Ch10
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Ch10

Course Number: BIOE 109, Spring 2009

College/University: UCSC

Word Count: 12783

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CHAPTER 10 THE SHAPES OF MOLECULES 10.1 To be the central atom in a compound, the atom must be able to simultaneously bond to at least two other atoms. He, F, and H cannot serve as central atoms in a Lewis structure. Helium is a noble gas, and as such, it does not need to bond to any other atoms. Hydrogen (1s1) and fluorine (1s22s22p5) only need one electron to complete their valence shells. Thus, they can only...

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10-1 CHAPTER 10 THE SHAPES OF MOLECULES 10.1 To be the central atom in a compound, the atom must be able to simultaneously bond to at least two other atoms. He, F, and H cannot serve as central atoms in a Lewis structure. Helium is a noble gas, and as such, it does not need to bond to any other atoms. Hydrogen (1 s 1 ) and fluorine (1 s 2 2 s 2 2 p 5 ) only need one electron to complete their valence shells. Thus, they can only bond to one other atom, and it does not have d orbitals available to expand its valence shell. 10.2 Plan: Draw a Lewis structure and then see if additional structures may be drawn. Solution: Resonance must be present any time that a single Lewis structure is inadequate in explaining one or more aspects of a molecule or ion. The two N-O bonds in NO 2 are equivalent; no single Lewis structure shows this. The following Lewis structures may be drawn for NO 2 : O N O O N O O N O O N O The average of all of these structures gives equivalent N-O bonds with a bond length that is between N-O and

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