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Course: CMPT 413, Fall 2009
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#4: Homework CMPT-413 Reading: NLTK Tutorial (http://nltk.sf.net/docs.html); Chapter 5 (Sections 5.1 to 5.4.2) and Chapter 7 Distributed on Feb 21; due on Mar 7 Anoop Sarkar anoop@cs.sfu.ca Only submit answers for questions marked with . (1) Once we have some text that has been tagged with part of speech labels, we can chunk words together into non-overlapping spans of text. Each chunk corresponds to some...

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#4: Homework CMPT-413 Reading: NLTK Tutorial (http://nltk.sf.net/docs.html); Chapter 5 (Sections 5.1 to 5.4.2) and Chapter 7 Distributed on Feb 21; due on Mar 7 Anoop Sarkar anoop@cs.sfu.ca Only submit answers for questions marked with . (1) Once we have some text that has been tagged with part of speech labels, we can chunk words together into non-overlapping spans of text. Each chunk corresponds to some meaningful unit, e.g. we can find all chunks that are noun phrases. Here is an example sentence from the Wall Street Journal where the noun phrases are marked up with brackets: [ The/DT market/NN ] for/IN [ system-management/NN software/NN ] for/IN [ Digital/NNP 's/POS hardware/NN ] is/VBZ fragmented/JJ enough/RB that/IN [ a/DT giant/NN ] such/JJ as/IN [ Computer/NNP Associates/NNPS ] should/MD do/VB well/RB there/RB ./. In this question, we will use regular expressions on the part of speech tags to identify chunks. First, we need to put the input sentence into the right format for nltk lite: from nltk_lite import chunk tagged_text = """ The/DT market/NN for/IN system-management/NN software/NN for/IN Digital/NNP 's/POS hardware/NN is/VBZ fragmented/JJ enough/RB that/IN a/DT giant/NN such/JJ as/IN Computer/NNP Associates/NNPS should/MD do/VB well/RB there/RB ./. """ input = chunk.tagstr2tree(tagged_text) print input Examine the output after executing the above. You will notice that the function tagstr2tree automatically puts a S chunk around the entire sentence (it assumes that the input is a full sentence). We are interested only in noun phrase (NP) chunks here, so we can ignore the S chunk. We can now use the nltk lite regular expression chunker to identify some NP chunks in the sentence: cp = chunk.Regexp("NP: {<DT><NN>}") print cp.parse(input) The above code finds the following two NP chunks in the sentence: (NP: ('The', 'DT') ('market', 'NN')) (NP: ('a', 'DT') ('giant', 'NN')) You can provide multiple regexp patterns for identifying NPs (and also provide comment strings) using this syntax: grammar = r""" NP: {<DT>?<JJ>*<NN>} # chunk determiners, adjectives and nouns {<NNP>+} # chunk sequences of proper nouns """ cp = chunk.Regexp(grammar) Note that the order of the patterns is important. You can debug your regexp patterns by using cp.parse(input, trace=1) which provides detailed information on the order of the pattern matching. Provide a program that chunks the example sentence provided and identifies all five of the noun phrase chunks as shown in the marked up example above. Print out the chunked output for the sentence. 