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University of Texas - ANT - 324L
ANT 324L Paper 1La MalincheWhen referring to the Spanish conquest of Mesoamerica, two names occupy the forefront of most peoples minds, Hernan Cortes and La Malinche, also known as Malintzin or Dona Marina. Cortes, the great conquistador, and Mal
University of Texas - ANT - 324L
ANT324L Dec 1 An Indigenous Death PactBeginning with the fall of the last great indigenous empires of the Aztecs and the Mayans, the Mexican Federal Government has continuously oppressed, or blatantly ignored, indigenous peoples throughout the coun
University of Texas - ANT - 345C
ANT 345C Sep. 20 Writing Assignment: Week 4 This weeks readings discussed the planning and development of the elegant Wacker Drive in Chicago and the horribly developed working-class neighborhoods of Manchester. While one article focuses on the devel
University of Texas - ANT - 345C
ANT 345C October 11 Writing Assignment: Week 6Fortified Enclaves by Teresa P. R. Caldeira brings to light the relatively recent phenomenon of fortified, segregated communities in large urban cities. While those who live in the enclaves see no probl
University of Texas - BIO - 309D
Organization of the Human Bodytissues, organs & organ systemsYour body has over 200 different specialized type of cellsOrganization of the Human Body Organizational hierarchy: Cells TissuesOrgansOrgan SystemsTissues Groups of similar cell
Michigan State University - ADV - 201
-sInfluences on the consumer decision-making process There are many.Learning and type of learning Elaboration Likelihood Model and routes to learning Brand Loyalty Evoked set Maslow's Hierarchy Primary data Secondary data Reliability and validity
Michigan State University - ADV - 201
Characteristics of effective adverting Advertising definition Johannes Gutenberg, Volney Palmer, Francis Ayer, Leo Burnett WWI impact on advertising industry Advertisings economic role Ethics Social criticisms of advertising puffery, offensive, subl
Michigan State University - COM - 225
COM 225 Review Sheet 1 Below you'll find the content for which you will be responsible on Exam 1. Exam items over "Material to know from lecture" will be written straight from lecture notes, and items involving content from the text will be written d
Michigan State University - COM - 225
EXAM 2 REVIEW - COM 225 RACHEL SHAPIROCHAPTER 4 The Nature of Emotion Emotion is the most powerful of human experiences and typically involves thoughts, intense arousal, and communication. Emotions are such significant life events that we feel comp
Sabancı University - FIN - 501
1If APR on a 3-month deposit is 20%, what is EAR? APR # Periods EAR 20.0% 4 21.6%5.00%2If EAR on a 3-month deposit is 25%, what is APR? EAR # Periods Period Rate APR 25.0% 4 5.74% 22.9%3You purchased 100 ABC Inc shares on May. 1, 2007, at
Sabancı University - FIN - 501
FINANCIAL ANALYSISPart 1Liquidity and Operational EfficiencyBalance SheetARENA, Dec. 31, 2006152,147 7,716 90,337 48,397 5,697 3,906 1 2,252 442 336 875 156,053 LIABILITIES and EQUITY Current Liabilities Short-term Debt Accounts Payable Rela
Texas A&M - MEEN - 222
CHAPTER 2ATOMIC STRUCTURE AND INTERATOMIC BONDINGPROBLEM SOLUTIONS2.1 (a) When two or more atoms of an element have different atomic masses, each is termed an isotope. (b) The atomic weights of the elements ordinarily are not integers because:
Texas A&M - MEEN - 222
CHAPTER 3THE STRUCTURE OF CRYSTALLINE SOLIDS PROBLEM SOLUTIONS 3.1 Atomic structure relates to the number of protons and neutrons in the nucleus of an atom, as well as the number and probability distributions of the constituent electrons. On the ot
Texas A&M - CVEN - 221
CHAPTER 4IMPERFECTIONS IN SOLIDSPROBLEM SOLUTIONS4.1 In order to compute the fraction of atom sites that are vacant in lead at 600 K, we must employ Equation (4.1). As stated in the problem, Q = 0.55 eV/atom. Thus, v Q 0.55 eV / atom = ex
Texas A&M - MEEN - 222
CHAPTER 5DIFFUSIONPROBLEM SOLUTIONS5.1 Self-diffusion is atomic migration in pure metals-i.e., when all atoms exchanging positions are of the same type. Interdiffusion is diffusion of atoms of one metal into another metal.5.2 Self-diffusion m
Texas A&M - MEEN - 222
CHAPTER 6 MECHANICAL PROPERTIES OF METALSPROBLEM SOLUTIONS6.1This problem asks that we derive Equations (6.4a) and (6.4b), using mechanics of materials principles. In Figure (a) below is shown a block element of material of cross-sectional area
Texas A&M - MEEN - 222
CHAPTER 7DISLOCATIONS AND STRENGTHENING MECHANISMSPROBLEM SOLUTIONS7.1 The dislocation density is just the total dislocation length per unit volume of material (in this case per 3 5 -2 cubic millimeters). Thus, the total length in 1000 mm of ma
