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Course: ECE 2331, Fall 2008School: U. Houston
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2331 ECE Project 1 Spring 2009 Selected Results Original Data Task 3: Define function myf(x) in terms of unitstep The value of myf at x =10 is 0.47569 x myf(x) 1.5000 0.9975 2.5000 0.5985 3.5000 -0.3508 4.5000 -0.9775 4.9000 1.0000 5.2000 1.0000 5.5000 1.0000 6.5000 -0.3051 10.0000 0.4757 Task 5: Use fzero to find root(s) Start Root Function 1.5000 -0.4200 0 2.5000 3.1416 -0.0000 3.5000 3.1416 0.0000 4.5000 4.7124...
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2331 ECE Project 1 Spring 2009 Selected Results Original Data Task 3: Define function myf(x) in terms of unitstep The value of myf at x =10 is 0.47569 x myf(x) 1.5000 0.9975 2.5000 0.5985 3.5000 -0.3508 4.5000 -0.9775 4.9000 1.0000 5.2000 1.0000 5.5000 1.0000 6.5000 -0.3051 10.0000 0.4757 Task 5: Use fzero to find root(s) Start Root Function 1.5000 -0.4200 0 2.5000 3.1416 -0.0000 3.5000 3.1416 0.0000 4.5000 4.7124 -1.0000 4.9000 4.7124 -1.0000 5.2000 4.7124 1.0000 5.5000 4.7124 -1.0000 6.5000 6.2832 -0.5000 10.0000 6.9763 0.0000 of myf Flag 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
Task 6: Experiment with fzero's options With iteration limit of 20 and tolerance of 5e-005 Starting at x=1.5 Search for an interval around 1.5 containing a sign change: Func-count a f(a) b f(b) 1 1.5 0.997495 1.5 0.997495 interval 3 1.45757 0.993597 1.54243 0.999598 5 1.44 0.991458 1.56 0.999942 7 1.41515 0.987911 1.58485 0.999901 9 1.38 0.981854 1.62 0.99879 11 1.33029 0.971219 1.66971 0.995112 13 1.26 0.95209 1.74 0.985719 15 1.16059 0.917038 1.83941 0.964139 17 1.02 0.852108 1.98 0.917438 19 0.821177 0.731949 2.17882 0.820777 21 0.54 0.514136 2.46 0.630031 23 0.142355 0.141875 2.85765 0.280147 24 -0.42 0 2.85765 0.280147 Search for a zero in the interval [-0.42, 2.85765]: Func-count x f(x) Procedure 24 -0.42 0 initial Zero found in the interval 2.85765] [-0.42, Solution is -0.42 Starting at x=3.5 Search for an interval around 3.5 containing a sign change: Procedure initial search search search search search search search search search search search search
Func-count 1 interval 3 5 7 9 10
a
3.5
f(a) -0.350783 -0.256513 -0.216675 -0.15973 -0.078327 0.0375636
b
3.5
f(b) -0.350783 -0.441619 -0.478027 -0.52813 -0.595917 -0.595917
Procedure initial search search search search search
3.40101 3.36 3.30201 3.22 3.10402
3.59899 3.64 3.69799 3.78 3.78
Search for a zero in the interval [3.10402, 3.78]: Func-count x f(x) Procedure 10 3.10402 0.0375636 initial 11 3.1441 -0.00251123 interpolation 12 3.14159 5.51438e-007 interpolation 13 3.14159 5.51438e-007 interpolation Zero found in the interval [3.10402, 3.78] Solution is 3.1416 Task 8: Define &...
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