1 (2) Provide a regular expression based chunker (using the nltk lite chunker) to identify noun phrase chunks for the CONLL-2000 chunk dataset which contains Wall Street Journal text that has been chunked by human experts. Your chunker should at least have 91% accuracy. Since you will have to deal with a large variety of noun phrase chunks you will need to generalize your regexp patterns. A tag pattern is a sequence of part-of-speech tags delimited using angle brackets, e.g. <DT><JJ><NN>. Tag patterns are the same as the regular expression patterns we have already seen, except for two differences which make them easier to use for chunking. First, angle brackets group their contents into atomic units, so <NN>+ matches one or more repetitions of the tag NN; and <NN|JJ> matches the NN or JJ. Second, the period wildcard operator is constrained not to cross tag delimiters, so that <N.*> matches any single tag starting with N. To test the accuracy of your chunker use the built-in nltk lite function: from nltk_lite import chunk from nltk_lite.corpora import conll2000, extract cp = chunk.Regexp("NP: {<DT><NN>}") print chunk.accuracy(cp, conll2000.chunked(files='test', chunk_types=('NP',))) You can compare the output of your chunker with the gold standard to find out which chunks you are missing. For instance, the following code prints the gold standard and then prints the chunker output: from nltk_lite import chunk from nltk_lite.corpora import conll2000, extract gold_tree = conll2000.chunked(files='train', chunk_types=('NP',)).next() print gold_tree print cp.parse(gold_tree.flatten()) Use the following steps in your development process: a. Write down a regexp chunker using tag patterns that can identify the following examples of noun phrases: another/DT sharp/JJ dive/NN trade/NN figures/NNS any/DT new/JJ policy/NN measures/NNS earlier/JJR stages/NNS Panamanian/JJ dictator/NN Manuel/NNP Noriega/NNP his/PRP$ Mansion/NNP House/NNP speech/NN 3/CD %/NN to/TO 4/CD %/NN more/JJR than/IN 10/CD %/NN the/DT fastest/JJS developing/VBG trends/NNS b. Write a tag pattern to match noun phrases containing plural head nouns, e.g. many/JJ types/NNS, two/CD weeks/NNS, both/DT new/JJ positions/NNS. Try to do this by generalizing the tag pattern that handled singular noun phrases. c. Write tag pattern to cover noun phrases that contain gerunds, e.g. the/DT receiving/VBG end/NN, assistant/NN managing/VBG editor/NN. d. Write one or more tag patterns to handle noun coordinated phrases, e.g. July/NNP and/CC August/NNP, all/DT your/PRP$ managers/NNS and/CC supervisors/NNS, company/NN courts/NNS and/CC adjudicators/NNS. e. Compare your output with the gold standard output on some randomly chosen examples from the training data of CoNLL-2000 dataset. See if there are any NP chunks missing in your output and find tag patterns that will include them. Generalize your tag patterns to avoid having one pattern per example. 2 (3) Warning: only attempt this question after you have finished Question 2. The file genia3.02-small-pos.txt contains a small amount of text extracted out of bio-medical journals. In this question, we will test how well the chunker you have developed on the Wall Street Journal can deal with text in a completely different domain. Note that you will now have to deal with the raw text and convert it into a format suitable for use with your chunker. As you can imagine, the text in this corpus can be very different. Here is a typical example sentence from our bio-medical corpus: These/DT findings/NNS should/MD be/VB useful/JJ for/IN therapeutic/JJ strategies/NNS and/CC the/DT development/NN of/IN immunosuppressants/NNS targeting/VBG the/DT CD28/NN costimulatory/NN pathway/NN ./. But does dealing with a different