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  • Title: w8-01-web
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  • School: Johns Hopkins
  • Course: PHYSICS 101
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Chapter 1 Measurement What is physics? jearl walker Answer: Measurements ... and relationships among measurements. Measurements are numbers. Chapter 1 Measurement Chapter 1, #31 A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.00 mm3 and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kg/minute) does the mass of the candies in the container increase? 14.0 cm 17.0 cm 50.00 mm3 0.0200 g 0.250 cm/s at what rate (kg/minute) Chapter 1 Measurement Chapter 1, #31 A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.00 mm3 and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kg/minute) does the mass of the candies in the container increase? 14.0 cm 17.0 cm 50.00 mm3 0.0200 g 0.250 cm/s at what rate (kg/minute) 10.0 mm = 1 cm Chapter 1 Measurement Chapter 1, #31 A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.00 mm3 and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kg/minute) does the mass of the candies in the container increase? 14.0 cm 17.0 cm 50.00 mm3 0.0200 g 0.250 cm/s at what rate (kg/minute) 10.0 mm = 1 cm 1000 g = 1 kg Chapter 1 Measurement Chapter 1, #31 A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.00 mm3 and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kg/minute) does the mass of the candies in the container increase? 14.0 cm 17.0 cm 50.00 mm3 0.0200 g 0.250 cm/s at what rate (kg/minute) 10.0 mm = 1 cm 1000 g = 1 kg 60 s = 1 minute Chapter 1 Measurement Chapter 1, #31 10.0 mm = 1 cm 1000 g = 1 kg 60 s = 1 minute A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.00 mm3 and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kg/minute) does the mass of the candies in the container increase? Height of candies increases at 15.0 cm 0.250 cm cm sec 60 = 15 min sec min 17.0 cm 14.0 cm volume = 15 14 17 = 3570 cm 3 Chapter 1 Measurement Chapter 1, #31 10.0 mm = 1 cm 1000 g = 1 kg 60 s = 1 minute Each candy has volume 50.00 mm3 and mass of 0.0200 g. At what rate (kg/minute) does the mass of the candies in the container increase? Height of candies increases at 15.0 cm cm cm sec 0.250 60 = 15 min sec min volume = 15 14 17 = 3570 cm 3 10 mm 3570 cm 1 cm 3 3 17.0 cm 14.0 cm = 3, 570, 000 mm 3 0.02 g 71, 400 candies = 1428 g candy ...in one minute, or 1.428 kg/minute 3, 570, 000 mm 3 = 71, 400 candies 3 50 mm / candy Chapter 1 Measurement Chapter 2, #13 Chapter 2, #43 Chapter 2, #63 Chapter 3, #31 Chapter 1 Measurement Example of a measurement: length The Metre Convention of 1875 mandated the establishment of a permanent International Bureau of Weights and Measures to be located in S vres, France. This organisation created a new prototype bar in 1889 at the first General Conference on Weights and Measures, establishing the International Prototype Metre as the distance between two lines on a standard bar of an alloy of ninety percent platinum and ten percent iridium, measured at the melting point of ice. from Wikipedia organisation or organization metre or meter meter, or yard, or foot, or ... Length: English: International Prototype Metre bar, made of an alloy of platinum and iridium, that was the standard from 1889 to 1960. Chapter 1 Measurement 1983 Forget the metre bar in S vres! The meter is the distance light goes in 1/299,792,458 of one second One second is the time taken by 9,192,631,770 oscillations of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium 133 atom. Chapter 1 Measurement It is the year 1889 You visit the International Bureau of Weights and Measures in S vres You suggest that the new platinum/iridium bar be thrown out, and that the meter be, from now on, defined as the distance a car can go in one second! They object that different cars go at different speeds. You say, Oops, right. Sorry! Let s say, instead, the DISTANCE light goes in the vacuum in 1/299792458 seconds! They say: Forget it! Light goes different distances in 1/299792458 seconds, depending on the time of year! Remember, the Earth is moving at about 30 km/s around the Sun! Chapter 1 Measurement The difference in speeds is only 1/100 of 1% not much! start end start end Chapter 1 Measurement An experimental test of non local realism Anton Zeilinger NATURE 2007 April 19 Most working scientists hold fast to the concept of realism a viewpoint according to which an external reality exists independent of observation. Here we show by both theory and experiment ...... Our result suggests that giving up the concept of locality is not sufficient to be consistent with quantum experiments, unless certain intuitive features of realism are abandoned. Chapter 1 Measurement 1925: Discovery of Quantum Mechanics: According to Sir James Jeans: the stream of knowledge is heading towards a non mechanical reality; the Universe begins to look more like a great thought than like a great machine. Mind no longer appears to be an accidental intruder