13 Lecture Electromagnetic Waves Ch. 33
Cartoon Opening Demo Topics Electromagnetic waves Traveling E/M wave - Induced electric and induced magnetic amplitudes Plane waves and spherical waves Energy transport Poynting vector Pressure produced by E/M wave Polarization Reflection, refraction,Snell's Law, Internal reflection Prisms and chromatic dispersion Polarization by reflection-Brewsters angle
Electromagnetic Waves
Eye Sensitivity to Color
Production of Electromagnetic waves
To investigate further the properties of electromagnetic waves we consider the simplest situation of a plane wave. A single wire with variable current generates propagating electric and magnetic fields with cylindrical symmetry around the wire. If we now stack several wires parallel to each other, and make this stack wide enough (and the wires very close together), we will have a (plane) wave propagating in the z direction, with E-field oriented along x, E = Ex (the current direction) and B-field along y B=By (Transverse waves)
Electromagnetic Wave
Wave Equation
How the fields vary at a Point P in space as the wave goes by
Spherical waves
Plane waves
Spherical Waves
A point source of light generates a spherical wave. Light is emitted isotropically and the intensity of it falls off as 1/r2
Let P be the power of the source in joules per sec. Then the intensity of light at a distance r is
I= P 4!r 2
What do we mean by Intensity of light?
17. The maximum electric field at a distance of 10 m from an isotropic point light source is 2.0 V/m. Calculate (a) the maximum value of the magnetic field and (b) the average intensity of the light there? (c) What is the power of the source? (a) The magnetic field amplitude of the wave is
2 .0 V Em m Bm = = c 2.998 " 10 8
(b) The average intensity is
m s
= 6.7 " 10 !9T
I avg =
E m = 2 0 c 2 4! " 10 #7 T $ V 2.998 " 10 8 m
2
(
( 2.0 V ) m
2
)(
m s
)
W = 5.3 " 10 #3 m2
(c) The power of the source is
P = 4#r 2Iavg = 4# ( m ) 5.3 ! 10 "3 10
2
(
W m2
)= 6.7W
Another property of light
Radiation pressure: Light carries momentum
I Pr = c 2I Pr = c
This is the force per unit area felt by an object that absorbs light. (Black piece of paper)) This is the force per unit area felt by an object that reflects light backwards. (Aluminum foil)
Polarization light
Pass of though a polarizing sheet aligned to pass only the y-component
Resolved into its y and z-components The sum of the y-components and z components are equal
Intensity I0
Pass though a polarizing sheet aligned to pass only the y-component Malus's Law
I0 I= 2
One Half Rule Half the intensity out
I0
I ! Ey 2 Ey = E cos"
I 2 = I1 cos 2 !
y
I1 =
I0 2
35. In the figure, initially unpolarized light is sent through three polarizing sheets whose polarizing directions make angles of !1 = 40o, !2 = 20o, and !3 = 40o with the direction of the y axis. What percentage of the light's initial intensity is transmitted by the system? (Hint: Be careful with the angles.) Let Io be the intensity of the unpolarized light that is incident on the first polarizing sheet. The transmitted intensity of is I1 = (1/2)I0, and the direction of polarization of the transmitted light is !1 = 40o counterclockwise from the y axis in the diagram. The polarizing direction of the second sheet is !2 = 20o clockwise from the y axis, so the angle between the direction of polarization that is incident on that sheet and the the polarizing direction of the sheet is 40o + 20o = 60o. The transmitted intensity is
I0 I1 I2 I3
I 2 = I1 cos 2 60o =
1 I 0 cos 2 60o , 2
and the direction of polarization of the transmitted light is 20o clockwise from the y axis.
35. In the figure, initially unpolarized light is ...