domain affect your chunker? Run your chunker on this dataset. Depending on the regexp patterns you created for the WSJ text, you may have to tweak your regexp chunker with some additional rules. Note that we cannot test accuracy on this domain since we do not have human labeled data. We will compare your output with our own chunker on this domain. (4) In nltk lite you can easily represent trees. For instance: from nltk_lite.parse import bracket_parse sent = '(S (S (NP Kim) (V arrived)) (conj or) (S (NP Dana) (V left)))' tree = bracket_parse(sent) print tree[0] left_tree = tree[0] print left_tree[0] The above code will print out two constituents of the tree: (S: (NP: 'Kim') (V: 'arrived')) (NP: 'Kim') Write a program that prints out all the constituents of a tree, one per line, using the nltk lite tree handling functions shown above. For the above input it should produce: (S: (S: (NP: 'Kim') (V: 'arrived')) (conj: 'or') (S: (NP: 'Dana') (V: 'left'))) (S: (NP: 'Kim') (V: 'arrived')) (NP: 'Kim') (V: 'arrived') (conj: 'or') (S: (NP: 'Dana') (V: 'left')) (NP: 'Dana') (V: 'left') (5) (6) Write down two trees, one for each reading of the phrase old men and women. Run the recursive descent parser demo: from nltk_lite.draw import rdparser rdparser.demo() 3 (7) Chapter 7 of the NLTK tutorial provides a good overview of the grammar development process that can be used to describe the syntax of natural language sentences. The notion of a context-free grammar allows us to describe nested constituents unlike a chunking grammar. Based on the ideas provided in Chapter 7 of the NLTK tutorial and the lecture notes, write a context-free grammar that can recognize the following sentences (taken from the NLTK tutorial, Chapter 7): (27a) (27b) (27c) (27d) Jodie won the 100m freestyle 'The Age' reported that Jodie won the 100m freestyle Sandy said 'The Age' reported that Jodie won the 100m freestyle I think Sandy said 'The Age' reported that Jodie won the 100m freestyle Write down your context-free grammar using the following format: productions = ''' S -> NP VP VP -> V NP | V NP PP V -> "saw" | "ate" NP -> "John" | "Mary" | "Bob" | Det N | Det N PP Det -> "a" | "an" | "the" | "my" N -> "dog" | "cat" | "cookie" | "park" PP -> P NP P -> "in" | "on" | "by" | "with" ''' You can then use your grammar to parse an input sentence. For example, the following code prints out a parse for the sentence Mary saw Bob when analyzed using the above grammar. from nltk_lite import parse from nltk_lite import tokenize grammar = parse.cfg.parse_grammar(productions) rd_parser = parse.RecursiveDescent(grammar) sent = list(tokenize.whitespace("Mary saw Bob")) for p in rd_parser.get_parse_list(sent): print p Print out the parses for the example sentences above using your context-free grammar. (8) A Treebank is a corpus of sentences such that each sentence is provided with it's most plausible syntax tree as determined by a human expert. You are provided with a Treebank for sentences from the Air Travel Information Service (ATIS) domain in the file atis3.treebank. From this Treebank, extract a context-free grammar. Provide the context-free grammar as a text file. Trim down the number of rules in your context-free grammar, either based on the frequency of the rule or manual inspection or both (this step is necessary to reduce the time taken by the parser). Use your reduced context-free grammar with the nltk lite recursive descent parser to parse all the sentences in the file atis.test. You may need to add lexical rules (e.g. NNP Miami) in order to parse some of these sentences. Submit your Python code and a text file containing a list of parse trees, one for each sentence in atis.test. (9) 4
