9 Pages

NS14loads

Course: ARCH 331, Fall 2008
School: Texas A&M
Rating:
 
 
 
 
 

Word Count: 1464

Document Preview

331 Note ARCH Set 14 F2008abn System Assemblies & Load Tracing Load Tracing LOAD TRACING is the term used to describe how the loads on and in the structure are transferred through the members (load paths) to the foundation, and ultimately supported by the ground. It is a sequence of actions, NOT reactions. Reactions in statically determinate members (using FBD's) can be solved for to determine the...

Register Now

Unformatted Document Excerpt

Coursehero >> Texas >> Texas A&M >> ARCH 331

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
331 Note ARCH Set 14 F2008abn System Assemblies & Load Tracing Load Tracing LOAD TRACING is the term used to describe how the loads on and in the structure are transferred through the members (load paths) to the foundation, and ultimately supported by the ground. It is a sequence of actions, NOT reactions. Reactions in statically determinate members (using FBD's) can be solved for to determine the actions on the next member in the hierarchy. The tributary area is a loaded area that contributes to the load on the member supporting that area, ex. the area from the center between two beams to the center of the next two beams for the full span is the load on the center beam The tributary load on the member is found by concentrating (or consolidating) the load into the center. ab a b w=( load ) x(tributary width) area tributary width plan where w = distributed load in units of load/length. Distributed Loads Distributed loads may be replaced by concentrated loads acting through the balance/center of the distribution or load area: THIS IS AN EQUIVALENT FORCE SYSTEM. w is the symbol used to describe the load per unit length. Note: It can also represent a load per unit area. W is the symbol used to describe the total load. w x =W w x W = 2 2 w w 0 x W 2w w x x W/2 W W/2 x/2 x/6 x/3 x/2 x/2 2x/3 x/3 1 ARCH 331 Note Set 14 F2008abn Framing Systems Horizontal levels must transfer loads to vertical elements. There are many ways to configure the systems. The horizontal levels can be classified by how many elements transfer loads in the plane. Decking is not usually considered a level in a multiple level system because it isn't significantly load bearing. It is considered a level when it is the only horizontal element and must resist loads. Foundations The final path of the load for the structure is to the foundation. The foundation must transfer the loads to the soil, which is a "natural" structural material. The soil conditions will determine if a shallow foundation (most economical an easy to construct) can be used, or a deep foundation (for larger loads or poorer soil capacities) must be considered. Distribution of Loads on Edge Supported Slabs Distributed loads on two-way slabs (i.e. not one-way like beams) do not have obvious tributary "widths". The distribution is modeled using a 45 degree tributary "boundary" in addition to the tributary boundary that is half way between supporting elements, in this case, edge beams. The tributary distribution from the area loads result in a trapezoidal distribution. Self weight will be a uniform distributed load, and will also have to be included for design of beam AB. Openings in Floor/Roof Plans Openings in a horizontal system usually are framed on all sides. This provides for stiffness and limiting the deflection. The edge beams may not be supporting the flooring, however, so care needs to be taken to determine if an opening edge beam must support tributary area, or just itself. Any edge beam supporting a load has load on only one side to the next supporting element. 2 ARCH 331 Note Set 14 F2008abn Beams Supported by Other Beams Joists are commenly supported by beams with beam hangers. The reaction at the support is transferred to the beam as a single force. A beam, in turn, can be supported by a larger beam or girder, and the reaction from this beam having a uniform distributed self weight, and the forces, will be an action on the girder. Horizontal Projection of Gravity Load on a Rafter When an angled member, such as a rafter has a self weight per unit length, that weight is usually converted to a weight per horizontal length: length wself wt . equiv . = wself wt . horizontal dis tan ce Retaining Walls Retaining walls are used to hold back soil or other material with the wall. The other key components include bases, counterforts, buttresses or keys. Gravity loads help provide resistance to movement, while the walls with lateral loads behave like cantilever beams. Loads The design of retaining walls must consider overturning, settlement, sliding and bearing pressure. The water in the retained soil can significantly affect the loading and the active pressure of the soil. The lateral force, P, acting at a height of h/3 is determined from the equivalent fluid weight (density), ', (in force/cubic area) as: 2 ph P= 2 where p is the maximum pressure at the base: p = h Overturning is considered the same as for eccentric footings: SF = M resist 1.5 - 2 M overturning 3 h/3 P ARCH 331 Note Set 14 F2008abn where Mresist = summation of moments about "o" to resist rotation, typically including the moment due to the weight of the stem and base and the moment due to the passive pressure. Moverturning = moment due to the active pressure about the toe "o". Sliding must also be avoided: SF = where Fhorizontal-resist = summation of forces to resist sliding, typically including the force from the passive pressure and friction (F=N where . is a constant for the materials in contact and N is the normal force to the ground acting down and is shown as R). Fsliding = sliding force as a result of active pressure. Pressure Distribution Because the resultant force from the gravity loads and pressure is not vertical, the vertical pressure distribution under the footing will not be uniform, but will be linearly distributed. The vertical component of the resultant must be in the same horizontal location as the pressure reaction force. W P o R Fresist Fhorizontal - resist 1.25 - 2 F sliding There can never be a tensile pressure because the footing will not be in contact with the soil. To make certain all the area under the footing is used to distributed the load, the vertical resultant needs to be within the middle third of the base width. This area is called the kern. Soil pressure is most commonly called q in the design texts and codes. 3x Ry x To determine the size of the maximim pressure we find the equivalent location of the pressure reaction, P, at x using moment calculations when Rx = W: W = P = 1/2p(3x) so and p = 2W/3x p = 2W/a when x < a/3 when x = a/3 p P = p(3x) a where x is the location of the resultant force and a is the width of the base. 4 ARCH 331 Note Set 14 F2008abn Wind Load Tracing For design purposes, wind loads are treated as static pressure distributions over the walls and roof. In the case of walls, the loads are traced just like those for horizontal surfaces. If there is a roof diaphragm, it is the "top" supporting element and the tributary boundary is half way "up" to the diaphragm. If the supporting elements are the side walls the tributary boundary is vertical and half way between sides. In either case, the traced action force at the top of the walls is a lateral shear force (V) that must be resisted. The shear over the width of a shear wall, v, is a unit shear used for determining the connection and framing capacity req...

