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61 Pages

### Oct9

Course: CS 557, Fall 2009
School: Wisconsin Milwaukee
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Today Announcements Finish RDM (Chapter 5), begin relational algebra Reading Sections 6.0-6.5 Program 2 Due Friday Exam Tuesday Oct 16, in class Closed book Will cover material through Thursday's lecture Class bufMgr{ ... // Call DB object to allocate a run of new pages and // find a frame in the buffer pool for the first page // and pin it. If buffer is full, ask DB to deallocate // all these pages...

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Today Announcements Finish RDM (Chapter 5), begin relational algebra Reading Sections 6.0-6.5 Program 2 Due Friday Exam Tuesday Oct 16, in class Closed book Will cover material through Thursday's lecture Class bufMgr{ ... // Call DB object to allocate a run of new pages and // find a frame in the buffer pool for the first page // and pin it. If buffer is full, ask DB to deallocate // all these pages and return error Status newPage(int& firstPageId, Page*& firstpage,int howmany=1); // Check if this page is in buffer pool, otherwise // find a frame for this page, read in and pin it. // Also write out the old page if it's dirty before reading // if emptyPage==TRUE, then actually no read is done to bring // the page in. Status pinPage(int PageId_in_a_DB, Page*& page, int emptyPage=0, const char *filename=NULL); ... } // // in your code // PageId pid; Page *pPageTmp SecondaryIndexHeaderPage *pHeaderPage; MINIBASE_BM->newPage( pid, pPageTmp ); pHeaderPage = (SecondaryIndexHeaderPage*)pPageTmp; Constraints Constraints A key aspect of RDM is the ability to impose constraints on the database state A constraint on a single relation places restrictions on valid relation states Examples: two students can't have same student ID number Example of key constraint Student name cannot be NULL Domain constraints (implicit) Key Constraints Superkey of R: Is a set of attributes SK of R with the following condition: No two tuples in any valid relation state r(R) will have the same value for SK That is, for any distinct tuples t1 and t2 in r(R), t1[SK] t2[SK] This condition must hold in any valid state r(R) Key of R: A "minimal" superkey That is, a key is a superkey K such that removal of any attribute from K results in a set of attributes that is not a superkey (does not possess the superkey uniqueness property) Key Constraints (continued) Example: Consider the CAR relation schema: CAR(State, Reg#, SerialNo, Make, Model, Year) CAR has two keys: Key1 = {State, Reg#} Key2 = {SerialNo} Both are also superkeys of CAR {SerialNo, Make} is a superkey but not a key. In general: Any key is a superkey (but not vice versa) Any set of attributes that includes a key is a superkey A minimal superkey is also a key Key Constraints (continued) If a relation has several candidate keys, one is chosen arbitrarily to be the primary key. The primary key attributes are underlined. Example: Consider the CAR relation schema: CAR(State, Reg#, SerialNo, Make, Model, Year) We chose SerialNo as the primary key The primary key value is used to uniquely identify each tuple in a relation Provides the tuple identity Also used to reference the tuple from another tuple General rule: Choose as primary key the smallest of the candidate keys (in terms of size) Not always applicable choice is sometimes subjective CAR table with two candidate keys LicenseNumber chosen as Primary Key Multiple Relations Typically, a RDB has many relations Relational Database Schema Relational Database Schema: A set S of relation schemas that belong to the same database. S is the name of the whole database schema S = {R1, R2, ..., Rn} R1, R2, ..., Rn are the names of the individual relation schemas within the database S COMPANY Database Schema Referential Integrity Constraints involve Two Relations Example: DEPT_LOCATION.Dnumber must refer to an existing tuple in DEPARTMENT