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Maple_hw3

Course: MATH 243, Fall 2008
School: Delaware
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Homework Maple 3 Due Date: Tuesday, May 6th Spring 2008 Partial derivatives Compute the second partial derivatives of f (x, y) = x3 + x2 y 3 2y 2 dfdx:=di(f,x); dfdy:=di(f,y); dfdx2:=di(f,x,x); dfdy2:=di(f,y,y); dfdxy:=di(f,x,y); dfdyx:=di(f,y,x); Compute fxxyz if f (x, y, z) = sin(3x + yz) Check that each of the following functions is a solution of the wave function 2 2u = c2 u t2 x2 (a) u = sin(kx)...

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Homework Maple 3 Due Date: Tuesday, May 6th Spring 2008 Partial derivatives Compute the second partial derivatives of f (x, y) = x3 + x2 y 3 2y 2 dfdx:=di(f,x); dfdy:=di(f,y); dfdx2:=di(f,x,x); dfdy2:=di(f,y,y); dfdxy:=di(f,x,y); dfdyx:=di(f,y,x); Compute fxxyz if f (x, y, z) = sin(3x + yz) Check that each of the following functions is a solution of the wave function 2 2u = c2 u t2 x2 (a) u = sin(kx) sin(ckt) (b) u = t/(c2 t2 x2 ) (c) u = (x ct)6 + (x + ct)6 (d) u = sin(x ct) + ln(x + ct) Method of Lagrange multipliers Find the extreme values of f (x, y) = x2 +2y 2 on the circle g(x, y) = x2 +y 2 = 1 In other words, solve the system f = g, g = 1 for (x, y, ). sol:=solve({di(f,x)=L*di(g,x), di(f,y)=L*di(g,y), {x,y,L}); g=1}, subs(sol[1],f); subs(sol[2],f); subs(sol[3], f); subs(sol[4],f); A rectangular box without a lid is to be made from 12 cm2 of cardboard. Find the maximum volume of such a box. In other words, nd the maximum of f (x, y, z) = xyz (volume) subject to g(x, y, z) = 2xz +2yz +xy = 12 (surface) Find the extreme values of f (x, y, z) = 2x + 6y + 10z subject to g(x, y, z) = x2 + y 2 + z 2 = 35 1 2 Double i...

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Delaware - MATH - 243
Project For Math 243, Spring 2008Due on Monday, May 19th, 20081. Consider a mountain in the shape of the surface z = 4000 y2 x2 10 10with the z axis pointing up and the x, y plane is horizontal. A car is traveling down this mountain and the pro
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 243
Delaware - MATH - 351
Exercises 3.2 6.e. y ' = 1 + ( y / x) 2 + ( y / x) Solution: Let w = y/xFrom 5.b. we have w ' = dw 1 + w2 dx x 1 + w2 + w - w 1 + w2 = x x=ln(w + 1 + w 2 ) = ln( x) + C w + 1 + w 2 = Ax 1 + w 2 = Ax - w 1 + w 2 = ( Ax - w) 2 2 Axw = ( Ax) 2 - 1
Delaware - MATH - 241
A Tutorial for Students Using MapleTALouis F. Rossi 14 February 2006 (Revised August 26, 2007)1For the computationally incompetent or uninterested.If you are comfortable using a web browser to buy something online, or identify that large spide
Delaware - MATH - 353
Engineering Mathematics III Math 353 lecture 010 EWG 203 - Monday & Wednesday 0905-0955 EWG 207 - Friday 0905-0955 c 2007 L. F. Rossi All rights reserved. Prof. L. F. Rossi Office: Ewing 524 Telephone: x1880 Email: rossi@math.udel.edu WWW: www.math.u
Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Final Exam 16 December 2002But when the world became bright with reason and riches, it began to sense the narrowness of the needle's eye, and that rankled for a world no longer willing to believe or y
Delaware - MATH - 241
Analytic Geometry & Calculus A (Math 241 sections 013, 014 & 015) KRB 005 - Monday, Wednesday, & Friday 0905-0955 SMI 219 - Tuesday & Thursday 0800-0850 (discussion section 013 only) SHL 123 - Tuesday & Thursday 1100-1150 (discussion section 014 only
Delaware - MATH - 241
