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6930 COT Advanced Topics in Theory Theory of Secu...
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Long Island U. - EE - 0406
Day High Monday Tuesday Wednesday Thursday Friday Saturday SundayLow 76 76 77 73 62 64 67 59 63 63 48 46 50 52 Temperature (F)Daily Temperatures90 80 70 60 50 40 30 20 10 0M on da y Tu es da y W ed ne sd ay sd ay da y Sa tu r Su nd ay Fr id ay
Long Island U. - EE - 0406
EIGHTH GRADE ENGLISHSpeakSummary Format: Main Character's Name: One Character Trait: Explain Why: Second Character Trait: Explain Why: Third Character Trait: Explain Why:Speak by Laurie Halse AndersonMargaret RyanMetz Meredith Hasemann-Cortes
Long Island U. - EE - 0406
Directions for The Power of a Penny Activity: 1. Ask the students, "Would you rather take $1,000,000 right now, or a penny that doubles every day for a month?" 2. Tell students that today they will be using a spreadsheet to calculate which choice wou
Long Island U. - EE - 0406
Margaret RyanMetz Grade: 7th Period: 2nd Lesson to be observed: Literature Circles Focus on clues Standard: English Language Arts Standard 1, 3, and 4 POST OBSERVATION REFLECTION FORM 1. The students were active participants in the lesson. The stude
East Los Angeles College - CHEM - 1005
LECTURE 2 Highly Reactive Carboxylic Acid Derivatives Preparation All of these functional groups are conveniently prepared from carboxylic acids as shown in the scheme below.OThe Chemistry of Acid Chlorides Dominated by Nucleophilic Substitution
East Los Angeles College - CHEM - 1005
Lecture 8 Reactions of Ketones and Aldehydes with bases Most C-H bonds are not considered to be acidic.H pKa ~ 51 H pKa ~ 44 H pKa ~ 43Lithium Diisopropyl Amide LDA is commonly used.Li NLDA =C-H bonds next to carbonyls are very weakly acidi
N.C. State - CSC - 440
CSC440 HW#1 SolutionProblem1 1 URL serves as a unique identifier for the Websites, so it is the key of the entity set Websites and it should be underlined. 2 For the subclasses Webstores and Personal Sites, they can not have the key attribute-URL, b
Arizona - AME - 352
AME 352, Exam-1, Answers 1. Number of moving bodies: 7 Number of full joints: 9 Number of half joints: 1 Number of degrees of freedom based on the mobility formula: 2 2. (a) Non-Grashof (b) Grashof 3.3 4= 0.16 CCW = 0.25 CWB P V = 0.96 P O VA
Arizona - AME - 352
AME 352, Fall 2008, Exam-2 1. Measurements in centimeters (a)Name: _ Solution _VC = VB + VCB RCB = 3.6 cm VCB = 3.6 2 = 7.2 VC = 8.3 cm/sec as shownn A C = A B + A CB + A tCB n ACB = 3.6 22 = 14.4 t ACB = 3.6 1.5 = 5.4AC = 17.8 cm/sec2 as sho
Arizona - AME - 352
AME 352, Exam-3 1. The moment arms with respect to C are shown in centimeters.Name: _ Solution _FAA3.5TFBBC8.4FC FAFBFCTC = 3.5 20 + 8.4FBFA = 20 0 FB =y30 = 0FB = 11.9 in positive y-directiony0 11.9 0 20 + FC = 0 +
Arizona - AME - 352
AME 352, Fall 08, HW-11. For each of the mechanical systems shown: (a) Identify each joint on the figure (write P for pin, S for slider, R for roll). (b) Assign numbers to the moving bodies (1, 2, 3, etc.). (c) Determine total number of moving bodi
