Washington - ART H - 203

Culture Wars Preparation Hints for Mid-term Exam, October 22 PLEASE BRING A BLUE BOOK TO CLASS 1. Slide Identifications (10 x 2 points each; 10 minutes) You will be tested on your ability to identify the name of the artist, title, and date of 10 work

UCLA - MAE - MAE 182A

Problem 1(5+5+10)Consider the first order differential equation (DE) ax where a, b, c are constants.by (bx cy )dy dx0a. Is the above equation linear or nonlinear? Explain your answer. b. Is there an integrating factor c. Solve the differe

Washington - CHEM - 142

Prelim 1 (Wks 1-6) Significant Figures Counting: 1. All nonzero digits are significant. 2. Zeroes to the left of the first nonzero digit are not significant. 3. Zeroes at the end of a number that includes a decimal point are significant. Addition an

Washington - LAW P - 528

Justifications for IP LawIncentive to create because knowledge that you can reap benefit o Even if luck into discovery, still want incentive to bring to market o Other incentives Glory, salary, personal need Moral entitlement to fruits of labor o S

Cal Poly - ME - 326

INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be

Cal Poly - ME - 302

Cal Poly - ME - 302

Washington - BIO - 106

Biology (Underlines and bold) Terms Lecture 14: Origin of life (26.1, 26.2, 26.3, 26.4) 4.6 billion years ago When Earth was formed, along with the rest of the solar system Protobionts Aggregates of abiotically produced molecules surrounded by a memb

Washington - ECON - 300

ECONOMICS 300 FINAL EXAM SPRING 2004 PLEDGE: _ NAME: _1. (3) In a model of oligopoly: a. There are many firms that are price takers. b. There are many firms that offer heterogeneous product. c. One firm that is a price setter. d. Several firms that

Cal Poly - ME - 302

Cal Poly - ME - 302

Cal Poly - ME - 302

Lehigh - PHYSIC - 2

1. The speed (assumed constant) is (90 km/h)(1000 m/km) / (3600 s/h) = 25 m/s. Thus, during 0.50 s, the car travels (0.50)(25) 13 m.2. Huber's speed is v0=(200 m)/(6.509 s)=30.72 m/s = 110.6 km/h, where we have used the conversion factor 1 m/s = 3

Lehigh - PHYSIC - 2

1. (a) The magnitude of the magnetic field due to the current in the wire, at a point a distance r from the wire, is given byB= 0i2r.With r = 20 ft = 6.10 m, we havec4 10 B=hb 2 b6.10 mg-7T m A 100 Ag = 3.3 10-6T = 3.3 T.(b

Lehigh - PHYSIC - 2

1. The initial speed of the car is v = (80.0)(1000/3600) = 22.2 m/s. The tire radius is R = 0.750/2 = 0.375 m. (a) The initial speed of the car is the initial speed of the center of mass of the tire, so Eq. 11-2 leads to0 =vcom0 R=22.2 = 59.3

Lehigh - PHYSIC - 2

1. The condition for a minimum of a single-slit diffraction pattern isa sin = mwhere a is the slit width, is the wavelength, and m is an integer. The angle is measured from the forward direction, so for the situation described in the problem, i

Lehigh - PHYSIC - 2

1. (a) Eq. 28-3 leads to 6.50 10-17 N FB v= = = 4.00 105 m s . -19 -3 eB sin 160 10 C 2.60 10 T sin 23.0 .chch(b) The kinetic energy of the proton isK=2 1 2 1 mv = 167 10-27 kg 4.00 105 m s = 134 10-16 J. . . 2 2chchThis is

Lehigh - PHYSIC - 2

1. Our notation is as follows: x1 = 0 and y1 = 0 are the coordinates of the m1 = 3.0 kg particle; x2 = 2.0 m and y2 = 1.0 m are the coordinates of the m2 = 4.0 kg particle; and, x3 = 1.0 m and y3 = 2.0 m are the coordinates of the m3 = 8.0 kg particl

Lehigh - PHYSIC - 2

1. (a) The magnitude of r is5.02 + ( -3.0) 2 + 2.02 = 6.2 m.(b) A sketch is shown. The coordinate values are in meters.2. Wherever the length unit is not specified (in this solution), the unit meter should be understood.^ (a) The position vect

