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Workshop 17 Solutions

Course: CHEM 2301, Summer 2008
School: Minnesota
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2301 Chemistry Workshop 17 Solutions: More Multistep Organic Synthesis Friday, March 27 Cl A challenge in both of these problems is to use the few reactions you know to make what you want. (You might imagine this issue could be resolved for professional chemists by knowing lots of reactions, but in the end, even they get stuckthere are never enough reactions to make everything.) Here, the only thing you know to...

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2301 Chemistry Workshop 17 Solutions: More Multistep Organic Synthesis Friday, March 27 Cl A challenge in both of these problems is to use the few reactions you know to make what you want. (You might imagine this issue could be resolved for professional chemists by knowing lots of reactions, but in the end, even they get stuckthere are never enough reactions to make everything.) Here, the only thing you know to do with a hydrocarbon is to halogenate it, and you only know how to do mono-halogenation and multi-halogenation, always at the more substituted/more stabilized position. Here, that is at the benzylic carbon. Di-halogenation here generates something that can be eliminated to yield the product. Cl excess Cl KOtBu Cl Cl2 h CN This problem is a bit harder, because chemistry clearly has to happena CN has to be addedat a position thats not the most substituted. So, although we have to start with halogenation again (we dont know anything else to do with propane), its clear were going to have to do some trickery to translate halogenation at the most substituted position to substitution at the least substituted position. One thing we cant do is just say Ill halogenate to get the material I want: Cl2 Cl Cl h Yes, if you were to expose propane to chlorine gas for a while, you would get this but molecule, youd get hundreds of other molecules too. (Monochlorinated, other dichlorinated, with chlorines all over the place.) A central goal of these synthesis problems is to propose ways of making the products selectively. An obvious way to approach these problems is to go forward from starting materials after all, thats what a chemist would physically do in the labbut another way to think about synthesis is backwards from the end. Given a product, from what materials might we start? Our product has two functional parts to it, an alkene and a cyano (CN) group. How might we get to those functional groups? The CN could be introduced via SN2 by cyanide (CN-), or the alkene could be made by elimination: Br CN N C KOt Bu (for E2) N Br C and not C Br Br N or N C The bottom, elimin...

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Minnesota - CHEM - 2301
Chemistry 2301 Workshop 18 Solutions Diastereoselectivity in Organic SynthesesFriday, March 27H 3C H3C XH3CORCH3 CH 2 OHCH3 CH 2 OH XCH 3 O X CH 3KMnO4, H2O/-OHmCPBA, H2OH3CCH 3 O XX H3C OH H 3C CH3 CH2 OH H 3C OH H3 C CH3 CH 2
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 19 Solutions Diverted Alkene Addition MechanismsFriday, March 27Br Br 2H (+ enantiomer) H 3C BrBrBr H Br OR H H3 C CH3 BrBr (also draw as H Br + + ; comes in f rom behind C-Br bond (SN2) H H3 C partial charge bette
Minnesota - CHEM - 2301
Chemistry 2301 In-Class Exercise: Alkynes in SynthesisWednesday, April 1Alkynes are useful building blocks for organic chemists because different molecular parts can be attached to them by nucleophilic addition reactions. The synthesis below illu
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 20 Interfering Functional GroupsFriday, April 3Complex organic molecules frequently have multiple functional groups, and it is sometimes challenging to design organic syntheses such that transformations of one functional g
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 21 Retrosynthetic AnalysisFriday, April 3Sometimes it is easier to think about organic synthesis in reverse, by disconnecting a complex molecule into simple parts that you know how to reconnect synthetically. Organic chemi
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 20 Solutions Interfering Functional GroupsFriday, April 3KMnO 4 H3C H 2O/- OH H3CHOOHKMnO4 will react with the alkyne too. Its not clear how far the alkyne will be oxidized; milder conditions than these (pH 7) would
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 21 Solutions Retrosynthetic AnalysisFriday, April 3There are many correct answers to each of these problems, only a few of which are shown below.can make from alkyne, or by ozonolysisO O H CH31. Sia2BH 2. H2O2/-OH (a
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 22 Alcohols from Alkylmetal ReagentsFriday, April 10Show how each of the alcohols one the right could be synthesized from at least one alkyl halide and a carbonyl-containing molecule as starting materials. A challenge: Mak
