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### exam1_sol

Course: ECE 438, Fall 2008
School: Purdue
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Purdue - ECE - 438
Purdue - ECE - 438
10 March 2000 EE 438 1.Name:_Exam No. 2 Spring 2000You have 50 minutes to work the following four problems. Be sure to show all your work to obtain full credit. The exam is closed book and closed notes. Calculators are permitted. (25 pts.) C
Purdue - ECE - 438
2 May 2000Name:_EE 438 1.Final ExamSpring 2000You have 120 minutes to work the following six problems. Each problem is worth 25 points. Be sure to show all your work to obtain full credit. The exam is closed book and closed notes. Calcu
Purdue - ECE - 438
Sample Questions for EE 438 Exam No. 2 - Spring 1997Problem 1. a. Derive a complete flow diagram for a 4 point FFT. Be sure to label all twiddle factors. b. The signal x(t) = cos[2 (6000)t] is sampled at a rate of 8 kHz, with the first sample at ti
Purdue - ECE - 438
May 5, 1997 EE 438 1.Name:_Final Exam Spring 1997You have 120 minutes to work the following 6 problems. Be sure to show all your work to obtain full credit. The exam is closed book and closed notes. However, you may bring with you 4 sheets o
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
12 April 2002 EE 438 1.Name:_Exam No. 3 Spring 2002You have 50 minutes to work the following four problems. Be sure to show all your work to obtain full credit. The exam is closed book and closed notes. Calculators are permitted. (30 pts.) a
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
Purdue - ECE - 438
University of Louisville - CIS - 480
E-mail Security1E-mail Security Secure e-mail techniques PGP S/MIME E-mail vulnerabilities Spam mail2Secure e-mail techniques Main features Confidentiality Integrity Authentication Non-repudiation Encryption Symmetric Asymmetric
University of Louisville - CIS - 480
Physical and Perimeter Security1Physical and Perimeter Security Physical controls Location, Locks, Surveillance Technical controls ID cards, Biometrics, Power supply, Fire suppression Perimeter security topologies Tunneling Virtual LAN2
University of Louisville - CIS - 480
Risk Management1Risk Management Risk controls Control categories Cost-benefit analysis Risk control methods2Risk Controls There are four main types: Avoidance Transference Mitigation Acceptance Strategy selection methods: Evaluati
Georgia Tech - MATH - 2605
Project 3 for Math 2605 You may use any language you like to do the programming. Java, C and MATLAB are good choices, but use whatever you like. Turn in source code with your results. You may discuss the project with others, but may not copy code or
UWO - DSMITH - 223
Assignment 11, due in class Monday, April. 9th 1. Let G be a graph on 6 vertices with an adjacency list: v1 : { v2 , v3 , v4 , v5 } v2 : { v1 , v3 } v3 : { v1 , v2 , v4 } v4 : { v1 , v3 , v5 } v5 : { v1 , v4 , v6 } v6 : { v5 } Compute PG (k). What is
UWO - DSMITH - 223
Assignment 10, due in class Monday, April. 2nd 1. Let G be a graph on 12 vertices with an adjacency list: v1 : { v2 , v3 , v4 , v5 , v9 } v2 : { v1 , v3 , v5 , v6 , v7 } v3 : { v1 , v2 , v7 , v8 , v9 } v4 : { v1 , v5 , v9 , v10 , v12 } v5 : { v1 , v2
UWO - DSMITH - 223
Assignment 9, due in class Monday, Mar. 26 1. Let G be a connected simple plane graph on n 4 vertices in which every face has degree 3. Suppose that G has no vertices of degree 3 or 4. Prove that G must have at least 12 vertices of degree at least 5
UWO - DSMITH - 223
Assignment 8, due in class Monday, Mar. 19th 1. Let G be a simple 4-regular planar graph. Prove that fG = 1 + G + G . Then prove that G has at least 4(1 + G ) faces of degree 3. Show all your work (15 marks).Solution: Let G be a simple 4-regular pla
