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CSU Northridge - KFS - 103
WARM UP EXERCISEThe ozone level (in parts per billion) on a summer day at R University is given by P(x) = 80 + 12t t 2 Where t is hours after 9 am. 1. P (x). 2. Find P (3) and P (3). 3. Write an interpretation.Given y = f (x) then the derivativ
CSU Northridge - KFS - 103
WARM UP EXERCISEThe total sales of a company (in millions of dollars) t months from now are given by S(t) = 0.015t 4 + 0.4t 3 + 3.4t 2 + 10t - 3 Find S (t). Find S (4) and S (4). Write a brief verbal interpretation of these results.19.5 Deriva
CSU Northridge - KFS - 103
LetWARM UP EXERCISEf (x) = e x f (0) = f (1) = Is the derivative of e x positive or negative at 0? Where is the derivative of e x positive? Where is the derivative of ln x positive? g(x) = 2 x g(0) = g(1) = g(!1) = g(5) = Is the derivative of 2 x
CSU Northridge - KFS - 103
Review for Exam IBasic Functions Shift, stretch, squish, flip Linear Quadratic Polynomials RationalDefinition of a FunctiondomainfrangeDef. a function is a rule that produces a correspondence between two sets of elements such that for each
U. Houston - SERVER - 2006083000
2 REAL 6 8 29 12 0 REAL 6 8 29 12 0 12BACKWARDOMEGA 6 8 30 0 29.696 -95.499 10.0 6 8 30 0 29.670 -95.129 10.0 6 8 30 0 30.039 -94.075
CSU Northridge - KFS - 103
10 8 6 4 2 10 8 6 4 2 2 4 6 8 10 2 4 6 8 10
U. Houston - SERVER - 2006083000
2 REAL 6 8 29 12 0 REAL 6 8 29 12 0 12BACKWARDOMEGA 6 8 30 0 29.696 -95.499 500.0 6 8 30 0 29.670 -95.129 500.0 6 8 30 0 30.039 -94.075 5
U. Houston - SERVER - 2009052106
2 REAL 9 5 20 18 0 REAL 9 5 20 18 0 12BACKWARDOMEGA 9 5 21 6 29.696 -95.499 1000.0 9 5 21 6 29.670 -95.129 1000.0 9 5 21 6 30.039 -94.075 10
CSU Northridge - MIDTERM - 103
Exam Totalpts 10 15 20 15 20 20 100 Lastname 1 2 3 4 5 6 Total w/0#4 Average 79 80 69 29 71 78 68 72 StdDev. 2 3 5 6 6 2 14 19 >75% 10 14 19 3 20 17 79 82 >50% 7 13 14 2 16 16 67 75 >25% 7 11 10 1 12 15 58 64 differencequotient wordproblemParabola
CSU Northridge - MIDTERM - 103
10 8 6 4 2 10 8 6 4 2 2 4 6 8 10 2 4 6 8 10
CSU Northridge - MIDTERM - 103
Exam I HistogramBreak down by problemAverage Std Dev. >75% >50% >25% 74.3 1.9 10.0 6.5 6.0 70.5 4.8 15.0 12.0 9.3 79.9 2.8 13.8 13.0 11.0 70.1 4.3 13.0 12.5 7.5 62.5 3.5 12.0 10.0 7.0 66.8 4.3 13.8 11.0 7.0 59.5 4.3 12.0 10.0 6.3 69 17 83 70 57c
U. Houston - SERVER - 2009052106
2 REAL 9 5 20 18 0 REAL 9 5 20 18 0 12BACKWARDOMEGA 9 5 21 6 29.696 -95.499 500.0 9 5 21 6 29.670 -95.129 500.0 9 5 21 6 30.039 -94.075 5
U. Houston - SERVER - 2009050400
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CSU Northridge - KFS - 103
48000 44000 40000 36000 32000 28000 24000 20000 16000 12000 8000 4000 200 400 600 800 1000 1200 1400 1600 1800
U. Houston - SERVER - 2009050400
2 REAL 9 5 3 12 0 REAL 9 5 3 12 0 12BACKWARDOMEGA 9 5 4 0 29.696 -95.499 10.0 9 5 4 0 29.670 -95.129 10.0 9 5 4 0 30.039 -94.075
CSU Northridge - KFS - 103
6 5 4 3 2 1 -6 -5 -4 -3 -2 -1 -1 -2 -3 -4 -5 -6 1 2 3 4 56
CSU Northridge - KFS - 103
