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Course: MATH 21-260, Fall 2007School: Carnegie Mellon
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11.3 1.4:
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Carnegie Mellon - MATH - 21-260
1.6:1 m31000 L 1 m3 2111.9 bottles1 gal 128 oz. 3.788 L 1 gal 2112 bottles1 bottle . 16 oz.The daily consumption must then be 1 yr bottles 2.11 103 yr 365.24 da5.78bottles . da
Carnegie Mellon - MATH - 21-260
1.7:1450 mi hr 1.61 km mi 2330 km hr . 2330 km hr 10 3 m km 1 hr 3600 s 648 m s.
Carnegie Mellon - MATH - 21-260
1.8:180,000furlongs fortnight1 mile 8 furlongs1 fortnight 14 day1 day 24 h67mi . h
Syracuse - CEN - 231
CHAPTER TWO2.1 (a)= 18144 10 9 ms . 1 wk 1 d 1 h 1 s 38.1 ft / s 0.0006214 mi 3600 s (b) = 25.98 mi / h 26.0 mi / h 3.2808 ft 1 h 3 wk 7d 24 h 3600 s 1000 ms(c)554 m 4 1d 1h d kg 24 h 60 min1 kg 108 cm 4 = 3.85 10 4 cm 4 / min g 1000 g 1
Syracuse - CEN - 231
CHAPTER THREE3.1 (a) m =16 6 2 m3 1000 kg 2 10 5 2 103 2 105 kg 3 mbgb gb gd i4 106(b) m =8 oz 2s1 qt106 cm31g332 oz 1056.68 qt cmb3 10gd10 i3 1 102 g / s(c) Weight of a boxer 220 lb m 12 220 lb m 1 stone Wmax
Syracuse - CEN - 231
CHAPTER ELEVEN11.1 a. The peroxide mass fraction in the effluent liquid equals that in the tank contents, which is:xp =Mp MTherefore, the leakage rate of hydrogen peroxide is m1 M p / M b. Balance on mass: Accumulation = input outputEdM =
Syracuse - CEN - 231
CHAPTER FOUR4.1 a. b. Continuous, Transient Input Output = Accumulation No reactions Generation = 0, Consumption = 06.00c.dn kg kg dn kg - 3.00 = = 3.00 dt dt s s st=100 m3 1000 kg 1 s . = 333 s 1 m3 3.00 kg4.2a. b. c.Continuous, S
Syracuse - CEN - 231
CHAPTER FIVE5.1Assume volume additivity Av. density (Eq. 5.1-1):1=0.400 0.600 + = 0.719 kg L 0.703 kg L 0.730 kg LAAOa.Dmmass of tank at time tA= mt + m0 m =mass of empty tankAb250 - 150gkg = 14.28 kg min bm = mass f
Syracuse - CEN - 231
CHAPTER SIX6.1 a.AB: Heat liquid - -V constantBC: Evaporate liquid - -V increases, system remains at point on vapor - liquid equilibrium curve as long as some liquid is present. T = 100 o C.CD: Heat vapor - -T increases, V increases .b. Point
Syracuse - CEN - 231
CHAPTER SEVEN0.80 L 35 10 4 kJ 0.30 kJ work . 1h 1 kW = 2.33 kW 2.3 kW h L 1 kJ heat 3600 s 1 k J s7.12.33 kW 10 3 W 1.341 10 -3 hp 1 kW7.21W= 312 hp 3.1 hp .All kinetic energy dissipated by friction(a) E k =mu 2 2 5500 lbm 552 mil
Syracuse - CEN - 231
CHAPTER EIGHT8.1 a.U (T ) = 25.96T + 0.02134T 2 J / molU (0 o C) = 0 J / mol U (100 o C) = 2809 J / mol Tref = 0 o C (since U(0 o C) = 0)b. We can never know the true internal energy. U (100 o C) is just the change from U (0 o C) to c.U (100 o
Syracuse - CEN - 231
CHAPTER NINE9.14 NH 3 (g) + 5O 2 (g) 4NO(g) + 6H 2 O(g) H ro = -904.7 kJ / mola.When 4 g-moles of NH3(g) and 5 g-moles of O2(g) at 25C and 1 atm react to form 4 g-moles of NO(g) and 6 g-moles of water vapor at 25C and 1 atm, the change in enth
Syracuse - CEN - 231
CHAPTER TEN10.1 b. Assume no combustionn 1 (mol gas),T1 (C) x 1 (mol CH4 /mol) x 2 (mol C2 H6 /mol) 1 x 1 x 2 (mol C3 H8 /mol) n 2 (mol air), T2 (C) n 3 (mol), 200C y 1 (mol CH /mol) 4 y 2 (mol C2 H6 /mol) y 3 (mol C3 H8 /mol) 1 y 1 y 2 y 3 (m