Texas A&M - MEEN - 222
CHAPTER 8FAILUREPROBLEM SOLUTIONS8.1 Several situations in which the possibility of failure is part of the design of a component or product are as follows: (1) the pull tab on the top of aluminum beverage cans; (2) aluminum utility/light poles
Texas A&M - MEEN - 222
CHAPTER 9PHASE DIAGRAMSPROBLEM SOLUTIONS9.1 Three variables that determine the microstructure of an alloy are 1) the alloying elements present, 2) the concentrations of these alloying elements, and 3) the heat treatment of the alloy.9.2 In or
Texas A&M - MEEN - 222
CHAPTER 10PHASE TRANSFORMATIONS IN METALSPROBLEM SOLUTIONS10.1 The two stages involved in the formation of particles of a new phase are nucleation and growth. The nucleation process involves the formation of normally very small particles of the
Texas A&M - MEEN - 222
CHAPTER 11APPLICATIONS AND PROCESSING OF METAL ALLOYSPROBLEM SOLUTIONS11.1 This question asks that we list four classifications of steels, and, for each, to describe properties and cite typical applications. Low-Carbon Steels Properties: nonres
Texas A&M - MEEN - 222
CHAPTER 12STRUCTURES AND PROPERTIES OF CERAMICSPROBLEM SOLUTIONS12.1The two characteristics of component ions that determine the crystal structure are:1) themagnitude of the electrical charge on each ion; and 2) the relative sizes of the
Texas A&M - MEEN - 222
CHAPTER 13APPLICATIONS AND PROCESSING OF CERAMICSPROBLEM SOLUTIONS13.1 The two desirable characteristics of glasses are optical transparency and ease of fabrication.13.2 (a) Devitrification is the process whereby a glass material is caused to
Texas A&M - MEEN - 222
CHAPTER 14POLYMER STRUCTURESPROBLEM SOLUTIONS14.1Polymorphism is when two or more crystal structures are possible for a material of given composition. Isomerism is when two or more polymer molecules or mer units have the same composition, but
Texas A&M - MEEN - 222
CHAPTER 15 CHARACTERISTICS, APPLICATIONS, AND PROCESSING OF POLYMERSPROBLEM SOLUTIONS15.1 From Figure 15.3, the elastic modulus is the slope in the elastic linear region of the 20C curve, which is(stress) 30 MPa - 0 MPa = = 3.3 GPa (strain) 9 x
Texas A&M - MEEN - 222
CHAPTER 16COMPOSITESPROBLEM SOLUTIONS16.1The major difference in strengthening mechanism between large-particle and dispersionstrengthened particle-reinforced composites is that for large-particle the particle-matrix interactions are not trea
Texas A&M - MEEN - 222
CHAPTER 17CORROSION AND DEGRADATION OF MATERIALSPROBLEM SOLUTIONS17.1 (a) Oxidation is the process by which an atom gives up an electron (or electrons) to become a cation. Reduction is the process by which an atom acquires an extra electron (or
Texas A&M - MEEN - 222
CHAPTER 18ELECTRICAL PROPERTIESPROBLEM SOLUTIONS18.1 This problem calls for us to compute the electrical conductivity and resistance of a silicon specimen. (a) We use Equations (18.3) and (18.4) for the conductivity, as= 1 Il = = VA Il d V
Texas A&M - MEEN - 222
CHAPTER 19THERMAL PROPERTIESPROBLEM SOLUTIONS19.1 The energy, E, required to raise the temperature of a given mass of material, m, is the product of the specific heat, the mass of material, and the temperature change, T, asE = cpm(T)The T is
Texas A&M - MEEN - 222
CHAPTER 20MAGNETIC PROPERTIESPROBLEM SOLUTIONS20.1 (a) We may calculate the magnetic field strength generated by this coil using Equation (20.1) asNI lH ==(200 turns)(10 A) = 10,000 A - turns/m 0.2 m(b) In a vacuum, the flux density is
Texas A&M - MEEN - 222
CHAPTER 21OPTICAL PROPERTIESPROBLEM SOLUTIONS21.1 Similarities between photons and phonons are: 1) Both may be described as being wave-like in nature. 2) The energy for both is quantized. Differences between photons and phonons are: 1) Phonons
Texas A&M - MEEN - 222
CHAPTER 22ECONOMIC, ENVIRONMENTAL, AND SOCIETAL ISSUES IN MATERIALS SCIENCE AND ENGINEERINGPROBLEM SOLUTION22.D1W The three materials that are used for beverage containers are glass, aluminum, and the polymer polyethylene terephthalate (designa
Texas A&M - PHYS - 218
1.61: a) Estimate the volume as that of a sphere of diameter 10 cm: 4 3 V r 5.2 10 4 m 3 3 Mass is density times volume, and the density of water is 1000 kg m3 , so m 0.98 1000 kg m3 5.2 10 4 m3 0.5 kg b) Approximate as a sphere of radius r 0.25m (pr
Texas A&M - PHYS - 218
1.62: a)x3M M , so V V 0.200 kg 2.54 10 5 m 3 3 3 7.86 10 kg/m x 2.94 10 2 m 2.94 cmb)4 3 R 2.54 10 5 m 3 3 R 1.82 10 2 m 1.82 cm
Texas A&M - PHYS - 218
1.63: Assume each person sees the dentist twice a year for checkups, for 2 hours. Assume 2 more hours for restorative work. Assuming most dentists work less than 2000 hours per year, this gives 2000 hours 4 hours per patient 500 patients per dentist.