Name: Solution guideMath 241: Calculus & Analytic Geometry A Exam 2 October 26 2005We all make mistakes. Overcoming them is survival as well. "Mountain" Mel Deweese in The Worst-Case Scenario Survival Handbook. Instructions: Show all work to rec
Delaware - MATH - 241
Name: Solution guideMath 241: Calculus & Analytic Geometry A Exam 1 30 September 2005Welcome to my house. Come freely. Go safely; and leave something of the happiness you bring! Count Dracula from Dracula by Bram Stoker. Instructions: Show all wo
Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 2 October 26 2005We all make mistakes. Overcoming them is survival as well. Mountain Mel Deweese in The Worst-Case Scenario Survival Handbook. Instructions: Show all work to receive full or part
Delaware - MATH - 241
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Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 1 30 September 2005Welcome to my house. Come freely. Go safely; and leave something of the happiness you bring! Count Dracula from Dracula by Bram Stoker. Instructions: Show all work to receive f
Delaware - MATH - 241
Name and section:Math 241: Calculus & Analytic Geometry A Exam 3 November 21 2005No great discovery was ever made without a bold guess. Sir Isaac Newton Instructions: Show all work to receive full or partial credit. All University rules and guide
Delaware - MATH - 241
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Delaware - MATH - 241
Name and section:Math 241: Calculus & Analytic Geometry A Exam 3 solution guide November 21 2005No great discovery was ever made without a bold guess. Sir Isaac Newton Instructions: Show all work to receive full or partial credit. All University
Delaware - MATH - 241
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Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 1 4 October 2002Always the beautiful answer who asks a more beautiful question. E. E. Cummings Instructions: Show all work to receive full or partial credit. All University rules and guidelines f
Delaware - MATH - 241
Sheet1Proctored practice exam rotation schedule Math 241 Section 011Name Barkey, Courtney Eliza Becraft, Ryan Michael Blake, Casey Amber Colby, Christopher Mic Collins, Jeffrey Kyle Davis, Joseph C. Diggins, Allison Clair Dobson, Patr
Delaware - MATH - 241
Sheet1Proctored practice exam rotation schedule Math 241 Section 010Name Ames, Samantha Jean Artes, John Joseph Boettger, John Thomas, Bryan, Carole Alicia Burnosky, Norman Gilbe Chlan, Brian Crawford, Bruce Dougla Dramstad, Er
Delaware - MATH - 241
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Delaware - MATH - 351
Name:Math 351: Engineering Mathematics I Exam 1 solution guide 4 March 2005Mathematics may claim to be the most original creation of the human spirit. Alfred Whitehead Instructions: Show all work to receive full or partial credit. You may use onl
Delaware - MATH - 241
Name: Solution GuideMath 241: Calculus & Analytic Geometry A Exam 1 4 October 2002Always the beautiful answer who asks a more beautiful question. E. E. Cummings Instructions: Show all work to receive full or partial credit. All University rules a
Delaware - MATH - 241
Calculus supplement: Periodic drug delivery In problem 10 in section 2.2 of Stewart, we consider a patient receiving an injection of a drug at regular intervals. Let's simplify the problem to receiving a unit dose at intervals of 1 time unit. One mod
Delaware - MATH - 241
Exam 1 performance Math 241 spring 2006 10 8 Frequency 6 4 2 0 20 N: 46 Mean: 74 Median: 77 Std. err: 15.44060 Score80100
Delaware - MATH - 241
