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Course: ECE 3140, Spring 2008
School: Cornell
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addu =? Iout Datapath: memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: addiu =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din...

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addu =? Iout Datapath: memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: addiu =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: lw =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: sw =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: beq =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Datapath: j =? Iout memory 32 32 register file CLK Iaddr 32 00 CLK PC new PC calculation 16 imm s-ext 0 30 30 32 0 1 daddr ALUsrc din ALUctrl dmc 32 alu 0 1 dout data memory 2 1 5 5 5 control tgt pc 30 26 4 0 1 30 newpc 30 30 0 1 30 carry = 1 extend + Performance IF instruction fetch Iout memory 32 RF regfile 32 register file CLK 32 =? ALU WB write- back 0 daddr 1 dout 32 alu 0 1 Iaddr 32 00 2 1 5 5 5 extend ALUsrc din ALUctrl MEM CLK PC new PC calculation data memory control dmc How fast can we run the clock? Multi-Cycle Datapath IF instruction fetch Iout memory 32 RF regfile 32 register file CLK 32 =? ALU WB write- back 0 daddr 1 dout 32 alu 0 1 Iaddr 32 00 2 1 5 5 5 extend ALUsrc din ALUctrl MEM CLK PC new PC calculation data memory control dmc Observation: we can run the clock faster by partitioning the execution into multiple stages. Multi-Cycle Datapath EX CLK register file MEM WB WB CLK PC alu 0 1 0 1 IF RF/RD = Stages: instruction fetch, register execute, fetch/decode, memory, writeback. Idea: break down single instruction execution into smaller parts, some instructions skip parts of execution. Multi-Cycle Datapath IF RD EX MEM WB lw $1,-4($3) add $1,$2,$3 beq $1,$2,L PC needs a write-enable signal Design FSM for control (textbook has details: sections 5.4, 5.5) Performance Suppose we had: IF: 5ns, RD: 3ns, ALU: 6ns, MEM: 5ns, WB: 4ns Single-cycle datapath cycle time: 23ns Multi-cycle datapath: lw: 30ns 24ns 18ns add: beq: Is this better? Depends on the instruction mix! (should have balanced pipeline stages) Pipelining Why not start executing the next instruction as soon as the rst one has been fetched? IF RD IF EX RD IF MEM EX RD WB WB EX lw $1,-4($3) add $1,$2,$3 beq $1,$2,L Hardware resource conict... Pipelining Simple x: make all instructions take the same number of cycles. IF RD IF EX RD IF MEM EX RD WB MEM EX WB MEM lw $1,-4($3) add $1,$2,$3 beq $1,$2,L WB Each instruction takes 30ns, but we complete an instruction every 6ns (caveat: op/latch overhead). Pipelined Datapath EX CLK register file MEM WB WB CLK PC alu 0 1 0 1 IF RF/RD = Introduce positive-edge triggered ip-ops between pipeline stages to hold intermediate values. Pipelined Datapath: Control IR1 IR2 EX CLK register file IR3 MEM IR4 WB CLK PC alu 0 1 0 1 IF RF/RD = WB Basic idea: copy the instruction, and generate local control in each pipeline stage. Pipelined Datapath: Timing IF i cycle i+1 i+2 i+3 i+4 ins1 ins2 ins3 ins4 ins5 RD EX MEM WB ins1 ins2 ins3 ins4 ins5 ins1 ins2 ins3 ins4 ins1 ins2 ins3 ins1 ins2 ins1 program Instructions ow through the datapath, advancing every cycle. Pipelined Datapath: Timing IF IR1 RD IR2 EX MEM IR3 WB IR4 CLK register file alu 0 CLK 0 1 1 PC Flops between stages: positive-edge triggered register le: negative-edge triggered PC, Single Instruction Execution IF IR1 RD IR2 EX MEM IR3 WB IR4 CLK register file alu 0 CLK 0 1 1 PC 0x1234 CLK Single Instruction Execution IF IR1 X CLK register file RD IR2 EX MEM IR3 WB IR4 alu 0 1 0x1234 CLK PC 0 1 CLK Single Instruction Execution IF IR1 RD IR2 EX MEM IR3 WB IR4 CLK register file alu 0 CLK PC 0 1 X 1 CLK Single Instruction Execution IF IR1 RD IR2 EX MEM IR3 WB IR4 CLK register file alu 0 CLK PC 0 1 X 1 CLK Register le output can change!
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