Register now to access 7 million high quality study materials (What's Course Hero?) Course Hero is the premier provider of high quality online educational resources. With millions of study documents, online tutors, digital flashcards and free courseware, Course Hero is helping students learn more efficiently and effectively. Whether you're interested in exploring new subjects or mastering key topics for your next exam, Course Hero has the tools you need to achieve your goals.
1 Page
chapter 7 - Thermochemistry
Course: CHEM 1a03, Spring 2008School: McMaster
Rating:
Word Count: 119
Document Preview
System a part of the universe chosen for study Surroundings Part of the universe outside the system that the system interacts with Open System Freely exchanges matter and energy with its surroundings Closed system Exchanges energy with its surroundings, but not matter Isolated System does not interact with its surroundings Energy the capacity to do work Work when a force acts though a distance Kinetic Energy the...
Unformatted Document Excerpt
Coursehero >> Canada >> McMaster >> CHEM 1a03Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
System a part of the universe chosen for study Surroundings Part of the universe outside the system that the system interacts with Open System Freely exchanges matter and energy with its surroundings Closed system Exchanges energy with its surroundings, but not matter Isolated System does not interact with its surroundings Energy the capacity to do work Work when a force acts though a distance Kinetic Energy the energy of a moving object Potential Energy energy due to condition, position, or composition and it is an energy associated with forces of attraction and repulsion Thermal Energy the kinetic energy associated with random molecular motion Heat energy transferred between a system and its surroundings as a result of a temperature difference
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more.
Course Hero has millions of course specific materials providing students with the best way to expand
their education.
Below is a small sample set of documents:
Below is a small sample set of documents:
McMaster - CHEM - 1a03
TUTORIAL #9 November 19th, 2007 Solutions Chapter 7 Correction to Q 4 _ CHEM 1A03 1. From the course notes, we had an expression for work:w = ! P"V = !"ngases RTFrom this, and our expressions for enthalpy and internal energy, we can re-write H as
Pittsburgh - COMMRC - 0052
Name: _Midterm Examination Public Speaking MONDAY Fall 200550 pointsDraw and clearly label the basic communication model (10 points 7 for accurate labels/3 for accurate drawing)Multiple choice (1 point each unless noted) please circle the m
McMaster - CHEM - 1a03
TUTORIAL #9 November 19th, 2007 Solutions Chapter 7 Correction to Q 4 _ CHEM 1A03 1. From the course notes, we had an expression for work:w = ! P"V = !"ngases RTFrom this, and our expressions for enthalpy and internal energy, we can re-write H as
Pittsburgh - COMMRC - 0052
Fact, Value, PolicyExamine each statement to determine whether it is an appropriate working thesis for a question of FACT, VALUE, POLICY, or none. A fact claim is an argumentative thesis which makes a quantifiable assertion; in other words, it is a
UCLA - LS - 2
AddictedWILLUSTRATION BY JANA BRENNING (photograph used for illustration purposes only)TheDrug abuse produces long-term changes in the reward circuitry of the brain. Knowledge of the cellular and molecular details of these adaptations could lea
Pittsburgh - COMMRC - 0052
Organizational Patterns Categorical - Parts that make up the whole Sequential - Develop a timeline or series of steps Spatial - Map ideas visually or literally with a visual aidCategoricalWhen you use the parts to the whole method you are simp
Pittsburgh - COMMRC - 0052
Name: _Examination Public Speaking- 50 Points Multiple choice (1 points each - 40 total) please circle the most correct answer1. As you present your speech, you notice that many of your listeners have interested looks on their faces and are noddin
