4 Pages

sinusoids368_4up

Course: SINUSOIDS 368, Fall 2009
School: Sveriges...
Rating:
 
 
 
 
 

Word Count: 1066

Document Preview

368: Sinusoids CMPT Lecture 3 Sinusoids Tamara Smyth, tamaras@cs.sfu.ca School of Computing Science, Simon Fraser University January 17, 2007 Sinusoids is a collective term referring to both sine and cosine functions. A sinusoid is a function having the following form: x(t) = A sin(t + ), where x is the quantity which varies over time and A f t t + 2 peak amplitude radian frequency (rad/sec) = 2f frequency...

Register Now

Unformatted Document Excerpt

Coursehero >> Other International >> Sveriges lantbruksuniversitet >> SINUSOIDS 368

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
368: Sinusoids CMPT Lecture 3 Sinusoids Tamara Smyth, tamaras@cs.sfu.ca School of Computing Science, Simon Fraser University January 17, 2007 Sinusoids is a collective term referring to both sine and cosine functions. A sinusoid is a function having the following form: x(t) = A sin(t + ), where x is the quantity which varies over time and A f t t + 2 peak amplitude radian frequency (rad/sec) = 2f frequency (Hz) time (seconds) initial phase (radians) instantaneous phase (radians) Amplitude 1 0 1 2 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Time (s) Figure 1: Sinusoid where A = 2, = 25, and = /4. 1 CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 2 Amplitude and Magnitude. Period peak amplitude: the nonnegative value of the waveforms peak (either positive or negative); often shortened to simply amplitude. instantaneous amplitude of x: the value of x(t) (either positive or negative) at time t. instantaneous magnitude: a nonnegative value given by |x(t)|; often shortened to simply magnitude. The period T of a sinusoid is the time (in seconds) it takes to complete one cycle. One cycle of a sinusoid is 2 radians. /2 3/2 2 Figure 2: Sinusoid. Since sinusoids are periodic with period 2, an initial phase of is indistinguishable from an initial phase of 2. We may therefore restrict the range of so that it does not exceed 2. Typically we choose the range but we many also encounter < < , 0 < < 2. CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 3 CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 4 Phase The initial phase , given in radians, tells us the position of the waveform cycle at t = 0. Also sometimes called: phase oset, phase shift, or phase factor. 2 Frequency The frequency f of the waveform is given in cycles per second or Hertz (Hz). Frequency is equivalent to the inverse of the period T of the waveform, f = 1/T Hz. Amplitude 1 0 1 2 1 0.8 0.6 0.4 0.2 0 0.2 0.4 0.6 0.8 1 Time (s) The radian frequency , given in radians per second, is equivalent to the frequency in Hertz scaled by 2, = 2f (rad/sec). Figure 3: Sine function = 0. 2 Amplitude 1 0 1 2 1 0.8 0.6 0.4 0.2 0 0.2 0.4 0.6 0.8 1 Time (s) Figure 4: Sine function with = /2. CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 5 CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 6 Sine and cosine functions. The sine and cosine function are very closely related and can be made equivalent simply by adjusting their initial phase: sin = cos( ) or cos = sin( + ). 2 2 1 Time-shifting a signal. If a signal can be expressed in the form x(t) = s(t t1), we say x(t) is a time-shifted version of s(t). s(t) x(t) = s(t2) 1 1 y(t) = s(t+1) Amplitude 0.5 1 0 0 1 0.5 0 1 2 3 1 0 1 2 Figure 6: Time-shifting a signal. 1 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 Time (s) Figure 5: Phase relationship between cosine and sine functions. Consider the simple function s(t) = t 0 t 1. 0t21 2 t 3, Shifting the function by t1 = 2 seconds yields x(t) = s(t 2) = t 2 = t2 In calculus, the sine and cosine functions are derivatives of one other. That is, d sin d cos = cos and = sin . dt dt which is simply s(t) with its origin shifted to the right, or delayed, by 2 seconds. CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 7 CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 8 Shifting the function by t1 = 1 yields seconds y(t) = s(t + 1) = t + 1 = t+1 0t+11 1 t 0, Sinusoidal and Circular Motion Consider a vector of length one (1), rotating at a steady speed in a plane, the vector tracing a circle with a radius equal to its length. /2 which is simply s(t) with its origin shifted to the left, or advanced in time, by 1 seconds. /4 3/2 Figure 7: A vector rotating along the unit circle. Each time the vector completes one rotation of the circle, it has completed a cycle of 2. The rate at which the vector completes one cycle is given by its frequency. The length of the vector is given by its amplitude (which for simplicity, in this case, is one (1)). CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 9 CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 10 Sinusoidal and Circular Motion cont. The x- and y-axis are the horizontal and vertical lines intersecting at the circles centre. y-axis (0, 1) 1 1 ( 2 , 2 ) Sinusoids and Circular Motion cont. Projecting onto the x- and y-axis gives a sequence of points that resemble a cosine and sine function respectively. amplitude > (0, -1) Figure 8: The vector coordinates are determined by projecting onto the x and y-axis. Projecting the vector onto the x- and y-axes allows us to determine its coordinates in the xy-plane. If the vector is rotated in a counterclockwise direction, at angle from the positive x-axis, projecting onto both the x- and y-axes creates right angle triangles. Trigonometric identities, with knowledge of and the vector length, will help us determine the coordinates. CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 11 (-1, 0) ! ! (1, 0) x-axis time > amplitude > time > Figure 9: Projecting onto the x and y axis. CMPT 368: Computer Music Theory and Sound Synthesis: Lecture 3 A positive phase indicates a shift to the left whereas a negative phase indicates a shift to the right. 1 2 # "# " 12 Adding two sinusoids of the same frequency Adding two sinusoids of the same frequency but with ...