Lehigh - PHYSIC - 2

1. (a) The second hand of the smoothly running watch turns through 2 radians during 60 s . Thus,=2 = 0.105 rad/s. 60(b) The minute hand of the smoothly running watch turns through 2 radians during 3600 s . Thus,=2 = 1.75 10 -3 rad / s. 360

Lehigh - PHYSIC - 2

1. (a) All the energy in the circuit resides in the capacitor when it has its maximum charge. The current is then zero. If Q is the maximum charge on the capacitor, then the total energy is2.90 10-6 C Q2 U= = = 117 10-6 J. . -6 2C 2 3.60 10 Fc

Lehigh - PHYSIC - 2

1. The vector area A and the electric field E are shown on the diagram below. The angle between them is 180 35 = 145, so the electric flux through the area is = E A = EA cos = (1800 N C ) 3.2 10-3 m cos145 = -1.5 10-2 N m 2 C.2()2. We u

Lehigh - PHYSIC - 2

1. (a) The amplitude is half the range of the displacement, or xm = 1.0 mm. (b) The maximum speed vm is related to the amplitude xm by vm = xm, where is the angular frequency. Since = 2f, where f is the frequency,vm = 2 fxm = 2 (120 Hz ) (1.0 10 -

Lehigh - PHYSIC - 2

1. The time it takes for a soldier in the rear end of the column to switch from the left to the right foot to stride forward is t = 1 min/120 = 1/120 min = 0.50 s. This is also the time for the sound of the music to reach from the musicians (who are

Lehigh - PHYSIC - 2

1. We take p3 to be 80 kPa for both thermometers. According to Fig. 18-6, the nitrogen thermometer gives 373.35 K for the boiling point of water. Use Eq. 18-5 to compute the pressure:pN =T 373.35 K p3 = 273.16 K 273.16 K(80 kPa) = 109.343kPa.

Lehigh - PHYSIC - 2

1. According to Eq. 39-4 En L 2. As a consequence, the new energy level E'n satisfiesEn L = En LFG IJ = FG L IJ H K H L K-22=1 , 2which gives L = 2 L. Thus, the ratio is L / L = 2 = 1.41.2. (a) The ground-state energy is( 6.63 10

Lehigh - PHYSIC - 2

1. Our calculation is similar to that shown in Sample Problem 42-1. We set K = 5.30 MeV=U = (1/ 4 0 )( q qCu / rmin ) and solve for the closest separation, rmin:rmin-19 9 q qCu kq qCu ( 2e )( 29 ) (1.60 10 C )( 8.99 10 V m/C ) = = = 4 0 K 4 0 K

Lehigh - PHYSIC - 2

1. The x and the y components of a vector a lying on the xy plane are given byax = a cos , a y = a sin where a =| a | is the magnitude and is the angle between a and the positive x axis. (a) The x component of a is given by ax = 7.3 cos 250 = 2

A.T. Still University - SDF - asdf

Economics 100b Professor Wood1/31/08 Lecture 4ASUC Lecture Notes Online is the only authorized note-taking service at UC Berkeley. Please do not share, copy or illegally distribute these notes. Our non-profit, student-run program depends on your i

Lehigh - PHYSIC - 2

1. Conservation of momentum requires that the gamma ray particles move in opposite directions with momenta of the same magnitude. Since the magnitude p of the momentum of a gamma ray particle is related to its energy by p = E/c, the particles have th

Lehigh - PHYSIC - 2

1. Each atom has a mass of m = M/NA, where M is the molar mass and NA is the Avogadro constant. The molar mass of arsenic is 74.9 g/mol or 74.9 103 kg/mol. 7.50 1024 arsenic atoms have a total mass of (7.50 1024) (74.9 103 kg/mol)/(6.02 1023 mol

Lehigh - PHYSIC - 2

1. From the time dilation equation t = t0 (where t0 is the proper time interval, = 1 / 1 - 2 , and = v/c), we obtain = 1-FG t IJ . H t K2 0The proper time interval is measured by a clock at rest relative to the muon. Specifically, t0 = 2.2

Lehigh - PHYSIC - 2

1. (a) The flux through the top is +(0.30 T)r2 where r = 0.020 m. The flux through the bottom is +0.70 mWb as given in the problem statement. Since the net flux must be zero then the flux through the sides must be negative and exactly cancel the tota