Analytic Geometry & Calculus A Math 241 lecture 010 discussion sections 020D, 021D & 022D KRB 004 - Monday, Wednesday, & Friday 0800-0850 EWG 203 - Tuesday & Thursday 0800-0850 (020D only) EWG 203 - Tuesday & Thursday 1400-1450 (021D only) EWG 203 -
Delaware - MATH - 241
Analytic Geometry & Calculus A (Math 241 sections 013, 014 & 015) Spring 2006 (Revised 7 May 2006) KRB 005 - Monday, Wednesday, & Friday 0905-0955 SMI 219 - Tuesday & Thursday 0800-0850 (discussion section 013 only) SHL 123 - Tuesday & Thursday 1100-
Delaware - MATH - 241
Exam 2 performance Math 241 Spring 2006 8 N: 42 Mean: 68.6 Median: 70.5 Std. err: 16.46 Frequency420 02040 60 Score80100
Delaware - MATH - 241
Exam 3 performance - Math 241 Spring 2006 8 N: 41 Mean: 62.3 Median: 63 Std. err: 14.96 Frequency420 02040 Score6080100
Delaware - MATH - 241
Name and section:Math 241: Calculus & Analytic Geometry A Exam 3 solution guide November 21 2005No great discovery was ever made without a bold guess. Sir Isaac Newton Instructions: Show all work to receive full or partial credit. All University
Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 1 solution guide 24 September 2007Humanitys deepest desire for knowledge is justication enough for our continuing quest. Stephen W. Hawking. Instructions: Show all work to receive full or partia
Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 1 solution guide 9 March 2007I don't believe I have to be loyal to one side or the other. I'm simply asking questions. Juror #11, 12 Angry Men Instructions: Show all work to receive full or part
Delaware - MATH - 241
Name: Section:Math 241: Calculus & Analytic Geometry AExam 2 solution guide 19 October 2007 You can have any color you want as long as it is black. Henry Ford. Instructions: Show all work to receive full or partial credit. All University rules a
Delaware - MATH - 241
Name: Section:Math 241: Calculus & Analytic Geometry AExam 2 solution guide 11 April 2007 And by-and-by Christopher Robin came to an end of the things, and was silent, and he sat there looking out over the world, and wishing it wouldnt stop. The
Delaware - MATH - 351
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Delaware - MATH - 351
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Delaware - MATH - 351
Exercises 4.2 8d. Solution:4 = cos 30 | u | 4 = cos 60 | v | | u |= 4 cos 30| v |= 8u v =| u | | v | cos 30 =4 8 cos 30 = 32 cos 30Exercises 4.6 2d. Solution: Let u 1 = (0,0,0,1), u 2 = (0,0,1,1), u 3 = (0,1,1,1), u 4 = (1,1,1,1)
Delaware - MATH - 351
Exercises 6.7 4h. Solution: y " 2 y ' + y = 6 x 2r 2 2r + 1 = 0 ( r 1) 2 = 0 r =1 y h = Ae x + Bxe x Take y1 = e x , y 2 = xe x' W(x) = y1 y '2 - y1 y 2 = e 2 xW1 ( x ) = f ( x) y 2 ( x) = 6 x 2 xe x = 6 x 3 e x W2 ( x ) = f ( x ) y 1 ( x )
Delaware - MATH - 351
Exercises 9.3 5b. Solution: 1 2 x1 6 2 0 x = 8 2 det( A - I ) = 2 - - 4 = 0 1 17 2 1 = 2.56,= 2 = -1.56 1.28 eigenvector e1 = 1 - 0.78 eigenvector e 2 = 1 1 = 2.56 2 = -1.56 6 1.28 8 1 c e1 = 1
Delaware - MATH - 351
Exercises 4.7. 6a. Solution: The statement is not true. Just need to give a counter-example to disprove the statement. e.g. Suppose u1=(1,0), u2=(2,0), v=(1,1) then -2 u1+ u2+0v=0, so {v, u1, u2} is LD. Butv span{u1 , u 2 } . So the statement is no
Delaware - MATH - 351
Exercises 2.4. 17.(b) Solution: mv ' = mg - f (v),mv ' = mg - cv 2 c v' = g - v2 m v(0) = 0, f(v) = cv 2(1)First, find a particular solution V(t) of (1). Suppose V(t) = constant, then 0 = g - V= mg c 1 u mg 1 + c u c 2 V mAccording to Exercise
Delaware - MATH - 351