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

Neumont - EN - 1973
Supreme Court of Canada Victor Investment Corp. Ltd. et al. v. Fidelity Trust Co., [1975] S.C.R. 251 Date: 1973-10-02 Victor Investment Corporation Ltd., Victor James Thiessen and Margaret Thiessen (Plaintiffs) Appellants; and The Fidelity Trust Comp
Sveriges lantbruksuniversitet - CMPT - 413
Introduction to Natural Language Processing with NLTKSteven Bird Edward Loper Ewan KleinUniversity of Melbourne, AUSTRALIA University of Pennsylvania, USA University of Edinburgh, UKminor edits by Anoop Sarkar any mistakes are his faultPython
Sveriges lantbruksuniversitet - CMPT - 825
Homework #3: CMPT-825Anoop Sarkar anoop@cs.sfu.ca(1) Part-of-speech Tagging: Consider the task of assigning the most likely part of speech tag to each word in an input sentence. We want to get the best (or most likely) tag sequence as dened by th
Allan Hancock College - MOPGPR - 20022002
MEMBERS OF PARLIAMENT (LIFE GOLD PASS) REGULATIONS 2002 2002 NO. 313 MEMBERS OF PARLIAMENT (LIFE GOLD PASS) REGULATIONS 2002 2002 NO. 313 - TABLE OF PROVISIONSPART 1-PRELIMINARY 1. Name of Regulations 2. Commencement 3. Definitions
Sveriges lantbruksuniversitet - CMPT - 825
CMPT 825 Natural Language ProcessingAnoop Sarkarhttp:/www.cs.sfu.ca/~anoopGoals of the Course Convince you that understanding language is a subtle, interesting, and tractable problem Give insight into various algorithms including statistical ma
Neumont - EN - 1973
Supreme Court of Canada Association of Radio and Television Employees of Canada (CUPE-CLC) v. Canadian Broadcasting Corporation, [1975] S.C.R. 118 Date: 1973-10-02 Association of Radio and Television Employees of Canada (CUPE-CLC) Appellant; and Cana
Sveriges lantbruksuniversitet - CMPT - 413
Homework #8: CMPT-413Distributed on Mon, Apr 4, Due on Mon, Apr 11Anoop Sarkar anoop@cs.sfu.ca(1)Implement the feature unification algorithm given in Figure 11.8 in Jurafsky and Martin (on page 423). Download the file FeatureStruct-inc.pm whic
Sveriges lantbruksuniversitet - CMPT - 880
CMPT 880 Fall 2007 Presentation Summary &amp; Question about BTName: Michael Jia Email: zmj@sfu.ca Student number: 301046057Towards a Global IP Anycast ServiceIP anycast was first proposed in 1993 and now became an important IP packet addressing and
Sveriges lantbruksuniversitet - CS - 401
Chapter7SynchronizationTopics Physicalclocksynchronization Logicalclocksynchronization Causalityrelation Lamportslogicalclock Vectorlogicalclock Multicast ISISvectorclockSnapshotNewIssuesinDS Globaltime Eventordere1at1
CSU Fullerton - BTO - 120
# classes script - place a list of students into course sectionssection=Awhile read inputdo echo &quot;BTO120$section $input&quot; &gt; /tmp/classes.temp.$ section=$(echo $section | tr [A-N] [B-NA])done &lt; classlist.txtsort -k1,1 -k3 /tmp/classes.temp.
Sveriges lantbruksuniversitet - STAT - 201
