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Course: CHEM 162, Fall 2008
School: Washington
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Solution for Homework 6Problem 2:1. a. p(x,y) 0 1 2 0 .30 .18 .12 .6 1 .05 .03 .02 .1 y 2 .025 .015 .01 .05 3 .025 .015 .01 .05 4 .10 .06 .04 .2x.5 .3 .2b. c. d.P(X 1 and Y 1) = p(0,0) + p(0,1) + p(1,0) + p(1,1) = .56 = (.8)(.7) = P(X 1)
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Solution for Homework 9Problem 2:a. b. The sample mean is the center of the interval, so x =114.4 + 115.6 = 115 . 2The interval (114.4, 115.6) has the 90% confidence level. The higher confidence level will produce a wider interval.Problem 4:
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