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Differential Equations Worksheet
Course: MATH 160, Fall 2008School: Boise State
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Equations Differential Worksheet 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. Key 1. 3. 2. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40.
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Equations Differential Worksheet
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Boise State - MATH - 160
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Boise State - MATH - 160
Derivatives - Chain Rule Worksheet Key 1. f ( x ) = ( 1 - x )3f ' ( x ) = -3 ( 1 - x )22. f ( x ) = 2 ( x 3 - 1) 3. f ( x ) =5f ' ( x ) = 30 x 2 ( x 3 - 1)4-3 1 ( 2x 2 + x ) 23 ( 1+ 4x ) df =- dy 2 ( 2x 2 + x )1 d ( y ) = ( 3 ) ( 3
Boise State - MATH - 160
Derivatives - Chain Rule 1. f ( x ) = ( 1 - x )3f' ( x) =2. f ( x ) = 2 ( x 3 - 1)5f' ( x) =3. f ( x ) =-3 1 ( 2x 2 + x ) 2df = dy4. y = ( 3 x 2 - 2 x + 1) 23d ( y) = dx dy = dx45. y = 3 x 2 - x6. y = ( x - 1)2( 2 x + 1)
Boise State - MATH - 160
Derivative Problems Use the definition of derivative to solve the following. 1. f ( x ) = 3x + 5 f' ( x) =2. y = x 3dy = dx3. f ( x ) = x 3 - 4 x 2df = dx4. y =1 5xd ( y) = dx5. f ( x ) = - x 2 + 3xf' ( x) =Use the rules of differ
Boise State - MATH - 160
Derivative Worksheet Use the definition of derivative to solve the following. 1. f ( x ) = 3 x + 5 f' ( x) =2. y = x 3dy = dx3. f ( x ) = x 3 - 4 x 2df = dx4. y =1 5xd ( y) = dx5. f ( x ) = - x 2 + 3 xf' ( x) =Use the rules of dif
Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
Math 160 Calculus Problem 27, page 42 Regression ExampleFirst, we enter the 5 columns of data into lists, L1 - Year, L2 - Men's 100 Times, L3 - Women's 100 Times, L4 - Men's 200 Times, L5 - Women's 200 Times.For each set of times we need to: a) l
Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
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Boise State - MATH - 160
1. f ( x ) = ( 1 - x )3Derivatives - Chain Rule 2 f ' ( x ) = -3 ( 1 - x )2. f ( x ) = 2 ( x 3 - 1)5f ' ( x ) = 30 x 2 ( x 3 - 1)43. f ( x ) =-3 1 ( 2x 2 + x ) 23 ( 1+ 4x ) df =- dy 2 ( 2x 2 + x )4. y = ( 3 x - 2 x + 1)23 21
Boise State - MATH - 160
Derivatives - Chain Rule 1. f ( x ) = ( 1 - x )3f' ( x) =2. f ( x ) = 2 ( x 3 - 1)5f' ( x) =3. f ( x ) =-3 1 ( 2x 2 + x ) 2df = dy4. y = ( 3 x 2 - 2 x + 1) 23d ( y) = dx dy = dx45. y = 3 x 2 - x6. y = ( x - 1)2( 2 x + 1)
Boise State - MATH - 160
Derivatives - Chain Rule 1. f ( x ) = ( 1 - x )3f' ( x) =2. f ( x ) = 2 ( x 3 - 1)5f' ( x) =3. f ( x ) =-3 1 ( 2x 2 + x ) 2df = dy4. y = ( 3 x 2 - 2 x + 1) 23d ( y) = dx dy = dx45. y = 3 x 2 - x6. y = ( x - 1)2( 2 x + 1)
Boise State - MATH - 160
Derivative Problems Use the definition of derivative to solve the following. 1. f ( x ) = 3 x + 5 f' ( x) =2. y = x 3dy = dx3. f ( x ) = x 3 - 4 x 2df = dx4. y =1 5xd ( y) = dx5. f ( x ) = - x 2 + 3 xf' ( x) =Use the rules of diff
Boise State - MATH - 160
Derivative Quiz Use the definition of derivative to solve the following. 1. f ( x ) = 3 x + 5 f' ( x) =2. y = x 3dy = dx3. f ( x ) = x 3 - 4 x 2df = dx4. y =1 5xd ( y) = dx5. f ( x ) = - x 2 + 3 xf' ( x) =Use the rules of differen
Boise State - MATH - 160
Derivatives - Exp Log Derivatives 1. f ( x ) = e 3 x f' ( x) =2. f ( x ) = x 3e xf' ( x) =3. f ( x ) =ew + 1 ewdf = dy4. y =x exd ( y) = dx dy = dx5. y = ( e x + 1)256. y = e 2 x1y' =e-x 7. f ( x ) = 1+ x 2f' ( x) =8.