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3 Pages

### Solutions05

Course: M 343, Fall 2009
School: Calvin
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Word Count: 3872

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odd Solutions 2.1 a) case: m is middle value; even case: middle values are m d and m + d for some d, so m is the median. b) Suppose L values are less than m and E values equal to m. Then there are also L values greater than m. Since m d + m + d = 2m, the sum of the values is xi = xi &lt;m xi + xi &gt;m xi + xi =m xi = 2Lm + Em = (2L + E)m, so the mean is m. c) {5, 1, 0, 2, 4} has both mean and median...

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