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Intra1997

Course: CHM 6315, Fall 2009
School: Neumont
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des FACULT ARTS et des SCIENCES - DPARTEMENT de CHIMIE SIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6310 Synthse stroslective Vendredi le 14 Mars 1997 NOM DU PROFESSEUR: A. CHARETTE SALLE: HEURE: Z-225 9h30-12h30 ATTENTION: - Les notes de cours et les modles molculaires sont permis. Rpondre dans un cahier crire vos NOM, PRNOM et CODE PERMANENT sur la premire page. ******************** QUESTION 1 (25...

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des FACULT ARTS et des SCIENCES - DPARTEMENT de CHIMIE SIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6310 Synthse stroslective Vendredi le 14 Mars 1997 NOM DU PROFESSEUR: A. CHARETTE SALLE: HEURE: Z-225 9h30-12h30 ATTENTION: - Les notes de cours et les modles molculaires sont permis. Rpondre dans un cahier crire vos NOM, PRNOM et CODE PERMANENT sur la premire page. ******************** QUESTION 1 (25 points) a) Proposer un modle d'tat de transition qui explique la formation du produit majoritaire 2 (Helv. Chim. Acta 1988, 71, 354 et J. Org. Chem. 1989, 54, 693, 702) (15 pts). Propose a transition state model that accounts for the formation of the major diastereomer 2 (15 pts). 1. N O H O D-glyceraldehyde (1) O S Bu4NF SiMe3 S N O N OH O O S 3 K S N OH + O O 2 O 5% 95% 2. Oxidation BH O 3 b) Proposer une synthse alternative qui vous permettrait de gnrer le diastroisomre 3 de faon majoritaire partir du D-glycraldhyde. Justifier par un modle (10 pts). Propose an alternative synthesis that would allow you to efficiently prepare diastereomer 3 starting from D-glyceraldehyde. Justify with a model (10 pts). QUESTION 2 (25 points) Proposer quatre faons de gnrer l'alcool 4 ou son nantiomre (sous forme nantiomriquement enrichie) partir d'un prcuseur achiral. Chacune des faons doit impliquer une disconnection diffrente: le lien form dans chacune des synthses, lors de l'introduction de la chiralit doit tre diffrent; les quatre prcurseurs doivent tre diffrents mais les mmes ractifs chiraux peuvent tre utiliss. Laquelle de vos synthses serait la meilleure (en terme d'excs nantiomre du produit attendu). Propose four routes to alcohol 4 or its enantiomer (in enantioenriched form) starting from an achiral precursor. different A bond disconnection must be involved in each synthesis: the bond that is formed when the chiral center is created must be different in each case; the four precursors must be different but the same chiral reagents can be used. Which one would be the most efficient as far as the enantiomeric excess of the produit is concerned. OH OH 4 FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIE SIGLE du COURS: CHM 6310 / 14 Mars 1997 PAGE: 2 de 2 QUESTION 3 (25 points) Proposer un mcanisme pour la transformation suivante en prenant bien soin d'indiquer la structure et la strochimie de tous les intermdiaires. Propose a mechanism for the following transformation. The structure and stereochemistry of all the intermediates must be clearly shown. OH O OEt OH 5 2. H 3C Br 6 O O O 3. NaN3 4. H2, Pd-C 1. CH3C(OCH3)3, H+ (cat) NH2 O OEt CH3 QUESTION 4 (25 points) a) Proposer un modle d'tat de transition pour les deux ractions A et B en indiquant clairement pourquoi la diastroslectivit est inverse (20 points). Propose a transitio...

