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### HW3

Course: CIE 337, Fall 2008
School: Syracuse
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Word Count: 258

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5.1 Problem Given: Standard and modified Proetor Compaction Curves Required: (a) Maximum dry density and optimum water content. (b) The placement water content range for 90% relative compaction for the modified proctor Curve and 95% for the standard Proefor Curve. (c) Maximum placement water content for the minimum compaction in part (b) Solution: 3 (a) standard proctor curve: d max = 1.73mg / m , wopt = 16% 3...

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5.1 Problem Given: Standard and modified Proetor Compaction Curves Required: (a) Maximum dry density and optimum water content. (b) The placement water content range for 90% relative compaction for the modified proctor Curve and 95% for the standard Proefor Curve. (c) Maximum placement water content for the minimum compaction in part (b) Solution: 3 (a) standard proctor curve: d max = 1.73mg / m , wopt = 16% 3 modified proctor curve: d max = 1.86mg / m , wopt = 12% (b) standard: 11.2%~20.5% modified: 6%~20% Problem 5.3 Given: w = 14%, = 1.89mg / m 3 Required: relative compaction Solution: (a) Standard Proctor 1.89 = = 1.66 1 + w 1 + 0.14 d max = 1.73mg / m 3 1.66 R.C = d = max 1.73 d = (b) Modified d max = 1.86mg / m 3 1.66 R.C = 1.86 Problem 5.11: Given: Fines=30% by weight; Coarse= 70% by weight PL=20; LL=40 = 2%; mix = 15%; dmix = 130 pcf ; Required: fines ; LI Solution: Assume: M mix = 100 g Therefore, M fine = 30 g ; M coarse 70 = g ; mass of water is 15 g. After compaction, coarse is fully saturated, and = 2% , So mass of water of coarse M ,coarse = 70 2% = 1.4 g Therefore, M , fine = 15 1.4 = 13.6 g Water content for fines is: fine = M w, fines M s , fines = 13.6 100% = 45.3% 30 Liquid limit LI = fine PL LL PL = 45.3 20 = 1.265 40 20 Problem 5.13: Given: Soil type (SP) Required: Suitability as a pavement subgrade. Solution: Item use 1. Applicability 2. frost Potential 3. Engineering Properties 4. Appropriate Compaction Equipment Pavement Subgrade Fair to good None to slight Almost none Compressibility, good strength CBR=10~40 Crawler-type tractor Rubber-tired rpller Problem 5.14: Required: What kind of soils would make the best foundation material for a structure? Solution: If seepage is important, GM and GC would be the first and second choice, respectively. If seepage is not important, GW and SW be the first and second choice, respectively.
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Syracuse - CIE - 337
Syracuse - CIE - 337
Syracuse - CIE - 337
Syracuse - CIE - 337
CIE 337 (All Class, 45 Students)Student Name Andreassen, Richard James Blake II, James Stansbury Brosnihan, Deirdre Wynne Cardillo, Greig Edward Conden, Robert Allen Cusick, Brendan P Daggett, James Donald Degracia, Matthew A Degueldre, Lindsay R D
Syracuse - CIE - 337
CIE337 Homework GradesSU ID 508865480 419158889 949237851 422912223 825665192 238554677 261500057 102522963 303007260 857139754 659567892 106134909 886093677 671250464 106136692 244079589 429328167 876430555 886223723 933048114 465503996 743083999 4
Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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Syracuse - CIE - 337
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