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TellingApplesFromOranges

Course: CSE 450, Spring 2008
School: Lehigh
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Web Enhanced Page Classification Xiaoguang Qi Background Utilizing features of neighbors Using fielded features Problem definition Classification A set of labeled data is used to train a classifier which can be applied to label future examples. Web page classification The process of assigning a web page to one or more predefined category labels. aka. web page categorization Why important? Web page...

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Web Enhanced Page Classification Xiaoguang Qi Background Utilizing features of neighbors Using fielded features Problem definition Classification A set of labeled data is used to train a classifier which can be applied to label future examples. Web page classification The process of assigning a web page to one or more predefined category labels. aka. web page categorization Why important? Web page classification is essential to Improving quality of retrieval Maintaining web directories Helping question answering systems Many more ... Why important? (Cont.) Tradition text classification approaches don't perform well on web pages An experiment on dmoz ODP dataset 12 topical categories 228,000 training documents, 12,000 for testing Na Bayes: 35% error rate ve Support vector machine: 27% error rate Text is not enough Text is not enough (Cont.) Textual features could be missing, misleading, or unrecognizable. Web page temporarily unavailable, robot exclusion, picture, flash, frame, etc ... There could be too much irrelevant text. Advertisement, navigational panel, spam follow-ups, etc ... Solution? Besides text, web pages have other features. Make use of them! On-page features On-page features (Cont.) Using on-page features HTML tags structural info embedded in HTML documents Golub and Ardo [2005] Assign significance indicators for different HTML tags Title, headings, metadata, and main text Kwon and Lee [2000, 2003] Divide all the HTML tags into three groups Assign each group an arbitrary weight Using on-page features (Cont.) Summarize then classify Classify web pages based on their summarization [Shen et al., 2004]. URL A web page can be reasonably classified just based on its URL! [Kan, 2004; Kan and Thi, 2005] Using on-page features (Cont.) Visual analysis Most approaches focus on text, ignoring visual info. Sometimes, it might be more expensive than using text. Analyze a web page's visual layout, represent the recognized parts in an adjacency graph, apply heuristic rules on the graph [Kovacevic et al., 2004]. Sibling ? Parent Target page Child Spouse Using features of neighbors Directly incorporate text from parent or child into the target page It does more harm than good [Chakrabarti et al., 1998; Ghani et al., 2001; Yang et al., 2002]. Parent and child pages == useless? No! We can make it useful! Using a subset of parent/child pages (not all of them) Using a portion of content of parent/child pages (not full content) Using features of neighbors (Cont.) Use a neighbor's feature only if its content is similar enough to the target page [Oh et al., 2000]. Use anchor text, the surrounding text of anchor text [Attardi et al., 1999; Furnkranz, 1999; 2001; Sun et al., 2002; Glover et al., 2002]. Sibling pages are more useful than parent/child pages [Chakrabarti et al., 1998; Slattery & Mitchell, 2000; Qi & Davison, 2006]. Using features of neighbors (Cont.) Labels [Chakrabarti et al., 1998; Slattery & Mitchell, 2000; Calado et al., 2003] Human-generated, accurate Only a small portion of the web is labeled Partial content [Glover et al., 2002; Cohen 2002] Full content Using artificial links Besides hyperlinks, we can create other types of links! Content similarity [Kurland and Lee, 2005; 2006] Pages co-occur in top results of a query Co-occur + clicked [Shen et al., 2006] ... Background Utilizing features of neighbors Using fielded features Outline of Neighboring algorithm Four types of neighbors are used. Parent, child, sibling, spouse. Information is linearly combined. Weights are adjusted through experiments. Both page content and human labeling are considered. Human labeling is used whenever available. A web page and its neighbors Sibling ? Parent Target page Child Spouse Topic distribution vectors Arts Business Sports (0.7, 0.2, 0.1) A probability distribution vector v p (v p,1 , v p, 2 ,, v p,i ,, v p,n ) Each component v p ,i is the normalized probability of the page p being in the category ci v4 v1 v5 Sibling v9 v1 0 v2 Parent v0 ? v1 4 v1 5 Child v3 v 6 v7 v8 Target page v1 1 Spouse v1 6 v1 2 v1 3 Neighboring pages Target page ...... Page level weighting Grouping Parent Child Sibling Spouse Group level weighting Topic vector of neighbors Weighting between target page and neighbors Final topic vector Bias on labeled pages A (1,0,0) A Sibling B A (1,0,0) A Parent ? Target page Child (0,0,1) A web directory C A Spouse ...... Bias on labeled pages (Cont.) Relative contributions of labeled pages and those unlabeled. Any classifier produces an