Arizona - AME - 352
AME 352, Fall 08, HW-10 1. For a slider-crank mechanism with no offset the lengths of the crank and the connecting rod are given as 2 = 1.5 and 3 = 4. The mass centers are at the geometric centers. The inertial data are given as: m2 = 2, I G = 0.375,
Arizona - AME - 352
AME 352, Fall 08, HW-12 1. A system of four non-coplanar weights is arranged on a shaft as shown schematically (arbitrarily). The shaft rotates at 100 rpm. Assume the following data (use any consistent unit system you prefer): link 1 2 3 4 m 3.0 6.5
Arizona - AME - 352
AME 352, Fall 08, HW-21. Design a four-bar Grashof crank-rocker for 55 of output rocker motion with a time ratio of 1:1 (no quick return). a) Design the four-bar on paper (or use drafting/drawing software) b) Construct the mechanism with WM c) Dete
Arizona - AME - 352
AME 352, Fall 08, HW-5 Problem 1: (Instant Center Method) Consider this inverted slider-crank mechanism: a) Find the instant centers. b) Assume that link 2 which has a unit length rotates clockwise with an angular velocity of 1.5 rad/sec. What is the
Arizona - AME - 352
AME 352, Fall 08, Answers to HW-1 Problem 1:S P P 1 3 P P 2 3 P R P 1 S 2 1 P 2 S 3 P(a)P 1(b)(c)2 P 3 P P 4 5 5 P S P P 3 21P 1 SPP P 4 PP2 R 3P(d)(e)(f)S1P 2 P 3 P 1P 2P1 S 2P3 S(g) Mobility formula:
Arizona - AME - 352
AME 352, Fall 08, Solution HW-11 1. Since this is a dynamic force analysis, we must determine all the velocities and accelerations (the method of solution is our choice).Velocity Polygon A1.0 0.49A G2, OV0.4Acceleration Polygon2.0G4 B0.8
Arizona - AME - 352
AME 352, Fall 08, Solution HW-13 1.BA3CVCOA2= 1(CCW ); O2 A = 1cm T2 2 + RCVC = 0 100 1 + RC ( 0.027) = 02VC = 2.7cm / sec RC = 3300N (to the right)3.70 mm 24 mm R R Q 10 mm 20 N 18 mm F 1 F 1 F 1 R 20 N 2.5 mm OF = 10 N HRF
Arizona - AME - 352
AME 352, Fall 08, Answers to HW-2 Problem 1: Follow the procedure from Example 3-1 in Chapter 3 of the textbook. One of infinite number of solutions to this design problem is: L1 = 5.45 (ground link), L2 = 1.15 (crank), L3 = 5.0 (coupler), L4 = 2.5 (
Arizona - AME - 352
AME 352, Fall 08, Answers to HW-3 Problem 1: a.1) 3 = 0.36 CCW a.2) 4 = 0.22 CW a.3) VB = 0.48 @60 a.4) VBA = 0.91 @147B VB V B/AO VVAAProblem 2: a.1) 3 = 0.14 CW a.2) VB = 0.86 @ 0 a.3) VBA = 0.35 @ 258V A OV VB B A V B/AB V B/A AVB VA
Arizona - AME - 352
AME 352, Fall 08, Answers to HW-4 Problem 1: a) Draw the velocity polygon and then determine: a.1) Angular velocity of link 4 and link 3; = 0.33 rad/sec CW a.2) Sliding velocity; = 0.7 unit/sec in the direction shown on the polygon a.3) Absolute velo
Arizona - AME - 352
AME 352, Fall 08, Solution HW-5 Problem 1:VPV2,31,4 2,3 1,2V2,42,43,4 @1,34=3= 0.49 rad/sec CWVP = 1.82 in the direction shownProblem 2: 2,4 @ 3,4 1,3 1,4 @VA 2,3 1,2 @VB4.b) 2.69 rad/sec CW 4.c) 2.23 unit/sec Problem 3:
Arizona - AME - 352
AME 352, Fall 08, Solution HW-6Problem 1: = 0.14 CW 34B C= 0.44 CW = 0.3 CW = 0.39 CCWO 2 A O 4VP = 1.23 4AP = 1.16A CVt VAO2t BABAtAOAn BAAAn AOACC22VCt VBOOAAn BO AtBO44AtBAB4OVProblem 2: = 0.