Review for Final Exam Course Coverage: Chapters 1 through 20. Excluded sections and topics: Ch 1: pie charts, bar graphs, stemplots, time plots. Ch 2: boxplots, computing formulas for quartiles. Ch 6: conditional distributions. Ch 7: using random num
Laurentian - MATH - 131
General Knowledge Questions from Old Exams Set III. General knowledge questions. (5 points each.) From April 2007. III.1. A circle with diameter AP intersects a circle with diameter BP at P and a second point Q. Prove that Q always lies on the line A
Laurentian - MATH - 103
MATH 103 200710 Problem Set 4Edward Doolittle Thursday, February 22, 2007The following problems may appear on the quiz on Thursday, March 1, 2007. 1. Find the stationary points of the following functions:2. For each of the functions in the previo
Laurentian - CS - 330
No questions yet.
Sveriges lantbruksuniversitet - ARTS - 19981
PROFILE OF STUDENTS IN SFU COURSES COURSE: CNS 380-3 H01 LOCATION: DOW TITLE: STT-CAN.POL.ECONOMY SECTION TYPE: SEC SEMESTER: 1998-1 ENROL: 16
Sveriges lantbruksuniversitet - POL - 19981
PROFILE OF STUDENTS IN SFU COURSES COURSE: POL 447-3 D02 LOCATION: SFU TITLE: INTER. POL. ECONOMY SECTION TYPE: SEM SEMESTER: 1998-1 ENROL: 14
Sveriges lantbruksuniversitet - APSC - 19983
Sheet1 PROFILE OF STUDENTS IN SFU COURSES COURSE: CMNS 240-3 D01 LOCATION: DOW TITLE: POLITICAL ECONOMY SECTION TYPE: LEC SEMESTER: 1998-3 ENROL: 36 = PROGRAM OF STUDENT (Top 5 programs reported in each category Programs with &lt; 3 students not shown s
Sveriges lantbruksuniversitet - APSC - 20031
Sheet1 PROFILE OF STUDENTS IN SFU COURSES COURSE: CMNS 240-3 ALL SECTIONS LOCATION: SFU TITLE: POLITICAL ECONOMY SECTION TYPE: LEC SEMESTER: 2003-1 ENROL: 71 = PROGRAM OF STUDENT (Top 5 programs reported in each category Programs with &lt; 3 students no
Sveriges lantbruksuniversitet - POL - 20003
Sheet1 PROFILE OF STUDENTS IN SFU COURSES COURSE: POL 447-4 D01 LOCATION: SFU TITLE: INTL.POL.ECONOMY SECTION TYPE: SEM SEMESTER: 2000-3 ENROL: 17 = PROGRAM OF STUDENT (Top 5 programs reported in each category Programs with &lt; 3 students not shown sep
Sveriges lantbruksuniversitet - POL - 20033
Sheet1 PROFILE OF STUDENTS IN SFU COURSES COURSE: POL 447-4 D01 LOCATION: SFU TITLE: INTL.POL.ECONOMY SECTION TYPE: SEM SEMESTER: 2003-3 ENROL: 16 = PROGRAM OF STUDENT (Top 5 programs reported in each category Programs with &lt; 3 students not shown sep
Allan Hancock College - SAA - 200536
Western Australia Stamp Amendment (Assessment) Act 2005 Western Australia Stamp Amendment (Assessment) Act 2005 CONTENTS 1. Short tit
Sveriges lantbruksuniversitet - POL - 20033
Sheet1 PROFILE OF STUDENTS IN SFU COURSES COURSE: POL 356-4 D01 LOCATION: SFU TITLE: POL.ECONOMY/LABOUR SECTION TYPE: SEM SEMESTER: 2003-3 ENROL: 27 = PROGRAM OF STUDENT (Top 5 programs reported in each category Programs with &lt; 3 students not shown s
Toledo - PHY - 110
35.SSM REASONING AND SOLUTION According to Equation 3.3b, the acceleration of the astronaut is a y = (vy - v0y )/ t = vy / t . The apparent weight and the true weight of the astronaut are related according to Equation 4.6. Direct substitution gives