UWO - DSMITH - 223
Mathematics 223b Second Midterm Exam March 10, 2007 Instructions: Print your name and your instructor's name on the SCANTRON answer sheet. Sign the SCANTRON answer sheet, and mark your student number and section on the SCANTRON answer sheet. Use a PE
UWO - DSMITH - 223
Assignment 6, due in class Monday, Feb. 19th 1. Let K10 be the complete graph on 10 vertices. Determine the number of Ki , i = 1, 2, . . . , 10 in K10 . Justify your count for full credit.Solution: Let Vj VK10 . Claim: The induced subgraph K10 [Vj
UWO - DSMITH - 223
Assignment 5 (due class time, Monday, February 12, 2007) 1. Determine whether or not the following two graphs are isomorphic. To prove that they are isomorphic, give a permutation of J8 and show that when is applied to an adjacency list for G1 , th
UWO - DSMITH - 223
UWO - DSMITH - 223
Mathematics for Computer ScientistsSolutions to Selected Exercises from Volume II: Number Theory, Modular Arithmetic and Graph TheoryTwelfth Edition, and 2004, 2005, 2006 Quizzes, Midterm Exams, and Final Exams with SolutionsS. A. Rankin &amp; I. J.
UWO - MATH - 208
The University of Western Ontario London Canada Department of Mathematics Mathematics 208a - MIDTERM TESTSolutions The test has two parts, A and B. You must do both parts. All questions have equal value, 10 marks. Work must be shown, and answers mus
U. Houston - ISAM - 5339
1Comprehensive Exercise Questions Assume that all 0 and all 1 subnets are NOT usable unless otherwise stated!1- UDP Means: (a) User Datagram Protocol (b) Useless Digital Procedures (c) Ultrafast Data Packing (d) Unclear Design Principle 2- Which on
U. Houston - FINC - 3331
ANSWERS TO END-OF-CHAPTER 16 QUESTIONS16-1The U.S. dollar. The primary reason for using the dollar was that it provided a relatively stable benchmark, and it was accepted universally for transactions. Under the fixed exchange rate system, the flu
U. Houston - PSYC - 6036
Experiments-DesignOverview Administrative Review from last week Experimental DesignAdministrative Introductions graded by next week As soon as your groups is graded, I will give it to the suite secretary for you to pick up and share with the
U. Houston - PSYC - 6036
U. Houston - PSYC - 6036
Graphing &amp; SummarizingOctober 30, 2008QuizOutline Administrative Help on Homework #4 Lecture on Summarizing DistributionsAdministrative Introductions due today HW #4 due November 13thHomework #4 Chapter 2Question #3Nonplayers 22.1
Old Dominion - CS - 330
2 0 Q u e s tio n s O bje ctsV e g e ta bleA n im a lM in e ra lC a rn iv o re sHe rbiv o re sO m n iv o re sR u m in a n tsHu m a n sC o ws
Old Dominion - CS - 330
A cco u n t1re g is t e r{ fo r a ll t ra n s a c t io n s T in t ra n , t .a c c o u n t = = c h e c kb o o k.re c o rd O f}re c o rd O f1 C h e ck bo o kt ra n s1account re c o rd e d In*Tra n s a ctio n s
Old Dominion - CS - 330
A cco u n tC h e ck bo o kTra n s a ctio n s
Old Dominion - CS - 330
Fig u re Edito r 1 1 1 W in do wd is p la y s d is p la y e d InPictu re 1 1 1 To o lba rcen ter1in s t a lle d0 .1 S tra te g yo p e ra t in g O n1 1 Me nu1*S h a pe 1 C re a tio n S tra te g ie s Editin g S tra te g ie sPo in t
Old Dominion - CS - 330
Fig u re Edito r 1 1 1 W in do wd is p la y s d is p la y e d InPictu re 1 1 1 To o lba r 11 1 Me nu*S h a pe
Old Dominion - CS - 330
A cco u n t1re g is t e r re c o rd O f1 C h e ck bo o kt ra n s re c o rd e d In1*Tra n s a ctio n s
Old Dominion - CS - 330
Tra n s a ctio nacco u n t: A cco u n t d ate: D ate amo u n t: M o n ey a p p ly (b a la n c e ) u n a p p ly (b a la n c e )