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Sveriges lantbruksuniversitet - CMPT - 413
Homework #5: CMPT-413Reading: NLTK Tutorial (http:/nltk.sf.net/docs.html); Chapter 8 and Chapter 9 Distributed on Mar 7; due on Mar 21Anoop Sarkar anoop@cs.sfu.caOnly submit answers for questions marked with . (1) Write down a grammar that deri
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop1/15/071Natural Language Processing (NLP) NLP is the application of a computational theory of human language Language is the predominant repository of human interaction
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop1/15/071Formal Languages: Recap Symbols: a, b, c Alphabet : finite set of symbols ! = {a, b} String: sequence of symbols bab Empty string: &quot; Define: !&quot; = ! # {&quot;} Se
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop1/19/071Algorithms for FSMs(finite-state machines) Recognition of a string in a regular language: is a string accepted by an NFA? Conversion of regular expressions to
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop1/22/071Finite-state transducers a : 0 is a notation for a mapping between two alphabets a ! &quot;1 and 0 ! &quot;2 Finite-state transducers (FSTs) accept pairs of strings Fini
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopFebruary 12, 20071 / 32Quick guide to probability theoryP(X) means probability that X is trueP(baby is a girl) = 0.5 percentage of total number of babies that are girls
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop2/9/071n-grams A simple model of language Computes a probability for observed input Probability is likelihood of observation being generated by the same source as the
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopFebruary 16, 20071 / 27How good is a modelSo far we've seen the probability of a sentence: P(w0 , . . . , wn ) What is the probability of a collection of sentences, that
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop4/16/071Sequence Learning British Left Waffles on Falkland Islands (N, N, V, P, N, N) (N, V, N, P, N, N) Segmentation (b, i, b, i, b, b, i, b, i, b, i, b, i, b, i,
Sveriges lantbruksuniversitet - CMPT - 413
Sveriges lantbruksuniversitet - CMPT - 413
p(a|.) p(b|.) p(e|.) p(q|.) p(r|.)p(.|q)0.4 0.6 0 0.2 0.8p(.|r)0.1 0.9 0 0.3 0.7p(.|start)0 0 1.0 1.0 0QuickTime an TIFF (LZW) decom are needed to see thisp(a,q|.) p(b,q|.) p(a,r|.) p(b,r|.) totals input = bbba best(q) best(r) e 1.0 0p
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop2/9/071Automatic Speech Recognition Acoustic observations: signal processing to extract energy levels at each frequency level Observation sequence o is composed of acou
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopMarch 2, 20071 / 29Parts of SpeechWe have seen that individual words can be classified into groups or classes that we call parts of speechDeterminers: a, the Verbs: arr
Sveriges lantbruksuniversitet - CMPT - 413
CMPT 413 Computational LinguisticsAnoop Sarkarhttp:/www.cs.sfu.ca/~anoop3/21/071Context-free Grammars Set of rules by which valid sentences can be constructed. Example:Sentence ! Noun Verb Object Noun ! trees | parsers Verb ! are | grow Ob