approximation to the desired human labeling. Use human judgment whenever it is available. Decisions of classifiers are down-weighted. v p ' v p * w( p) if p is labeled 1 where w( p) if p is not labeled (0 1) Counting the multiple paths Sibling ? Parent Target page Child Spouse Tuning the page level bias 0.95 0.90 Weighted path Unweighted path Accuracy 0.85 0.75 0.80 0.70 0.65 0.60 0 0.5 1 1.5 2 2.5 3 3.5 4 Weighted path works better than unweighted path. if 1 Human labeling is important. p is labeled v p ' v p * w( p) where w( p) (0 1) if p is not labeled Neighboring pages Target page ...... Page level weighting Grouping Parent Child Sibling Spouse Group level weighting Topic vector of neighbors Weighting between target page and neighbors Final topic vector Bias among neighboring groups Parent Child Sibling Spouse * * 1 2 3 * 4 * vp" pParent pParent + vneighbors vneighbors 1 3 0 i 1, pSibling w( p) 1, i 1,2,3,4 w( p) vp" pSibling 2 vp" pChild pChild 4 w( p) vp" pSpouse pSpouse w( p) i 1 4 i Individual contribution of the four types of neighbors 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 Parent Child Sibling Spouse Accuracy Sibling pages contribute the most. Weight of sibling pages 0.92 0.90 Accuracy 0.88 0.86 0.84 0.82 0.80 0.3 0.4 0.5 (0.2, 0.2, 0.4, 0.2) Parent 0.6 Weight of sibling Child 0.7 0.8 Sibling 0.9 Spouse 1 Combining neighbors with target page A combined vector: a weighted average of the topic vector of the target page and that of the neighboring pages The category corresponding to the major component is chosen as the classification result v vtarget (1 ) vneighbors, where 0 1 Topic vector of the target page: Computed by a textual classifier Aggregated topic vector of the neighboring pages : combining the neighbors with the target page Experimental setup Dataset Open Directory Project (ODP) A web directory, September 2004, contains 0.6 million categories, 4.4 million web pages. We used 12 out of the 17 top-level categories. Training: 19,000 documents * 12 categories Tuning: 500 documents * 12 categories Test: 500 documents * 12 categories Three disjoint sets of documents randomly selected from ODP dataset Plus 6.5 million neighboring documents Experimental setup (Cont.) Textual classifiers A Na bayes classifier (Rainbow) ve A SVM classifier ( SVM Light ) Experimental result of labeled ODP dataset 0.95 0.90 0.85 Accuracy 0.80 0.75 0.70 0.65 0.60 Na ve bayes SVM K+C IO-bridge Neighboring Neighboring + NB + SVM Textual classifiers ~70% Prior approaches <80% Neighboring Alg. ~90% With and without human labeling 0.95 0.9 0.85 0.8 0.75 0.7 0.65 0.6 0.55 0.5 Na Bayes ve Neighboring (without labels) Neighboring (with labels) Neighboring alg. still has a fairly good performance w/o labeling. Prior approaches can't perform well. Accuracy Section summary Our Neighboring algorithm is able to improve the accuracy of common textual classifiers from 70% to more than 90%. can improve accuracy even when neighboring pages are unlabeled. While all neighbor types can contribute, sibling pages are the most important. Background Utilizing features of neighbors Using fielded features Motivation Most existing classification work uses web page as a whole. Should all the content on a web page be treated the same? In retrieval, BM25f [Robertson et al., 2004] is a successful fielded extension to BM25 [Robertson & Walker., 1994]. In classification, information from different parts of web pages should also have different importance. E.g., anchor text should be of extra value. F-Neighbor Algorithm A fielded extension to Neighboring Algorithm. Break up web pages (target page, as well as its neighbors) into text fields. Combine them linearly with different weights. Perform classification on the combined representation. Text fields Title of the target page; Full text of the target page; Titles of parent, child, sibling, and spouse pages (as four separate fields); Full text of parent, child, sibling, and spouse pages; Anchor text (referring to target) on parent page; Surrounding text of anchor text on parent pages (referred to as "extended anchor text"). Text representation Each field is represented by a TFIDF vector . d fi , i 1,, K The combined representation of a target document is the weighted combination of all the associated fields. d comb w fi d f i i 1 K where w fi 1 i 1 K The weights will be determined through experiments. Parameter tuning Exploring the full K-dimensional parameter space is expensive! Divide and conquer! Lower layer: tune weights within each neighbor type Upper layer: tune weights among neighbor types Lower-layer optimization results oEmphasizing titles 0.80 0.70 0.60 0.50 benefits all neighbor types. oSignificant Accuracy 0.40 0.30 0.20 0.10 0.00 improvement for parent, child, and spouse. oMarginal benefit target parent child sibling spouse 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 for target and siblings. Weight of title 0.95 0.90 0.85 Accuracy 0.80 0.75 0.70 0.65 0.60 SVM IO-bridge Neighboring SVM F-Neighbor Section summary We can further improve performance based on Neighboring algorithm. Fielded information is useful in web page classification.