Operationalized through concept of foreign key Referential Integrity Tuples in the referencing relation R1 have attributes FK (called foreign key attributes) that reference the primary key attributes PK of the referenced relation R2. A tuple t1 in R1 is said to reference a tuple t2 in R2 if t1[FK] = t2[PK]. A referential integrity constraint can be displayed in a relational database schema as a directed arc from R1.FK to R2. Referential Integrity (or foreign key) Constraint Statement of the constraint The value in the foreign key column (or columns) FK of the the referencing relation R1 can be either: (1) a value of an existing primary key value of a corresponding primary key PK in the referenced relation R2, or (2) a null. In case (2), the FK in R1 should not be a part of its own primary key. Referential Integrity Constraints for COMPANY database Other Types of Constraints Semantic Integrity Constraints: based on application semantics and cannot be expressed by the model per se Example: "the max. no. of hours per employee for all projects he or she works on is 56 hrs per week" A constraint specification language may have to be used to express these SQL-99 allows triggers and ASSERTIONS to express for some of these Update Operations on Relations Must not Violate Constraints INSERT a tuple. DELETE a tuple. MODIFY a tuple. Several update operations may have to be grouped together (a transaction) Updates may propagate to cause other updates automatically. This may be necessary to maintain integrity constraints. Update Operations on Relations In case of integrity violation, several actions can be taken: Cancel the operation that causes the violation (RESTRICT or REJECT option) Perform the operation but inform the user of the violation Trigger additional updates so the violation is corrected (CASCADE option, SET NULL option) Execute a user-specified error-correction routine Possible violations for each operation INSERT may violate any of the constraints: Domain constraint: if one of the attribute values provided for the new tuple is not of the specified attribute domain Key constraint: if the value of a key attribute in the new tuple already exists in another tuple in the relation Referential integrity: if a foreign key value in the new tuple references a primary key value that does not exist in the referenced relation Entity integrity: if the primary key value is null in the new tuple Possible violations for each operation DELETE may violate only referential integrity: If the primary key value of the tuple being deleted is referenced from other tuples in the database Can be remedied by several actions: RESTRICT, CASCADE, SET NULL (see Chapter 8 for more details) RESTRICT option: reject the deletion CASCADE option: propagate the new primary key value into the foreign keys of the referencing tuples SET NULL option: set the foreign keys of the referencing tuples to NULL One of the above options must be specified during database design for each foreign key constraint Possible violations for each operation UPDATE may violate domain constraint and NOT NULL constraint on an attribute being modified Any of the other constraints may also be violated, depending on the attribute being updated: Updating the primary key (PK): Similar to a DELETE followed by an INSERT Need to specify similar options to DELETE Updating a foreign key (FK): May violate referential integrity Updating an ordinary attribute (neither PK nor FK): Can only violate domain constraints In-Class Exercise (Taken from Exercise 5.15) Consider the following relations for a database that keeps track of student enrollment in courses and the books adopted for each course: STUDENT(SSN, Name, Major, Bdate) COURSE(Course#, Cname, Dept) ENROLL(SSN, Course#, Quarter, Grade) BOOK_ADOPTION(Course#, Quarter, Book_ISBN) TEXT(Book_ISBN, Book_Title, Publisher, Author) Draw a relational schema diagram specifying the foreign keys for this schema. Relational Algebra Chapter 6 Relational Algebra