Texas A&M - PHYS - 218
1.64: a)(6.0 1024 kg)6.0 1023 atoms mole 3 kg 14 10 mole2.6 1050 atoms.b)The number of neutrons is the mass of the neutron star divided by the mass of a neutron:(2) (2.0 1030 kg) 2.4 1057 neutrons. 27 (1.7 10 kg neutron) c) The average ma
Texas A&M - PHYS - 218
1.65: Let D be the fourth force. A B C Ax Bx D 0, so D A B C A cos30.0 B cos30.0 50.00 N 69.28 N 31.90 NA cos30.0 B sin 30.0 86.6 N, Ay 40.00 N, B yCx C cos53.0 24.07 N, C y C sin 53.0 22 .53 N, Dy 87 .34 N Then D xD2 Dx 2 D
Texas A&M - PHYS - 218
1.66:Rx Ry RAx AyBx By R x2(170 km) sin 68 (170 km) cos 682 Ry(230 km) cos 48 (230 km) sin 482311.5 km 107.2 km 330 km311.5 km Ry Rx107.2 km 0.3442tan RR 19 south of east107.2 km 311.5 km
Texas A&M - PHYS - 218
1.67: a) b) Algebraically, A C B, and so the components of A areAx Ayc) ACx CyBx By26.40 cm cos 22.0 6.40 cm sin 22.08.10 cm26.40 cm cos 63.0 6.40 cm sin 63.08.10 cm 3.03 cm3.03 cm 8.10 cm.69 .53.03 cm8.65 cm, arctan
Texas A&M - PHYS - 218
1.68:a) RxAxBxCx12.0 m cos 90 Ry 15.7 m, and Ay By C y 12.0 m sin 90 5.3 m.3715.00 m cos 406.0 m cos 180603715.00 m sin406.0 m sin 18060The magnitude of the resultant is R2 Rx2 Ry16.6 m , and the direction from53 1
Texas A&M - PHYS - 218
1.69:Take the east direction to be the x - direction and the north direction to be the y - direction. The x- and y-components of the resultant displacement of the first three displacements are then180 m210 m sin 45280 m sin 30108 m,210
Texas A&M - PHYS - 218
1.71: a)b) The net east displacement is 2.80 km sin 45 7.40 km cos 30 3.30 km cos 22 1.37 km, and the net north displacement is 2.80 km cos 45 7.40 km sin 30 3.30 km sin 22.0 0.48 km, and so the distance traveled is1.37 km20.48 km21
Texas A&M - PHYS - 218
1.70:The third leg must have taken the sailor east a distance5.80 km 3.50 km cos 45 2.00 km 1.33 kmand a distance north3.5 km sin 45 The magnitude of the displacement is 2.47 km(1.33 km)2(2.47 km)22.81 km2 47 and the direction is arct
Texas A&M - PHYS - 218
1.72: The eastward displacement of Manhattan from Lincoln is147 km sin 85 106 km sin 167 and the northward displacement is 147 km cos 85 106 km cos 167 166 km sin 235 34 .3 km166 km cos 235 185 .7 km(A negative northward displacement is a
Texas A&M - PHYS - 218
1.73: a) Angle of first line is second line is 42tan1 200 20 210 1042 . Angle of3072. Therefore X 10 250 cos 72 87 Y 20 250 sin 72 258for a final point of (87,258). b) The computer screen now looks something like this:The length of the
Texas A&M - PHYS - 218
1.74: a)b)To use the method of components, let the east direction be the x-direction and the north direction be the y-direction. Then, the explorer's net xdisplacement is, in units of his step size,40 cos 45 80 cos 60 11 .7and the y-displace
Texas A&M - PHYS - 218
1.75: Let +x be east and +y be north. Let A be the displacement 285 km at 40.0 north of west and let B be the unknown displacement. A B B R Bx Ax Rx Rx R, where R 115 km, east A Ax , B y Ry 0 183.2 km. Ay A sin 40.0 183.2 km A cos 40.0 115