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Lehigh - IE - 426
14
Arizona - PHYS - 241
Chapter 9 Solutions9.1m = 3.00 kg, v = (3.00i 4.00j) m/s (a) p = mv = (9.00i 12.0j) kg m/s Thus, px = 9.00 kg m/s and py = 12.0 kg m/s (b) p= p x + py =2 2(9.00)2 + (12.0)2 = 15.0 kg m/s = tan1 (py/px) = tan1 (1.33) = 307*9.2 (a) (b)
Lehigh - IE - 426
1 2 2 3
Lehigh - IE - 426
6 8 214 5 6 1 7 6 3 1 4 26 7 5 7 5 6 89
Arizona - PHYS - 241
Chapter 10 Solutions i 12.0 rad/s = = 4.00 rad/s2 t 3.00 s1 2 1 t = (4.00 rad/s2)(3.00 s) 2 = 18.0 rad 2 210.1(a) =(b) = it + (a) = (b) = *10.310.22 rad 1 day 1 h = 1.99 107 rad/s 365 days 24 h 3600 s 2 rad 1 day 1 h = 2.65 106
Lehigh - IE - 426
6 8 2 8 6 7 5 7 41 34 5 651 4 7 3 9 1 4 2 2 5 6 8 9 7 6
Lehigh - IE - 426
Scenario Mean Stdev Buy Optimal q c r 100 30 100 85 0.7 0.5 0.05YOUR CHOICE OPTIMAL Demand Sell Salvage Profit Sell Salvage 1 121 100 0 70 85 0 2 71 71 29 51.15 71 14 3 110 100 0 70 85 0 67 67 33 48.55 67 18 59 59 41 43.35 59 26 51 51 49 38.15 51 3
Arizona - PHYS - 241
Chapter 11 Solutions11.1( a ) Ktrans =1 1 mv2 = (10.0 kg)(10.0 m/s) 2 = 500 J 2 2(b) Krot =1 1 1 v2 1 I2 = mv 2 2 = (10.0 kg)(10.0 m/s) 2 = 250 J 2 2 2 r 4 (c) 11.2 K=Ktotal = Ktrans + Krot = 750 J 1 1 I 2 + mv2 2 2 1 4.00 m/s 2 1
Lehigh - IE - 426
Informal Homework SurveySeptember 14, 2006Please answer the following questions. This is an anonymous survey, but even if it wasn't, I wouldn't hold your answers against you.DifficultyOn a scale of 1-10, with a 10 being &quot;I hate you. Why are you
Lehigh - IE - 426
IE426 Course Survey-Quiz #0Name:email:BackgroundMathematicsMathematicians are like Frenchmen: whatever you say to them they translate into their own language and forthwith it is something entirely different.&quot; -Johann Wolfgang von Goethe Please
Arizona - PHYS - 241
Chapter 12 Solutions12.1To hold the bat in equilibrium, the player must exert both a force and a torque on the bat to make Fx = Fy = 0 and = 0F 0.600 mFy = 0 F 10.0 N = 0, or the player must exert a net upward force of F = 10.0 N To satisf
Lehigh - IE - 426
IE 426 Case Study Integer Programming1Wireless Capacity Expansion PlanningNote: This is a real consulting problem. The names have been changed to protect the innocent. Prof. Linderoth will be acting as the client. You have been contracted by a
Lehigh - IE - 426
IE 426 Case Study #3 Stochastic ProgrammingDue Date: December 16, 20061Networks for Private Line ServicesThe RoaDMaP Corporation is in the business of providing telecommunication services. We are going to build a planning model for the priva
Arizona - PHYS - 241
Chapter 12 Solutions12.51 Choosing torques about R, with = 0, L 2L (350 N) + (T sin 12.0) (200 N)L = 0 2 31Ry Rx T 12.0From which, T = 2.71 kN350 N200 NLet Rx = compression force along spine, and from Fx = 0, Rx = Tx = T cos 12.0 = 2.