Relational Algebra: a formal query language associated with the relational model example query: "retrieve the last name and department location of all employees that more than 35,000" "select" operator TMP1 Salary > 30000 (EMPLOYEE) "join" operator TMP1 (Dno == Dnumber) DEPT_LOCATION RESULT Lname, DLocation (TMP2) "projection" operator TMP2 Relational Algebra queries are composed of a set of operators Inputs and outputs of queries are relations thus the algebra is "closed" Query is evaluated using states of the input relations and produces a state of the output relation. unary operator input relation input relation binary operator Output relation input relation Output relation Relational Algebra expression Output from one operator can input to another EMP. TMP1 TMP2 Dept. Loc RESLT Relational Algebra Overview Relational Algebra consists of several groups of operations Unary Relational Operations SELECT (symbol: (sigma)) PROJECT (symbol: (pi)) RENAME (symbol: (rho)) Relational Algebra Operations From Set Theory UNION ( ), INTERSECTION ( ), DIFFERENCE (or MINUS, ) CARTESIAN PRODUCT ( x ) Binary Relational Operations JOIN (several variations of JOIN exist) DIVISION Additional Relational Operations OUTER JOINS, OUTER UNION AGGREGATE FUNCTIONS (These compute summary of information: for example, SUM, COUNT, AVG, MIN, MAX) SELECT Unary Relational Operations: SELECT The SELECT operation (denoted by (sigma)) is used to select a subset of the tuples from a relation based on a selection condition. The selection condition acts as a filter Keeps only those tuples that satisfy the qualifying condition Tuples satisfying the condition are selected whereas the other tuples are discarded (filtered out) Examples: Select the EMPLOYEE tuples whose department number is 4: DNO = 4 (EMPLOYEE) Select the employee tuples whose salary is greater than $30,000: SALARY > 30,000 (EMPLOYEE) Unary Relational Operations: SELECT In general, the select operation is denoted by <selection condition>(R) where the symbol (sigma) is used to denote the select operator the selection condition is a Boolean (conditional) expression specified on the attributes of relation R tuples that make the condition true are selected appear in the result of the operation tuples that make the condition false are filtered out discarded from the result of the operation Unary Relational Operations: SELECT (contd.) SELECT Operation Properties The SELECT operation <selection condition>(R) produces a relation S that has the same schema (same attributes) as R SELECT is commutative: <condition1>( < condition2> (R)) = <condition2> ( < condition1> (R)) Because of commutativity property, a cascade (sequence) of SELECT operations may be applied in any order: <cond1>(<cond2> (<cond3> (R)) = <cond2> (<cond3> (<cond1> ( R))) A cascade of SELECT operations may be replaced by a single selection with a conjunction of all the conditions: <cond1>(< cond2> (<cond3>(R)) = <cond1> AND < cond2> AND < cond3>(R))) The number of tuples in the result of a SELECT is less than (or equal to) the number of tuples in the input relation R PROJECT Unary Relational Operations: PROJECT PROJECT Operation is denoted by (pi) This operation keeps certain columns (attributes) from a relation and discards the other columns. PROJECT creates a vertical partitioning The list of specified columns (attributes) is kept in each tuple The other attributes in each tuple are discarded Example: To list each employee's first and last name and salary, the following is used: LNAME, FNAME,SALARY(EMPLOYEE) Unary Relational Operations: PROJECT (cont.) The general form of the project operation is: <attribute list>(R) (pi) is the symbol used to represent the project operation <attribute list> is the desired list of attributes from relation R. The project operation removes any duplicate tuples This is because the result of the project operation must be a set of tuples Mathematical sets do not allow duplicate elements. Unary Relational