Pittsburgh - COMMRC - 0052
Name: _Final Examination Public Speaking Spring 20051.50 pointsMultiple choice (1 point each 20 points total) please circle the most correct answer Persuasive appeals to the emotions are called _ a) ethos b) mythos c) pathos d) struthering S
Pittsburgh - COMMRC - 0052
Introduction to Public Speaking 0052 Spring 2005 W 6 8:40pm biddle 248 This class will be fun & entertaining Informal and comfortable EVERYONE is frightened Many reasons given for being here: Improve self confidence Aid in professional life 2002 su
Georgia Tech - ECE - 2030
ECE 2030F: Introduction to Computer Engineering Fall 2007Homework 1 Solution (Total 40 Points) 1. (10 points) a) f1 = (a AND b) or (NOT b AND c) = ab+ bc abc 000 001 010 011 100 101 110 111b)f2 = (a NAND b) NAND c = ab cab0 0 0 0 0 0 1 1bc
Georgia Tech - ECE - 2030
ECE 2030F: Introduction to Computer Engineering Fall 2007Homework 2 Solution (Total 50 Points) 1. (10 points) Here is an example: F = A'B'D + A'BC' + ABD' + ACD = A'C'D + BC'D' + ABC + B'CD All product terms are prime implicants, but none of them ar
Georgia Tech - ECE - 2030
ECE 2030F Fall 2007 Homework 3 Solution (Total 50 Points) 1. Mano/Kime 3rd Ed. Question 3-1 (4th Ed. Question 3-13) (25 points) Logic diagram and symbol of the hierarchical component: (10 points) H = X Y + X Z =Y X +Z XX Y H Z Hierarchy X YHzO
Georgia Tech - ECE - 2030
ECE 2030F Fall 2007Homework 4 Solution (Total 100 Points) 1. Mano/Kime 3rd Ed. 4-11 (10 points) Truth table of a decimal-to-binary priority decoder (assume that 9 is the highest priority and V indicates a valid output):Decimal Inputs 9876543210 000
UCLA - LS - 2
ATHEROSCLEROSIS in an artery feeding the heart can set the stage for a heart attack.50SCIENTIFIC AMERICANTHE SCIENCE OF STAYING YOUNGCOPYRIGHT 2004 SCIENTIFIC AMERICAN, INC.IT CAUSES CHEST PAIN, HEART ATTACK AND STROKE, LEADING TO MORE DEAT
Georgia Tech - ECE - 2030
ECE 2030FHomework 5 Solution (Total 50 points) 1. Draw a transistor-level schematic for a dynamic CMOS latch with a reset. (15 points)2. Draw a state transition graph for a 5-state counter with a reset to state 0. (15 points) The reset is the inpu
UCLA - CHEM - 14B
CHEM 14B: Spring 2008Instructor: Dr. Eric ScerriGENERAL CHEMISTRY FOR LIFE SCIENCE MAJORSCOURSE ORGANIZATION & SYLLABUS DESCRIPTION: This course provides the chemistry foundation required to pursue a career in the life sciences. We begin with an
UCLA - LS - 2
FORUMThe Benefits and Ethics of Animal ResearchExperiments on animals are a mainstay of modern medical and scientific research. But what are the costs and what are the returns?by Andrew N. RowanFCHRISTOPHER BURKE/QBor the past 20 years, we h
Georgia Tech - ECE - 2030
ECE 2030FHomework 6 Solution (Total 50 points) 1. (Mano/Kime 3rd ed problem 6-5): (15 points) (a) Logic diagram of the circuit (5 points)(b) State table (5 points)(c) State diagram (5 points)Inputs XY 0 0 0 1 1 0 1 1 0 0 0 1 1 0 1 1 0 0 0 1 1 0
UCLA - LS - 2
Animal Research Is Wasteful and Misleadingby Neal D. Barnard and Stephen R. KaufmanThe use of animals for research and testing is only one of many investigative techniques available. We believe that although animal experiments are sometimes inte
Georgia Tech - ECE - 2030
ECE 2030FHomework 7 Solution (Total 50 points) 1. (Mano/Kime 3rd ed problem 7-5): (10 points) (a) Clear all even bit positions to 0 (3 points) AND 1010 1010 1010 1010 (b) Set the leftmost 4 bits to 1 (3 points) OR 1111 0000 0000 0000 (c) Complement
UCLA - LS - 2
Animal Research Is Vital to Medicineby Jack H. Botting and Adrian R. MorrisonExperiments using animals have played a crucial role in the development of modern medical treatments, and they will continue to be necessary as researchers seek to alle
Georgia Tech - ECE - 2030
ECE 2030FHomework 9 Solution (Total 50 points) 1. (Mano/Kime 3rd ed problem 10-12 a,b): (20 points) (a) (10 points) The maximum total delay from register file to register file is 2+1+3+4+4 = 14ns, so the maximum clock frequency is 1/14ns = 71.4MHz.