Toledo - PHY - 110
6.REASONINIG AND SOLUTION Using Equation 28.1 with v 1v 1 1 2 c c we have2 1v t0 = t 1 2 c 22The difference between t and t0 is v Time difference = t t0 = t ( 1 ) 2 c2 8.64 104 s 1 7800 m/s 2 4 Time difference = (15 day
Toledo - PHY - 110
REASONING AND SOLUTION From Equation 16.1, we have O = v/f. But v = x/t, so we find v x 2.5 m = = 0.49 m O= = f t f (1.7 s )( 3.0 Hz ) _ 5.13.SSMREASONINGThe tension F in the violin string can be found by solvingEquation 16.2 for F to obtai
Toledo - PHY - 205
From http:/www.glenbrook.k12.il.us/gbssci/phys/Class/momentum/u4l1b.html - by TomHendersonThe Impulse-Momentum Change TheoremMomentum and Impulse ConnectionMomentum is a commonly used term in sports. When a sports announcer says that a team ha
Toledo - PHY - 138
Solution to PHYS 138 Waves Assignment 2 Due November 22, 20041 Problem 13.8y(x, t) = (0.120 m) sin(x/8 + 4t) a) To determine the transverse speed and acceleration at any time and position you must dierentiate the transverse position equation wrt ti
Toledo - PHY - 138
PHY138Y - Waves - Term Test 2 To better understand the Waves section of PHY138Y, review the following material. Think about the phenomena which were demonstrated during the lectures. The equations cited below appear in the text and the lectures. Mult
Toledo - PHY - 138
PHY138 Waves Written Homework Solutions1. a.) The intensity is given by the power P divided by the area A of the ultrasound transducer: I = 15 W/6 104 m2 = 25 103 W m2 . b.) For sound waves, the intensity I is related to the pressure amplitude A
Toledo - PHY - 138
PHY138Y - Waves - Solutions for Problem Set 1A number in brackets () following an equation indicates an equation number.1. (Problem 12.4) (a) The amplitude of the motion is A = 5.00 cm. The total distance that the particle moves during one cycle
Toledo - PHY - 138
SOLUTIONS TO PROBLEM SET #4 (NUCLEAR PHYSICS)Question #1. Calculating the Q value for the process38 17 Cl38 Ar + e- + v 18we have Q = (mcl - mAr ) c2 = (37.967931u - 37.962732u) 931.494 = 4.84M eV So the maximum kinetic energy of the beta par
Toledo - PHY - 138
PHY138Y Assignment 4 prepared by: Amit Ghosh 2.38 g of algae carbon : 5365 counts g of modern carbon : 25437 counts Half-life of : yrs. and decay constant is Activity is given by:2.72 Na nuclei is introduced at a rate s . At , the number of Na nuc
Toledo - PHY - 138
SOLUTIONS TO ASSIGNMENT #5 Supplementary Problem Fixed quantities are the initial speeds of both the left and right hand carts (1m/s and 0 m/s respectively) and the mass of the left hand block (1 kg). 1. Elastic Collision Chart: (mL /mR -mass of left
Toledo - PHY - 138
MarkingScheme.nb1PHY138 Mechanics TestProblem Answers and Marking SchemeGeneral PrinciplesRight answers always get full marks. There are other correct ways to solve almost all of the questions. Marks for method(s) other than shown here are app
Toledo - PHY - 138
