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Course: ARCH 631, Fall 2008
School: Texas A&M
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Footbridge Maillart's over the Triftwasser River A Case Study in Reinforced Concrete GSD 6202 Spring 2000 Kyle Dugdale Jacquie Scott Youngsun Sonn Paul Wolff Tyrone Yang Copyright 2000 President and Fellows of Harvard College 1 Footbridge over the Triftwasser 1932 photos after Max Bill Copyright 2000 President and Fellows of Harvard College 2 Bridge Dimensions 68.88 ft Length: 68.88 ft Slope 5.72 degrees...

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Footbridge Maillart's over the Triftwasser River A Case Study in Reinforced Concrete GSD 6202 Spring 2000 Kyle Dugdale Jacquie Scott Youngsun Sonn Paul Wolff Tyrone Yang Copyright 2000 President and Fellows of Harvard College 1 Footbridge over the Triftwasser 1932 photos after Max Bill Copyright 2000 President and Fellows of Harvard College 2 Bridge Dimensions 68.88 ft Length: 68.88 ft Slope 5.72 degrees *Slope of bridge has no impact on reactions and calculations for shearing, bending and torsion. Copyright 2000 President and Fellows of Harvard College 3 Dimensions of Bridge 5.77 4.92 Width of web 1.05 ft Depth of flange 0.39 ft Depth of beam 4.1 ft Cross section width 5.77 ft Pedestrian traffic 4.92 ft 4.1 Copyright 2000 President and Fellows of Harvard College 4 Weight of Bridge VOLUME = (cross-sectional area) x (length) = 438 ft3 DEAD LOAD = volume x (weight of reinforced concrete) = 438 ft3 x 150 lb ft3 = 65768 lb Weight Copyright 2000 President and Fellows of Harvard College 5 Weight of Bridge VOLUME = (cross-sectional area) x (length) = 438 ft3 DEAD LOAD = volume x (weight of reinforced concrete) = 438 ft3 x 150 lb ft3 = 65768 lb Weight Weight of side volumes: 89393 lb (Total weight would be 155,161 lbs.) Copyright 2000 President and Fellows of Harvard College 6 Weight of Bridge VOLUME = (cross-sectional area) x (length) = 438 ft3 DEAD LOAD = volume x (weight of reinforced concrete) = 438 ft3 x 150 lb ft3 = 65768 lb Weight LIVE LOAD (pedestrians) = 27126 lb TOTAL WEIGHT = (dead load) + (live load) = 92894 lb Copyright 2000 President and Fellows of Harvard College 7 Shear and Bending Moment Calculations Max Moment = 801,500 lb-ft Max Shear = 46447 lb Copyright 2000 President and Fellows of Harvard College 8 Torsion Calculations Torsion Moment = (1/2 x Live Load) x Lever Arm = (1/2 x 27126 lb) x 1.44 ft = 19579 lb-ft Torsion at each abutment = 33356 / 2 = 16678 ft-lb Torsion (perp. to beam) Bending (along length of beam) 1.44 ft. Copyright 2000 President and Fellows of Harvard College 9 wind calculations Copyright 2000 President and Fellows of Harvard College 10 Copyright 2000 President and Fellows of Harvard College 11 Reinforcing Patterns Beam: Skin reinforcement Bending moments Shear Copyright 2000 President and Fellows of Harvard College 12 Reinforcing Patterns Beam: Skin reinforcement Bending moments Shear Copyright 2000 President and Fellows of Harvard College 13 Reinforcing Patterns Abutments: Shear Bending moments Diagonal reinforcing prevents shear Copyright 2000 President and Fellows of Harvard College Bending moments 14 Reinforcing Patterns Slab: Torsion Horizontal reinforcing on top of beam to counter negative moment due to cantilever. Copyright 2000 President and Fellows of Harvard College 15 calculation necessary of steel reinforcements 4 values: balanced steel maximum steel required steel minimum steel (purely for purposes of calculation) (as calculated by Excel spreadsheet) Copyright 2000 President and Fellows of Harvard College 16 required steel (Excel spreadsheet) i.e. inches, pounds d fc fy Es using 1.7x[live load] & 1.4x[dead load] e.g. bending 0.9, shear/torsion 0.85 required steel reinforcement Copyright 2000 President and Fellows of Harvard College 17 balanced steel & maximum steel Copyright 2000 President and Fellows of Harvard College 18 minimum steel Copyright 2000 President and Fellows of Harvard College 19 summary balanced steel: maximum steel: minimum steel: required steel: 16.15 in2 12.11 in2 2.33 in2 7.017 in2 so, use 10 x No.8 reinforcing bars i.e. 10 x 0.79 in2 Copyright 2000 President and Fellows of Harvard College 20 transverse reinforcement i.e. inches, pounds depth of flange at cross-section for a 1-foot section of the bridge fc fy Es using 1.7x[live load] & 1.4x[dead load] e.g. bending 0.9, shear/torsion 0.85 required steel, for every foot Copyright 2000 President and Fellows of Harvard College 21 Railing:T-section 200 lb Section view of rail Copyright 2000 President and Fellows of Harvard College 22 F=200 lb R=200 lb Section view of rail Copyright 2000 President and Fellows of Harvard College 23 F=200 lb d M= Fd R=200 lb Section view of rail Copyright 2000 President and Fellows of Harvard College 24 Top 200 lb d Bottom Deflection Shear Bending Moment Maximum Shear Force : 200 lb Maximum Bending M : 754 lb-ft Maximum Deflection : 0.111 in Distance d : 45.276 in Copyright...

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