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Course: MAE 5083, Fall 2008
School: Oklahoma State
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Word Count: 1522

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Oklahoma State - MAE - 4263
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Duke - MATH - 290
The size of LONG is: 4 The size of UNSIGNED LONG is: 4 The size of DOUBLE is: 8 The default LONG is: 1073851552 The default UNSIGNED LONG is: 1073851552 The default DOUBLE is: 7.12893e-270 The smallest LONG is: -2147483648 The largest LONG
Oklahoma State - MAE - 5073
Part ISimple SystemsChapter 1INTRODUCTION and resourcesWhy do we study vibrations? Because most serious dynamic problems in mechanical engineering involve vibrations. There are two main paths by which vibrations lead to trouble: either a reson
Oklahoma State - MAE - 5073
Chapter 2FORMULATION OF TRANSLATIONAL SYSTEMS and review of unitsThe first step in solving any vibrations problem is to identify the physical system and formulate it as a mathematical equation. The simplest systems are those which can be represent
Oklahoma State - MAE - 5073
Chapter 3FORMULATION OF ROTATIONAL SYSTEMS and review of second momentsMany engineering problems involve rotation, and it is not realistic to speak of a single &quot;point&quot; mass. But if we idealize the mass system as rigid, we can write similar differe
Oklahoma State - MAE - 5073
Chapter 4UNDAMPED FREE VIBRATION and static deflectionIn the simplest vibration analyses, damping is neglected, and the motion is the result of initial conditions. These assumptions lead to the first of the Standard Form equations we will study.
Oklahoma State - MAE - 5073
Chapter 5ENERGY METHODS FOR NATURAL FREQUENCY with an introduction to Hamiltonian methodsOne of the most important tasks of the engineer is to find the appropriate mathematical representation of a physical problem. In previous chapters, the govern
Oklahoma State - MAE - 5073
Chapter 6APPROXIMATIONS FOR DISTRIBUTED SYSTEMS and hydrodynamic inertiaThe Conservation of Energy method can be extended to situations that are not strictly single-degree-of-freedom systems, if we have a pretty good idea what is the &quot;mode shape&quot;
National Taiwan University - SOC - 549
FORMULASSociology 549, Paul von HippelDescriptive statisticsMeasures of center1. mode 2. median 3. trimmed mean Y or, for a frequency table, Y = fY 4. mean Y = N N For a dummy variable the mean is p, the proportion of observations with a value
Oklahoma State - MAE - 5073
Exercise 18.1: The probability density of a steady sine-wave A sin !t is not bell-shaped, since it spends more time near the peaks than near x = 0; it extends only over A x A (it is zero outside that range) and spikes at the maximum positive and nega
National Taiwan University - SOC - 549
Sociology 549 - Quantitative Research Techniques in Sociology I Spring 2005 Course web page: http:/sociology.osu.edu/classes/soc549/krivo/Any student who feels s/he may need an accommodation based on the impact of a disability should contact me pri
National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Autumn 2005 Note: This is an edited exam whose answer key differs slightly from the one used in Autumn 2005Midterm (40 points): ANSWER KEY Time allotted: 90 minutes. Be concise. Stick to concepts that were covered in
National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Autumn 2005 Note: This is an edited exam whose answer key differs slightly from the one used in Autumn 2005Midterm questions (40 points) Time allotted: 90 minutes. Be concise. Stick to concepts that were covered in c
National Taiwan University - SOC - 549
Sociology 549, Winter 2006 Instructor: Paul von Hippel Your name_Assignment #2 (37 points+1 extra) due Th 10/12 at the beginning of labGeneral guidelines 1. Get used to working from the formula sheet in your binder. Youll use it for the exams. 2.
