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Course: PHY 007, Spring 2008School: UniFor
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The 7. volume of ice is given by the product of the semicircular surface area and the thickness. The semicircle area is A = r2 /2, where r is the radius. Therefore, the volume is V = 2 r z 2 where z is the ice thickness. Since there are 103 in m 1 km and 102 cm in 1 m, we have r = (2000 km) In these units, the thickness becomes z = (3000 m) Therefore, V = 102 cm 1m 2 103 m 1 km 102 cm 1m = 2000 105 cm . =...
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The 7. volume of ice is given by the product of the semicircular surface area and the thickness. The semicircle area is A = r2 /2, where r is the radius. Therefore, the volume is V = 2 r z 2
where z is the ice thickness. Since there are 103 in m 1 km and 102 cm in 1 m, we have r = (2000 km) In these units, the thickness becomes z = (3000 m) Therefore, V = 102 cm 1m
2
103 m 1 km
102 cm 1m
= 2000 105 cm .
= 3000 102 cm .
2000 105 cm 2
3000 102 cm = 1.9 1022 cm3 .
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UniFor - PHY - 008
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UniFor - PHY - 009
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UniFor - PHY - 022
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16. Since a change of longitude equal to 360 corresponds to a 24 hour change, then one expects to change longitude by 360 /24 = 15 before resetting one's watch by 1.0 h.
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