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Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6310 Synthse stroslective Vendredi le 27 Fvrier 1998 NOM DU PROFESSEUR: A. CHARETTE SALLE: HEURE: D-560 10h30-13h30ATTENTION:-Les notes
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 NOM DU PROFESSEUR: A. CHARETTE Synthse stroslective SALLE: G-835 Vendredi le 26 Fvrier 1999 HEURE: 8h30-10h30ATTENTION:-Les notes
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 NOM DU PROFESSEUR: A. CHARETTE Synthse stroslective SALLE: D-560 Vendredi le 10 Mars 2000 HEURE: 14h00-17h00ATTENTION:-Les notes d
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 NOM DU PROFESSEUR: A. CHARETTE Synthse stroslective SALLE: G-815 Vendredi le 30 Mars 2001 HEURE: 2 - 5 pmATTENTION:-Les notes de c
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 NOM DU PROFESSEUR: A. CHARETTE Synthse stroslective SALLE: G-835 Vendredi le 28 Fvrier 2003 HEURE: 9h - 12hATTENTION:-Les modles m
Neumont - CHM - 6315
FACULT DES ARTS ET DES SCIENCES DPARTEMENT DE CHIMIESIGLE DU COURS: CHM 6315 TITRE DU COURS: Synthse stroslective DATE DE L'EXAMEN: Mardi, le 2 mars 2004 NOM DU PROFESSEUR: Andr Charette SALLE: Z-315 HEURE: De 14 h 30 17 h 30** ATTENTION: Seuls
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Mardi le 1er Mars 2005 NOM DU PROFESSEUR: SALLE: HEURE: A. CHARETTE G-415 13h00-16h00ATTENTION: Les notes de cour
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Mardi 28 fvrier 2006 NOM DU PROFESSEUR: SALLE: Z-220 HEURE: 9h - 12h A. CHARETTEATTENTION:-Les modles molcula
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Mardi 20 fvrier 2007 NOM DU PROFESSEUR: SALLE: Z-317 HEURE: 9h - 12h A. CHARETTEATTENTION:-Les modles molcula
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Jeudi 21 fvrier 2008 NOM DU PROFESSEUR: SALLE: Z-305 HEURE: 9h - 12h A. CHARETTEATTENTION:-Les notes de cours
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 NOM DU PROFESSEUR: A. CHARETTE Synthse stroslective SALLE: G-815 Vendredi le 28 Fvrier 2003 HEURE: 9h - 12hATTENTION:-Les modles m
Neumont - CHM - 6315
FACULT DES ARTS ET DES SCIENCES DPARTEMENT DE CHIMIESIGLE DU COURS: CHM 6315 TITRE DU COURS: Synthse stroslective DATE DE L'EXAMEN: Mardi, le 2 mars 2004 NOM DU PROFESSEUR: Andr Charette SALLE: Z-315 HEURE: De 14 h 30 17 h 30** ATTENTION: Seuls
Neumont - CHM - 6315
Question 1 TMSCl, Et3N LiHMDS, CH2Cl2, -78 C, 30 minRL Me Me ATBSOO H Me TBSO OH O OTBS RLOOTBSBF3OEt2, -78 C 30 min, 85%MeMeMei-Pr TBSOO H H H Me Me OTBS RL Li TMS O OTBS RL Me3Si H H H RLH MeFelkin-Anh TS (6 pts)O BF3i-Pr
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Mardi 28 fvrier 2006 NOM DU PROFESSEUR: SALLE: Z-220 HEURE: 9h - 12h A. CHARETTE* SOLUTIONS * QUESTION 1 (20 poin
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Mardi 20 fvrier 2007 NOM DU PROFESSEUR: SALLE: Z-317 HEURE: 9h - 12h A. CHARETTEATTENTION:-Les modles molcula
Neumont - CHM - 6315
FACULT des ARTS et des SCIENCES - DPARTEMENT de CHIMIESIGLE du COURS: TITRE du COURS: DATE de L'EXAMEN: CHM 6315 Synthse stroslective Jeudi 21 fvrier 2008 NOM DU PROFESSEUR: SALLE: Z-305 HEURE: 9h - 12h A. CHARETTEATTENTION:-Les notes de cours
Ohio State - MATH - 153
MATH 153 - AUTUMN QUARTER, TWO THOUSAND AND TWO TEACHING ASSISTANT: Cosmin ROMAN office: Math Tower 529 office phone: 292-1923 e-mail: cosmin@math.ohio-state.edu webpage: http:/www.math.ohio-state.edu/~cosmin/Math153.html Note: mind the capital "