National Taiwan University - SOC - 549
Sociology 549 Quantitative Research Techniques in Sociology I Professor Lauren Krivo Spring 2005 Assignment 1: Frequency Distribution This assignment is due in recitation on Wednesday April 6. Turn in your computer printout and your typed discussion
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National Taiwan University - SOC - 549
Sociology 549 Professor Lauren Krivo Study Guide for Final Examination Each of the following are either things that you should be able to do OR are the types of concepts and questions you should be able to answer or explain. The exam will take place
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Paul von Hippel Sociology 549 Practice for final These problems are intended to help students prepare for the final exam. They require skills similar to those needed for the final. However, you should not expect an exact correspondence between the pr
National Taiwan University - SOC - 549
Paul von Hippel Sociology 549, Winter 2006Your name_Pre-final extra problem due T 11/21 at the beginning of lab Note. This problem will not be collected or graded, but you should treat it just like any graded assignment. It will be discussed in l
National Taiwan University - SOC - 549
Sociology 549, Winter 2006 Instructor: Paul von Hippel Your name_Pre-midterm extra problems due Th 10/26 at the beginning of lab Note. These problems will not be collected or graded, but you should treat them just like any graded assignment. They w
National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Winter 2005 Your name_Midterm questions (43 points) Time allotted: 90 minutes. Be concise! General grading guideline: Dont be fussy about rounding error. 1. (8 points) The following graph is linked to the White House
National Taiwan University - SOC - 549
Quantitative Research TechniquesSociology 549Autumn 2006 http:/www.sociology.ohio-state.edu/classes/soc549/vonhippel/index.php Instructor &amp; GTAs Lecture &amp; lab Office hours Phone Mailbox Email Paul von Hippel MW 530-648 PM Psychology 14 MW 6:48-7:30
National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Winter 2005 Your name_Midterm questions (43 points) Time allotted: 90 minutes. Be concise! 1. (8 points) The following graph is linked to the White House web site.a. (1 point) Despite its appearance, I would not ca
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Sociology 549, Winter 2006 Instructor: Paul von Hippel Your name_Assignment #1 (30 points) due Th 10/5 at the beginning of labWrite your answers directly on the assignment, unless instructed otherwise. Problems 1) (1 point) Do SSDS exercise 3 on p
National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Autumn 2004Midterm questions (53 points) Time allotted: 90 minutes Clock yourself! Please write your name and answers on the answer sheet providednot on this question sheet. 1. (4 points) During the week of March 7,
Oklahoma State - MAE - 4263
Function Samples Example 1 Compute saturation temp. of steam, given pressure Pressure (kPa) Temperature (C) 101 #MACRO? Example 2 Compute saturation pressure of steam, given temp. Temperature (C) Pressure (kPa) 100 #MACRO? Example 3 Compute specific
Oklahoma State - MAE - 4263
Ideal wet-steam Cycle Prob.2-1 Station p in KPa T in deg.C v in m3/kg h in KJ/kg s in KJ/kg-K quality INPUTS 1 300 2 40 RESULTS 1 # 300 #MACRO? #MACRO? 1 sat/g 2 sat/f 3 4 1 net # # # # # # 300 40 40 40 40 #MACRO? #MACRO? #MACRO? #MACRO? #MACRO? #MAC
Oklahoma State - MAE - 4263
Ideal with closed FWH Prob.2-3D p No. Kpa cnv 6.89 10 6894.8 Turbine1 15 689.48 FWHa 17 689.48 Turbine2 20 6.89 Condenser 30 6.89 Pump 40 6894.8 FWHb 46 6894.8 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h psi deg.C deg.F KJ/kg 1000 100 10
Oklahoma State - MAE - 4263
Ideal with closed FWH and pump Prob.2-3F p No. Kpa cnv 6.89 10 6894.8 Turbine1 15 689.48 FWHa 17 689.48 Turbine2 20 6.89 Condenser 30 6.89 Pump 40 6894.8 FWHb 45 6894.8 Aux.Pump 46 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h psi deg.C de
Oklahoma State - MAE - 4263
Review Problem 1-6: Find the speci.c volume v of steam at p = 5000 psia and T = 1000 o F (a) We can look it up in the supercritical steam Table A-3 (page 777 of Powerplant Technology by E Wakil) v = 0:1312 ft3 /lbm (b) If we didn' have superheated va
