# Register now to access 7 million high quality study materials (What's Course Hero?) Course Hero is the premier provider of high quality online educational resources. With millions of study documents, online tutors, digital flashcards and free courseware, Course Hero is helping students learn more efficiently and effectively. Whether you're interested in exploring new subjects or mastering key topics for your next exam, Course Hero has the tools you need to achieve your goals.

6 Pages

### solutiontoPSIX

Course: MAE EE IEN mae ee ien, Spring 2009
School: WVU
Rating:

Word Count: 919

#### Document Preview

to Solution Problem Set IX Chapter 10, Problem 2. (a) If -10 cos t + 4 sin t = A cos( t + ) , where A &gt; 0 and - 180 o &lt; 180 o , find A and . (b) If 200 cos(5t + 130 o ) = F cos 5t + G sin 5t , find F and G. (c) Find three values of t, 0 t 1 s, at which i (t ) = 5 cos 10t - 3 sin 10t = 0 . (d) In what time interval between t = 0 and t = 10 ms is 10 cos 100t 12 sin 100t ? 1 Chapter 10,...

Register Now

#### Unformatted Document Excerpt

Coursehero >> West Virginia >> WVU >> MAE EE IEN mae ee ien

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

WVU - MAE EE IEN - mae ee ien
Solution to Problem Set VChapter 4, Problem 36. Determine each mesh current in the circuit of Fig. 4.65.12 0.1vx 5 + 6V+ 11 vx +12 2V 3 +1.5 VFIGURE 4.65Chapter 4, Solution 36. We define a clockwise mesh current i3 in the upper righ
WVU - MAE EE IEN - mae ee ien
Solution to Problem Set VIChapter 5, Problem 20. With the assistance of the method of source transformations, (a) convert the circuit of Fig. 5.65a to a single independent voltage source in series with an appropriately sized resistor; and (b) conver
WVU - MAE EE IEN - mae ee ien
Solution to Problem Set VIIChapter 5, Problem 47. (a) Find the Thvenin equivalent of the network shown in Fig. 5.89. (b) What power would be delivered to a load of 100 at a and b?40 100 a +120 V200 i11.5i1bFIGURE 5.89Chapter 5, Solu
WVU - MAE EE IEN - mae ee ien
Solution to Problem Set VIIIChapter 7, Problem 3. Calculate the current flowing through a 1 mF capacitor in response to a voltage v across its terminals if v equals: (a) 30te t V; (b) 4e 5t sin 100t V.1Chapter 7, Solution 3.i=C dv dt(a) (b)
WVU - MAE EE IEN - mae ee ien
Solution to Problem Set XChapter 10, Problem 41. Find Zin at terminals a and b in Fig. 10.58 if equals (a) 800 rad/s; (b) 1600 rad/s.2 F a 300 bFIGURE 10.5816000.6 HChapter 10, Solution 41. (a) = 800 : 2F - j 625, 0.6H j 480 300(- j 6
WVU - MAE EE IEN - mae ee ien
Solution to Problem Set XIChapter 11, Problem 12.1Calculate the average power generated by each source and the average power delivered to each impedance in the circuit of Fig. 11.30.10 A5 508 20j10 AFIGURE 11.30Chapter 11, Solution
WVU - MAE EE IEN - mae ee ien
1. A tank is filled with seawater to a depth of 12 ft. If the specific gravity of seawater is 1.03 and the atmospheric pressure at this location is 14.8 psi, the absolute pressure (psi) at the bottom of the tank is most nearly A. 5.4 B. 20.2 C. 26.8
WVU - MAE EE IEN - mae ee ien
1. A tank is filled with seawater to a depth of 12 ft. If the specific gravity of seawater is 1.03 and the atmospheric pressure at this location is 14.8 psi, the absolute pressure (psi) at the bottom of the tank is most nearly A. 5.4 B. 20.2 C. 26.8
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien
WVU - MAE EE IEN - mae ee ien