rxn to generate P and free E 13 Amino acids in general acid-base catalysis and covalent catalysis Listed aa can act as proton donors and acceptors Listed aa can also act as nucleophiles Enzyme cofactors (not shown) may also have functional groups that serve similar purposes 14 Metal Ion Catalysis Metal ion may be tightly associated with E or may be acquired from solution Oxidation-reduction rxn may be mediated by metal ion Ionic interactions between S and metal ion may contribute to binding energy by positioning S or stabilizing charged transition state 15 Examples of Enzymatic Reactions Hexokinase Induced fit mechanism (we've already discussed this) Also uses general acid-base catalysis and transition state stabilization but we won't go into this Enolase Metal ion catalysis Lysozyme Covalent catalysis and general acid catalysis Chymotrypsin Serine protease 16 Enolase (Lyase) 17 18 19 20 Hen egg white lysozyme (hydrolase) 21 22
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CHAPTER 22.1 Based upon Table 2.1, a resistivity of 2.6 -cm < 1 m-cm, and aluminum is a conductor. 2.2 Based upon Table 2.1, a resistivity of 1015 -cm > 105 -cm, and silicon dioxide is an insulator. 2.3 I max 2.4 10-8 cm2 7 A = 10 1 = 500 mA (
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CHAPTER 44.1 (a) VG > VTN corresponds to the inversion region (b) VG < VTN corresponds to the accumulation region (c) VG < VTN corresponds to the depletion region 4.2 (a)" ox -14 3.9o 3.9 8.854x10 F / cm F nF C = = = = 6.91x10-8 2 = 69.1 2 -9 Tox T
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CHAPTER 55.1 Base Contact = B n-type Emitter = D 5.2v BC iB + B + E iE C iCCollector Contact = A n-type Collector = FEmitter Contact = C Active Region = EFor VBE > 0 and VBC = 0, IC = F I B or F =IC 275A = = 68.8 4A IBR =0.5 R = =1 1-
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CHAPTER 33.1(1019 cm-3 )(1018 cm-3 ) = 0.979V NA ND j = VT ln 2 = (0.025V )ln ni 10 20 cm -62( 11.7 8.854 x10-14 F cm-1 ) 2s 1 1 1 1 w do = + 19 -3 + 18 -3 (0.979V) j = -19 10 cm q NA ND 1.602x10 C 10 cm w do = 3.73 x 10-6 cm = 0
Cal Poly - EE - 307
Cal Poly - EE - 307
Cal Poly - EE - 307
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CHAPTER 1111.1v O = vS iS = v 1M 1k (1000)1k + 0.5 | Av = vO = 990 or 59.9 dB 1M + 5k S | Ai = iO 990 6 = 10 = 9.9x105 or 120 dB iS 1000 vO 5V = = 5.05 mV AV 990 vS 990vS and iO = 1M + 5k 1kAP = Av Ai = 990 9.9x105 = 9.8x108 or 89.9 dB | v S =(
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Cal Poly - EE - 307
CHAPTER 1414.1 (a) Common-collector Amplifier (npn) (emitter-follower)RIQ1viR1R2+RER3vo-(b) Not a useful circuit because the signal is injected into the drain of the transistor.RI viRDM1+R3vo-R1(c) Common-em
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Cal Poly - EE - 307
CHAPTER 1616.1 Av (s) = 50 s2 s2 | Amid = 50 | FL (s)= | Poles : - 2,-30 | Zeros : 0,0 (s + 2)(s + 30) (s + 2)(s + 30) s rad | L 30 s (s + 30) | fL = Yes, s = -30 | Av (s) 50 fL = L 30 = 4.77 Hz 2 22 2 1 302 + 22 - 2(0) - 2(0) = 4.79 Hz 2 50
Cal Poly - EE - 307
CHAPTER 1717.1(a) T = A = (b) A = 10Av =80 20|Av =1=5|FGE = 0= 10000 | T = 10000(0.2)= 2000A 10000 100% 100% = = 5.00 | FGE = = = 0.05% 1+ A 1+ 2000 1+ A 2001 A 10 100% (c) T = 10(0.2)= 2 | Av = 1+ A = 1+ 2 = 3.33 | FGE = 1+ 2
Cal Poly - EE - 228
Cal Poly - EE - 228
Cal Poly - EE - 228
Cal Poly - EE - 228
Cal Poly - EE - 228