Solutions to Math 103 Sample Final 1a) The y-intercept is (0, 5) and the x-intercept is (2.5, 0). The graph is the line passing through the two points. b) y = 2 x 5 2a) f ( x ) = 6 x 2 3 b) g ( x ) = 1 / x - 2x 2 + 3 h x) = ( c) 2 2x 2 - x + 3 d)
U. Houston - SERVER - 2009050400
2 REAL 9 5 3 12 0 REAL 9 5 3 12 0 12BACKWARDOMEGA 9 5 4 0 29.696 -95.499 1500.0 9 5 4 0 29.670 -95.129 1500.0 9 5 4 0 30.039 -94.075 15
CSU Northridge - KFS - 103
NAME: INSTRUCTORs NAME: Math 103 Spring 2006: Draft Final May 1.General Instructions 1. NO Calculators. 2. Please show all your work, unless explicitly instructed not to do so. 3. Please ask if you are not sure of anything on the exam. 4. You have
U. Houston - SERVER - 2006090506
2 REAL 6 9 4 18 0 REAL 6 9 4 18 0 12BACKWARDOMEGA 6 9 5 6 29.696 -95.499 1000.0 6 9 5 6 29.670 -95.129 1000.0 6 9 5 6 30.039 -94.075 10
U. Houston - SERVER - 2006090506
2 REAL 6 9 4 18 0 REAL 6 9 4 18 0 12BACKWARDOMEGA 6 9 5 6 29.696 -95.499 10.0 6 9 5 6 29.670 -95.129 10.0 6 9 5 6 30.039 -94.075
U. Houston - SERVER - 2009043000
2 REAL 9 4 29 12 0 REAL 9 4 29 12 0 12BACKWARDOMEGA 9 4 30 0 29.696 -95.499 1000.0 9 4 30 0 29.670 -95.129 1000.0 9 4 30 0 30.039 -94.075 10
U. Houston - SERVER - 2009043000
2 REAL 9 4 29 12 0 REAL 9 4 29 12 0 12BACKWARDOMEGA 9 4 30 0 29.696 -95.499 1500.0 9 4 30 0 29.670 -95.129 1500.0 9 4 30 0 30.039 -94.075 15
U. Houston - SERVER - 2009043000
2 REAL 9 4 29 12 0 REAL 9 4 29 12 0 12BACKWARDOMEGA 9 4 30 0 29.696 -95.499 500.0 9 4 30 0 29.670 -95.129 500.0 9 4 30 0 30.039 -94.075 5
Princeton - EE - 464
Compact disc players Devicecharacteristics. Hardwarearchitectures. Software. 2003 Wayne WolfCD audio 44.1kHzsamplerate. 16bitsamples. Stereo. Additionaldatatracks. 2003 Wayne WolfCompact disc Datastoredonbottomofdisc:substratealum
Princeton - EE - 464
I/O devices I/Odevices: seriallinks timersandcounters keyboards displays analogI/O 2000 Morgan KaufmanOverheads for Computers as ComponentsTimers and counters Verysimilar: atimerisincrementedbyaperiodicsignal; acounterisincrementedbyan
Princeton - EE - 464
The embedded systems platform Example:alarmclock 2000 Morgan KaufmanOverheads for Computers as ComponentsAlarm clock interfaceAlarm on PM Alarm off buzzerlight set time 2000 Morgan KaufmanAlarm ready set alarm hour minute buttonOverhea
U. Houston - SERVER - 2009041706
2 REAL 9 4 16 18 0 REAL 9 4 16 18 0 12BACKWARDOMEGA 9 4 17 6 29.696 -95.499 1000.0 9 4 17 6 29.670 -95.129 1000.0 9 4 17 6 30.039 -94.075 10
Princeton - EE - 464
Networks Networkbaseddesign. Communicationanalysis. Systemperformanceanalysis. Internetenabledsystems. 2000 Morgan KaufmanOverheads for Computers as ComponentsCommunication analysis First,understanddelayforsingle message. Delayformultipl
Princeton - EE - 464
Networks Example:elevatorcontroller. 2000 Morgan KaufmanOverheads for Computers as ComponentsTerminology Elevatorcar:holdspassengers. Hoistway:elevatorshaft. Carcontrolpanel:buttonsineachcar. Floorcontrolpanel:elevatorrequest,etc. perfloor
U. Houston - SERVER - 2009041706
2 REAL 9 4 16 18 0 REAL 9 4 16 18 0 12BACKWARDOMEGA 9 4 17 6 29.696 -95.499 10.0 9 4 17 6 29.670 -95.129 10.0 9 4 17 6 30.039 -94.075