into the realm of matter ... we ought rather hail it as the creator and governor of the realm of matter. According to Sir Arthur Stanley Eddington: It is difficult for the matter of fact physicist to accept the view that the substratum of everything is of mental character. Chapter 1 Measurement Chapter One discusses: length, time, mass, density Conversion from one unit of mass (the atomic mass units, u) to another unit of mass (kilogram, kg): 1 u = 1.66053886 10 27 kg u and kg are independent units: we don t accurately know precisely how many amu are in one kg Chapter 1 Measurement Next, length Yard of beer at end! Conversion from one unit of length (yard) to another unit of length (meter, m): 1 yard = 0.9144 m yard and m are NOT independent units: we do know precisely how many yards are in one meter Chapter 1 Measurement OK, done mass, length, time...which leaves density. (I have no real idea why Jearl chose density!) c a b m m density = = = V a b c A grey glow on the sky: N photons cm 2 s 1sr 1 1 (In fact, once, people liked expressing I ergs cm 2 s 1sr 1 Hz 1 ) surface brightnesses as Suppose you wanted to express this, instead, in units of ergs cm 2 s 1sr 1 Hz 1 E = h ergs photon 1 c ccm s 1 = cm Hz = N photons cm s sr 2 1 1 1 hc hc 1 E = h = ergs photon = ergs photon 1 cm 10 8 hc N hc 1 ergs photon = ergs cm 2 s 1sr 1 1 10 8 10 8 So far, so good! But, the next bit is somewhat tricky! c = = c 1 d = d c 1 = c 2 d ( ) d = d c 1 = c 2 d ( ) Hz Hz c c = cm = cm cm cm If = 1 the passband width is c Hz cm N h c ergs cm 2 s 1sr 1 N h c ergs cm 2 s 1sr 1 = 8 c 10 1 10 8 Hz cm N h cm N hc 2 1 1 1 = ergs cm s sr Hz = 8 ergs cm 2 s 1sr 1 Hz 1 10 8 10 N hc = 8 ergs cm 2 s 1sr 1 Hz 1 10 h c 6.625 10 27 3 1010 1 8 = = 1.9875 10 ; 8 8 10 10 5 10 7 So! N photons cm s sr 2 1 1 1 N > ergs cm 2 s 1sr 1 Hz 1 5 10 7 If N is independent of frequency (a flat spectrum), then for constant b b b N photons cm s sr 2 1 1 d 1 = N ergs cm 2 s 1sr 1 Hz 1d 5 10 7 N N N N b b = ln = ln (b ) ln ) = ln = ln b 7 7( 7 7 5 10 5 10 5 10 5 10 ...which is a constant. There is equal energy per factor b in frequency b 1 e = 2.718.. 10 ln(b) 0 1 2.303.. In the past, people often used units I ergs cm s sr Hz 2 1 1 1 Suppose a spectrum were flat in those units. b I ergs cm s sr 2 1 1 Hz d = I = I (b ) = I (b 1) 1 b This says that for a spectrum that is flat in these units, the amount of energy per factor b in frequency increases linearly with frequency! So the spectrum looks flat, but there is really much more energy at the high frequency end, than at the low frequency end. Not a very satisfactory way to display a spectrum! Recall that N photons cm s sr 2 1 1 1 N > ergs cm 2 s 1sr 1 Hz 1 5 10 7 and that if N is independent of frequency (flat spectrum) we proved there is equal energy per factor b in frequency (which we like). N 2 1 1 1 ergs cm s sr Hz Let I = 7 5 10 Form the quantity with N constant N N 2 1 1 1 I = ( Hz ) ergs cm s sr Hz = ergs cm 2 s 1sr 1 5 10 7 5 10 7 Since N is independent of frequency, so is this. I This technique is often used (unfortunately) to display spectra. I I photons cm 2 s 1sr 1 1 All the spectra shown have equal energy per factor b in frequency Chapter 1

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Path: Cornell >> CS >> 478 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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hw2_soln
Path: Cornell >> CS >> 478 Spring, 2008
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hw1_soln
Path: Cornell >> CS >> 478 Spring, 2008
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Path: Cornell >> CS >> 482 Spring, 2008
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sol9
Path: Cornell >> CS >> 482 Spring, 2008
Description: Introduction to Algorithms CS 482, Spring 2008 Solution Set 9 (1) Let T be the number of trucks used by the algorithm, and suppose the trucks are labeled 1, 2, . . . , T in the order that the algorithm loads them up. Observe that for i = 1, 2, . . ...
08 - NP-complete numerical problems- subset sum
Path: Cornell >> CS >> 482 Spring, 2008
Description: 30 3/31/08 - NP-complete numerical probl. NP-Complete Problems 3SAT Vtx Cover Indep. Set (even in deg 3) Clique Hamiltonian Path Set cover/packing Traveling salesman 3D matching Subset Sum. 3-D Matching Given sets X, Y, Z, with n elts each. Given 3...
08 - Case Theory; distribution of PRO
Path: Cornell >> LING >> 404 Spring, 2008
Description: 4 1/23/08 - Case Theory; distribution of PRO 4 levels of structure D structure move S-structure move LF PF For next week: read rst 2 chapters Londau D-Structure and S-structure connected by move-alpha Passive: _ was arrested John Johni was arrest...
08 - Binding Theory
Path: Cornell >> LING >> 404 Spring, 2008
Description: 5 1/28/08 - Binding Theory The binding theory divides into three types of things anaphors, pronouns, R-expressions The binding theory has three conditions. A. An anaphor must be bound in its governing category. C-Command condition: *Himselfi pinche...

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