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SOLUTION MANUAL ENGLISH UNIT PROBLEMS CHAPTER 3SONNTAG BORGNAKKE VAN WYLENFUNDAMENTALSofThermodynamicsSixth EditionSonntag, Borgnakke and van WylenCONTENT CHAPTER 3SUBSECTION Correspondence table Study guide problems Phase diagrams, tr
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CHAPTER 4 SI UNIT PROBLEMS SOLUTION MANUALSONNTAG BORGNAKKE VAN WYLENFUNDAMENTALSofThermodynamicsSixth EditionSonntag, Borgnakke and van WylenCONTENTSUBSECTION Correspondence table Concept problems Force displacement work Boundary work:
University of Florida - EML - eml3007
SOLUTION MANUAL SI UNIT PROBLEMS CHAPTER 5SONNTAG BORGNAKKE VAN WYLENFUNDAMENTALSofThermodynamicsSixth EditionSonntag, Borgnakke and van WylenCONTENTSUBSECTION Correspondence table Concept-Study Guide Problems Kinetic and potential ene
University of Florida - EML - eml3007
SOLUTION MANUAL SI UNIT PROBLEMS CHAPTER 6SONNTAG BORGNAKKE VAN WYLENFUNDAMENTALSofThermodynamicsSixth EditionSonntag, Borgnakke and van WylenCONTENTSUBSECTION Correspondence table Concept-Study guide problems Continuity equation and f
Iowa State - MGMT - 370
Top Managers- Make up a small group of executives who manage the overall organization. President Vice President CEO Middle Management- Largest group of managers in an organization. Plant Manager Operations Manager Division head. Responsible primarily
Iowa State - MGMT - 370
CHAPTER 1 MANAGING AND THE MANAGER'S JOBLearning Objectives First Things First An Introduction To Management The Management ProcessPlanning and Decision Making: Determining Courses of Action Organizing: Coordinating Activities and Resources Leadin
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STAT 226Homework 1Due Tuesday, February 5th in ClassSHOW ALL YOUR WORK FOR FULL CREDIT! PRINT AND TURN IN JMP OUTPUT AS INDICATED!Carefully read the Homework Guidelines that can be found on the course web page for all Stat 226 sections (see a
Iowa State - STAT - 226
STAT 226Homework 2Due Thursday, February 14th in ClassSHOW ALL YOUR WORK FOR FULL CREDIT! PRINT AND TURN IN JMP OUTPUT AS INDICATED!For general homework rules, read the Homework Guidelines that can be found on the course web page for all Stat
Michigan State University - FIN - 853
Chapter 4 4-2 (a) PVBP PVBP=-MD*P*0.0001 Bond A: -1.8149*0.0001*100=-0.0181 Bond B: -3.9944*0.0001*104.055=-0.0416 (b) Macaulay duration Using Excel functions (DURAION, MDURATION) DA=1. 1.887546 (=DURATION("2006/10/02","2008/10/02",0.08,0.08,2,1) DB=
Michigan State University - FIN - 853
Chapter 2 2-2 Cash flow after would be $13,661,977(10.4*1.0625). Thus they would not have sufficient funds from this investment to meet the $14million obligation. 2-3 (a)First 4 years: $500,000*1.057^4=$624,122 Reinvestment: $624,122*1.072^3=$768,872
Michigan State University - FIN - 853
Q1. * Dates that the Fed changed interest rate. Date Fed Fund Rate 2001/01/03 6.00% 2001/01/31 5.50% 2001/03/20 5.00% 2001/04/18 4.50% 2001/05/15 4.00% 2001/06/27 3.75% 2001/08/21 3.50% 2001/09/17 3.00% 2001/10/02 2.50% 2001/11/06 2.00% 2001/12/11 1.