Princeton - EE - 464
Topics Instructionlevelparallelism. VLIW. Superscalar. 2004 Wayne WolfParallelism in programsParallelismexists inseverallevels ofgranularity:Task. Data. Instruction.P1 Ld r1, r2 Add r3,r4 Sub r5,r6P2P3 2004 Wayne WolfInstruct
U. Houston - SERVER - 2009051318
2 REAL 9 5 13 6 0 REAL 9 5 13 6 0 12BACKWARDOMEGA 9 5 13 18 29.696 -95.499 1000.0 9 5 13 18 29.670 -95.129 1000.0 9 5 13 18 30.039 -94.075 10
U. Houston - SERVER - 2009051318
2 REAL 9 5 13 6 0 REAL 9 5 13 6 0 12BACKWARDOMEGA 9 5 13 18 29.696 -95.499 1500.0 9 5 13 18 29.670 -95.129 1500.0 9 5 13 18 30.039 -94.075 15
Brookdale - MECH - 4851
Assignment #2 Solutions3.15)13.21)3.26)23.34)3.45)3
Brookdale - MECH - 4851
MECH 4851HEATING VENTILATION AND AIR CONDITIONING FALL TERM 2008 WEEK 3Don Baker P.Eng.MOIST AIR PROPERTIESCONDITIONING PROCESSES IN AIR CONDITIONING SYSTEMS CHAPTER 2 & 3MOIST AIR PROPERTIES ABILITY TO ANALYSE PROCESSES INVOLVING MOIST AIR I
St. Francis IL - CPSC - 122
1 3Exception Handling1 2005 Pearson Education, Inc. All rights reserved.2It is common sense to take a method and try it. If it fails, admit it frankly and try another. But above all, try something. Franklin Delano RooseveltO! throw away
CSB-SJU - PHYSICS - 211
Physics 211EXAM 22004 November 22Answer ve questions: #1 and four of the remaining questions Physical Constants = 5.6705 108 W m2 K4 R = 8.3145 J/(K mol) NA = 6.0221 1023 k = 1.3807 1023 J/K 1 eV = 1.6022 1019 J 1 atm = 1.0133 105 Pa P
Brookdale - MECH - 4851
Finding3possiblepeakloadhoursforeachroomfromSHGFtable(table19)Room WindowDirection Time 8 26 38 38 214 252 9 30 75 75 191 266 10 34 113 113 143 256 11 36 138 138 79 217 12 39 146 146 39 185 13 79 138 138 36 174 14 143 113 113 34 147 15 191 75 75 30
U. Houston - SERVER - 2009041706
2 REAL 9 4 17 6 6 REAL 9 4 17 6 6 12FORWARD OMEGA 9 4 17 6 29.696 -95.499 1500.0 9 4 17 6 29.670 -95.129 1500.0 9 4 17 6 30.039 -94.075 15
St. Francis IL - CPSC - 122
Polymorphism IllustrationJohn LamertinaSuperclass AnimalAnimal - name + Animal() + Animal(String name) + getName(): String + setname(String name) + toString(): String + speak(): StringItalics indicate abstractSubclass DogAnimalDog + Dog() +
CSB-SJU - PHYSICS - 211
Intensity, I, of light (with k = 2/) that has gone throught N-slits, separated by d, and is headed towards the screen at an angle of : I sin(kNd sin()/2) sin(kd sin()/2)2
CSB-SJU - PHYSICS - 211
Diffraction Grating 10080Light Intensity6040200 3 2 1 0 y (m) 1 2 3
U. Houston - SERVER - 2006082012
2 REAL 6 8 20 0 0 REAL 6 8 20 0 0 12BACKWARDOMEGA 6 8 20 12 29.696 -95.499 1500.0 6 8 20 12 29.670 -95.129 1500.0 6 8 20 12 30.039 -94.075 15
CSB-SJU - PHYSICS - 211
Diffraction Grating 10080Light Intensity6040200 .6 .4 .2 0 y (m) .2 .4 .6
CSB-SJU - PHYSICS - 211
18-38. The heat needed is found by integrating the heat capacity:Tf TfQ=Ticm dT = mTi 15.0 Cc dT= = =(2)5.0 C(0.20 + 0.14T + 0.023T 2) dT15.0(2.0)(0.20T + 0.070T 2 + 0.00767T 3)5.0(cal)81.8 cal .18-39. (a) We work in Celsi
CSB-SJU - PHYSICS - 211