Operations: PROJECT (contd.) PROJECT Operation Properties The number of tuples in the result of projection <list>(R) is always less or equal to the number of tuples in R If the list of attributes includes a key of R, then the number of tuples in the result of PROJECT is equal to the number of tuples in R PROJECT is not commutative <list1> ( <list2> (R) ) = <list1> (R) as long as <list2> contains the attributes in <list1> Set Theory Operators: UNION, INTERSECTION & MINUS Relational Algebra Operations from Set Theory: UNION UNION Operation Binary operation, denoted by The result of R S, is a relation that includes all tuples that are either in R or in S or in both R and S Duplicate tuples are eliminated The two operand relations R and S must be "type compatible" (or UNION compatible) R and S must have same number of attributes Each pair of corresponding attributes must be type compatible (have same or compatible domains) Relational Algebra Operations from Set Theory: UNION Example: To retrieve the social security numbers of all employees who either work in department 5 (RESULT1 below) or directly supervise an employee who works in department 5 (RESULT2 below) We can use the UNION operation as follows: DEP5_EMPS DNO=5 (EMPLOYEE) RESULT1 SSN(DEP5_EMPS) RESULT2(SSN) SUPERSSN(DEP5_EMPS) RESULT RESULT1 RESULT2 The union operation produces the tuples that are in either RESULT1 or RESULT2 or both Example of the result of a UNION operation UNION Example Relational Algebra Operations from Set Theory Type Compatibility of operands is required for the binary set operation UNION , (also for INTERSECTION , and SET DIFFERENCE , see next slides) R1(A1, A2, ..., An) and R2(B1, B2, ..., Bn) are type compatible if: they have the same number of attributes, and the domains of corresponding attributes are type compatible (i.e. dom(Ai)=dom(Bi) for i=1, 2, ..., n). The resulting relation for R1R2 (also for R1R2, or R1R2, see next slides) has the same attribute names as the first operand relation R1 (by convention) Relational Algebra Operations from Set Theory: INTERSECTION INTERSECTION is denoted by The result of the operation R S, is a relation that includes all tuples that are in both R and S The attribute names in the result will be the same as the attribute names in R The two operand relations R and S must be "type compatible" Relational Algebra Operations from Set Theory: SET DIFFERENCE (cont.) SET DIFFERENCE (also called MINUS or EXCEPT) is denoted by The result of R S, is a relation that includes all tuples that are in R but not in S The attribute names in the result will be the same as the attribute names in R The two operand relations R and S must be "type compatible" Example to illustrate the result of UNION, INTERSECT, and DIFFERENCE Relational Algebra Operations from Set Theory: CARTESIAN PRODUCT CARTESIAN (or CROSS) PRODUCT Operation This operation is used to combine tuples from two relations in a combinatorial fashion. Denoted by R(A1, A2, . . ., An) x S(B1, B2, . . ., Bm) Result is a relation Q with degree n + m attributes: Q(A1, A2, . . ., An, B1, B2, . . ., Bm), in that order. The resulting relation state has one tuple for each combination of tuples--one from R and one from S. Hence, if R has nR tuples (denoted as |R| = nR ), and S has nS tuples, then R x S will have nR * nS tuples. The two operands do NOT have to be "type compatible" Relational Algebra Operations from Set Theory: CARTESIAN PRODUCT (cont.) Generally, CROSS PRODUCT is not a meaningful operation Can become meaningful when followed by other operations Example (not meaningful): FEMALE_EMPS SEX='F'(EMPLOYEE) EMPNAMES FNAME, LNAME, SSN (FEMALE_EMPS) EMP_DEPENDENTS EMPNAMES x DEPENDENT EMP_DEPENDENTS will contain every combination of EMPNAMES and DEPENDENT whether or not they are actually related Relational Algebra Operations from Set Theory: CARTESIAN PRODUCT (cont.) To keep only combinations where the DEPENDENT is related to the EMPLOYEE, we add a SELECT operation as follows