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 22 Solutions Alcohols from Alkylmetal ReagentsFriday, April 10Unless Ive indicated specifically that only one alkylmetal reagent is possible, either alkyllithiums or Grignard reagents can be used. (They are interchangeable
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 23 Diagnostic Tests Based on Oxidation and ReductionFriday, April 17Biomedical diagnostic testsused to detect the levels of specific molecules in bodily fluids such as blood or urineare frequently based on detecting the sp
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 24 Mechanisms with Nucleophilic Attack on CarbonylsFriday, April 17Write mechanisms for the following transformations involving carbonyl groups.OMgBrOMgBr+O O(excess)O O1. LiAlH4 2. H3O+OHOH
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 23 Solutions Diagnostic Tests Based on Oxidation and ReductionFriday, April 17H OH H O HO HO H H OH OH Hglucose oxidaseH OH H O HO HO H H OHREDUCTIONorOXIDATIONOor(-H2)NEITHERglucosegluconolactoneAs yo
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 24 Solutions Mechanisms with Nucleophilic Attack on CarbonylsFriday, April 17OMgBrOMgBr+O OOMgBr OO MgBr O OOO OMgBrO OMgBrBrMg OOMgBrOBrMgOMgBrO O1. LiAlH4 2. H3O+OHOHH H Al
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 25 Functional Group Interconversion with TosylatesFriday, April 24Although the syntheses below look simpleeach just involves changing a functional group into a new onethey all require multiple steps, and tosylation is a us
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 26 Equivalent and Inequivalent NucleiFriday, April 24For each of the molecules below, Label each inequivalent set of protons with a lower-case letter (a, b); In the box, write the number of resonances you would expect to
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 25 Solutions Functional Group Interconversion with TosylatesFriday, April 24OIONaBH4, EtOHOHTsCl, pyridineOTsNaIICH3 CH 3CH2H OHCH 3CH 2HCH 3 CH 2CH 2CH3backside attack, inversionCH 3 C CCH3 C
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 26 Solutions Equivalent and Inequivalent NucleiFriday, April 24number of resonancesH ClaHHCHa Ha Hbnumber of resonancesbHb Cl2b4H H H H a a a aH c HdH cH ClbHb Br3bHaHCHa Ha HbHa
Minnesota - CHEM - 2301
Chemistry 2301 In-Class Exercise: IR Spectroscopy and MS Fragmentation PatternsFriday, May 1Cladosporium resinae, sometimes called fuel fungus, colonizes aircraft fuel lines in wet climates. To use aircraft fuel as food, the fungus must first oxi
Minnesota - CHEM - 2301
Chemistry 2301 In-Class Exercise Solutions: IR Spectroscopy and MS Fragmentation PatternsFriday, May 1a. IR spectra are typically interpreted by looking at characteristic resonances in the 1600-3600 cm-1 range of the spectrum; the region lower th
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 27 Complex Splitting Patterns in NMRFriday, May 1This Workshop deals with the NMR spectrum of vinyl acetate, shown below. The lower two spectra are close-ups from the upper spectrum.O H H O CH 3 H31 1187651
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 28 Structure Determination with NMRFriday, May 1Morgan, a chemist, had planned to use 1,2-dibromo-1-ethoxyethane (drawn below) as a starting material in a substitution reaction. However, he found that even weak Lewis bases
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 27 Solutions Complex Splitting Patterns in NMRFriday, May 1When we covered complex splitting patterns in lecture, I showed the simplest complex splitting pattern (if you will), the doublet of doublets; I also showed that t
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 28 Solutions Structure Determination with NMRFriday, May 1The problem tells us that the decomposition reaction is an elimination reaction, in which one of the two Br atoms acts as a leaving group. It's not clear from the p
Minnesota - CHEM - 2301
Exact Masses and Molecular Formulae12Cmass set to 12 amu, exactly.As a result, 1H mass is actually higher than 1 amu. amu And 16O mass is lower than 16 l th amu. Isotopes vary from unit masses by mass defect. I t f it b d f t1Hhas positive m
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 29 Using IR, MS and NMR Data for Structure ElucidationFriday, May 8Fragrance chemists frequently use spectroscopic tools to try to determine what molecules are responsible for a particular natural scentso that, say, the sm
Minnesota - CHEM - 2301
Chemistry 2301 Workshop 29 Solutions Using IR, MS and NMR Data for Structure Elucidation a.Elemental Composition Calculator v1.0 Calculations for : monoisotopic mass atom C H N O S P mass 12.0000 1.0078 14.0030 15.9949 31.9720 30.9737 min 0 0 0 0 0
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, February 16, 2009 Exam 1When the exam begins, write your name at the top of each page. You may use pen or pencil. However, re-grades will be considered only for exams completed in pen.