Old Dominion - CS - 330
Tra n s a ctio nacco u n t: A cco u n t d ate: D ate amo u n t: M o n ey a p p ly (b a la n c e ) u n a p p ly (b a la n c e )C h e ckW ith dra wlD e po s it
Duke - STA - 113
Solution for HW1STA113 ISDS September 5, 200413.a. A1 A2 = {awarded project 1 or 2} P (A1 A2 ) = P (A1 ) + P (A2 ) P (A1 A2 ) = 0.22 + 0.25 0.11 = 0.36b. A1 A2 ={awarded neither project 1 nor 2} P (A1 A2 ) = P (A1 A2 ) ) = 1 P (A1 A2
Duke - STA - 113
31/12/2003 1111.9230/12/2003 1109.6429/12/2003 1109.4826/12/2003 1095.8924/12/2003 1094.0423/12/2003 1096.0222/12/2003 1092.9419/12/2003 1088.6718/12/2003 1089.1817/12/2003 1076.4816/12/2003 1075.1315/12/2003 1068.0412/12/2003 1074.1411/
UC Riverside - CS - 120
Digilent Board Interconnect TableDigilent, Inc.D2SB to DIO4 Interconnect TablesDio4 Pinout Connector P1Pin 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 SignalD2SB Pinout Connec
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ChemE 3900 - Chemical Kinetics &amp; Reactor DesignChemical Engineers design and analyze processes and products based on chemical change. The chemical reactor is the essence of any chemical process. The chemical reaction is the essence of any chemical p
Cornell - WEB - 390
Cornell - WEB - 390
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design - Spring 2009 Solution to Homework Assignment 21. Devise a progression of steps that includes all the species needed for each reaction. Let M be CO2.CH 4 + CO 2 CH 3 + H + CO 2 CH 3 + OH + CO C
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solutions to Exercises for Calculation Session 21. As derived in lecture, the activation energy may be extracted from the slope of a straight line drawn through a plot of log10k vs. 1/T.slope = Ea 2.
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solutions to Exercises for Calculation Session 41. It is useful to sketch the time dependence of [B] on each plot. A mass balance on the reactor yields [B] = [A]0 [A] [C].[A] concentration[C][B
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solutions to Exercises for Calculation Session 61. The rate equation suggests an elementary step that is bi-molecular in A and is opposed by B.A + A X + Bk 1 k1The intermediate X (the unknown) the
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solutions to Exercises for Calculation Session 71. The mechanism involves two steps: adsorption/desorption of reactant A and the surface reaction of two adsorbed A molecules to form A2. Examine the tem
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solutions to Exercises for Calculation Session 81.(A) Calculate the number of red blood cells in an average person.5.6 L blood 5 10 6 cells 1000 mL = 2.8 1010 cells 1 mL blood 1LCalculate the li
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Templates for graphical analysis of CSTRs and PFRs 1st Order Reaction, k = 1/min, [A]0 = 1 mol/L108 reciprocal rate, 1/r (Lmin)/mol6420 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 fractional conv
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solution to 1st Preliminary Exam, Spring 20091. error 1. To extract a half life from the graph, one needs to subtract the initial time from the final time. For example, [A] = 2 mol/L at 2.75 min and [A
Cornell - WEB - 390
ChemE 3900 - Chemical Kinetics &amp; Reactor Design Solution to 2nd Preliminary Exam, Spring 20091. The first experiment is represented by a rectangle with one vertex at the origin and the opposite vertex at X = 0.4, y = the 1/rate line. For all four pl
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