Arizona - AME - 352
AME352, Fall 2008, Solution HW-7 Problem 1:C(2)V C 3.1BV B 6.1 6.14,2(4) 1,43.41,2V 4,2 9.74,55.11,5(5)D V D3.22,5V2,5= 0.3 CW V4,2 = 1.8 cm/sec2= 0.3 CCW VC = 0.9 cm/sec V2,5 = 2.9 cm/sec4= 0.9 CW VD = 4.6 cm/s
Arizona - AME - 352
AME352, Fall 2008, Solution HW-8 Problem 1: a)2A3R2 R1 R3 R441= 270 o = 0oO4CPR2 + R3 R4R1 = 0b)R2 cos R2 sin2 2+ R3 cos + R3 sin33R4 cos R4 sin3 3 44R1 cos R1 sin11=0=0By plugging in the constant values
Arizona - AME - 352
AME352, Fall 2008, Solution HW-9 1. RO = 636.4 N @ 225o2.FB = 2010 N perpendicular to the contact surface 3.R = 1600 N upward4.FB = 1410 N upward
Wisconsin - PA - 880
PA 880 Problem set #9 Fall 2006 Problem #1 Online Dating In Freakonomics, economist Steven Levitt discusses the online dating world. According to him, about 40 million Americans a year try to date online. Clearly, there are information problems in o
NMT - EE - 231
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NMT - EE - 231
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NMT - EE - 231
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NMT - EE - 231
q ce c vhbgfps b ce dhbgfc u tsgfgq ce c rqgfpi ce c hbgfdb ce c ` Y XB@ IB S Q I F DB@ aPWV UCT@RPHG'ECA9 8 7532 1'%$" 6 4 ) 0 ) (& # # !
NMT - EE - 231
stuvge ct c ct c y uvut t y uvg cr c t cr dsruvc y xwusruvur c cr c t ce c dsrgfgq i ce c phbgfdb ` Y XB@ IB S Q I F DB@ aPWV UCT@RPHG'ECA9 8 7532 1'%$" 6 4 ) 0 ) (& # # !
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #21.) Use algebraic manipulation to prove the expression in problem 2.5. 2.) What is the Dual of the expression in problem 2.5?Fall 20013.) For the following expressions represent the Digital logic functi
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #3Fall 20011.) Problems from Brown: 4.1, 4.2, 4.4, 4.14, 4.15, 4.19 (min. number of AND & OR gates: NOT is free), 4.20 NOTE: Do not use Brown's minimum cost eqn. 2.) BONUS QUESTION (+5%) Convert the proble
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #4Fall 20011.) Design a minimum SOP combinational logic circuit that converts 4-bit sign & magnitude numbers into the corresponding ones complement representation. 2.) Problems from Brown: 5.3, 5.4, 5.5, 5
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #5Fall 20011.) Problems from Brown: 5.21, 5.22 (HINT: use FA blocks), and 5.259 (HINT: For minimum think min. SOP then Extraction). 2.) Design a circuit to multiply two 2-bit (unsigned) numbers. .