SOLUTIONS TO ASSIGNMENT #6Supplementary Problem 1. Elastic Collision ChartmL /mR is the mass of the Left/Right hand cart Right-hand cart mass (kg) VF,L (m/s) VF,R (m/s) Initial Momentum (kg.m/s) Pi = mL Vi,L Final Momentum (kg.m/s) Pf = mLVf,L+ mRV
Toledo - PHY - 138
PHY 138Y Physics for the Life Sciences I Electromagnetism Quarter Spring Term, 2006 Test 3 Solutions and Marking SchemeMULTIPLE CHOICE QUESTIONS (8 marks each for 64 marks total)Solutions for Version 1:Question 1 X and Y are two uncharged meta
Toledo - PHY - 138
PHY138 Quarter Test SolutionsFebruary 10, 2004Multiple Choice Questions1. What is the relationship between the electric field vector at a point and the electric field line going through that point? (A) They are perpendicular to each other. (B) Th
Toledo - P - 352
Toledo - P - 352
S S Drrh u 2S70v2fwBVdCd 'h |3@VAg `h d11rh $@8Q1r@3w3Ac38&amp;gv b u &amp;7 u u p &amp; I(7(Q &amp; 2 0( I9 ph u d W u e e@ @`ph 'V'1'D 89g@382@SWS&quot;v3 @u82@SWS I (a 7 P 6 Q P Q &amp; Q E 2 0 (a 7 P 6 Q P Q &amp; Q HTHTBga@73Pv2TSR3A3ovW1
Toledo - P - 352
0 i srqiowig} t pg yr t y p y h p y g ~r z t y p p p pg 6g i sorqwspd oqTpzrq$6D6o6g6wrEq|iip6 u u pg h t pgnl y eg t r u oqpiBstrwiodyid2q{pwv u y p ~r t t p t r vioEqU6|rwspwid2q{pwv u wi |6rqw66Bq{pdowwpirHii6@qqo
Toledo - P - 352
k kq o e e l y s h h ut6si16gxtsn!ju#ejl6qk @ %YQRI#gisRTDFtu%aTf#FPW Q Uf h c h fS VQVDiSqiIRPPPXaYSRwwgPG2#XQPTsmYhqE2mREdTGifYWREPRiIYhdPXatxrVDXD}PTsPTDVQ S a h hDa e FI r h` S h aD FIx I QIs DD h h FIWa Q e S f h e hl k e e y s
Toledo - P - 352
Toledo - P - 352
Bry { mW@20eW P0S x$T8eHig b s s s s s v v p v y GX a) 7 feB|B9 D C IQ 7 Q a ) 9 )D ) IQ A1d G 7D a ) b Q a )11 C c ) I )1 C 7 ) ) s s v EV@DUf2B23WVB3eHQ8EeWp238EeWU$8EBH9%e#W P PHD7 2V23S 1)Q) R1R QR 1AQc) a 7
Toledo - P - 352
e h eX ` q X V qh e t b ` b ` w t r e b dX m ` w e d h q b dX m hX i h qX ` h b ` e t b ` mX ` q T )al$cdll~3r4gaccxrdaca!)rl$crxlUe V b ` h b x n m wX d q $c$lV tavplcp3Y$Pla'k$lY3Yl$ykrxr~r!&amp;rcYar$6e v `X X ` `X r V b t `X f V b ` `
Toledo - P - 352
x Bg)`2C(!TB2C)d)SqCpTb2f5)!Sy(|S$`p!5B`$1tuS$1tY()%(BFd$CCRA%5BTB2S$3R&quot;)%q`wXY()CFT%q&quot; F F $ &amp; $ q AP w 5 W &quot; $ p 5 &quot; ( W bF $ &quot; 5 &quot; ( P ( A W &amp; F $q z#&quot;BsdS$A Vtr10( { w gy&quot;!F)5$ %q`2&quot; %qvB&amp;!$ R&quot;W 5bC)qA W Sd(uY$Sm&quot; q T39F `Xb(`w&quot; 9P( !( )`2
Toledo - P - 352
90&quot;C(aB#'#%&amp;!)s0U 1$ )51D!rX3#'$%#79)(%f&quot;#5y(8CYl&quot;%9&quot;(%#sayxwu 6#'#8!b%X9&quot;%(6)!)0W5D16$V9C(aBb#Ij bzhg &quot; 1 B )X t B 3 $&amp; U B X 1 &amp; $ i s`a~ uVx5ywuWi'&amp;0DW'U%$C)B9U'(0D#8!76!)Sp5U#q8CYm9)#I&amp;6$#5o| y t t ( ( &amp; 3 1E ( B ( &quot;
Toledo - P - 352
dz o r ~ ~ ~ u q u ~ ~ r u xctj'xeUtnt u ~ w w u q n u ~ ~ r ~ u u o r u r ~ ~ q u w } w ~ u u u ~ w ~ r z 1hx'ttcxxx2'n z w u s r I|v ~ u u r q w o ~ u u u ~ ~ r ~ w w u s r u u u ~ o u
Toledo - P - 352
w yEv ) %2~jdb w x8 9x w )y v 22x|db dx 298 ) 43639V6U%|G3%P&quot;Ff{U98$4D%T6$D 1 3$5 D 1 H D z ) 17 6f(%| 0PUf8U{D|92P&quot;%E6Ujf6U{D|8$EC8$9%G&amp;SxH63n4)2f9%fEGh9EG61}n6&amp;P$H@ e DU ' $&quot; H i z &amp;$ H )&amp;B H i z 3B D5
