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4-ph-3

Course: WEB 112, Fall 2009
School: Cornell
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Solution (A) 4.ph.3 Regions 1, 2, 3, and 4 are labeled on the diagram below. These are the same as the analogous regions on the pressure-volume phase diagram. (B) A line across the liquid-vapor region connects a liquid phase in equilibrium with a vapor phase. Both phases have the same pressure and the same temperature, so the line is horizontal, as shown below. (C) The relationship between temperature and volume...

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Solution (A) 4.ph.3 Regions 1, 2, 3, and 4 are labeled on the diagram below. These are the same as the analogous regions on the pressure-volume phase diagram. (B) A line across the liquid-vapor region connects a liquid phase in equilibrium with a vapor phase. Both phases have the same pressure and the same temperature, so the line is horizontal, as shown below. (C) The relationship between temperature and volume in the vapor region is PV = nRT. If volume were plotted on a linear scale a constant pressure path would be a straight line with slope P/nR. However, because volume is plotted on a logarithmic scale, must we plot temperature versus log10(volume). PV = nRT P V nR P T = 10 log10 V nR P 2.303(log10 V ) T = e nR T = The constant pressure path rises exponentially, as shown on the phase diagram below. 1.solid C 4. vapor temperature (linear scale) B 3. liquid + vapor 2. solid + vapor molar volume (log scale) (D) Steps 1-5 are labeled on the phase diagram bel...

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Cornell - WEB - 112
4.ph.6 Solution(A) We begin by labeling the map, then identifying the starting point and the destination. The starting point is water vapor at 29C and 75% humidity. At 29C the vapor pressure is 0.04 atm, so 75% humidity is 0.75 0.04 = 0.03 atm. The
Cornell - WEB - 112
4.ph.8 SolutionWork backwards from the output, stream 5 at 150C and 500 atm. To avoid condensing H2O at 150C, the H2O partial pressure cannot exceed 4.7 atm. (See point 5 on the phase diagram below.) For the H2O partial pressure to stay below 4.7 at
Cornell - WEB - 112
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Cornell - WEB - 112
4.37(A) A mass of 3 is placed at 0.10 mol fraction methanol and the fulcrum is placed at 0.20. Whatmass placed at 0.5 balances the lever?3 0.0 0.4 ? 0.6 0.8 1.0mol fraction methanol(3)(0.2 0.1) = (mass)(0.5 0.2). The mass is 1. Thus the flow
Cornell - WEB - 112
4.37(A) A mass of 3 is placed at 0.10 mol fraction methanol and the fulcrum is placed at 0.20. Whatmass placed at 0.5 balances the lever? 3 0.0 0.4 ? 0.6 0.8 1.0 (3)(0.2 - 0.1) = (mass)(0.5 - 0.2). The mass is 1. Thus the flow rate of stream 1 is 1.
Cornell - WEB - 112
4.41(A) The tie line at 87.5C is shown on the temperature composition phase diagram below. Thecomposition of the liquid phase is 0.22 mol fraction G and the vapor phase is 0.50 mol fraction G. temperature-composition phase diagram for G-H mixtures a
Cornell - WEB - 112
4.42(A) See the line labeled A on the diagram.(i) 60 Btu/lb (ii) 22 Btu/lb (iii) 22 (60) = 82 Btu/lb (B) (i), (ii) See the line labeled B on the diagram on the next page. (iii) 55 wt% H2SO4 (iv) The point lies about one third the distance from the
Cornell - WEB - 112
4.42(A) See the line labeled A on the diagram.(i) -60 Btu/lb (ii) 22 Btu/lb (iii) 22 - (-60) = 82 Btu/lb (B) (i), (ii) See the line labeled B on the diagram on the next page. (iii) 55 wt% H2SO4 (iv) The point lies about one third the distance from t
Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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Cornell - WEB - 112
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