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopMarch 28, 20071 / 36Why are parsing algorithms important?A linguistic theory is implemented in a formal system to generate the set of grammatical strings and rule out un
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopMarch 28, 20071 / 30Probabilistic CFG (PCFG)S VP VP PP NP NP NP NP V P NP VP 1 V NP 0.9 VP PP 0.1 P NP 1 NP PP 0.25 Calvin 0.25 monsters 0.25 school 0.25 imagin
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopApril 17, 20071 / 34Writing a grammar for natural language: Grammar DevelopmentGrammar development is the process of writing a grammar for a particular language This can
Sveriges lantbruksuniversitet - CMPT - 413
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopMarch 28, 20071 / 19Lexical SemanticsSo far, we have listed words in our lexicon or vocabulary assuming a single meaning per word: Consider n-grams P (wi | wi -2 , wi -1
Sveriges lantbruksuniversitet - CMPT - 413
CMPT-413 Computational LinguisticsAnoop Sarkar http:/www.cs.sfu.ca/anoopApril 4, 20071 / 28Discourse ProcessingMultiple sentences, dialogs Human-human (Switchboard corpus) and human-computer interaction (ATIS corpus) New phenomena at the dis
Berkeley - IEOR - 263
Fall 08, IEOR 263A Homework 10 Solutions 1. We have that the transition probability matrix of {Xnd } is P d and by definition of d, gcd{n 1 : (nd) pii &gt; 0} = 1, then {Xnd } is aperiodic. Consider the matrix P = 0 1 1 . 0In this case d = 2, {Xn } i
Iowa State - ECON - 101
Economics &quot;The study of choice under conditions of scarcity&quot; Scarcity Individual consumers: Spending power (or income) &amp; time Society: Factors of Production: (Land, Labor, Capital, Human Capital) Land: All gifts of nature (land, natural resources, et
Wisconsin - BOTANY - 422
PERSPECTIVES2006. The number of grains will be limited (~100 interstellar and ~1000 cometary grains), but but determination of cosmic ray exposure ages of interstellar dust, cometary GEMS/IDPs, and crystalline silicates will be very revealing. Techn
Iowa State - CPRE - 185
Prelab for Lab 2For CprE 185 labs January 22 and 23You should have a basic understanding of variables and how to declare them in C before you come to lab this week. This prelab is meant to help you learn these concepts.References The following re
Iowa State - CPRE - 185
Problems Boolean logic program to review lab 9 o Write a program that will use logical operations to model the following truth table. A B C O 0 0 0 0 1 1 1 1 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 1 1 1 0 0 1 1 0 0Play with structures: o Create a structure
Berkeley - ASTRO - 00177408
-55.955000 -42.915000 148.22206 47.985281 -42.915000 -34.765000 203.50748 60.794655 -34.765000 -20.095000 138.50015 45.039814 -20.095000 -7.0550000 159.26452
Berkeley - ASTRO - 00177408
-55.955000 -42.915000 148.22206 47.985281 -42.915000 -34.765000 203.50748 60.794655 -34.765000 -20.095000 138.50015 45.039814 -20.095000 -7.0550000 159.26452
Berkeley - ASTRO - 00177408
# Time [days] Mag Magerr Band Uplim Ref 0.00120 19.5 -0.2 V yes GCN4516 0.00138 18 -0.2 V yes GCN4509 0.00377 20.4 -0.2 B yes GCN4516 0.0
Berkeley - ASTRO - 00177408
360.288 -0.2 0 no GCN4510 1139.62 19.1 0.5 Rc no 1735.78 18.1 0.2 none yes 2039.9 19.2 0.4 Rc no 2879.71 19.1 0
Berkeley - ASTRO - 00177408
360.288 5.139853e+03 0.000000e+00 no GCN4510 1139.62 9.793788e-05 4.510206e-05 Rc no 1735.78 2.460088e-04 4.531650e-05 none yes 2039.9 8.932041e-05 3.290686e-05