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #7Fall 20011.) Problems from Brown: 3.45 (HINT: get min. SOP first), 3.49 (HINT: see pp. 44-45), 3.50 (HINT: use only 3-input NAND gates), 7.3. 2.) Given: X(A,B,C,D)=SUM of m(1,2,3,5,7,9,11,13,15), Y(A,B,C
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #81.) Problems from Brown: 7.1 (NOTE: One is a gated latch and the other two are FF's) and 7.8. 2.) Complete the following timing diagram for a J-K latch assuming that: a) It is a basic (transparent) latch b)
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #9Fall 20011.) Problems from Brown: 7.18 (HINT: Create the State Transition Table (STT), 7.35, 8.1 (simply give the Boolean eqns. For D2, D1, and Z), 8.2 (simply give the Boolean eqns. For J2, K2, J1, K1,
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #10Fall 20011.) Problems from Brown: 8.5 (include a STD), 8.6 (include a STD), 8.9 (Design as a Moore machine and produce a STD. Omit the circuit design), 8.29 (refer to the upper DFF as #1 and the lower a
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #111.) Given the State Transition Table: Present Next State State w=0 w=1 A B C B D G C F E D B G E F C F E D G F C Output w=0 w=1 0 0 0 0 0 1 0 0 0 1 0 1 0 1Fall 2001i) Minimize the number of states via
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Assignment #13Fall 20011.) From Brown: Show that the "Hazard-free circuit" in Figure 9.62 (pp. 573) is not free of hazards. Specifically, complete the following waveform assuming that all gates have a 10ns gate-delay
NMT - EE - 231
NMT - EE - 231
NMT - EE - 231
NMT - EE - 231
NMT - EE - 231
EE/CS 231 Assignment #6 Solutions6.1.w3 w2 w1w0 w1 w2y0 y1 y2 y3 y4 y5 y6f1Eny76.2.w3 w2 w1w0 w1 w2y0 y1 y2 y3 y4 y5 y6f1Eny76.3.w1 w2 w3 0 0 0 0 1 1 1 1 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 1f 1 0 1 1 0 0 1 0 w1 0 1 f w2
NMT - EE - 231
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Soln to Assignment #8Fall 20012.) Complete the following timing diagram for a J-K latch assuming that: I assumed that q=0 at the start. a) It is a basic (transparent) latch b) It is a gated latch c) It is a positive-
NMT - EE - 231
NMT - EE - 231
8.36ResetS1D0 01N1S31D0N1 S20 0NS5 z 11D0 0N1S4 z 1D01N08.37. An ASM chart for the FSM in Figure 8.58 isResetS11D0N1 S3z01D0N1 S20z 1 0 0DN1SUBDESIGN lab11_table % EE/CS 2
NMT - EE - 231
NMT - EE - 231
NMT - EE - 231
EE/CS 231 DIGITAL ELECTRONICS Soln to Assignment #13Fall 20011.) From Brown: Show that the "Hazard-free circuit" in Figure 9.62 (pp. 573) is not free of hazards. Specifically, complete the following waveform assuming that all gates have a 10ns ga
Colorado - CHEM - 1131
Recap of lecture for Monday, Apr. 10: Optical isomers are observed for the following octahedral formulas (other Oh formulas may also give optical isomers): cis-cis-cis-MA2B2C2 M(bidentate)3 cis-M(bidentate)2A2 cis-MA2BCDE Optical isomers are observed
Colorado - CHEM - 1131
Recap of lecture on Wednesday, Apr. 12: The crystal field splitting energy, , depends on: 1) the nature of the ligand (see the Spectrochemical series). 2) The charge on the metal ion. 3) The principal quantum number of the metal ion. Complexes with s
Colorado - CHEM - 1131
Recap of lecture on Friday, Apr. 14: Octahedral metal complexes with d4 through d7 metal ions can be either high spin or low spin. If the pairing energy is larger than , the complex will be high spin. If the pairing energy is smaller than , the compl
Colorado - CHEM - 1131
Recap of lecture on Monday, Apr. 17: The d orbitals in tetrahedral complexes are split in the opposite way to those in octahedral complexes. The value for in tetrahedral complexes is approximately that of in octahedral complexes with a similar met
Colorado - CHEM - 1131
Recap of lecture on Wednesday, Apr. 19: Nuclear particles are identified by a superscript that indicates relative mass and a subscript that indicates charge. Both the relative masses and the charges on each nuclear particle must be balanced in a nucl
Colorado - CHEM - 1131
Recap of lecture on Monday, Apr. 24 The ratio of neutrons to protons (N/Z) helps to determine the stability of a nucleus. Z Stable N/Z 1-20 1.0 to 1.1 20-40 1.1 to 1.25 40-80 1.25 to 1.50 > 83 Unstable (or radioactive) If N/Z is too large, the nucleu
Colorado - CHEM - 1131
Recap of lecture on Wednesday, Apr. 26: Radioactive dacays are first order processes and obey the rate law ln(N/No) = -kt, where N = the number of radioactive nuclides. N is also proportional to the mass of the nuclide. A second useful relationship f