Lehigh - PHYSIC - 2

1. The air inside pushes outward with a force given by piA, where pi is the pressure inside the room and A is the area of the window. Similarly, the air on the outside pushes inward with a force given by poA, where po is the pressure outside. The mag

Lehigh - PHYSIC - 2

1 1. The potential energy stored by the spring is given by U = 2 kx 2 , where k is the spring constant and x is the displacement of the end of the spring from its position when the spring is in equilibrium. Thusk=2 25 J 2U = 2 x 0.075 mb g b g

Lehigh - PHYSIC - 2

1. If R is the fission rate, then the power output is P = RQ, where Q is the energy released in each fission event. Hence, R = P/Q = (1.0 W)/(200 106 eV)(1.60 10 19 J/eV) = 3.1 1010 fissions/s.2. We note that the sum of superscripts (mass number

Lehigh - PHYSIC - 2

1. (a) An Ampere is a Coulomb per second, so84 A h = 84FG HCh sIJ FG 3600 s IJ = 3.0 10 K H hK5C.(b) The change in potential energy is U = qV = (3.0 105 C)(12 V) = 3.6 106 J.2. The magnitude is U = eV = 1.2 109 eV = 1.2 GeV.3. T

Lehigh - PHYSIC - 2

1. In air, light travels at roughly c = 3.0 108 m/s. Therefore, for t = 1.0 ns, we have a distance of d = ct = (3.0 108 m / s) (1.0 10-9 s) = 0.30 m.2. (a) From Fig. 33-2 we find the smaller wavelength in question to be about 515 nm, (b) and the

Lehigh - PHYSIC - 2

1. We are only concerned with horizontal forces in this problem (gravity plays no direct role). We take East as the +x direction and North as +y. This calculation is efficiently implemented on a vector-capable calculator, using magnitude-angle notati

Lehigh - PHYSIC - 2

1. (a) Let E = 1240 eVnm/min = 0.6 eV to get = 2.1 103 nm = 2.1 m. (b) It is in the infrared region.2. The energy of a photon is given by E = hf, where h is the Planck constant and f is the frequency. The wavelength is related to the frequency b

Lehigh - PHYSIC - 2

1. Comparing the light speeds in sapphire and diamond, we obtainv = vs - vd = cFG 1 - 1 IJ Hn n K F 1 - 1 IJ = 4.55 10 m s. = c2.998 10 m sh G H 177 2.42 K .s d 8 72. (a) The frequency of yellow sodium light is c 2.998 108 m s f = = = 5.09

Lehigh - PHYSIC - 2

1. Charge flows until the potential difference across the capacitor is the same as the potential difference across the battery. The charge on the capacitor is then q = CV, and this is the same as the total charge that has passed through the battery.

Lehigh - PHYSIC - 2

1. (a) For a given value of the principal quantum number n, the orbital quantum number ranges from 0 to n 1. For n = 3, there are three possible values: 0, 1, and 2. (b) For a given value of , the magnetic quantum number m ranges from - to + . For =

Lehigh - PHYSIC - 2

1. With speed v = 11200 m/s, we findK= 1 2 1 mv = (2.9 105 ) (11200) 2 = 18 1013 J. . 2 22. (a) The change in kinetic energy for the meteorite would be1 1 K = K f - K i = - K i = - mi vi2 = - 4 106 kg 15 103 m/s 2 2()()2= -5 1014 J

Lehigh - PHYSIC - 2

Instructor's Manual forFUNDAMENTALS OF PHYSICSSeventh Edition by David Halliday, Robert Resnick, and Jearl WalkerPrepared byJ. Richard ChristmanProfessor Emeritus United States Coast Guard Academywith the assistance of Stanley A. Williams I

Lehigh - PHYSIC - 2

1. (a) The motion from maximum displacement to zero is one-fourth of a cycle so 0.170 s is one-fourth of a period. The period is T = 4(0.170 s) = 0.680 s. (b) The frequency is the reciprocal of the period:f = 1 1 = = 1.47 Hz. T 0.680 s(c) A sinuso

Lehigh - PHY - 2

1. (a) The magnitude of the magnetic field due to the current in the wire, at a point a distance r from the wire, is given byB= 0i2r.With r = 20 ft = 6.10 m, we havec4 10 B=hb 2 b6.10 mg-7T m A 100 Ag = 3.3 10-6T = 3.3 T.(b

Lehigh - PHYSIC - 2

Chapter 1:MEASUREMENT1. The SI standard of time is based on: A. the daily rotation of the earth B. the frequency of light emitted by Kr86 C. the yearly revolution of the earth about the sun D. a precision pendulum clock E. none of these Ans: E 2.

