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### Fem1D_fixed

Course: MEEN 4354, Fall 2008
School: TAMU Kingsville
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FEM1D PROGRAM &lt;&lt; BAR ANALYSIS EXAMPLE 3.6, corrected temp NN NE NM NDIM 5 2 2 1 ND NL NCH 2 1 2 NODE# X-COORD 1 0 2 0 3 -4500 4 -3000 5 0 EL# N1 N2 MAT# 1 1 3 1 2 2 4 2 DOF# DISP 3 0 4 0 DOF# LOAD 5 MAT# 30000 E Alpha 1 200000 1.20E-05 2 70000 2.30E-05 B1 I B2 J 1 1 -0.33 5 1 2 -0.83 5 Solve the Problem NEN 2 NDN Delete Results Sheet AREA 1200 900 TEMP RISE 0 0 B3 0 0 he Problem Results Sheet

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FEM1D PROGRAM << BAR ANALYSIS EXAMPLE 3.6, corrected temp NN NE NM NDIM 5 2 2 1 ND NL NCH 2 1 2 NODE# X-COORD 1 0 2 0 3 -4500 4 -3000 5 0 EL# N1 N2 MAT# 1 1 3 1 2 2 4 2 DOF# DISP 3 0 4 0 DOF# LOAD 5 MAT# 30000 E Alpha 1 200000 1.20E-05 2 70000 2.30E-05 B1 I B2 J 1 1 -0.33 5 1 2 -0.83 5 Solve the Problem NEN 2 NDN Delete Results Sheet AREA 1200 900 TEMP RISE 0 0 B3 0 0 he Problem Results Sheet
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TAMU Kingsville - MEEN - 4354
&lt; BEAM ANALYSIS &gt; EXAMPLE 8.1 NN NE NM 3 2 1 ND NL NMPC 4 4 0 NODE# X-COORD 1 0 2 1000 3 2000 EL# N1 N2 1 1 2 2 2 3 DOF# Displ. 1 0 2 0 3 0 5 0 DOF# LOAD 3 -6000 4 -1.00E+06 5 -6000 6 1.00E+06 MAT# E 1 200000 B1 I B2 JSolve the ProblemNDIM 1NEN
TAMU Kingsville - MEEN - 4354
&lt;2-D FRAME ANALYSIS &gt; EXAMPLE 8.2 NN NE NM 4 3 1 ND NL NMPC 6 1 0 Node# X Y 1 0 96 2 144 96 3 0 0 4 144 0 Elem# N1 N2 1 2 1 2 3 1 3 4 2 DOF# Displ. 7 0 8 0 9 0 10 0 11 0 12 0 DOF# Load 1 3000 MAT# E 1 3.00E+07 B1 i B2Solve the Problem NDIM 2 NEN 2
TAMU Kingsville - MEEN - 4354
Problem 11.4h := 0.025 Ae := h bb := 0.075rho := 78503Ae = 1.875 10Le := .8i :=bh 123i = 9.766 108Ee := 200 109 12 Ee i 6 Le K1 := 3 Le 12 6 Le 6 Le 4 Le2126 Le 6 Le 22 6 Le 2 Le 6 Le 2 Le2
TAMU Kingsville - MEEN - 4354
Fall 2004 MEEN 4354 Final Project group sign-up sheet Group 1 2 3 4 5 6 7 8 Student 1 HERZIG, ANDREW MENDOZA, VICTOR RUST, CHRISTOPHER LACKEY, STEPHEN ESPINOSA, EDUARDO YBARRA, NICHOLAS LONGORIA, CHRISTEN NIX, KENNETH Student 2 WRANOSKY, JOHN URIBE,
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TAMU Kingsville - MEEN - 4354
x -2 -1.5 -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3 3.1 3.2 3.3 3.4 3.5 3.6 3.7f(x) 14 5.5 -1 -2.06 -3.04 -3.94 -4.76 -5.5 -6.
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Equilibrium of stress and internal forces
TAMU Kingsville - MEEN - 5314
MachineDesign.com: A closer look at Model MeshingA closer look at Model MeshingWatch out You can get different results depending on how you mesh the model.Paul M. Kurowski Design Generator Inc. London, Ontario, Canada pkurowski@rogers.com There
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Results from Program FEM1D Test - problem 7 Node# Displacement 1 0 2 0 3 0 Element# Stress 1 25 2 5 Node# Reaction 1 -25PROGRAM FEM1D &lt; BAR ANALYSIS Test - problem 7 NN NE NM NDIM 3 2 1 1 ND NL NCH 1 2 0 NODE# X-COORD 1 0 2 10 3 20 EL# N1 N2 MAT# 1
TAMU Kingsville - MEEN - 5314
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TAMU Kingsville - MEEN - 5314
x-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 -1 21 18.84 17.16 15.96 15.24 15 15.24 15.96 17.16 18.84 21 -0.8 16.68 14.52 12.84 11.64 10.92 10.68 10.92 11.64 12.84 14.52 16.68ex=3+12*x^2+6*y^2 ey=x gamxy=12*x*y+y-14*xx - horizontal, y - vertical
TAMU Kingsville - MEEN - 4354
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