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### Assignment1

Course: SOC 549, Fall 2009
School: National Taiwan University
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Word Count: 756

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549, Sociology Winter 2006 Instructor: Paul von Hippel Your name____________________________ Assignment #1 (30 points) due Th 10/5 at the beginning of lab Write your answers directly on the assignment, unless instructed otherwise. Problems 1) (1 point) Do SSDS exercise 3 on page 27 in the 3rd edition, or page 25 in the 4th edition. Put your answers below, and check them against the back of the book. 3a 3b 3c 3d...

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National Taiwan University - SOC - 549
Sociology 549, Paul von Hippel, Autumn 2004Midterm questions (53 points) Time allotted: 90 minutes Clock yourself! Please write your name and answers on the answer sheet providednot on this question sheet. 1. (4 points) During the week of March 7,
Oklahoma State - MAE - 4263
Function Samples Example 1 Compute saturation temp. of steam, given pressure Pressure (kPa) Temperature (C) 101 #MACRO? Example 2 Compute saturation pressure of steam, given temp. Temperature (C) Pressure (kPa) 100 #MACRO? Example 3 Compute specific
Oklahoma State - MAE - 4263
Ideal wet-steam Cycle Prob.2-1 Station p in KPa T in deg.C v in m3/kg h in KJ/kg s in KJ/kg-K quality INPUTS 1 300 2 40 RESULTS 1 # 300 #MACRO? #MACRO? 1 sat/g 2 sat/f 3 4 1 net # # # # # # 300 40 40 40 40 #MACRO? #MACRO? #MACRO? #MACRO? #MACRO? #MAC
Oklahoma State - MAE - 4263
Ideal with closed FWH Prob.2-3D p No. Kpa cnv 6.89 10 6894.8 Turbine1 15 689.48 FWHa 17 689.48 Turbine2 20 6.89 Condenser 30 6.89 Pump 40 6894.8 FWHb 46 6894.8 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h psi deg.C deg.F KJ/kg 1000 100 10
Oklahoma State - MAE - 4263
Ideal with closed FWH and pump Prob.2-3F p No. Kpa cnv 6.89 10 6894.8 Turbine1 15 689.48 FWHa 17 689.48 Turbine2 20 6.89 Condenser 30 6.89 Pump 40 6894.8 FWHb 45 6894.8 Aux.Pump 46 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h psi deg.C de
Oklahoma State - MAE - 4263
Review Problem 1-6: Find the speci.c volume v of steam at p = 5000 psia and T = 1000 o F (a) We can look it up in the supercritical steam Table A-3 (page 777 of Powerplant Technology by E Wakil) v = 0:1312 ft3 /lbm (b) If we didn' have superheated va
Oklahoma State - MAE - 4263
Jan 26, 2005MAE 4263 Vapor Power SystemsProblem 1-4: Draw a symbolic turbine and indicate the inlet (Station 1) and outlet (Station 2). From Equation 1-21 W out = m (h1 where we insert h2 )h from the integral Equation 1-18 W out = m ZT2cp dT
Oklahoma State - MAE - 4263
Steam Turbine Prob.1-21 Station Property 1 and 2 m-dot 1pGiven units Given value Conversion S.I. Value S.I. Units Conversion Report value Report units lbm/hr 1000000 0 126 kg/s psia 2500 0.07 170.11 atm 6.89 17236.89 KPa 1T deg.F 1000 459.67 1459.6
Oklahoma State - MAE - 4263
Non-ideal wet-steam Cycle Prob.2-2 Station eta 1 2s 0.88 2 3 0.75 4 1 net # # -1000 # #MACRO? # 300 #MACRO? # # 125 # # # 40 40 #MACRO? # #MACRO? #MACRO? 0 # p KPa # T deg.C 300 v m3/kg h KJ/kg s KJ/kg-K quality sat # q w m-dot kg/s MW#MACRO? #MACR
Oklahoma State - MAE - 4263
Ideal with open FWH Prob.2-3 p No. Kpa cnv 6.89 10 6894.8 Turb1 15 689.48 FWHa 17 689.48 g 20 6.89 f 30 6.89 Pump1 40 689.48 FWHb 45 689.48 Pump2 46 6894.8 Econ 47 6894.8 StGen 48 6894.8 SuHeat 10 6894.8 netT h s psi deg.C deg.F KJ/kg KJ/kg-K 1000
Oklahoma State - MAE - 4263
MAE 4263 Vapor Power SystemsProblem 2-17: Follow the notation of Figure 2-16, and the example on page 72, either on an Excel/VBA spreadsheet, or else using page 777: p1 = 7000 psia, T1 = 1400o F, h1 = 1638.6 BTU/lbm, s1 = 1.5355 BTU/lbm-o R; p2 = 16
Oklahoma State - MAE - 4263
Powerplant Technology Problem 3-1: Draw a SSSF control-volume around the boiler, with entering fuel and air and water, and departing refuse (slag &amp; ashes), ue-gas, steam, and heat-loss. The mass balance of the tube-side H2 O is mwater = msteam = 375