Minnesota - CHEM - 2301
Chemistry 2301 Exam 1 Answer Key Exam 1 Mean: Exam 1 Median: Exam 1 St. Dev.: 77 80 14Monday, February 16, 2009FrequencyExam Grade11. (9 pts) Draw Lewis dot structures for each of the molecules below. Draw all valence electrons as dots. If
Binghamton - CS - 220
1: d)2: c)3: c)4: d)
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CS 220: Computer Systems II: Architecture and ProgrammingSpring 2009 - Section A0Quiz #7 - 2009/04/27 Name: _=1:Circle which one (1) of the following is the term for the processor feature which allows a system to appear to be able to us
Minnesota - CHEM - 2301
NAME _UM Internet ID_ORGANIC CHEMISTRY I (2301-001) 9:05 9:55 am, February 18, 2008 Exam 1When the exam begins, write your name at the top of the first two pages. You may use pen or pencil. However, re-grades will be considered only for exams
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1: b)2: c), d)3: b)4: g), h)
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, October 1, 2007 Exam 1When the exam begins, write your name at the top of the first two pages. You may use pen or pencil. However, re-grades will be considered only for exams completed
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CS 220: Computer Systems II: Architecture and ProgrammingSpring 2009 - Section A0Quiz #8 - 2009/05/04 Name: _=1:Circle which of the following (it could be any number of them) aretrue statements about key-pair type encryption systems:
Minnesota - CHEM - 2301
Chemistry 2301 Exam 1 Answer KeyMonday, February 18, 2007Exam 1 Mean: Exam 1 Median: Exam 1 St. Dev.:78 80 1511. (9 pts) Draw Lewis dot structures for each of the molecules below. Draw all valence electrons as dots. If there are formal char
Binghamton - CS - 220
1: a), c), e)2.1: a)2.2: b)2.3: a)2.4: c)2.5: b)3: a), d)4: c)
Binghamton - CS - 220
CS 220: Computer Systems II: Architecture and ProgrammingSpring 2009 - Section A0Final Exam - 2009/05/11 Name: _=1:Circle which of the flags (it can be any number of them) listed undereach set of numbers will be set (to 1) after each pa
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, March 9, 2009 Exam 2We will be handing out a periodic table as an aide for this test. Otherwise, you are not permitted to use any other materials (including notes, books, or electronic
Minnesota - CHEM - 2301
Chemistry 2301 Exam 2 Answer KeyMonday, March 9, 2009Exam 2 Mean: Exam 2 Median: Exam 2 St. Dev.:57 56 17FrequencyExam Grade11. (12 pts) How would you describe the relationship between each of the pairs of structures below? Are they ena
Binghamton - CS - 220
1:OF,CF,ZFCF,SFCF,SFNone.OF,SF2: f)3:-1-646417-1204: c)5:CF,ZFSF,OF,ZFZF6: c)7:movl$var1, %eax8: f)9: f)10:0x14011: b), d)12: a), c), d)13: b)14: a)15: b)16:xchgw%bx, %cx-or-xchgw%cx, %b
Minnesota - CHEM - 2301
NAME _UM Internet ID _ORGANIC CHEMISTRY I (2301-001) 9:05 9:55 am, March 10, 2008 Exam 2You are allowed one 8-" x 11" piece of paper, with any writing on it you like, as an aide for this test. Otherwise, you are not permitted to use any other
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, April 6, 2009 Exam 3A periodic table and a chart of reaction conditions are attached to the back of this exam as aides. Otherwise, you are not permitted to use any other materials (incl
Minnesota - CHEM - 2301
Chemistry 2301 Exam 3 Answer KeyMonday, April 6, 2009Exam 3 Mean: 42 Exam 3 Median: 42 Exam 3 St. Dev.: 18FrequencyExam Grade11. (16 pts) Each of the reactions below is drawn with two possible reaction conditions. If only one of the two r