Lehigh - IE - 426
Optimization ModelsDraft of August 26, 2005III. Beyond Linear OptimizationRobert FourerDepartment of Industrial Engineering and Management Sciences Northwestern University Evanston, Illinois 60208-3119, U.S.A. (847) 491-31514er@iems.northwest
Arizona - PHYS - 241
Chapter 13 Solutionsx = (4.00 m) cos (3.00t + ) Compare this with x = A cos (t + ) to find ( a ) = 2f = 3.00 or f = 1.50 Hz (b) A = 4.00 m (c) T= 1 = 0.667 s f13.1 = rad(d) x(t = 0.250 s) = (4.00 m) cos (1.75) = 2.83 m 13.2 ( a ) Since the c
Lehigh - IE - 426
e P D 9 D 6 1ucbU g 2Vq2V2Q2tbQ1qYCVo152CA tsTquhdT21&amp;Vy2V12' Xd CsqD v IU D 8 8 IU v I 8 0 R IU 8 w D 8 ( 8 D I % (U 0 rU 0 P 6 % % 6 8 0 R (U ( I %U R ( 8 g e D %F 8 r I 8D 8F 8 8 R 9 GU R3 ' 8 0 g e 1)b1V2)2CX Xd VCnqQcbcd21foW
Waterloo - CHE - 101
3.2 ENERGY BALANCES ON NON-REACTIVE SYSTEMSWe will now investigate methods to estimate specific internal energy and enthalpy changes when tables of those properties are not available. We will focus on on-reactive systems including situations where t
Lehigh - IE - 426
Optimization ModelsDraft of August 26, 2005I. Formulating an Optimization Model: An Introductory ExampleRobert FourerDepartment of Industrial Engineering and Management Sciences Northwestern University Evanston, Illinois 60208-3119, U.S.A. (84
Arizona - PHYS - 241
Chapter 14 Solutions*14.1 For two 70.0-kg persons, modeled as spheres, Fg = 14.2 (a) Gm1m2 (6.67 1011 N m2/kg2)(70.0 kg)(70.0 kg) = = ~ 10 7 N r2 (2.00 m)2At the midpoint between the two masses, the forces exerted by the 200-kg and 500-kg Gm1m2
Lehigh - IE - 426
Optimization ModelsDraft of August 26, 2005II. Elementary Linear Optimization ModelsRobert FourerDepartment of Industrial Engineering and Management Sciences Northwestern University Evanston, Illinois 60208-3119, U.S.A. (847) 491-31514er@iems
Lehigh - IE - 426
461. Introduction and Examples While weather effects do no~ vary greatly over 25-year periods, fire damage can be quite variable. Assume that in each 25-year block, the probability is 1/3 that 15% of all timber stands are destroyed and that the pro
Arizona - PHYS - 241
Chapter 15 Solutions15.14 M = ironV = (7860 kg/m3) (0.0150 m)3 3 M = 0.111 kg15.2The density of the nucleus is of the same order of magnitude as that of one proton, according to the assumption of close packing:=m 1.67 1027 kg ~ 4 ~ 10
Lehigh - IE - 426
1Introduction and Ex~mples.,.fJ.&quot;,':;1-&quot;q.; 'i &quot;I1J )1.1 &gt;Iinil, l'.'&lt;'!.This chapter presents stochastic progt8.InrQing examples from aareas with wide applicationin stochastic progrsunmi&quot;g.These examPk!S~.~ intended
Waterloo - CHE - 101
CHE 101: Chemical Engineering Concepts 2Processes Involving Phase Change + Energy BalancesCLASS NOTES1. IntroductionQuestion 1: What are chemical engineers? What do they do? How are they different from chemists?Answers:Question 2: Answers:
Lehigh - CSE - 342
CSE342: Fundamentals of InternetworkingInstructor: Prof. Brian D. DavisonHH Hdavison@cse.lehigh.edu http:/www.cse.lehigh.e du/~brian/Students: Little or no networking background Can program in C/C+Have taken CSE109/411 Juniors/Seniors/