UCLA - LING - 20
LING 20 NAME: SECTION:Homework 1: PhoneticsPart I: Complete each of the following comparisons, following the model given for the first item. These are to be read (as for example in 2.) "[tS] is to [dZ] what [q] is to what?" 1. 2. 3. 4. 5. 6. 7. 8
Georgia Tech - ECE - 2030
ECE 2030FHomework 8 Solution (Total 50 Points) 1. (Mano/Kime 3rd ed problem 9-8): (10 points) A DRAM has 4096 (= 212) rows, so the minimum number of address pins is 12. The interval between refreshes is 128ms/4096 = 31.25s. 2. (Mano/Kime 3rd ed prob
UCLA - LS - 2
Trends in Animal ResearchIncreased concern for animals, among scientists as well as the public, is changing the ways in which animals are used for research and safety testingby Madhusree Mukerjee, staff writerThere is no question about it: the
UCLA - LING - 20
LING 20 NAME SECTIONHomework 6: SyntaxConsider the hypothetical grammar and lexicon below. The parentheses surround an optional component of the sentence. Notice that categories B and C are themselves `complex', or phrasal. Grammar (a set of gene
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1371 Computing for Engineers Test 1 Practice Test - Fall Semester 2006 Use this practice test and the book questions for chapters 1-7 excluding Section 7.3 enumerated types for practice.There
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1371 Computing for Engineers Test 2 Practice Test - Fall Semester 2006 Use this practice test and the book questions for chapters 1-11 excluding Sections 7.3 and 11.6.There is some measurable
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1372 Computing for Engineers Test 3 Version A - Fall Semester 20060 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q
Pontifical Catholic University of Peru - ENG - LP2
La ROM: Esta registrada permanentemente en la circuiteria de los chips del pc y no puede ser alterada borrada o perdida Contiene programas y los datos que son necesarias para activar y hacer funcionar al ordenador y sus dispositivos perifricos. Hay c
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1372 Computing for Engineers Test 3 Version B - Fall Semester 20060 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q
Pontifical Catholic University of Peru - ENG - LP2
ADAPTADORES DE VIDEO: Tarjeta especial, que se conecta en uno de los conectares de expansin del ordenador que es necesaria para producir la imagen de video. Conecta el ordenador al monitor a travs de un chip llamado controlador de CRT. El adaptador t
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1372 Computing for Engineers Test 2 - Spring Semester 20070 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U
Pontifical Catholic University of Peru - MATH - Calc
Pontificia Universidad Catlica del Per Facultad de Ciencias e IngenieraIntroduccin al paquete MATLAB MATLAB es un paquete de software matemtico basado en matrices. El paquete consiste de una extensa biblioteca de rutinas numricas, fcilmente se acced
Georgia Tech - CS - 1372
Georgia Institute of Technology College of Computing CS 1372 Computing for Engineers Test 3 - Spring Semester 2007g p b u r d e l l0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L