Ohio State - MATH - 254
CALCULUS WITH ANALYTIC GEOMETRY - MATH 254 - SP QT 2004LECTURER: Cosmin ROMAN office: Math Tower 529 office phone: 292-1923 e-mail: cosmin@math.ohio-state.edu OFFICE HOURS: T,R 6:00pm-7:25pm; F 10:30am-12:00 (also by appointment) TEXT: Calculu
Ohio State - MATH - 150
MATH 150AUTUMN 2001TA: Cosmin ROMAN office: Math Tower (MW) 529 phone: 292-1923 e-mail: cosmin@math.ohio-state.edu webpage: http:/www.math.ohio-state.edu/~cosmin/Math150.html Office Hours: Tuesday 9:30-11:30 AM; Wednesday 8:00-9:15 AM; by appo
Ohio State - MATH - 150
SOLUTIONS SAMPLE MIDTERM 2 AUTUMN 2000 AND SPRING 2001MATH 150 AU01Comment: no number computation is presented, but rather the method used . AU 2000 1. (1) false: log(4x3 ) = log(4) + log(x3 ) = log(4) + 3 log(x) (2) false: 2x = eln(2)x (3) false:
Ohio State - MATH - 150
Math 150Final ExamSample Exams QuestionsSp 20011. Let g ( x ) = 7 x - 2 and f (x ) = x 2 - 3 . f ( x) a) Find the domain of . g(x) b) Find f (4) - g (4 ) . c) Find a formula for ( f o g )( x) . d) Find a formula for g -1 . 2. Factor the polyno
Ohio State - MATH - 150
SAMPLE EXAM SOLUTIONSCOSMIN ROMAN1. autumn 20003 2 f (x) g(x)(1) (a) g(x) = 0 2x - 3 = 0 x =3 2so the domain ofis all real numbers except(b) f (4) - g(4) = (42 + 4) - (2 4 - 3) = 20 - 5 = 15 (c) (f g)(x) = f (g(x) = f (2x-3) = (2x-3)2
Ohio State - MATH - 150
POLAR COORDINATES - INTERESTING GRAPHSCOSMIN ROMANStart with graphs of functions of the form r = sin(k x), where k = 1, 2, 3 etc (keep in mind that the corresponding graphs for cosine are the very same ones, only rotated 90 degrees counterclockwi
Ohio State - MATH - 150
POLAR COORDINATES - INTERESTING GRAPHS, PART 2COSMIN ROMANHere we have graphs of the form r = a + b sin(). The important (and interesting) issue here is not how big a and b are, but rather how big they are with respect to each other. The first thr
Ohio State - MATH - 132
MATH 132WINTER 2001TA: Cosmin ROMAN office: Math Tower (MW) 529 phone: 292-1923 e-mail: cosmin@math.ohio-state.edu webpage: http:/www.math.ohio-state.edu/ cosmin/Math132.html Office Hours: MW 9:30-10:20; T 11:30-12:20 Homework Turn-in Schedule
Ohio State - MATH - 132
QUIZ # 1MATH 132 WI01Name (1p): . Problem: Let f be the following function: f (x) = Compute the following limits: a) (6p)x0 x+x2 -x-x2 -x-x2 x+x2if x > 0 if x < 0lim f (x)Answer: because of multiple definitions, we need to compute partial l
Ohio State - MATH - 132
QUIZ # 2MATH 132 WI01Name (1p): . Problem (9p): Find the equation of the tangent line to the following curve at the given point. f (x) = x x+1(-2, 2) Answer: we need the slope - and we'll use definition this time: f (-2 + h) - f (-2) lim = lim h
Ohio State - MATH - 132
QUIZ # 3MATH 132 WI01Name (1p): . Problem: Differentiate the following functions: (a) f (x) = ln(x - 1)(x + 1)(x + 3)(x + 5) 2 (b) g(x) = ln(ex ) (3 points) 2 (c) h(x) = ex +x+1 (3 points)(3 points)Answer: (a) Use natural logarithm's propertie
Ohio State - MATH - 132
QUIZ # 4MATH 132 WI01Name (1 point): . Problem: Let f (x) = xe ex . (a) Find intervals of increase/decrease of f (b) Find relative extrema (3 points) (3 points)(c) Find y-intercept, and sketch the graph (you can use straight lines to connect poi
Ohio State - MATH - 132