Lehigh - PHYSIC - 2

1. The image is 10 cm behind the mirror and you are 30 cm in front of the mirror. You must focus your eyes for a distance of 10 cm + 30 cm = 40 cm.2. The bird is a distance d2 in front of the mirror; the plane of its image is that same distance d2

Lehigh - PHYSIC - 2

1. The magnitude of the force of one particle on the other is given by F = Gm1m2/r2, where m1 and m2 are the masses, r is their separation, and G is the universal gravitational constant. We solve for r:Gm1m2 = r= F( 6.67 10-11N m 2 / kg 2 ) (

Lehigh - PHYSIC - 2

1. (a) The charge that passes through any cross section is the product of the current and time. Since 4.0 min = (4.0 min)(60 s/min) = 240 s, q = it = (5.0 A)(240 s) = 1.2 103 C. (b) The number of electrons N is given by q = Ne, where e is the magnitu

Lehigh - IE - 111

Applied Statistics and Probability for EngineersThird EditionDouglas C. MontgomeryArizona State UniversityGeorge C. RungerArizona State UniversityJohn Wiley & Sons, Inc.ACQUISITIONS EDITOR Wayne Anderson ASSISTANT EDITOR Jenny Welter MARKE

Cornell - HADM - 2225

HADM225 Practice FinalName:_1. A stock has an expected rate of return of 8.3 percent and a standard deviation of 6.4 percent. Which one of the following best describes the probability that this stock will lose 11 percent or more in any one given y

Cal Poly Pomona - HIST - 101

Seung Yeo Per:2 Chapter 3 VocabsExercise 1 1. C 2. C 3. A 4. D 5. B 6. D 7. B 8. C 9. B 10. D Exercise 2 1. Delightful 2. Arousing pity 3. Plight 4. Blandishment 5. Careworn 6. Self-denying 7. Perfect happiness 8. Weakened 9. Slavish Follower 10. Ho

USC - MUHL - 232

Ch. 59 Music and Ballet in 19th Cent. Russia No. 161 Modest Mussorgsky, "with in four walls" from Sunless 1874 Genre: Russian song cycle - 1st song of song cycle - chords hover over D major triad; D is constant - m2-4 contrast in textures between clo

USC - MUHL - 232

Terms Ballets Russes Russian Ballet; established by Sergei Diaghilev in 1909; toured in Europe and Americas. "Beethoven's 10th" Brahms 3rd symphony illustrates his modern extension of Beethoven symphonic style. Ex of this are non tradition tonal pl

USC - GEOG - 100gm

HOLY LAND (Pg. 61, # 116) I cannot tell you what I care for, I can only tell you what I fear to lose. This quote embodies what Lakewood is all about, and how the people there lived their lives, and why they would even want to go there in the first pl

Cal Poly Pomona - ENG - 1B

Seung Yeo Per:2 English IB Mr.Costa CeremonyThe struggles engulfed in Ceremony had plenty to do with before, during, and after the war. It not only captured the people who were physically involved in the war but also, among others around them. Even

USC - MUHL - 232

Modest Mussorsgsky Russia. The mighty handful: folksong were more imp than anything that they learned in school. was totally Russian Peter Ilyich Tchaikovsky Born in Russia. Western influenced. Did not exemplify Russian nationalism. Bedrich Smetana C

USC - MUHL - 232

Ch.55 German Opera of the 19th Century: Weber & Wagner Singspiel play w/ singing; far more modest Carl Maria Von Weber 1786-1826 Friderich kind was librettist for Der Freischutz Romantic opera term used by Weber for certain of his operas and by W

Cal Poly Pomona - COM - 413

Man Kiu Chu COM 413 Mariusz Ozminkowski, Ph.D. 2:06 p.m. 3:40pm 10/10/07 "Though Letter"At each naturalization ceremony, every newly "naturalized" U.S. citizens have to declare if they are Democratic or Republican, etc. So it is very hard to be un