Texas A&M - PHYS - 218
1.76:(a) (b) (c)par perp par sin cos sin par sin 550 N sin 35.0 0 960 N
Texas A&M - PHYS - 218
1.77: B is the force the biceps exerts. E is the force the elbow exerts. E B R, whereR 132.5 N and is upward. Ex Bx Rx Rx 0, R y2 Ex 2 EyBx , E yRyBy B cos 43 169.7 NB sin 43158.2 N, B y 37.2 N132.5 N 158.2 N, E y 160 N;Then E x
Texas A&M - PHYS - 218
1.79: Let the displacement from your camp to the store be A.A 240 m, 32 south of east B is 32 south of westand C is 62 south of west Let x be east and y be north A B C 0 Ax Bx Cx 0, so A cos 32 B cos 48 C cos 62 0 Ay B y C y 0, so A sin
Texas A&M - PHYS - 218
1.78: (a) Take the beginning of the journey as the origin, with north being the ydirection, east the x-direction, and the z-axis vertical. The first displacement is then ^ ^ 30k , the second is 15 ^ , the third is 200 i (0.2 km 200 m) , and the fourt
Texas A&M - PHYS - 218
1.81: a) With Az Bz 0, Eq. (1.22) becomes Ax Bx Ay B y A cos A B cos BAB cos Acos B AB cos A AB cos BA sin A B sin B sin Asin Bwhere the expression for the cosine of the difference between two angles has been used (see Appendix B). b) W
Texas A&M - PHYS - 218
1.80: Take your tent's position as the origin. The displacement vector for Joe's tent is ^ ^ 21 cos 23 i 21 sin 23 ^ 19 .33 i 8.205 ^. The displacement vector for Karl's tent is j j ^ ^ 32 cos 37 i 32 sin 37 ^ 25 .56 i 19 .26 ^ . The difference b
Texas A&M - PHYS - 218
1.82:a)The angle between the vectors is 210 70 140 , and so Eq. (1.18) gives A B 3.60 m 2.40 m cos 140 6.62 m 2 Or, Eq. (1.21) gives A B Ax Bx Ay By3.60 m cos 70 2.4 m cos 210 6.62 m 2 3.6 m sin 70 2.4 m sin 210 b)From Eq. (1.22),
Texas A&M - PHYS - 218
1.83: a) Parallelogram area 2 area of triangle ABC Triangle area 1 2 base height 1 2 B A sin Parellogra m area BA sin b) 90
Texas A&M - PHYS - 218
1.84: With the +x-axis to the right, +y-axis toward the top of the page, and +z-axis out of the page, A B x 87.8 cm2 , A B y 68.9 cm2 , A B z 0.
Texas A&M - PHYS - 218
1.85: a)A B A B2.00 3.00Ax2 23.00 1.00^ Bx i2 24.00 3.00Ay2 25.39. 4.36.Az ^ Bz kb)By ^ j^ 5.00 i2.00 ^ j2^ 7.00 kc)5.0022.0027.008.83, and this will be the magnitude of B A as well.
Texas A&M - PHYS - 208
1.22: Assuming about 10 breaths per minutes, 24 60 minutes per day, 365 days per year, and a lifespan of fourscore (80) years, the total volume of air breathed in a lifetime is about 2 10 5 m 3 . This is the volume of a room 100 m 100 m 20 m , which
Texas A&M - PHYS - 208
1.21: Assuming the two-volume edition, there are approximately a thousand pages, and each page has between 500 and a thousand words (counting captions and the smaller print, such as the end-of-chapter exercise and problems), so an estimate for the nu
Texas A&M - PHYS - 218
2.54 cm in . 1 km 10 5 cm 1.61 km 1.1: 1 mi 5280 ft mi 12 in. ft Although rounded to three figures, this conversion is exact because the given conversion from inches to centimeters defines the inch.
Texas A&M - PHYS - 218
1.2:0.473 L1000 cm3 1L1in 2.54 cm328.9 in 3 .