QUIZ # 5MATH 132 WI01Name (1 point): . Problem: Compute the ones from the following integrals that can be computed (and point out which one cannot): (a) (x4 + 3x2 + 1)(4x3 + 6x) dx (b) (c)1 x2 +12(3 points) (3 points) (3 points) 2x dxex dx
Ohio State - MATH - 132
QUIZ # 6 - OR - LAST QUIZ - OR - FINALLY, IT'S OVER! OR - . WHAT DID I DO TO DESERVE THIS? .MATH 132 WI01Name (1 point): . Problem: Compute the following (1) the definite integralln 3e3x dxln 2(2) the definite integral 1 2x dx x2 + 1 0 (3)
Ohio State - MATH - 132
SAMPLE PROBLEMS MIDTERM IMATH 132 WI01I. Compute the following limits (if the limit is + or - or DNE, state whether it is + or - or DNE; leave the answer in fractions) 4 - x2 x2 x2 - x - 2 lim x2 + 6x + 9 x (7x - 5)2 lim lim x-3(a)(b)(c)x
Ohio State - MATH - 132
SOLUTIONS SHEET FOR SAMPLE PROBLEMS MIDTERM IMATH 132 WI01I. Compute the following limits (if the limit is + or - or DNE, state whether it is + or - or DNE; leave the answer in fractions) 4 - x2 x2 x2 - x - 2 lim Answer: - 4 3 x2 + 6x + 9 x (7x -
Ohio State - MATH - 132
MIDTERM I, FORM AMATH 132 WI00I. Compute the following limits (if the limit is + or - or DNE, state whether it is + or - or DNE; leave the answer in fractions)(a)t2lim3t2 + 1(6 points)(b)4 - x2 x2 x2 - 5x + 6 lim(6 points)(c)
Ohio State - MATH - 132
MIDTERM II, FORM AMATH 132 WI00I. Find the derivatives of the following functions. (a) y = ln(2x + 1) (5 points)(b)y = ln( 41+x2 ) 1-x2(10 points)(c)y = e5x2 -11x+12(10 points)II.(x3 -1 x4+ 2) dx(10 points)III. Given y
Ohio State - MATH - 132
MIDTERM IIIMATH 132 WINTER 2000I. Evaluate the following integralsa)x(7x2 + 2)4 dx(10p)b)x2 + 6x + 3 dx x(10p)Date: 03/03/2000.12MATH 132 WINTER 20006c)0100 + 6x2 dx(10p)d)ex dx ex + 5(10p)(at this point have th
Ohio State - MATH - 132
MIDTERM IIIMATH 132 WINTER 2000I. Evaluate the following integrals a) x(7x2 + 2)4 dx (10p)1 14use substitution: u = 7x2 + 2) du = 7 2x dx = 14x dx The integral then becomes: u4 1 1 du = 14 14 u4 du =du = x dx.1 u5 (7x2 + 2)5 +C = +C 14 5
Ohio State - MATH - 132
FINAL EXAMMATH 132 WINTER 20001. Compute the following limits (leave the answers in fractions) (a) x2 - 4x + 4 x2 x2 + x - 6 lim (8 points)(b)x2 - 9x + 3 x- x - 3 - 72 lim(8 points)2. Find the derivatives of the following function (do not
Ohio State - MATH - 132
FINAL EXAMMATH 132 WINTER 20001. Compute the following limits (leave the answers in fractions) (a) x2 - 4x + 4 x2 x2 + x - 6 lim (8 points)Proof. plug in x = 2 . we get 0 ! so we need to simplify it first: 0 x2 - 4x + 4 (x - 2)(x - 2) x-2 = = 2+
Ohio State - MATH - 415
MIDTERMS' ANSWERSCOSMIN S. ROMANMidterm 2 1. (a) the equation giving the r is: r2 - 4r + 4 = 0 Double solution - r = 2. y = C1 e2t + C2 te2t (b) the equation is now: r2 - 4r + 13 = 0 Complex roots: r = 2 3i y = C1 e2t cos(3t) + C2 e2t sin(3t)
Ohio State - MATH - 131
MATHEMATICAL ANALYSIS FOR BUSINESS II(MATH 131) WINTER QUARTER, 2003Lecturer: Cosmin ROMAN office: Math Tower (MW) 529 office phone: 292-1923 e-mail: cosmin@math.ohio-state.edu web: http:/www.math.ohio-state.edu/~cosmin/Math131.html Office Ho
Ohio State - MATH - 131
REVIEW PROBLEMS - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one begi
Ohio State - MATH - 131
REVIEW PROBLEMS (PINK SHEET LIST) - SOLUTIONS MIDTERM 3READ THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, s
Ohio State - MATH - 131