Pontifical Catholic University of Peru - ENG - SO
PONTIFICIA UNIVERSIDAD CATLICA DEL PER FACULTAD DE CIENCIAS E INGENIERA SEGUNDO EXAMEN DE SISTEMAS OPERATIVOS (1er perodo de 2006) Horarios 0881, 0883: prof. V. Khlebnikov Duracin: 3 horas.1. (6 puntos) (Cigarette Smokers Problem [Patil 1971; Parnas
Pontifical Catholic University of Peru - ENG - SO
PONTIFICIA UNIVERSIDAD CATLICA DEL PER FACULTAD DE CIENCIAS E INGENIERA SISTEMAS OPERATIVOS (4ta hoja de trabajos prcticos) (1er perodo de 2006) Horarios 0881, 0883: Prof. V. Khlebnikov Duracin: 1 h. 50 min.The QNX Neutrino Microkernel:Barriers A b
Pontifical Catholic University of Peru - ENG - SO
PONTIFICIA UNIVERSIDAD CATLICA DEL PER FACULTAD DE CIENCIAS E INGENIERA SISTEMAS OPERATIVOS (1ra hoja de trabajos prcticos) (2do perodo de 2006) Horarios 0881 (V. Khlebnikov), 0883 (A. Bello) Duracin: 1 h. 50 min.Segn los dumps proporcionados, prese
Georgia Tech - PHYSICS - 2211
1.26.Solve:(a) We need kg/m3. There are 100 cm in 1 m. If we multiply by 100 cm = (1) 3 1m we do not change the size of the quantity, but only the number in terms of the new unit. Thus, the mass density of aluminum is3kg 100 cm kg 2.7
Georgia Tech - PHYSICS - 2211
1.34. Solve: growth isMy barber trims about an inch of hair when I visit him every month for a haircut. The rate of hair1(inch ) 2.54 cm 10 -2 m 1 month 1 day 1 hr = 9.8 10 -9 m /s ( month ) 1 inch 1 cm 30 days 24 hr 3600 s
Pontifical Catholic University of Peru - ENG - SO
PONTIFICIA UNIVERSIDAD CATLICA DEL PER FACULTAD DE CIENCIAS E INGENIERA SISTEMAS OPERATIVOS (2da hoja de trabajos prcticos) (2do perodo de 2006) Horarios 0881 (V. Khlebnikov), 0883 (A. Bello) Duracin: 1 h. 50 min.En esta ocasin trabajemos con la tar
Georgia Tech - PHYSICS - 2211
2.39.Solve:The position is the integral of the velocity.x1 = x 0 + v x dt = x 0 + kt 2 dt = x 0 + 1 kt 3 3t0 0t1t1t1 0= x 0 + 1 kt13 3We're given that x0 = 9.0 m and that the particle is at x1 = 9.0 m at t1 = 3.0 s. Thus9.0 m = (
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: ELIMINACION GAUSSIANA CON PIVOTEO ESCALONADO % Descripcion: El programa encuentra las raices de un conjunto de ecuaciones lineales de la forma % A x X = B, utilizando el metodo de eliminacion gaussiana con la estrategia de % pivoteo escal
Georgia Tech - PHYSICS - 2211
2.24. Model: We will represent the skier as a particle. Visualize:Note that the skier's motion on the horizontal, frictionless snow is not of any interest to us. Also note that the acceleration parallel to the incline is equal to g sin10. Solve: Us
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: ELIMINACION GAUSSIANA % Descripcion: El programa encuentra las raices de un conjunto de ecuaciones lineales de la forma % A x X = B, utilizando el metodo de eliminacion gaussiana. % curso: Calculo Numerico % programacion: Rony Yupanqui G.
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: ELIMINACION GAUSSIANA CON PIVOTEO PARCIAL % Descripcion: El programa encuentra las raices de un conjunto de ecuaciones lineales de la forma % A x X = B, utilizando el metodo de eliminacion gaussiana con la estrategia de % pivoteo parcial.