Arizona - PHYS - 241
Chapter 16 Solutions16.1 Replace x by x vt = x 4.5t to get y = 16.2y (cm) y (cm) y (cm) 66 [(x 4.5t)2 + 3]444t=2s2 t=1s2 t = 1.5 s2x0 y (cm) 2 6 10 14 0 y (cm) 2 6 10 14x0 2 6 10 14x44 t = 2.5 s 2 t=3s2x0 2 6 10
Arizona - PHYS - 241
Chapter 17 SolutionsSince vlight &gt; vsound, d (343 m/s)(16.2 s) = 5.56 km17.1Goal Solution G: There is a common rule of thumb that lightning is about a mile away for every 5 seconds of delay between the flash and thunder (or ~3 s/km). Therefore,
Lehigh - CSE - 342
Chapter 8 Network SecurityA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide con
Lehigh - CSE - 342
Chapter 4 Network LayerA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide conten
Lehigh - CSE - 342
Chapter 3 Transport LayerA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide cont
Arizona - PHYS - 241
Chapter 18 Solutions18.1 The resultant wave function has the form y = 2A0 cos (a) sin kx t + 2 2( /4) = 2(5.00) cos = 9.24 m 2 2 A = 2A0 cos f=(b) *18.21200 = = 600 Hz 2 2We write the second wave function as y2 = A sin(kx t
Waterloo - CHE - 101
2.2.4 Multi-Component Phase EquilibriumApplictions and processes: &gt; Distillation &gt;Any other separation technique &gt;Absorbers/strippersPreviously we have focused on system with only one pure component or only one condensable component. Now we will
Lehigh - CSE - 342
Chapter 6 Wireless and Mobile NetworksA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) an
Arizona - PHYS - 241
Chapter 19 Solutions*19.1 (a) To convert from Fahrenheit to Celsius, we use TC = 5 5 (T 32.0) = (98.6 32.0) = 37.0C 9 F 9and the Kelvin temperature is found as T = TC + 273 = 310 K (b) In a fashion identical to that used in (a), we find TC = 20.
Lehigh - CSE - 342
Chapter 8 Network SecurityA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide con
Lehigh - CSE - 342
Chapter 7 Multimedia NetworkingA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slid
Arizona - PHYS - 241
Chapter 20 Solutions20.1 Taking m = 1.00 kg, we have Ug = mgh = (1.00 kg)(9.80 m/s2)(50.0 m) = 490 J But Ug = Q = mcT = (1.00 kg)(4186 J/kg C)T = 490 J Tf = Ti + T = (10.0 + 0.117)C so T = 0.117 CGoal Solution G: Water has a high specific heat, s
Lehigh - CSE - 342
Chapter 3 Transport LayerA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide cont
Waterloo - CHE - 101
2.3.6 NON IDEAL LIQUID-LIQUID OR LIQUID-GAS SYSTEMS Thought question: Is it better to store opened pop inside a fridge or on the counter? RAOULTS AND HENRY'S LAWS Concepts and Definition Raoult's Law:PAy A PTx A p * (T ) APa = partial pressur
Lehigh - CSE - 342
Chapter 5 Link Layer and LANsA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide
Arizona - PHYS - 241
Chapter 21 Solutions*21.1 One mole of helium contains Avogadro's number of molecules and has a mass of 4.00 g. Let us call m the mass of one atom, and we have NAm = 4.00 g/mol or m= 4.00 g/mol = 6.64 1024 g/molecule 6.02 1023 molecules/molm = 6.