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231DR. ANNE NICHOLS SPRING 2008twenty sevenframes: rigid and bracedRigid Frames 1 Lecture 27 Architectural Structures I ENDS 231 S2008abnlectureRigid Frames rigid frames ha
Texas A&M - ENDS - 231
ENDS 231Note Set 24S2008abnSteel &amp; Wood Column DesignDesign Aims If we know the loads, we can select a section that is adequate for strength &amp; buckling. If we know the length, we can find the limiting load satisfying strength &amp; buckling. Desig
Texas A&M - ARCH - 631
ARCHITECTURAL STRUCTURES III: STRUCTURAL ANALYSIS AND SYSTEMSARCH 631DR. ANNE NICHOLS FALL 2008tutorialusing Multiframe4DMultiframe4D 1 Tutorial Architectural Structures III ARCH 631 F2008abnframesMultiframe4D (Version 10) on college comp
Texas A&M - ENDS - 231
ENDS 231Note Set 8F2007abnTruss Analysis using Multiframe4D 1. The software is on the computers in the college computing lab (http:/thelab.tamu.edu) in Programs under the Windows Start menu. Multiframe4D is under the COSC menu. 2. There is a tu
Texas A&M - ENDS - 231
ENDS 231SymbolsF2007abnList of Symbol Definitionsa long dimension for a section subjected to torsion (in, mm); acceleration (ft/sec2, m/sec2) area bounded by the centerline of a thin walled section subjected to torsion (in2, mm2) area, often c
Texas A&M - ENDS - 231
ENDS 231Note Set 26F2007abnConnections and Tension Member DesignConnections Connections must be able to transfer any axial force, shear, or moment from member to member or from beam to column. Steel construction accomplishes this with bolt and
Texas A&M - ARCH - 331
ARCH 331Study GuideF2008abnARCH 331. Study Guide for Final ExaminationThis guide is not providing answers for the conceptual questions. It is a list of topical concepts and their application you should be familiar with. It is an aid to help pr
Texas A&M - ARCH - 331
FOUNDATIONS STRUCTURES: FORM, BEHAVIOR, AND DESIGNARCH 331Systems beams separate from slab beams integral with slab close spacedDR. ANNE NICHOLS SPRING 2009twenty threeconcrete construction:T-beams &amp; slabsConcrete Slabs 1 Lecture 23 Foun
Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231Centric &amp; Eccentric Loading centric allowable stress from strength or bucklingDR. ANNE NICHOLS SPRING 2008twenty fiveeccentric loading: beam-columnsColumn Eccentricity 1
Texas A&M - ARCH - 631
ARCHITECTURAL STRUCTURES III: STRUCTURAL ANALYSIS AND SYSTEMSARCH 631Rigid Frames composed of linear elements member geometry fixed at joints no relative rotationDR. ANNE NICHOLS FALL 2008sevenrigid frames: analysis &amp; designRigid Frames 1
Texas A&M - ARCH - 331
FOUNDATIONS STRUCTURES: FORM, BEHAVIOR, AND DESIGNARCH 331Beam Bending Galileo relationship between stress and depth2DR. ANNE NICHOLS SPRING 2009tenlecture can see top squishing bottom stretchingbeams: bending and shear stressBeam S
Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231Structural Loads gravity acts on mass (F=mg) forces acts at a point ie. joist on beamDR. ANNE NICHOLS SPRING 2008tenlecture acts along a line ie. floor on a beamlo
Texas A&M - ENDS - 231
THE DEACONS MASTERPIECE Or, the Wonderful one-Hoss Shay A Logical Story By Oliver Wendell HomesHAVE you heard of the wonderful one-hoss-shay, That was built in such a logical way It ran a hundred years to a day, And then, of a sudden, it-ah, but sta
Texas A&M - ARCH - 631
ARCH 631F2008abnUsing Turnitin in ARCH 6311As a faculty member at Texas A&amp;M University, I know that many of you are unfamiliar with what constitutes plagiarism, commonly defined as the act of passing off someone else's work as your own. This sem
Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231DR. ANNE NICHOLS SPRING 2008fifteenmechanics of materialsMechanics of Materials 1 Lecture 15 Architectural Structures I ENDS 231 S2008abnlectureMechanics of Materials ME
Texas A&M - ENDS - 231