Exercises 5.2. 22. Solution: P ( 2) = [P (1) ]20. 0 0 0 1 0. 0 0 0 1 1 / 2 0 1 / 2 0 1 / 2 0 1 / 2 0 0 0 = 0 1/ 2 0 1/ 2 0 0 1/ 2 0 1/ 2 0 0 1 / 2 0 1 / 2 0 0 1 / 2 0 1 / 2 0 0 0 0 0 1 0 0 0 0 1 0. 0 0 0 1 1 / 2 1 / 4
Delaware - MATH - 351
Exercises 5.2. 20. Solution: Let B = c d 1 2 a b a b 1 2 3 4 c d = c d 3 4 a + 2c b + 2d a + 3b 2a + 4b 3a + 4c 3b + 4d = c + 3d 2c + 4d a + 2c = a + 3b - 3b + 2c = 0 2a + 3b - 2d = 0 b + 2d = 2a + 4b
Delaware - MATH - 351
Exercises 6.7 2e. Solution: y ' + y = 5 e x(1) y ' + y = 0 r +1 = 0 r = -1 y h = Ae x (2) f 1 = 5, let y p1 = B B' + B = 5 B=5 y p1 = 5 (3) f 2 = -e - x , Because of the duplication , let y p2 = Cxe - x Ce - x - xCe - x + Cxe - x = -e - x C = -1
Delaware - MATH - 351
Exercises 9.3 3e. Solution: 4 2 2 A = 2 4 2 2 2 4 4 det( A I ) = det 2 2 2 4 2 2 2 = ( 2) 2 ( 8) 4 = 2, 2, 8 2 2 2 a 0 = 2, 2 2 2 b = 0 2 2 2 c 0 a+b+c=0 1 1 Let e1 = 0 , e 2 = 2 1 1 t
Delaware - MATH - 351
Exercises 4.5 13b. Solution: 2 x y = x x + 2 y = y (1) (2)Method 1.(2 ) x y = 0 x + ( 2 ) y = 0 1 2 -1 0 -1 2- 0 0 1 =0 To get non-trivial solutions, we have 2 - 2 0 1 0 -1 -1 2 2- (2 - ) 2 = 1 = 1, = 3 -1
Delaware - MATH - 351
Exercises 2.2 1.f. xy ' + 3 y = 0 Solution: Method 1. y ' + y = 03 y ( x) = A exp( p ( x)dx) = A exp( dx) x = A exp(3 ln | x |) = A exp(ln | x | 3 ) = Ax 3 3 xMethod 2. Using separation of variables.y' + 3 y=0 xdy 3 + dx = 0 y x dy 3 y + x
Delaware - MATH - 241
Name and section:Math 241: Calculus & Analytic Geometry A Exam 3 solution guide May 5 2006Towering genius disdains a beaten path. It seeks regions hitherto unexplored. Abraham Lincoln Instructions: Show all work to receive full or partial credit.
Delaware - MATH - 241
Name:Math 241: Calculus & Analytic Geometry A Exam 1 solution guide 10 March 2006Our tragedy today is a general and universal physical fear so long sustained by now that we can even bear it. Because of this, the young man or woman writing today h
Delaware - MATH - 241
Name and section:Math 241: Calculus & Analytic Geometry A Final Exam 12 December 2005But when the world became bright with reason and riches, it began to sense the narrowness of the needle's eye, and that rankled for a world no longer willing to
Delaware - MATH - 241
Name: Section:Math 241: Calculus & Analytic Geometry AExam 2 11 April 2007 And by-and-by Christopher Robin came to an end of the things, and was silent, and he sat there looking out over the world, and wishing it wouldn't stop. The House at Pooh
Delaware - M - 353
University of Delaware Department of Mathematical Sciences Math 353 Engineering Mathematics III 07S C. Bacuta Homework 1: 1.2 # 2a, 3b, 4a, 6a. 1.3 # 1a, 5abc, 12, Use (MATLAB) and both formulas (1) and (2) on page 39 to solve 13d. Comment the result
Delaware - M - 353
Beginning Matlab ExercisesR. J. Braun Department of Mathematical Sciences University of Delaware1IntroductionThis collection of exercises is intended to help you start learning Matlab. Matlab is a huge package with many capabilities, but it is
Delaware - M - 349
Project MATH 349, Fall 2005 Instructor: C Bacuta The goal of this project is to learn how to apply the Least Squares Method (Section 4.6) to smoothing data (data fitting) with the help of MATLAB. Start by a quick tour of the MATLAB tutorial and MATLA
Delaware - MATH - 456
Homework 7 (or PA3): MATH/CSE 456, Spring 2004 Instructor: C Bacuta The goal of this assignment is to learn how to write or to use matlab routines for smoothing data or fit polynomial to data. I) Implementation. Implement the polynomial regression al