Example (meaningful): FEMALE_EMPS SEX='F'(EMPLOYEE) EMPNAMES FNAME, LNAME, SSN (FEMALE_EMPS) EMP_DEPENDENTS EMPNAMES x DEPENDENT ACTUAL_DEPS SSN=ESSN(EMP_DEPENDENTS) RESULT FNAME, LNAME, DEPENDENT_NAME (ACTUAL_DEPS) RESULT will now contain the name of female employees and their dependents Relational Algebra Operations from Set Theory: CARTESIAN PRODUCT CARTESIAN (or CROSS) PRODUCT Operation This operation is used to combine tuples from two relations in a combinatorial fashion. Denoted by R(A1, A2, . . ., An) x S(B1, B2, . . ., Bm) Result is a relation Q with degree n + m attributes: Q(A1, A2, . . ., An, B1, B2, . . ., Bm), in that order. The resulting relation state has one tuple for each combination of tuples--one from R and one from S. Hence, if R has nR tuples (denoted as |R| = nR ), and S has nS tuples, then R x S will have nR * nS tuples. The two operands do NOT have to be "type compatible" Binary Relational Operations: JOIN JOIN Operation (denoted by ) The sequence of CARTESIAN PRODECT followed by SELECT is used quite commonly to identify and select related tuples from two relations A special operation, called JOIN combines this sequence into a single operation This operation is very important for any relational database with more than a single relation, because it allows us combine related tuples from various relations The general form of a join operation on two relations R(A1, A2, . . ., An) and S(B1, B2, . . ., Bm) is: ... Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education. Below is a small sample set of documents: Wisconsin Milwaukee - CS - 557 Announcements Progress Reports (mini design document) due Tuesday Dec 4 in class. It will be graded and count to the final grade of the project. Homework 3 due next Friday Next week advanced topics: Chapters 15, 17-19, 28-29 Textbook lab files at Iowa State - CPRE - 310 Here are some hints on how to do the symbolic proof for problem #5 in the Study Guide for Test #1. Thanks to Nate Pierce for making these suggestions. For part a), look at the implication in Table 5. We know that p must be false for the implication t Otterbein - MATH - 365 A A (VERY SHORT) GUIDE TO L TEX.LaTeX is a typesetting system. A typical LaTeX document starts with a preamble this includes command definitions, page-styles, etc. The body of your document should appear between the lines \begin{document} and \end{ Otterbein - IS - 410 INST 410Our Place in the UniverseThe Sungburk@otterbein.eduThe Sun A typical Star The only star in the solar system Diameter: 100 that of Earth Mass: 300,000 that of Earth Density: 0.3 that of Earth (comparable to the Jovians) Rotation Otterbein - IS - 410 INST 410 Our Place in the UniverseThe Stars gburk@otterbein.edu Office: Science 222 Secretary: Sandra Salee FAX: 823-1968 OfficeHours: by appointment.The Stars Part I What properties can we measure? distance velocity temperature size Otterbein - IS - 410 1SKYLABS 2009 Doug Ingram, University of Washington [adapted] Supplemented with CLEA virtual experiments on 15Sept08 IntroductionIncluded in this handout are seven possible astronomy projects: you must choose one of these to do at some point duri Otterbein - PHYS - 172 PHYSICS 172 Solutions to HomeworkWQ 2009#81. Giancoli Chapter 28, Problem 7Since the magnetic field from a current carrying wire circles the wire, the individual field at point r P from each wire is perpendicular to the radial line from that w Otterbein - IS - 410 INST 410Homework #6 Due by 4pm Friday, March 13, 2009Winter 2009In this assignment you will calculate the age of the universe. Sound dicult? It really isnt. All you need to know is how far away some galaxies are, and how fast they are moving aw Wisconsin Milwaukee - LIB - 4741 16761676:62234:1584:601a40853:42413:689:474 14691:38566:485:401abstract12417:31764:4036:401achieved24195:36013:4471:382almost33776:21535:2810:328among9402:29193:3525:601an52913:42431:1507:492and10322:37727:1941:364 27798:38529:1941:455 Otterbein - IS - 410 INST 