Oklahoma State - MAE - 4263
Jan 26, 2005MAE 4263 Vapor Power SystemsProblem 1-4: Draw a symbolic turbine and indicate the inlet (Station 1) and outlet (Station 2). From Equation 1-21 W out = m (h1 where we insert h2 )h from the integral Equation 1-18 W out = m ZT2cp dT
Oklahoma State - MAE - 4263
Steam Turbine Prob.1-21 Station Property 1 and 2 m-dot 1pGiven units Given value Conversion S.I. Value S.I. Units Conversion Report value Report units lbm/hr 1000000 0 126 kg/s psia 2500 0.07 170.11 atm 6.89 17236.89 KPa 1T deg.F 1000 459.67 1459.6
Oklahoma State - MAE - 4263
Non-ideal wet-steam Cycle Prob.2-2 Station eta 1 2s 0.88 2 3 0.75 4 1 net # # -1000 # #MACRO? # 300 #MACRO? # # 125 # # # 40 40 #MACRO? # #MACRO? #MACRO? 0 # p KPa # T deg.C 300 v m3/kg h KJ/kg s KJ/kg-K quality sat # q w m-dot kg/s MW#MACRO? #MACR
Oklahoma State - MAE - 4263
Ideal with open FWH Prob.2-3 p No. Kpa cnv 6.89 10 6894.8 Turb1 15 689.48 FWHa 17 689.48 g 20 6.89 f 30 6.89 Pump1 40 689.48 FWHb 45 689.48 Pump2 46 6894.8 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h s psi deg.C deg.F KJ/kg KJ/kg-K 1000
Oklahoma State - MAE - 4263
MAE 4263 Vapor Power SystemsProblem 2-17: Follow the notation of Figure 2-16, and the example on page 72, either on an Excel/VBA spreadsheet, or else using page 777: p1 = 7000 psia, T1 = 1400o F, h1 = 1638.6 BTU/lbm, s1 = 1.5355 BTU/lbm-o R; p2 = 16
Oklahoma State - MAE - 4263
Powerplant Technology Problem 3-1: Draw a SSSF control-volume around the boiler, with entering fuel and air and water, and departing refuse (slag &amp; ashes), ue-gas, steam, and heat-loss. The mass balance of the tube-side H2 O is mwater = msteam = 375
Oklahoma State - MAE - 4263
Powerplant Technology Problem 3-2: Fuel oils generally are a mix of components such as Cn H2n+2 (see Table 4-4 on page 147); to convert from a mass-analysis to moles-per-pound-of-fuel, we need to introduce the elemental weights M mflbm lbmM=lbm
Oklahoma State - MAE - 4263
Problem 4-11: The composition is mflbm lbm coalM=lbmol lbm coallbm lbmolC . S . 0.75 . 0.023 . 1.00012.011 . 32.066 .0.062443 . 0.000717 .and the chemical equation shows that each S atom produces one CaSO4 molecule and requires CaCO
Oklahoma State - MAE - 4263
Problem 4-16: Gaseous propane (M = 44.097) at STP burns with air at 300o F (422 K), and produces 1700o F (1200 K). If there is exactly stochiometric air C3 H8 + 5 (O2 + 3.76N2 ) 4H2 O + 3COz + 18.8N2 The left-hand side of the Energy Balance, using h
Oklahoma State - MAE - 4263
Five Feed-Water Heaters P.2-12 P psia T Tsat hf h hg sf s sg Kpa deg.F deg.C deg.C KJ/kg KJ/kg-K 6.89 16548 1000 538 # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 16548 16548 16548 16548 16548 16548 16548 # # # # # 538 # # # # # # #
Oklahoma State - MAE - 4263
MAE 4263 Vapor Power SystemsProblem 2-12: Following the notation of Excel spreadsheed Prob0212.xls, the FWH energy balances are (h15 - h14 ) = (h2a - hf 2 ) (h15 - h14 ) = (h2a - hf 2 ) (h14 - h13 ) = (h3a - hf 3 ) + (hf 2 - hf3 ) (h14 - h13 ) -
Oklahoma State - MAE - 4263
Problem 7-3: The air enters with a dry-bulb temperature of 50 o F and, at 50% relative humidity, with a wetbulb temperature of 42 o F, according to the Psychrometric Chart (page 821). The main evaporative process follows a constant-enthalpy line, whi
Oklahoma State - MAE - 4263
Problem 6-6: The ideal Rankine cycle uses saturated steam, so it can' be at 1000 o F, since the critical t temperature of water is 705:44 o F; we believe that the conditions of Problem 6-7 were intended, and the thermodynamic cycle calculation for th
Oklahoma State - MAE - 4263
Problem 6-7: The reference cycle from Problem 6-6 with a condenser pressure of 1.0 psia has the states p1 h1 s1 p2 T2 2 h2 h3 h4 and the transfers w12 q23 w34 q41 with the results wnet th msteam W net Q23 = = = = = = = = =1000 psia 1192.4 BTU/l
Oklahoma State - MAE - 4263
Brayton Cycles: From the .rst law, the maximum transfers for component SSSF control volumes are w1 q2 w3 q42 3 4 1 th= (h1 = (h3 = (h3 = (h1 wnet $ q2 3h2 ) = h2 ) = h4 ) = h4 ) = =1negative positive positive negative T1 T2Generally the maxi