THINGS TO KNOWThis list comes as a completion of the list I designed for the second midterm. Again, it's not exhaustive, and contains a bare minimum. Notations: x, y stand for variables and/or functions; f , g, h stand for functions; n stands for c
Ohio State - MATH - 131
SAMPLE MIDTERM 1 - PROBLEMSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one begi
Ohio State - MATH - 131
SAMPLE MIDTERM 1 - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one beg
Ohio State - MATH - 131
REVIEW PROBLEMS - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one begi
Ohio State - MATH - 131
REVIEW PROBLEMS - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one begi
Ohio State - MATH - 131
SAMPLE - MIDTERM 3READ THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one begins and wh
Ohio State - MATH - 131
SAMPLE MIDTERM 3 - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one beg
Ohio State - MATH - 131
SAMPLE FINAL EXAM - PROBLEMSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one beg
Ohio State - MATH - 131
SAMPLE FINAL EXAM - SOLUTIONSREAD THIS NOTE: I will be using parenthesis "(", ")" and brackets "[", "]" interchangeably (when there are too many parenthesis involved, I will put brackets to clear the situation a bit out, so you can see where one be
Ohio State - MATH - 132
HOMEWORK PROBLEMSMATH 132 WI00For all chapters the following holds: "Odd-numbered problems are to be done, but not to be turned in." with the exception of chapter 17.5, where all problems from 1 through 8 are to be done. The following problems are
Ohio State - MATH - 132
Ohio State - MATH - 132
SAMPLE MIDTERM II HINTS AND SOLUTIONSMATH 132 - WI '001. f (x) = 2x e-x + x2 e-x (-1) = 2xe-x - x2 e-x = xe-x (2 - x) (always a good idea to factor out common factors, so you get a product of simple factors) When is f (x) = 0? x = 0, e-x is nev
Ohio State - MATH - 132
Your TAFirst Name: Cosmin Last Name: Roman Preference for name to be called by: first (any way to pronounce it will do) Place of origin: Romania more accurately: Transylvania (yes, the place really DOES exist) Office: Math Tower, Room 200 (231 W 1
Ohio State - MATH - 548
HOMEWORK 7MATH 549 SP001 Proof. if lim n2 an exists lim |n2 an | exists lim n2 |an | exists. But 1 then, let's look at the series |an |: if we compare it against (Limit n2 Comparison Test) we get that |an | is convergent (which means an is absol
Ohio State - MATH - 549
HOMEWORK 7MATH 549 SP001 Proof. if lim n2 an exists lim |n2 an | exists lim n2 |an | exists. But 1 then, let's look at the series |an |: if we compare it against (Limit n2 Comparison Test) we get that |an | is convergent (which means an is absol
Ohio State - MATH - 254
OFFICE HOURS & HOMEWORK TURN-IN SCHEDULEOffice: Math Tower 529 (phone number 292-1923) Times: WR 10:30-12:00 and by appointmentHomework: 12.5 due 04/13 12.6 due 04/20 12.8 due 04/27 13.8 due 05/25 - For your convenience here's the list of the ass
Ohio State - MATH - 254
RECITATION POLICYMATH 254 - AUTUMN 2000Your TA name: Cosmin ROMAN office: Math Tower (MW) 529 phone: 292-1923 e-mail: cosmin@math.ohio-state.edu dedicated homepage: www.math.ohio-state.edu/ cosmin/Math254 country of origin: Romania (more exa
Ohio State - MATH - 254
WELCOME TO MATH 254, SPRING 2000!General Information About Your Instructor: office: Math Tower 529 phone number: 292-1923 e-mail: cosmin@math.ohio-state.edu webpage (dedicated): http:/www.math.ohio-state.edu/ ~cosmin/Math254 country of origin: Roma