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2 Pages

### quiz6Soln

Course: JDD 5747, Fall 2009
School: RIT
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Word Count: 219

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05 Quiz 1016-273-02, 6 Name:______Solutions________ To receive full credit, you must show ALL work for each problem. This quiz is worth 30 points and covers material from Sections 7.3 and 7.4. There are two problems on the back page. 2 sec 3 ( ) = 27 u - 1 du = 27 - sec( ) + C = 9 sec 3 ( ) - 27 sec( ) + C 3 2 =9 - 27 Using x = 3 tan ( ) for original substitution Using x = 2 sin ( ) for original...

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05 Quiz 1016-273-02, 6 Name:______Solutions________ To receive full credit, you must show ALL work for each problem. This quiz is worth 30 points and covers material from Sections 7.3 and 7.4. There are two problems on the back page. 2 sec 3 ( ) = 27 u - 1 du = 27 - sec( ) + C = 9 sec 3 ( ) - 27 sec( ) + C 3 2 =9 - 27 Using x = 3 tan ( ) for original substitution Using x = 2 sin ( ) for original substitution =2 + 2 sin ( ) cos( ) x x 4 - x2 + C = 2 + 2 sin ( ) cos( ) + C = 2 arcsin + +C 2 2 2 2. ( 4 - x )dx = 4 (cos ( ))d = 2 (1 + cos(2 ))d = 2 + sin (22 ) 2 2 9 + x2 3 3 9 + x2 1 +C = 3 3 ( ) 1. 9+ x x3 dx = 27 sec( ) tan 3 ( ) d = 27 sec 2 ( ) 1 - (sec( ) tan ( )d ) ( ) ( ) ( 9+ x ) -9 2 3 9 + x2 + C +C 3. x2 R ( x) = S ( x) + Hint: First use long division so that where deg(R ( x) ) < deg( x - 3) . x -3 x-3 x2 x2 = + x -3 x = x +3+ 3x - (3)( x - 3) 9 9 = x +3+ = ( x + 3) + x-3 x-3 x-3 4. 2 1 3 = ln x + 2 + ln x + 6 + C 4 4 x+3 A A = 1 + 2 x + 8 x + 12 x + 2 x + 6 2 x = 2: 1 = 4 A1 + 0 - 3 = 0 - 4 A2 x = 6: x+3 dx = x + 8 x + 12 A1 A + 2 dx = ...

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RIT - JDD - 5747
.maxe siht etelpmoc ot setunim 09 evah uoY .V .dewolla ton era seton dna srotaluclaC .VI .tsrif smelborp 'ysae` eht hsinif ot tseb si tI .detimil si emit sa melborp txen eht ot no evom ,melborp a no kcuts teg uoy fI .III .stniop 01 htrow era 31 hguor
RIT - JDD - 5747
HW #1 Due 3/17 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 3.1: Section 3.2: 1,
RIT - JDD - 5747
HW #2 Due 3/24 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 7.1: Section 3.3: 2,
RIT - JDD - 5747
HW #3 Due 3/31 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 3.4: 2, 6, 11, 12, 1
RIT - JDD - 5747
HW #4 Due 4/9 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 11.2: 2, 3, 7, 8, 12,
RIT - JDD - 5747
HW #5 Due 4/16 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 11.5: 1, 3, 6, 8, 9,
RIT - JDD - 5747
HW #6 Due 4/23 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 8.2: Section 8.3: Se
RIT - JDD - 5747
HW #7 Due 4/30 Name: _Discrete Math for Tech II - 206LDC/Math Lab/Math Study Center Help OKPlease show ALL work. Correct answers without any supporting work may not be given full points unless the answer is obvious. Section 8.4: Section 8.5: Se
RIT - JDD - 5747
HW #3 Section 3.4: 2. The relation is not an equivalence relations (fails to be transitive as 1R3, 3R4, not 1R4) 4.1016 20602The relation is an equivalence relation. There are three distinct classes: [1] = [3] = [5] = {1, 3, 5} [2] = {2} [4] = {4
RIT - JDD - 5747
HW #4 Section 11.2: 2. ( x1 x2 ) x1 = ( x1 x2 ) x11016 20602since( x1 x2 ) x1 = ( x1 x1 ) ( x2 x1 ) = x1 ( x2 x1 )1 2 1 3 1 2 33.( x x ) ( x x ) = x ( x x ) since (x x )(x x ) = (x x ) (x x ) = x (x1 2 1 3 1 2 1 31
RIT - JDD - 5747
HW #51016 20602Section 11.5: 1. Since OR and NOT is in the gate set, we must show that AND can be implemented using only OR and NOT gates. Here is one implementation: 3.x y = x y With just a single gate type, the only circuits we can form are: x
RIT - JDD - 5747
HW #61016 20602Section 8.2: 3. Non-simple path, not a cycle, not a simple cycle 5. Non-simple path, cycle, not a simple cycle 11. Impossible (sum of vertex degrees equals twice number of edges and so sum of vertex degrees must be even) 15. There
RIT - JDD - 5747
.setunim 05 ni smelborp eht fo lla hsinif lliw uoy taht ylekilnu si tI .smelborp 6 tsael ta hsinif ot yrT .V .tsrif smelborp 'ysae` eht hsinif ot tseb si tI .detimil si emit sa melborp txen eht ot no evom ,melborp a no kcuts teg uoy fI .VI .niaga rev
RIT - JDD - 5747
.maxe siht etelpmoc ot setunim 06 evah uoY .V .dewolla ton era seton dna srotaluclaC .VI .tsrif smelborp 'ysae` eht hsinif ot tseb si tI .detimil si emit sa melborp txen eht ot no evom ,melborp a no kcuts teg uoy fI .III .stniop 02 htrow era 11 hguor
RIT - JDD - 5747
.maxe siht etelpmoc ot setunim 06 evah uoY .V .seton nettirwdnah esu yam uoy tub dewolla ton era srotaluclaC .VI .tsrif smelborp 'ysae` eht hsinif ot tseb si tI .detimil si emit sa melborp txen eht ot no evom ,melborp a no kcuts teg uoy fI .III .stni
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Wisconsin - CS - 736
Message passing vs. shared memory Semaphore vs. monitorLinux/POSIX: lock, unlock, cond_. Java: monitor, only one conditional variable Recent: futex, RCU Previously, lock/unlock always go through OS system calls, where OS does several things: 1. Put
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Date: Mon, 10 Feb 2003 16:16:20 -0600 (CST) From: Mark Jacobson &lt;jacobson@math-cs.cns.uni.edu&gt; To: 810-151-01@uni.eduSubject: Back and Forward buttons on browser application.Hi Visual Basic students, One student asked me last week
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Date: Sat, 10 Dec 2005 21:48:07 -0600 (CST) From: Mark Jacobson &lt;jacobson@math-cs.cns.uni.edu&gt; To: 810-030-01@uni.eduSubject: RecordSource property at Design time.Hi Visual Basic students,It is best for avoiding possible problems to s