Oklahoma State - MAE - 4263
Problem 8-3: Brayton Cycle in Figure 8-13 (page 324) operating at p1,4 T1 p2,3 T3 = = = = 14.696 psia 60 o F = 520 o R 8 14.696 = 117.57 psia 1800 o F = 2260 o RBase Case: Reversible Brayton Cycle (no regenerator) using Standard Air Table I-1 (pag
Oklahoma State - MAE - 4263
PWR turbines Prob.10-12 Station Property Given Value Conversion S.I. Value S.I. Units source m-dot lbm/hr 10000000 0 1259.98 kg/s source p psia 1100 0.07 74.85 atm 6.89 7584.23 KPa source T # deg.C source s # KJ/kg-K source h # KJ/kg (1-alpha) # HPT
Duke - MATH - 290
The size of LONG is: 4 The size of UNSIGNED LONG is: 4 The size of DOUBLE is: 8 The default LONG is: 1073851552 The default UNSIGNED LONG is: 1073851552 The default DOUBLE is: 7.12893e-270 The smallest LONG is: -2147483648 The largest LONG
Oklahoma State - MAE - 4063
;2;25334Xqghujudgxdwh0V|oodexv Dwwdfkphqw=Judgh Frpsrqhqwv= Lq frxuvhv frghg WK +Wkhru|,/ dv glvwlqjxlvkhg iurpOE +Oderudwru|,/ GV +Glvfxvvlrq, ru LV +Lqghshqghqw Vwxg|,/ wkh iroorzlqj hohphqwv duh judghg=+z,Fodvv dwwhqgdqfh/ glvfxvvlrq sduwl
National Taiwan University - SOC - 703
Sociology 703 Advanced Single Equation Techniques ASSIGNMENT 4 Due Monday May 11th by 5:00 pmBob Kaufman Spring 2009You have decided to study the causes of state-level income inequality, measured by the gini coefficient of family income. (Note: T
Oklahoma State - MAE - 4063
Part ISimple SystemsChapter 1INTRODUCTION and resourcesWhy do we study vibrations? Because most serious dynamic problems in mechanical engineering involve vibrations. There are two main paths by which vibrations lead to trouble: either a reson
Oklahoma State - MAE - 4063
Chapter 2FORMULATION OF TRANSLATIONAL SYSTEMS and review of unitsThe first step in solving any vibrations problem is to identify the physical system and formulate it as a mathematical equation. The simplest systems are those which can be represent
Oklahoma State - MAE - 4063
Chapter 3FORMULATION OF ROTATIONAL SYSTEMS and review of second momentsMany engineering problems involve rotation, and it is not realistic to speak of a single &quot;point&quot; mass. But if we idealize the mass system as rigid, we can write similar differe
Oklahoma State - MAE - 4063
Chapter 4UNDAMPED FREE VIBRATION and static deflectionIn the simplest vibration analyses, damping is neglected, and the motion is the result of initial conditions. These assumptions lead to the first of the Standard Form equations we will study.
Oklahoma State - MAE - 4063
Chapter 5ENERGY METHODS FOR NATURAL FREQUENCY with an introduction to Hamiltonian methodsOne of the most important tasks of the engineer is to find the appropriate mathematical representation of a physical problem. In previous chapters, the govern
Oklahoma State - MAE - 4063
Chapter 6APPROXIMATIONS FOR DISTRIBUTED SYSTEMS and hydrodynamic inertiaThe Conservation of Energy method can be extended to situations that are not strictly single-degree-of-freedom systems, if we have a pretty good idea what is the &quot;mode shape&quot;
National Taiwan University - SOC - 703
SOC 703Spring 2009OLS and EGLS Regressions of Number of Voluntary Association Memberships on Age, Education, College, Sex, City Size and ClassOLS ResultsVariable Age Education College Sex Size Class Intercept OLS Metric b .009931 .173950 .25662
National Taiwan University - SOC - 703
Sociology 703 Advanced Single Equation Techniques ASSIGNMENT 6 Due Wednesday June 3rd by 5:00 pmBob Kaufman Spring 2009You have been hired as a statistical consultant to analyze data for an urban sociologist. The research project is a study of th
National Taiwan University - SOC - 703
Introduction to Generalized Least SquaresGLS Assumptions Identical to OLS except #5(1) y = X + u (2) X has full column rank (3) X contains random variables from an unspecified distribution (4) (5)The motivation for changing Assumption #5 is the
National Taiwan University - SOC - 703
-log: x:\example_sil.log log type: text opened on: 29 Mar 2009, 10:34:19 . infix prestige 1-2 papres 3-4 age 5-6 ed 7-8 paed 9-10 maed 11-12 sex 13 race 14 region 16 15 / &gt; size 19-22 bwlaw 24 class10 29-30 memnum 31-32 contact 49 activism 50-51 / &gt;