410 Our Place in the UniverseWinter 2009Lecture 3 Light and Telescopesgburk@otterbein.edu Office: Science 230 Secretary: Sandra Sallee (x1316) FAX: 823-1968 OfficeHours: by appointment.Properties of Light The vast majority of informa University of Louisville - PHS - 398 GGOther SupportThere is no form page for other support. Information on other support should be provided in the format shown below, using Continuation Pages. Include the Principal Investigators name at the top and number consecutively with the rest Virginia Tech - MATH - 1206 Centers of MassParticles of masses 6, 1, 3 are located at (-2,5), (3,3) &amp; (3,-4) respectively. Find ( x, y )Find the centroid (center of mass with uniform density) of the region shown, by locating the centers of the rectangles and treating them a Wisconsin Milwaukee - LIB - 1672 &quot;don'10235,24117,1304,7444&quot;goo9903,8144,1304,7178&quot;heigh-h7477,17008,1642,12395&quot;her8474,41957,1282,6845&quot;ho10534,33026,1304,6713&quot;n10501,27649,1642,5217&quot;o10833,38313,1619,5018&quot;tip-top9737,13543,562,115315952142,5016,1304,2392a12395,40 Wisconsin Milwaukee - LIB - 924 !33026,32683,1132,232!25888,34193,1132,258!51931,10195,1111,232!13422,31529,1132,181&quot;24413,39962,440,646&quot;i16034,38662,923,2948'*9206,54164,377,620(he49267,15775,1090,32067929560,2622,1090,1758:50534,52507,713,310:52138,44074,713, Wisconsin Milwaukee - LIB - 1156 &quot;9899,44817,377,1573&quot;i10292,30203,1022,2971&quot;literar9636,8416,1006,8784&quot;musica9767,12789,991,8216&quot;socia9877,11326,975,6643&quot;thi10030,14236,975,4698'stor11669,44738,1352,51782487364,6087,880,2840a24277,26097,613,852a27140,15872,644,87 Wisconsin Milwaukee - LIB - 2438 'a6976,49211,740,2913110464,53393,597,8202emed6935,45243,836,57453551541,8054,956,2380:am5909,23398,764,4513;48545,15630,860,410;13952,53441,884,369[whe4760,17064,1147,5868^av6483,43068,932,3816a35332,8293,740,1354a29135,45697,64 Wisconsin Milwaukee - LIB - 2592 18744787:7300:3000:937;47824:42941:402:887\vatt25430:50809:5452:1011^f21405:50859:3073:986a26711:27057:914:641 31797:7646:1024:764 16502:34999:878:690 23784:29030:878:616 8159:27106:878:616 9916:19090:951:641about14453:24763:5525:961ample Wisconsin Milwaukee - LIB - 2482 7948169,7929,1050,2226;9633,52252,900,445a32342,8129,675,1295a32544,19660,650,971a33111,48600,625,1011a15948,23612,775,1052a25299,34093,650,1011a49384,11606,650,971a20077,56680,625,1011a41490,50702,650,1011a25906,23462,975,1659a Wisconsin Milwaukee - LIB - 2450 !12164,19578,1038,327&quot;4956,32013,469,1146&quot;4505,11371,469,1105&quot;4669,19653,444,1105'le6676,21704,939,3645*!2990,50826,1730,19254748209,7910,988,22935en4095,34263,667,2949;33545,19999,914,368[hav1392,15499,914,5242^n2375,23509,1161, Wisconsin Milwaukee - LIB - 2180 &quot;15599:39892:594:373/k15410:14184:1784:10991212030:7609:1135:505a50367:38243:757:681 30820:33801:729:615 41256:47567:757:615 36903:49151:757:615 33118:35340:729:615after26954:33801:3379:681again53395:25884:4352:835alice17924:42861:3785:9 Wisconsin Milwaukee - LIB - 2596 &quot;8141,11212,417,994&quot;8178,17199,441,957&quot;8178,25149,490,114119145900,7802,956,2947;26486,25345,858,405a32749,8047,662,1031a32085,55303,662,994a8693,15383,637,920able45826,47354,687,3610afflicted34701,33344,613,6962alive34369,27332, Wisconsin Milwaukee - LIB - 2142 &quot;37533:31826:704:376 53550:16522:648:354 37448:14971:704:398.55298:51006:140:44;37702:21350:253:819a22531:55125:761:597 34177:28991:874:620 52732:51936:761:620after10179:44428:3383:597all10320:56742:1776:597alone12661:56720:4032:597 4235 Wisconsin Milwaukee - LIB - 1328 &quot;48726:54630:610:446 48835:27726:610:429 49707:39649:675:446 35819:21773:675:429 31394:29245:610:446 49663:29210:588:429 35797:30711:675:446 45281:32177:610:429 45107:23257:610:429&quot;an35601:27690:4164:947&quot;bu35579:35145:3706:947&quot;don'53195:36646: Wisconsin Milwaukee - CS - 317 4.1 Mathematical InductionLet P (n) be a statement regarding integer n. In many instances, the goal is to show that P (n) is true for every positive integer n. We can of course try to do this using the previous proof methods weve discussed e.g., di Wisconsin Milwaukee - CS - 217 GG B@ CA9 US6 CA9 6 uA 0 QPG 0 0 B@ 3 0$( G G 45E)0 PQG 0 0 3 0 $( G G ! 421)0 PPG 0 0 e G 3 0 3 0$ ( 42t45pC( a3 1)a451C( 0 $(3 0$ e 3 0 $451C( 3 ECQsrp$ ( 0 $( 3 q 0 e 3 0$ 451C( 0 $h 1i0$ e e 3 0 \$ 451C( 3