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, November 12, 2007 Exam 3When the exam begins, write your name at the top of the first two pages. You may use pen or pencil. However, re-grades will be considered only for exams complete
Minnesota - CHEM - 2301
Chemistry 2301 Exam 3 Answer KeyMonday, April 7, 2008Exam 3 Mean: Exam 3 Median: Exam 3 St. Dev.:50 50 1811. (24 pts) Each of the reactions below is drawn with two possible products. If one of the two products predominates, circle that pref
Minnesota - CHEM - 2301
Chemistry 2301 Exam 3 Answer KeyMonday, November 12, 2007Exam 3 Mean: Exam 3 Median: Exam 3 St. Dev.:53 54 1911. (24 pts) Each of the reactions below is drawn with two possible products. If one of the two products predominates, circle that
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 1:25 2:15 pm, May 4, 2009 Exam 4A periodic table, a chart of reaction conditions, and tables of typical NMR chemical shifts and coupling constants are attached to the back of this exam as aides. Othe
Minnesota - CHEM - 2301
Chemistry 2301 Exam 4 Answer KeyMonday, May 4, 2009Exam 4 Mean: 61 Exam 4 Median: 61 Exam 4 St. Dev.: 17FrequencyExam Grade11. (9 pts) Identify each of the transformations below as a reduction, an oxidation, or neither. Circle one answer
Minnesota - CHEM - 2301
NAME _ UM Internet ID _ORGANIC CHEMISTRY I (2301-001) 9:05 9:55 am, May 5, 2008 Exam 4You are allowed one 8- x 11 piece of paper, with any writing on it you like, as an aid for this test. Otherwise, you are not permitted to use any other materia
Minnesota - CHEM - 2301
Chemistry 2301 Exam 4 Answer KeyMonday, May 5, 2008Exam 4 Mean: Exam 4 Median: Exam 4 St. Dev.:57 60 2011. (9 pts) Identify each of the transformations below as a reduction, an oxidation, or neither. Circle one answer only. REDUCTIONO- O
Minnesota - CHEM - 2301
NAME _UM Internet ID _ORGANIC CHEMISTRY I (2301-003) 4:00 6:00 pm, May 16, 2009 Final ExamA periodic table, a chart of reaction conditions, and tables of typical NMR chemical shifts, coupling constants, and IR stretching frequencies are attach
Minnesota - CHEM - 2301
Chemistry 2301 Final Exam Answer Key Final Exam Mean: 117 Final Exam Median: 116 Final Exam St. Dev.: 33May 16, 200911. (14 pts) For each of the pairs of acids (or bases) below, Draw the conjugate base (or acid). Circle whether you think the
Minnesota - CHEM - 2301
NAME _ UM Internet ID _ORGANIC CHEMISTRY I (2301-001) 1:30 3:30 pm, May 16, 2008 Final ExamYou are allowed one 8- x 11 piece of paper, with any writing on it you like, as an aid for this test. Otherwise, you are not permitted to use any other ma
Minnesota - CHEM - 2301
NAME _ID #_ORGANIC CHEMISTRY I (2301-003) 8:00 10:00 am, December 19, 2007 Final ExamWhen the exam begins, write your name at the top of the first two pages. You may use pen or pencil. However, re-grades will be considered only for exams com
Minnesota - CHEM - 2301
Chemistry 2301 Final Exam Answer Key Final Exam Mean: 114 Final Exam Median: 112 Final Exam St. Dev.: 40May 16, 200811. (10 pts) On the structures below, label each chiral center with its appropriate Cahn-IngoldPrelog designation [(R) or (S)].
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BTD210 In-Class Exercise 1: Conceptual Modeling EXAMPLE 1: Draw an Entity Relationship Diagram using Crows Foot notation based on the following business rules. Show the entities and the relationships between the entities. Do not show any attributes.
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