Georgia Tech - PHYSICS - 2211
2.55. Model: We will model the lead ball as a particle and use the constant-acceleration kinematic equations. Visualize:Note that the particle undergoes free fall until it hits the water surface. Solve: The kinematics equation y1 = y0 + v0 (t1 - t
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: METODO DE GAUSS SEIDEL % Descripcion: El programa encuentra las raices de un conjunto de ecuaciones lineales de la forma % A x X = B, utilizando el metodo iterativo de Jacobi. % curso: Calculo Numerico % programacion: Rony Yupanqui G. % f
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: METODO DE JACOBI % Descripcion: El programa encuentra las raices de un conjunto de ecuaciones lineales de la forma % A x X = B, utilizando el metodo iterativo de Jacobi. % curso: Calculo Numerico % programacion: Rony Yupanqui G. % fecha:
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: BISECCION % Descripcion: El programa encuentra las raices de una funcion f(x) en el intervalo [a, b] % utilizando el metodo de biseccion. % curso: Calculo Numerico % programacion: Rony Yupanqui G. % fecha: Agosto 2006 % VARIABLES % extrem
Georgia Tech - PHYSICS - 2211
2.73. Model: The rocket and the bolt will be represented as particles to investigate their motion. Visualize:The initial velocity of the bolt as it falls off the side of the rocket is the same as that of the rocket, that is, vB0 = vR1 and it is pos
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: NEWTON PARA UNA VARIABLE % Descripcion: El programa encuentra la raiz de una funcion f(x) con una aproximacion inicial "xo" % utilizando el metodo de Newton. % curso: Calculo Numerico % programacion: Rony Yupanqui % fecha: Agosto 2006 % V
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: NEWTON PARA DOS VARIABLES % Descripcion: El programa encuentra la raiz (x,y) para un sistema de ecuaciones f(x,y) y g(x,y) % con una aproximacion inicial "(xo,yo)" utilizando el metodo de Newton % para dos variables. % curso: Calculo Nume
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: UBICA RAICES PARA 2 VARIABLES. % descripcion: El programa define intervalos sobre los que se ubican las soluciones % para un sistema de ecuaciones con 2 variables. Se ingresan % las dos funciones, los intervalos en los que se realizara %
Georgia Tech - PHYSICS - 2211
2.78. Model: Jill and the grocery cart will be treated as particles that move according to the constantacceleration kinematic equations. Visualize:Solve:The final position of Jill when the cart is caught is given byx J1 = x J0 + vJ0 (t J1 - t J
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: PUNTO FIJO % Descripcion: El programa encuentra la raiz de una funcion f(x) con una aproximacion inicial "xo" % utilizando el metodo del punto fijo. % curso: Calculo Numerico % programacion: Rony Yupanqui G. % fecha: Agosto 2006 % VARIABL
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: PUNTO FIJO PARA DOS VARIABLES % Descripcion: El programa encuentra la raiz (x,y) para un sistema de ecuaciones f(x,y) y g(x,y) % con una aproximacion inicial "(xo,yo)" utilizando el metodo del Punto Fijo % para dos variables. % curso: Cal
Pontifical Catholic University of Peru - MATH - Calc
% PROGRAMA: UBICA RAICES % Descripcion: El programa divide un intervalo [a, b] en "n" partes iguales y define los intervalos % en los cuales existe una raiz para una funcion f(x). % curso: Calculo Numerico % programacion: Rony Yupanqui G. % fecha: Ag
Georgia Tech - PHYSICS - 2211
3.10. Visualize:We will follow the rules given in the Tactics Box 3.1. Solve: (a) rx = -(2 km) sin 30 = -1 km ry = (2 km) cos 30 = 1.73 km (b) vx = -(5 cm/s)sin 90 = -5 cm/s vy = (5 cm/s)cos 90 = 0 cm/s (c) a x = -(10 m /s 2 )sin 40 = -6.43 m /s 2
Georgia Tech - PHYSICS - 2211
3.11. Visualize:r r The components of the vector C and D , and the angles are shown. v v Solve: For C we have Cx = -(3.15 m )cos15 = -3.04 m and Cy = (3.15 m )sin 15 = 0.815 m. For D we have Dx = 25.67 sin 30 = 12.84 and Dy = -25.67 cos 30 = -22.2
Georgia Tech - PHYSICS - 2211
3.26. Visualize: Refer to Figure P3.26.Solve:From the rules of trigonometry, we have Ax = 4 cos 40 = 3.06 and Ay = 4 sin 40 = 2.57. Also, Bx = r r r r r r r r r ^ ^ -2 cos10 = -1.97 and By = +2 sin 10= 0.35. Since A + B + C = 0, C = - A - B = ( -