Toledo - P - 352
S UF!gY21b5w23%u&quot;pE p% 7 gCE pC 7 EpE p% 7 xpCE pC 7 6 ) u @ #bd t 5p b g!y 9FTi@ Y&quot;1 hl'j@ j@ y P H cF F 46ya5w!pe5y72!0&amp;58x9&quot;#e)41y5&amp;535'v)9u7'Ao!pf 1 3&amp; 3x uc 3 a 3 3 ) 3 dXF8!0&amp;!c!0&amp;j0x!g!4&amp;Aoe34y9yC1g
Toledo - P - 352
p ( D u $ ( ( (&amp; q k 7 I &quot; S D 7 F 1 &quot; ( ( 84 #R5i#'CYFx!twey6)9(fB0&amp;#0TT9'`$YD#Su#9S#'`$r!0pr96|#961{%&quot;6&quot;#0`(YD'(#! a $&amp; 7 1&amp; t 8 $ $ D $ ( D &quot; 7 I z!E`$EDT#!6hF9)#T!Sxx0DE(#t5'7%$')u`5EDV g WyP891hB6)R(E#`5w6)9( Bw#9'`$YD#So9I 6`(hDC
Toledo - P - 352
IUS0WkiPhh T X R ) T R) ikhh(V FAt US| fhiiEkD6Q5&quot; 0iPhFjiFh`0 H 5 1 ) 9 9 C B 1 ) IG|2FQcEiwD(A20V h@QQF86%#4320('%#!| 9 7 5 &quot; 1 ) &amp; $ &quot;
Toledo - P - 352
Toledo - P - 352
y 8x k Su t5Cdee5 k {Su t5Cdee5S 779d(H7G7(2%d1Pe&amp;7(%U'A%4d%d1l5B73%2U)1P!fb &amp; 6 ( &amp; b 6$B 9&quot; ( &amp; (c ( &amp; ( f ( &amp; @ ( &amp; b 6 ( &amp; b &amp; ($B b ( &amp; (c !dbU)1Cf0%5BA@)fUE$0!(dY!9a12%d1C3!3)0%D53!3%0%)1P79( l5B73%4BE(!Y)b49( %)1e&amp;)1WV%1 dh b(&amp; b&amp;
Toledo - PHY - 110
49.SSM REASONING The ray diagram is constructed by drawing the paths of two rays from a point on the object. For convenience, we will choose the top of the object. The ray that is parallel to the principal axis will be refracted by the lens so that
Toledo - PHY - 110
41. REASONING AND SOLUTION The equivalent resistance of the circuit is Rs = R1 + R2 = 36.0 + 18.0 = 54.0 Ohm's law for the circuit gives I = V/Rs = (15.0 V)/(54.0 ) = 0.278 A a. Ohm's law for R1 gives V1 = (0.278 A)(36.0 ) = 10.0 V b. Ohm's law fo
Toledo - PHY - 138
PHY138 Waves, Lecture 6 Todays overview Waves in the Electric and Magnetic Fields The Electromagnetic Spectrum The Special Properties of Laser LightReadingAssignmentPlease read the following from Serway and Jewett before class on Mond
Toledo - PHY - 138
PHY138 Waves, Lecture 6Todays overview Waves in the Electric and Magnetic Fields The Electromagnetic Spectrum The Special Properties of Laser LightReading AssignmentPlease read the following from Serway and Jewett before class on Monday: Chapter
Toledo - PHY - 138
PHY138 Waves, Lecture 9Today's overview Lenses The Thin Lens Equation Lenses Used in CombinationIt's the last week of the fall semester!The last Waves Problem Set is due at 5:00 PM today in your TA's mailbox. There is no Web-CT quiz until Jan.3.
Toledo - PHY - 138
Quiz 1A light wave travels through three transparent materials of equal thickness. Rank is order, from the largest to smallest, the indices of refraction n1, n2, and n3.A. n2 &gt; n1 &gt; n3 D. n3 &gt; n2 &gt; n1B. n3 &gt; n1 &gt; n2 E. n1 = n2 = n3C. n1 &gt; n2 &gt;
Toledo - PHY - 138
PHY138 Waves, Lecture 8Todays overview:Course Evaluations in Tutorial this week!Your chance to officially evaluate Vatche and me is this week during tutorial. Your comments will make it into the 2008-09 Anti-Calendar and will form part of the te
Toledo - PHY - 138