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21 Pages

### ch05

Course: SYST 4060, Fall 2008
School: Colorado
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Word Count: 233

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Process Managing Flows Cycle Time Analysis Inflow and Outflow Rates Per Time Period Work-in-Process Level over Time Littles Law WIP = CT WIP = CT WIP CT = Cycle Time Calculation with a Rework Loop Cycle Time Calculation with Multiple Paths Cycle Time Calculation with Parallel Activities An Example of Cycle Time Analysis Cycle Time Efficiency Use processing times Cycle Time Efficiency = Process Time...

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Process Managing Flows Cycle Time Analysis Inflow and Outflow Rates Per Time Period Work-in-Process Level over Time Littles Law WIP = CT WIP = CT WIP CT = Cycle Time Calculation with a Rework Loop Cycle Time Calculation with Multiple Paths Cycle Time Calculation with Parallel Activities An Example of Cycle Time Analysis Cycle Time Efficiency Use processing times Cycle Time Efficiency = Process Time Cycle Time Use activity times Activity time = Processing time + Waiting time Activity Times for Example 5.7 Process Time Calculation A (2) 0.7 C (8) 0.3 B (5) D (3) 0.1 E (4) F (2) H (2) G (4) I (4) PT = 2 + 0.3*5 + 8 + 1.1*(3 + 4 + 4) + max (2,4) + 2 = 29.6 minutes Cycle Time Efficiency 29.6 = 32% Cycle Time Efficiency = 92.5 Managing Process Flows Capacity Analysis Number of Jobs in a Process with Rework Number of Jobs in Process with Multiple Path Number of Jobs in a Process Parallel with Activities Capacity Analysis Example 5.11 A (10) 0.7 C (23) 0.3 B (20) D (10) 0.1 E (20) F (9) H (2) G (13) I (5) Resource Capacity Data for Example 5.11 Activity A B C D E Inspection F G H Processing time 2 5 8 3 4 4 2 4 2 Resource requirement R1 R1 R2 R2 R2 R1 R3 R3 Number of jobs 1 0.3 1 1.1 1.1 1.1 1 1 1 Pool Capacity Calculation for Example 5.11 Resource Unit load (min) R1 R2 R3 2 + 5*0.3 + 2 = 5.5 8 + 1.1*(3+4) = 15.7 4+2=6 Unit capacity (jobs/min) 1/5.5 1/15.7 1/6 Available resources (units) 2 2 1 Po...

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