Oklahoma State - MAE - 4263
Powerplant Technology Problem 3-2: Fuel oils generally are a mix of components such as Cn H2n+2 (see Table 4-4 on page 147); to convert from a mass-analysis to moles-per-pound-of-fuel, we need to introduce the elemental weights M mflbm lbmM=lbm
Oklahoma State - MAE - 4263
Problem 4-11: The composition is mflbm lbm coalM=lbmol lbm coallbm lbmolC . S . 0.75 . 0.023 . 1.00012.011 . 32.066 .0.062443 . 0.000717 .and the chemical equation shows that each S atom produces one CaSO4 molecule and requires CaCO
Oklahoma State - MAE - 4263
Problem 4-16: Gaseous propane (M = 44.097) at STP burns with air at 300o F (422 K), and produces 1700o F (1200 K). If there is exactly stochiometric air C3 H8 + 5 (O2 + 3.76N2 ) 4H2 O + 3COz + 18.8N2 The left-hand side of the Energy Balance, using h
Oklahoma State - MAE - 4263
Five Feed-Water Heaters P.2-12 P psia T Tsat hf h hg sf s sg Kpa deg.F deg.C deg.C KJ/kg KJ/kg-K 6.89 16548 1000 538 # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 16548 16548 16548 16548 16548 16548 16548 # # # # # 538 # # # # # # #
Oklahoma State - MAE - 4263
MAE 4263 Vapor Power SystemsProblem 2-12: Following the notation of Excel spreadsheed Prob0212.xls, the FWH energy balances are (h15 - h14 ) = (h2a - hf 2 ) (h15 - h14 ) = (h2a - hf 2 ) (h14 - h13 ) = (h3a - hf 3 ) + (hf 2 - hf3 ) (h14 - h13 ) -
Oklahoma State - MAE - 4263
Problem 7-3: The air enters with a dry-bulb temperature of 50 o F and, at 50% relative humidity, with a wetbulb temperature of 42 o F, according to the Psychrometric Chart (page 821). The main evaporative process follows a constant-enthalpy line, whi
Oklahoma State - MAE - 4263
Problem 6-6: The ideal Rankine cycle uses saturated steam, so it can' be at 1000 o F, since the critical t temperature of water is 705:44 o F; we believe that the conditions of Problem 6-7 were intended, and the thermodynamic cycle calculation for th
Oklahoma State - MAE - 4263
Problem 6-7: The reference cycle from Problem 6-6 with a condenser pressure of 1.0 psia has the states p1 h1 s1 p2 T2 2 h2 h3 h4 and the transfers w12 q23 w34 q41 with the results wnet th msteam W net Q23 = = = = = = = = =1000 psia 1192.4 BTU/l
Oklahoma State - MAE - 4263
Brayton Cycles: From the .rst law, the maximum transfers for component SSSF control volumes are w1 q2 w3 q42 3 4 1 th= (h1 = (h3 = (h3 = (h1 wnet \$ q2 3h2 ) = h2 ) = h4 ) = h4 ) = =1negative positive positive negative T1 T2Generally the maxi
Oklahoma State - MAE - 4263
Problem 8-3: Brayton Cycle in Figure 8-13 (page 324) operating at p1,4 T1 p2,3 T3 = = = = 14.696 psia 60 o F = 520 o R 8 14.696 = 117.57 psia 1800 o F = 2260 o RBase Case: Reversible Brayton Cycle (no regenerator) using Standard Air Table I-1 (pag
Oklahoma State - MAE - 4263
PWR turbines Prob.10-12 Station Property Given Value Conversion S.I. Value S.I. Units source m-dot lbm/hr 10000000 0 1259.98 kg/s source p psia 1100 0.07 74.85 atm 6.89 7584.23 KPa source T # deg.C source s # KJ/kg-K source h # KJ/kg (1-alpha) # HPT
Duke - MATH - 290
The size of LONG is: 4 The size of UNSIGNED LONG is: 4 The size of DOUBLE is: 8 The default LONG is: 1073851552 The default UNSIGNED LONG is: 1073851552 The default DOUBLE is: 7.12893e-270 The smallest LONG is: -2147483648 The largest LONG
Oklahoma State - MAE - 4063
;2;25334Xqghujudgxdwh0V|oodexv Dwwdfkphqw=Judgh Frpsrqhqwv= Lq frxuvhv frghg WK +Wkhru|,/ dv glvwlqjxlvkhg iurpOE +Oderudwru|,/ GV +Glvfxvvlrq, ru LV +Lqghshqghqw Vwxg|,/ wkh iroorzlqj hohphqwv duh judghg=+z,Fodvv dwwhqgdqfh/ glvfxvvlrq sduwl
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Oklahoma State - MAE - 4063
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Oklahoma State - MAE - 4063
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Oklahoma State - MAE - 4063
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Oklahoma State - MAE - 4063
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Oklahoma State - MAE - 4063
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