19-25. (a) We use = LV /N , where LV is the heat of vaporization and N is the number of molecules per gram. The molar mass of atomic hydrogen is 1 g/mol and the molar mass of atomic oxygen is 16 g/mol so the molar mass of H2 O is 1 + 1 + 16 = 18 g/m
Brookdale - MECH - 4851
MECH 4851HEATING VENTILATION AND AIR CONDITIONING FALL TERM 2008 WEEK 9Don Baker P.Eng.HAPHOURLY ANALYSIS PROGRAM CARRIER V4.3.1HAPHAP is a computer based program used to determining: 1. Heating Loads for spaces, zones & coils. 2. Cooling Loa
U. Houston - SERVER - 2006091212
2 REAL 6 9 12 0 0 REAL 6 9 12 0 0 12BACKWARDOMEGA 6 9 12 12 29.696 -95.499 1000.0 6 9 12 12 29.670 -95.129 1000.0 6 9 12 12 30.039 -94.075 10
CSB-SJU - PHYSICS - 211
Heat Capacity vs. Temperature3heat capacity (J/K)210 10 100 T (K) 1000
CSB-SJU - PHYSICS - 211
Physics 211EXAM II Answer ve of the following six problems2006 October 311. The intensity of sunlight outside the Earths atmosphere is about 1367 W/m2 . (a) Find the corresponding maximum electric eld for such intense light. (b) Find the radiat
Brookdale - MECH - 4810
DALHOUSIE UNIVERSITY DEPARTMENT OF MECHANICAL ENGINEERING MECH 4810 ENERGY CONVERSION SYSTEMS Instructor Professor Prabir Basu, Room C301. Telephone 494-3227. Email: prabir.basu@dal.ca Teaching Assistant Tanuja Bhattacharjee, Room F108B, CFB Laborato
CSB-SJU - PHYSICS - 211
MEAN= -16.88689, 804.1 290.0 755.0 289.4 749.2 287.8 735.2 287.7 725.4 285.5 697.2 282.0 686.0 281.2 660.5 281.1 634.2 281.0 623.2 277.9 620.6 277.6 595.0 277.0 554.5 276.1 544.9 274.6 533.0 273.6 528.0 273.3 524.8 273.2 520.5 272.9 519.0 271.7 510.9
CSB-SJU - PHYSICS - 211
2.5 2 1.5 1 0.5246810
Brookdale - MECH - 4810
1. Which of the following is not considered one of the six basic greenhouse gases?a. Carbon Dioxide b. Methane c. Nitrous Oxide d. Ozone e. Hydroflurocarbons2. Current climate change models predict highest average temperatue increases in which ge
U. Houston - SERVER - 2006081018
2 REAL 6 8 10 6 0 REAL 6 8 10 6 0 12BACKWARDOMEGA 6 8 10 18 29.696 -95.499 1500.0 6 8 10 18 29.670 -95.129 1500.0 6 8 10 18 30.039 -94.075 15
CSB-SJU - PHYSICS - 211
ScheduleDay 1/1 1/3 1/5 2/1 2/3 2/5 3/1 3/3 3/5 4/1 4/3 4/5 5/1 5/3 5/5 6/1 6/3 6/5 7/1 7/3 7/5 8/1 8/3 8/5 9/1 9/3 9/5 10/1 10/3 Date Aug 29 Aug 31 Sep 4 Sep 6 Sep 8 Sep 12 Sep 14 Sep 18 Sep 20 Sep 22 Sep 26 Sep 29 Oct 3 Oct 9 Oct 11 Oct 13 Oct 17
U. Houston - SERVER - 2006081018
2 REAL 6 8 10 6 0 REAL 6 8 10 6 0 12BACKWARDOMEGA 6 8 10 18 29.696 -95.499 500.0 6 8 10 18 29.670 -95.129 500.0 6 8 10 18 30.039 -94.075 5
Brookdale - MECH - 4810
Kyoto Protocol & Emissions TradingPrabir BasuOutline1. Kyoto protocol 2. Emission trading basics 3. Kinds of emission trading 4. Emission limit or targets 5. Key elements of a trading system11.1 Kyoto background UN established a non-binding
CSB-SJU - PHYSICS - 211
path p-constant V -constant T -constant S-constant line free cycleW Q pV nCp T 0 nCV T nRT ln (Vf /Vi ) W nCV T 0 1 (p + pi )V W + E 2 f 0 0 area area Note: nRT Cp = C V + R CV =Eint S nCV T nCp ln (Tf /Ti ) nCV T nCV ln (Tf /Ti ) 0 nR ln (Vf /Vi