Michigan State University - FIN - 853
FI853 Debt, Money Instruments & MarketsAssignment #5 (Nov. 28th 2006)Cho, Gyu HoFIN853: Fall 2006 Assignment #5 Chapter 10-21 F0 [r(1+r)n]/[(1+r)n1] To solve this problem, we can use a calculator: N 360 I/Y 0.6667( 8%/12) PV 150000 FV 0 CPT PM
Michigan State University - FIN - 853
FI853 Debt, Money Instruments & MarketsAssignment #4 (Nov. 21th 2006)Cho, Gyu Ho1-1. (BDY*100)=100-(0.04100) = 96 1-2. 10,000*[100*(1-BDY*n/360)]=10,000*[100*(1-0.04*90/360)]=990,000 1-3. -The worth of long position=10,000*[100*(1-0.042*90/360)
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Texas A&M - ENGL - 301
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USC - BUAD - 306
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Iowa State - EM - 378
Iowa State - EM - 378
N. Central IL - ACC - 202
Exercise 8-8a.b. c. d. e. f.Activity Materials are moved from the receiving dock to the assembly area by a material-handling crew Direct labor workers assemble various products Diversity training is provided to all employees in the company A pr
N. Central IL - ACC - 202
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Iowa State - EM - 378
2.1172.47 An open tank containing water has a bulge in its vertiea! side that is semicin:ula! in shape as shown in rig. 1"2.47. Determine the horizontal and vcrlical components of the force that the water eKerts on the bulge. BIIsc your analysis on
N. Central IL - ACC - 202
Exercise 8-1 a. Various individuals manage the parts inventories. b. A clerk in the factory issues purchase orders for a job. c. The personnel department trains new production workers. d. The factory's general manager meets with other department head
N. Central IL - ACC - 202
Exercise 8-18 (continued) 3. Computation of the overhead costs for the Indus Telecom order:Activity Cost Pool Direct labor support . $15.50 per DLH Order processing . $305 per order Customer support $1,275 per customer Total ..*0.5 DLH per unit 1
N. Central IL - ACC - 202
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N. Central IL - ACC - 202
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N. Central IL - ACC - 202
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N. Central IL - ACC - 202
Exercise 5-3 1. High activity level (August) . Low activity level (October) . Change .MonthOccupancyDays3,608 186 3,422Electrical Costs$8,111 1,712 $6,399Variable cost = Change in cost Change in activity = $6,399 3,422 occupancy-days = $1
N. Central IL - ACC - 202
Page 1 of 8Chapter 3Systems Design: Job-Order CostingExercise 3-5 Actual direct labor-hours. 12,600 Predetermined overhead rate . $23.10 = Manufacturing overhead applied . $291,060 Exercise 3-6 1. Actual manufacturing overhead costs . Manufactu
N. Central IL - ACC - 202
Exercise 6-5 1. The equation method yields the break-even point in unit sales, Q, as follows: Sales = $8Q = $2Q = Q= Q= Variable expenses + Fixed expenses + Profits $6Q + $5,500 + $0 $5,500 $5,500 $2 per basket 2,750 baskets2. The equation method
Iowa State - EM - 378
Iowa State - EM - 378
Northeastern - MIS - 301
RJ Puntoni Professor Zack Assignment for Class 11 #1.#2. -The company needs supplies o They pay the supplier The supplier ships it to the warehouse The warehouse distributes it to the stores The stores sell it to customers The customers buy it Th
Northeastern - MIS - 301
RJ Puntoni, Chris Waslin, Michael Rooney Marketing Professor Lerra Vitango Case Study Which of the textbook's criticisms of marketing's impact on consumers, if any, are found in the cases of Vitango and Nutristar? Although it may appear that both Coc