Otterbein - IS - 410
Next: How Johannes Kepler found a much more accurate scheme for predicting planetary positions, based on new mathematical lawsThe Baroque Setting Counter-reformation in the 1600s; church much stricter Giordano Bruno (Italian, b. 1548) proposes t
Wisconsin Milwaukee - MATH - 225
You have 70 minutes. You may use a scientic calculator, but not a graphing calculator if you wish. 60% will guarantee you a C on this exam if you have passed the Gateway exams on Graphing and Integration/Antidierentiation. 1. Graphing and the Mean Va
Wisconsin Milwaukee - LIB - 425
Wisconsin Milwaukee - LIB - 258
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Christian Brothers - M - 232
QUIZ 12 Name 1. Find x dy dx where R = {(x, y) | y 0, y R below by y = 0 and above by y = 4 - x2 ) 4 - x2 } (That is: the region bounded2. Find the volume of an ice cream cone bounded by the hemisphere z = cone z = x2 + y 2 .8 - x2 - y 2 and
University of Louisville - PHYSICS - 298
1 298HW05 (Questions 25-27) Due AT 4:00PM on 02/20/07 NAME_Section_ (please print)25. Consider the sliding block system from problem 22 of 298HW04. Suppose that the acceleration due to gravity is slightly increased. Compute the acceleration of the b
University of Louisville - PHYSICS - 298
1 298HW02 (Questions 7-12) Due at 4:00PM on 01/31/07 NAME_ (please print)7. (Uncertainty and measurements) To give you an idea of how to estimate uncertainty consider the following measurements of my gas mileage. I drive a 1998 Honda Civic which acc
University of Louisville - PHYSICS - 298
6298 Test 0I Time allowed: 50 minutes Please answer ALL questions 02/23/07 Name_PLEASE READ THE FOLLOWING INSTRUCTIONS CAREFULLY 1. Please answer all questions and show all necessary work. There are TEN multiple choice and FOUR long problems
University of Louisville - PHYSICS - 298
1 298HW06 (Questions 25-27) Due AT 4:00PM on 03/09/07 NAME_Section_ (please print)28. Now lets expand on previous 298 classes. We want to know if gas mileage depends on the temperature of the air. Consider solely the force of air resistance, f r =b
University of Louisville - PHYSICS - 298
1 298HW01 (Questions 1-6) Due AT 4:00PM on 01/24/07 NAME_ (please print)1. (i) What are the dimensions of the 3 fundamental observationally defined physical observables? What are the units in both imperial and SI scales? What are the conversions for
University of Louisville - PHYSICS - 298
1 298HW10 (Questions 49-52) Due at 4:00PM on 4/23/07 NAME_ (please print) Grade Option (Circe One): Syllabus Alternate49. Compute the force and potential energy of gravity at the points A and B below. The masses are arranged on a square as shown and
University of Louisville - PHYS - 299
University of Louisville - PHYS - 299
Otterbein - IS - 410
So what is science? Search for order or patterns in nature In physics and astronomy the patterns are expressed mathematically E.g. for a falling body released from rest, d t2 Analogy: the rules of a giant chess game (At least) two amazing fact
Wisconsin Milwaukee - LIB - 2490
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!23748,54470,1023,328&quot;6656,54421,399,1109&quot;43594,34166,424,1068&quot;24652,54520,399,9038748976,8017,974,2300;17051,17807,874,369;46429,46628,874,410a33116,8241,774,1150a4273,38162,649,1027a41621,21903,674,1109a32130,19855,649,1027a4
Wisconsin Milwaukee - LIB - 1102
&quot;i8522,17964,1006,2797&quot;s47485,19380,1006,3146486009,5222,865,1835a7932,50370,597,852a13329,25578,629,874a41235,56112,644,852a9352,11074,613,874a26332,18326,613,852a23775,13969,613,895a15493,19773,613,874able22595,31383,597,3277a