Lehigh - CSE - 342
Chapter 4 Network LayerA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide conten
Arizona - PHYS - 241
Chapter 22 SolutionsW 25.0 J = = 0.0694 Qh 360 J22.1(a) (b)e=or6.94%Qc = Qh W = 360 J 25.0 J = 335 J e= W W 1 = = = 0.333 Q h 3W 3 or 33.3%22.2(a) (b)Qc = Qh W = 3W W = 2W Therefore, Q c 2W 2 = = Q h 3W 3 Qh Qc Qc W = =1 = 0.2
Lehigh - CSE - 342
Chapter 6 Wireless and Mobile NetworksA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) an
Lehigh - CSE - 342
Chapter 2 Application LayerA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide co
Arizona - PHYS - 241
Chapter 23 Solutions 10.0 grams electrons 24 23 atoms 47.0 = 2.62 10 N= 6.02 10 atom mol 107.87 grams mol # electrons added = Q 1.00 10 -3 C = = 6.25 1015 e 1.60 10 -19 C electron23.1(a)(b)or2.38 electrons for every 10 9 al
University of Texas - LEB - 323
Chapter 7 Entry Level Quiz Multiple Choice 1. Which of the following is a business or organizational customer? A. B. C. D. E. producers of goods or services. a retailer. a wholesaler. a government agency. All of the above are business and organizatio
Lehigh - CSE - 342
Chapter 1 IntroductionA note on the use of these ppt slides:We're making these slides freely available to all (faculty, students, readers). They're in PowerPoint form so you can add, modify, and delete slides (including this one) and slide content
Arizona - PHYS - 241
Chapter 24 Solutions24.1 (a) (b) (c) E = EA cos = (3.50 103)(0.350 0.700) cos 0 = 858 N m2/C = 90.0E = 0E = (3.50 103)(0.350 0.700) cos 40.0 = 657 N m2/C24.2E = EA cos = (2.00 104 N/C)(18.0 m2)cos 10.0 = 355 kN m2/C24.3E = EA
Lehigh - PHYS - 352
Midterm Phys 352 Name:1. (10pts) You have two lasers that can be changed in power: (1) Argon Laser (490nm) and a (2) Krypton laser (650nm). a. Determine the color code of a combination of 400mW from the Argon Laser and the 200mW from the Krypton la
Lehigh - PHYS - 352
Homework 3 with Solutions1. An Ar laser emits 1 watts of continuous light (wavelength = 5.145 10-7 m) in a parallel beam of 2 mm diameter in vacuum. (Use tables in next pages, and write all units properly.) (A) What is the wavelength (in , nm, m,
Arizona - PHYS - 241
Chapter 25 Solutions25.1V = 14.0 V and Q = N A e = (6.02 1023)(1.60 1019 C) = 9.63 104 C V = W 4 Q , so W = Q(V) = ( 9.63 10 C)(14.0 J/C) = 1.35 J25.2K = q V q = 6.41 10-19 C7.37 10-17 = q(115)25.3W = K = q V1 2mv 2 = e(120 V
Lehigh - PHYS - 352
1. (A) Find the thicknesses of a particular birefringent crystal (n1 = 1.4737 and n2 = 1.4714) needed to produce /4, /2, and retardation plates, respectively, for the Argon laser line ( = 488 nm).Retardation = d(n1 n2) d = (n1 n2)where (n
Arizona - PHYS - 241
Chapter 26 Solutions*26.1(a) (b)Q = C (V) = (4.00 106 F)(12.0 V) = 4.80 105 C = 48.0 C Q = C (V) = (4.00 106 F)(1.50 V) = 6.00 106 C = 6.00 C26.2(a)C=10.0 10 - 6 C Q = = 1.00 10 - 6 F = 1.00 F V 10.0 V Q 100 10 - 6 C = = 100 V C
Lehigh - PHYS - 352
Winter 1996HOMEWORK 4 with Solutions1. Find the image of the object for the single concave mirror system shown in Fig.1 (see next pages for worksheets) by: (a) measuring the radius R and calculating the focal length for the concave mirror, (b) dra
Lehigh - PHYS - 352
HOMEWORK 2 with Solutions 1(a) A light beam is incident perpendicular on face A of an unsymmetric 30 prism of refractive index n = 1.5 as indicated. Determine with the appropriate laws and describe with a sketch how the beam propagates, considering b
University of Adelaide - HUM - 101
There has always been controversy about whether boys were smarter than girls. What do you think? Are there gender differences in IQ? If so, what are they? How can we prove it?Even after reading the chapter I think that boys shouldn't be underestima
Arizona - PHYS - 241
Chapter 27 SolutionsQ t27.1I=Q = I t = (30.0 106 A)(40.0 s) = 1.20 103 CN=Q 1.20 103 C = = 7.50 1015 electrons e 1.60 1019 C/electron*27.2The atomic weight of silver = 107.9, and the volume V is V = (area)(thickness) = (700 10-4
Lehigh - PHYS - 352
Homework 8 with Solutions (1) Using Stokes Vectors and Mller Matrices calculate the output polarization for an input polarzation of 45o after the following for elements in series i. Polarizer at 600 ii. Polarizer at 45o iii. /2 plate oriented with sl
Lehigh - PHYS - 352
HOMEWORK V with Solutions1. (A) From the given location of C1 and C2 and the values of R1, R2, n, and d of the thick lens shown in Fig.1, determine its focal length, the location of its focal points, and principal planes. (Use the concepts and relat