Berkeley - ASTRO - 00177408
1735.78 2.460088e-04 4.531650e-05 none yes 2879.71 9.793788e-05 1.804082e-05 Rc yes 42120 3.555910e-04 6.550228e-05 R yes 48960.3 1.073868e-05 1.978137e-06
Berkeley - ASTRO - 00177408
11.410000 34.230003 4.8801518 0.15476824 25.162871 34.230003 55.420002 -7.1583672 3.4018788 327.59974 55.420002 84.760002 15.829904 -2.3030588 299.73961
Berkeley - ASTRO - 00177408
11.4100 34.2300 -0.697075 0.799869 34.2300 55.4200 6.68627 1.05591 55.4200 84.7600 -3.93089 0.648640 84.7600 141.810 9.20444 1.45795 141.810 146.700 27.497
Berkeley - ASTRO - 00177408
chi^2/nu= 277.78127 / 193The fit is rejectable at 99.993871 % Confidence -42.9150 -34.7650 201.17938 -34.7650 -20.0950 219.12440 -20.0950 -7.05500 233.67896 -7.05500 -3.7950
Berkeley - ASTRO - 00177408
&lt;html&gt;&lt;head&gt;&lt;title&gt;Your NED Search Results&lt;/title&gt;&lt;/head&gt;&lt;body background=&quot;/pics/NEDbgHelp.gif&quot; bgcolor=&quot;#FFFFFF&quot;&gt;&lt;center&gt;&lt;font size=6 color=&quot;#CC3333&quot;&gt;&lt;b&gt;N&lt;/b&gt;&lt;/font&gt;&lt;font size=4 color=&quot;#000000&quot;&gt;&lt;b&gt;ASA/IPAC&lt;/b&gt;&lt;/font&gt;&amp;nbsp;&lt;font size=6 color=&quot;#CC
Berkeley - ASTRO - 00177408
120.556 121.049 45.8159 10.81121.049 121.336 39.0268 12.7458121.336 121.994 48.5438 9.27936121.994 122.412 49.6199 11.6955122.412 122.716 73.6888 17.0173122.716 123.857 46.1726 6.85523123.857 123.997 80.005 26.129123.997 124.293 42.361 13.6598
Berkeley - ASTRO - 00177408
Source Contamination: 5.26E-08 +/- 1.5E-08 cts/s
Berkeley - ASTRO - 00177408
#ra dec hmag dhmag053.962761 17.109814 13.829 0.025053.944143 17.116085 16.804 0.137053.989731 17.119774 16.009 0.077053.955925 17.112076 13.050 0.024054.056998 17.110207 12.890 0.025054.025218 17.114105 15.171 0.044054.046284 17.102865
Berkeley - ASTRO - 00177408
;instrument XRT;exposure 64937.415;xunit kev;bintype counts 0.0000000 0.0049999999 13.416170 1.00000 0.0049999999 0.0099999998 13.464069 1.00000 0.0099999998 0.015000000 13.511968 1.0
Berkeley - ASTRO - 00177408
;instrument XRT;exposure 269.05439;xunit kev;bintype counts 0.0000000 0.0049999999 14.516683 1.00000 0.0049999999 0.0099999998 14.568504 1.00000 0.0099999998 0.015000000 14.620325 1.0
Berkeley - ASTRO - 00177408
#ra dec rmag drmag54.22221817.13006516.2050.00553.98003217.11030819.2820.07054.22023517.10499716.2420.00554.26303917.10549519.6410.09854.28926317.10327016.6720.00754.28071717.10326216.8100.00853.83690717.09809516.8320.008
Berkeley - ASTRO - 00177408
chi^2/nu= 90.229770 / 328.000The fit is rejectable at 2.1718713e-40 % Confidence#index t1 t2 fade_index delta_mag_pk hindex dhindex rate1 drate1 rate2 drate2 logr dlogr 0 0.1206 0.2380 -3.01 0.0 0.17 0.08 1.15E+0
Berkeley - ASTRO - 00177408
# t1 t2 hardness error 0.12055600 0.12133600 -0.14044738 0.19090244 0.12133600 0.12199400 0.082234260 0.19072434 0.12199400 0.12271600 0.26708790 0.15921771 0.12271600 0.12385700
Berkeley - ASTRO - 00177408
output00177408000_999/sw00177408000xpcw2po_cl.evtoutput00177408001_999/sw00177408001xpcw2po_cl.evtoutput00177408002_999/sw00177408002xpcw2po_cl.evtoutput00177408003_999/sw00177408003xpcw2po_cl.evtoutput00177408004_999/sw00177408004xpcw2po_cl.evt
Berkeley - ASTRO - 00177408
# t1 t2 dt rad_min rad_max cts err scl bg bg_rat wt 0.120556 0.120813 0.000257 0. 16. 10.60 3.52 0.867841 5.000000 0.279570 1 0.120813 0.121049 0.000237 0. 16. 9.00
Berkeley - ASTRO - 00177408
tmin 2.0695142e-05tmin 0.00011504599
Berkeley - ASTRO - 00177408