Wisconsin Milwaukee - LIB - 1003
!17061:35305:202:1132&quot;35391:38305:684:419 29915:36690:633:503 12650:22865:659:419 14349:38305:608:419*'14298:36879:684:440.stirre12270:51626:5526:37715812447:3629:2585:713;25199:9020:228:881?29053:36690:507:1153a26188:48375:861:734 546
Wisconsin Milwaukee - LIB - 1541
'32220,12344,267,156'33157,12659,661,17401128204,51536,1133,21643tu6eii&gt;tsy34719,9526,992,82784.87809,9620,1023,26338.713388,7841,1070,2543&gt;&quot;v\35121,13069,62,4842^49759,37884,1039,2164a9929,14470,1086,1539a48822,14297,850,914a111
Neumont - CSC - 1957
Supreme Court of Canada Maxine Footwear Company Ltd. v. Canadian Government Merchant Marine Ltd., [1957] S.C.R. 801 Date: 1957-10-01 Maxine Footwear Company Ltd. et al. (Plaintiffs) Appellants; and Canadian Government Merchant Marine Ltd. (Defendant)
Wisconsin Milwaukee - LIB - 1842
907578:2895:1984:1045a58342:58677:992:744 28385:55178:992:744 54042:50634:964:723 47621:47356:964:744 33456:18158:1488:1126 54153:45788:964:744 57542:42590:1019:744 20724:45607:964:723 53794:53851:964:744 15432:5891:1019:744 39133:42490:937:744 62
Wisconsin Milwaukee - LIB - 1843
&quot;i1971:29390:2860:1257&quot;w18133:57056:4304:1135&quot;watc3471:26246:7358:11569156537:2941:1888:1034:16467:57462:222:730a18827:21865:971:770 11218:6977:1527:1115 11690:42858:971:750air17522:13833:2415:730all6997:59044:2193:750and16633:17058:
Wisconsin Milwaukee - LIB - 2272
a51056:41305:764:605 57749:39835:710:605 47614:28963:764:605 32671:19539:846:670 49718:16794:846:670 57421:56651:737:670about47068:22868:4124:605all51766:32119:1748:583 26088:24035:1748:583an21116:28487:1721:605and47614:30454:2677:670 56001:
Neumont - CSC - 1904
Supreme Court of Canada Letourneau v. Carbonneau, 35 S.C.R. 110 Date: 1904-06-08 Edmond Letourneau and Joseph Bernier (Defendants) Appellants; and Charles Eugene Carbonneau and Belinda Ann Carbonneau (Plaintiffs) Respondents.1904: May 25, 26; 1904:
Wisconsin Milwaukee - LIB - 341
&quot;lor10159:39491:3105:1238a40771:44529:528:725 42010:29245:512:725 16107:19382:446:704 42010:27324:462:725 34906:32682:809:1110 16503:41711:462:704 21145:24975:462:704 16090:21240:462:704about44471:35008:2874:725all17065:30526:1189:704and3492
Wisconsin Milwaukee - LIB - 372
a43474:17945:526:753all50658:27605:1528:1129and39144:21933:1952:775 50284:25943:1919:775 38685:40034:1919:775 44969:25965:1919:775 43746:19939:1919:775ball39874:25522:1919:1218boys45648:19518:2292:1218 41453:19518:2275:1218but37514:35581:1
Wisconsin Milwaukee - LIB - 179
'15842:60342:966:384-10494:60363:49:64.10661:60492:16:42down10028:14337:8762:3504i^'ira^10711:60363:1449:106notvervfaroff3531:20171:21606:2222stailri36032:51902:9095:2179way4497:15513:6197:3547yonder17808:15683:11161:2094
Wisconsin Milwaukee - LIB - 347
191924169:17771:1903:928a26253:25285:508:738 16556:34825:459:696 26696:27184:508:717about20920:36682:2887:696alone25154:19628:2773:738and19476:29147:1837:696 12880:38624:1788:738 46255:42233:1821:738 16949:38603:1460:717 34867:36556:1821:759
Wisconsin Milwaukee - LIB - 1886
Wisconsin Milwaukee - LIB - 1340
&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;&lt;Error&gt;&lt;Code&gt;NoSuchKey&lt;/Code&gt;&lt;Message&gt;The specified key does not exist.&lt;/Message&gt;&lt;Key&gt;f55059d98ac553c985e18669b64c05073051906f.txt&lt;/Key&gt;&lt;RequestId&gt;CC9F084E465B4CC5&lt;/RequestId&gt;&lt;HostId&gt;ZOPNhHgfKT4udUhgyNkFLEdXhQ7n
Wisconsin Milwaukee - LIB - 2157
&quot;35995,36006,354,628&quot;9970,35962,354,685&quot;49851,37404,88,257'49136,37692,244,228,48079,38424,221,1992152279,8031,554,1142;16140,37714,865,228;10027,49983,843,228&gt;50822,37847,687,599a9227,33055,687,885a17312,45368,621,799a40138,19
Wisconsin Milwaukee - LIB - 1817
!39792,13956,1132,277!43200,9162,1092,304&quot;th5015,47694,1173,41566556252,3256,1112,2050a20505,3135,1132,1524a33030,51234,748,969a10613,6290,728,997a22085,40473,707,1025a30703,47634,1112,1440a47911,48018,748,969a27987,52852,728,942
Wisconsin Milwaukee - LIB - 794