ENDS 231Note Set 12F2007abnMoments of InertiaThe cross section shape and how it resists bending and twisting is important to understanding beam and column behavior. Definition: Moment of Inertia; the second area moment yI y = x 2 dAI
Texas A&M - ARCH - 614
ELEMENTS OF ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGNARCH 614DR. ANNE NICHOLS SPRING 2009ninelecturebeams: bending and shear stressBeam Stresses 1 Lecture 9 Elements of Architectural Structures ARCH 614 S2009abnBeam Bending Ga
Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231DR. ANNE NICHOLS SPRING 2008twenty onebeams: deflection &amp; designBeam Deflection &amp; Design 1 Lecture 21 Architectural Structures I ENDS 231 S2008abnlectureDesign for Streng
Texas A&M - ENDS - 231
ARCHITECTURAL STRUCTURES I: STATICS AND STRENGTH OF MATERIALSENDS 231DR. ANNE NICHOLS SPRING 2008elevencenters of gravity- centroidsCentroids 1 Lecture 11 Architectural Structures I ENDS 231 S2008abnlectureCenter of Gravity location of eq
Texas A&M - ENDS - 231
ENDS 231Note Set 21F2007abnBeam Design and DeflectionsCriteria for Design Allowable normal stress or normal stress from LRFD should not be exceeded: Knowing M and Fb, the minimum section modulus fitting the limit is:Fb or Fn f b =S req 'd
Texas A&M - ARCH - 631
Texas A&M - ARCH - 631
ARCHITECTURAL STRUCTURES III: STRUCTURAL ANALYSIS AND SYSTEMSARCH 631Earthquake Design dynamic vs. static loading amplification of static affect time duration acceleration &amp; velocityDR. ANNE NICHOLS FALL 2008seventeenseismic design Reute
Texas A&M - ARCH - 631
ARCH 631Sample ExamF2008abnARCH 631: Sample ExamNote: This is a sample exam with the types of questions that will be on mid-term exams. The subject is Physics 101. The exam is closed book. Part 1) Worth ~50% (~2.5 points each)Circle the answ
Texas A&M - ARCH - 631
ARCH 631F2008abnARCH 631. Assignment #9Date: 10/30/08, due 11/11/08 Problems: 1. The sketch to the right illustrates which ofthe following? I. II. III. IV. A. B. C. D. Soft story Re-entrant corner Torsional irregularity Stiffness irregularity I
Texas A&M - ARCH - 631
ARCH 631F2008abnARCH 631. Study Guide for Exam 1This guide is not providing &quot;answers&quot; for the conceptual questions. It is a list of topical concepts and their application you should be familiar with. It is an aid to help prepare for the mid-term
Texas A&M - ARCH - 631
ARCH 631F2008abnARCH 631. Case Study ProjectDate: 9/9/08 Problem Statement: A case study of an architectural structure is to be undertaken by a team of 4-5 class members. The structure being investigated can be new or old, still standing or torn
Texas A&M - ARCH - 631
ARCHITECTURAL STRUCTURES III: STRUCTURAL ANALYSIS AND SYSTEMSARCH 631DR. ANNE NICHOLS FALL 2008fifteendesign for lateral loadsLateral Load Design 1 Lecture 15 Architectural Structures III ARCH 631 F2008abnlectureLateral Load Resistance st
Texas A&M - ARCH - 631
Academic IntegrityAcademic IntegrityAcademic integrity is defined differently from culture to culture. In some cultures, sharing homework assignments, providing friends with answers to test questions, and allowing someone to copy one's papers is c
Texas A&M - ARCH - 631
ARCHITECTURAL STRUCTURES III: STRUCTURAL ANALYSIS AND SYSTEMSARCH 631Lateral Load Resistance stability important for any height basic mechanisms shear walls diaphragms diagonal bracing frame actionDR. ANNE NICHOLS FALL 2008fifteendesign
Texas A&M - ARCH - 631
ARCH 631Note Set 28.2F2007abnUS Historical Structure Examples from Historical Building Construction, Donald Friedman, 1995.1835 Obadiah Parker House, New York, Parker designer, demolished. House walls were monolithic concrete, probably with na
Texas A&M - ARCH - 631
ARCH 631Note Set 8.3F2008abnExamples: Plate and Grids Example 1What is the maximum positive and negative bending moments developed in a 52 x 40 ft fully fixed plate that carries a load of 120 lb/ft2?area load = 120 lb/ft2The aspect ratio o