tmin 32.099833tmin 181.93968 364.16423 2064.0582 0.20484306 0.033045668 5 2064.0582 46869.069 0.12453600 0.012811805 9tmax 46869.069
Berkeley - ASTRO - 00177408
# t1 t2 dt rad_min rad_max cts err scl bg bg_rat wt 0.120556 0.120813 0.000257 0. 16. 10.60 3.52 0.867841 5.000000 0.279570 1 0.120813 0.121049 0.000237 0. 16. 9.00
Berkeley - ASTRO - 00177408
# tmin tmax 0.254029 468.41556 [ksec];instrument XRT;exposure 60143.753;xunit kev;bintype counts0.000000 0.010000 0.000000 0.0000000.010000 0.020000 0.000000 0.0000000.020000 0.030000 0.000000 0.0000000.030000 0.040000 0.00000
Berkeley - ASTRO - 00177408
# tmin tmax 0.254029 468.41556 [ksec];instrument XRT;exposure 60143.753;xunit kev;bintype counts0.000000 0.010000 0.000000 0.0000000.010000 0.020000 0.000000 0.0000000.020000 0.030000 0.000000 0.0000000.030000 0.040000 0.00000
Berkeley - ASTRO - 00177408
# tmin tmax 0.12055600 5.38475 [ksec];instrument XRT;exposure 266.08283;xunit kev;bintype counts0.000000 0.010000 0.000000 0.0000000.010000 0.020000 0.000000 0.0000000.020000 0.030000 0.000000 0.0000000.030000 0.040000 0.00000
Berkeley - ASTRO - 00177408
# tmin tmax 0.12055600 5.38475 [ksec];instrument XRT;exposure 266.08283;xunit kev;bintype counts0.000000 0.010000 0.000000 0.0000000.010000 0.020000 0.000000 0.0000000.020000 0.030000 0.000000 0.0000000.030000 0.040000 0.00000
Berkeley - ASTRO - 00177408
Wavdetect Sources with S/N&gt;3: # ra dec err [&quot;] signif counts steady? -log10(Prob_steady) 054.03492117.3458570.16673.8725.0 0-323.0 154.10150117.3244240.51014.141.8 1-0.7 254.01671417.2622120.65812.338.3 1-0.1 354.155
Berkeley - ASTRO - 00177408
output00177408000_999/sw00177408000xwtw2po_cl.evtoutput00177408001_999/sw00177408001xwtw2po_cl.evtoutput00177408002_999/sw00177408002xwtw2po_cl.evtoutput00177408003_999/sw00177408003xwtw2po_cl.evtoutput00177408004_999/sw00177408004xwtw2po_cl.evt
Berkeley - ASTRO - 00177408
SIMPLE = T / file does conform to FITS standardBITPIX = 8 / number of bits per data pixelNAXIS = 0 / number of data axesEXTEND = T / FITS dataset may contain extensio
Berkeley - ASTRO - 00177408
# Ep dEp lprob lEiso dlEiso67.040 0.054 3.49e-05 121.421 0.07467.097 0.061 3.07e-04 121.521 0.08467.163 0.070 5.88e-04 121.521 0.08467.238 0.081 8.49e-04 121.521 0.08467.325 0.092 1.10e-03 121.521 0.08467.423 0.106 1.29e-03 121.521 0.08467.537
Berkeley - ASTRO - 00177408
# Ep lEiso37.400 121.94840.123 121.88245.004 121.87446.499 121.58146.920 121.42847.877 121.33148.473 121.58348.868 121.63749.323 121.34449.341 121.34849.662 121.44650.219 121.40150.425 121.54350.808 121.47751.066 121.54551.173 121.583
Berkeley - ASTRO - 00177408
# Ep dEp lprob lNiso dlNiso67.040 0.054 3.49e-05 137.769 0.38167.097 0.061 3.06e-04 137.769 0.38067.163 0.070 5.87e-04 137.769 0.38067.238 0.081 8.65e-04 137.769 0.38067.325 0.092 1.10e-03 137.769 0.38067.423 0.106 1.29e-03 137.769 0.38067.537
Berkeley - ASTRO - 00177408
# Ep lNiso37.362 137.60340.096 137.25245.016 138.22146.520 138.10846.941 137.70147.899 137.88448.495 138.38548.881 138.62249.337 137.33249.355 137.35049.676 137.78350.234 137.58650.440 138.20350.817 137.91451.076 137.64251.182 137.219
Berkeley - ASTRO - 00177408
# x=Log_e(Beaming Fraction) y=Log_e(Egam/10^52 erg) z=Log_e(Tjet/days)# mean(x)= -4.6913 xdown= -5.0763 xup= -4.3622# mean(y)= -2.8349 ydown= -3.4214 yup= -2.2964# mean(z)= 1.8541 zdown= 1.3195 zup= 2.2750-5.9761 -3.7625 0.1152-5.8878 -3.7402
Berkeley - ASTRO - 00177408
Ep=55.60 Chi/nu= 51.27/57 (0.899)