Coursehero >>
New York >>
Cornell >>
CHEM 2090 Course Hero has millions of student submitted documents similar to the one below including study guides, homework solutions, papers, and exam answer keys.
209 Chemistry Chapter 8: Homework #5 answers 6 This is most easily done by referring to Figure 8-3, which orders the different wavelengths (or frequencies) of the electromagnetic spectrum, from high energy at the left to low energy at the right end. We have 4 sources; one in the visible, at red, which belongs in the "middle" of our chart of energies; a radio wave in the FM band, thus at the far right portion of the spectrum (91.9 MHz corresponding to 0.919 108 Hz, as M stands for Mega, or 106 ); light with frequency 3 1014 corresponds to the infrared region, between our red light and our radio waves; and light at = 485 ; the unit is popular in the older literature, and corresponds A A to 10-10 m; so 485 is equal to 4.85 10-8 m, and looks to be safely in the ultraviolet region. A So in order of increasing frequency that being our scale at the top, frequency increasing to the left we have at lowest frequency the radio waves at 91.9 MHz, next the infrared light with frequency 3 1014 , then the red traffic light, and last the light at = 485 . A 18 The Lyman series, all of which appears at higher energy than the Balmer lines, is not visible to the naked eye and thus was discovered after the Balmer series. It involves transitions from any of the "outer" shells down to the lowest (n = 1) shell in the H atom, and the series of frequencies observed are given by = 3.2881 1015 s-1 1 1 - 2 2 1 n as given in the problem, where the n parameter is the principle quantum number of the excited (source) state (and therefore is an integer greater than 1). (a) The largest energy (remember, frequency is proportional to energy!) arises when the transition is from the most excited state, i.e. for n a maximum. There is no official maximum n value for the solutions to the H atom, so it might seem that we have a problem; but that's not a real problem, as all we need to realize is that for n very large 1 1 the difference between 2 and is negligible, as both are effectively zero. So n (n + 1)2 max = 3.2881 1015 s-1 1 = 3.2881 1015 s-1 2 1 Similarly, the minimum frequency line is found for the smallest allowed value for the n of the excited state, which would be n = 2, and for the Lyman series min = 3.2881 1015 s-1 1 3 1 - 2 = 3.2881 1015 s-1 = 2.4661 1015 s-1 2 1 2 4 Of course, that's not the end of the story; the problem asks for the maximum and minimum wavelengths, , in nm; we have frequencies . Of course they are related, as = c = 2.99792458 108 m-s-1 = 2.99792458 1017 nm-s-1 ; and of course, max is associated with min and min is associated with max . So min = and max = 121.57 nm. 2.99792458 1017 nm - s-1 = 91.175 nm 3.2881 1015 s-1 1 (b) There are a number of ways to figure this one; let's start from the rule in the text (generalized from Equation 8.2) that = 3.2881 1015 s-1 1 1 - 2 2 1 n c 1 = , or = . RearWe are asked to talk about wavelengths , where = c or c ranging the equation above to focus on we arrive at (n) = 91.175 nm 1 1 - 2 2 1 n -1 = 121.57 nm ( n2 ) n2 - 1 95.0 n2 = = 1.0420; n2 - 1 91.175 that holds only if 0.420n2 = 1.0420 or for n2 25; meaning that for n = 5 we would expect a line at 95.0 nm. (c) We need to go through the same process as above; if there were a line at 108.5 nm, that 108.5 n2 = = 1.1900. Solving would require that there exist an integer n for which 2 n -1 91.175 1.1900 6.26 and n 2.5. That doesn't look like an integer, even for n2 we find n2 = 0.1900 assuming some degree of rounding error; so we expect that there is no line at 108.5 nm. So where there to be a line at 95.0 nm, that would mean that 36 Hydrogen-like atoms are "just like" hydrogen except that there is a greater nuclear charge, Z; that scales all the energies of the different stable orbitals of the H-like atom by an amount Z 2 . So our expression for the energies of the hydrogen-like atomic transitions will look like = Z 2 3.2881 1015 s-1 1 1 - 2 2 n1 n2 where n1 is the shell our transition ends in, and n2 is the shell from which we start. If we look at the spectrum, the transitions at the left where they all merge correspond to the high-energy transitions from the closely-spaced levels where is n2 very large; at the right, the lower-energy transitions which arise from the widely-spaced levels where n2 is not very different for n1 . In fact, we can be more specific the transition at the far right is that corresponding to n2 = n1 + 1; the next line to the left, for n2 = n1 + 2, and so on. (a) Therefore the line labeled "A" must correspond to n2 = n1 + 3 and "B" to n2 = n1 + 4. Still, we would like to know what n1 and Z are; to do that we must take one more step. For our H atom, adapting our results from the previous problem, # 18, we find that A = 1 91.175 1 nm - 2 2 2 Z n1 n2 -1 but we know that n2 = n1 + 3 so we can simplify somewhat; and A = n2 (n1 + 3)2 91.175 1 nm = 434 nm Z2 6n + 9 and moving all the unknowns to one side, we find Z2 n2 1 6n1 + 9 91.175 = 0.21 = 2 + (n1 + 3) 434 2 where, of course, Z and n1 are integers. Fastest method to solve is to assume n1 is small and see what is possible; for n1 = 1 there are no integer solutions for Z. For n1 = 2 we find Z = 1; that corresponds to the H atom itself. No other solutions present themselves to me...so this would seem to be the Balmer lines themselves. 52 The box has a dimension 100 pm; the lowest order solution to the "particle-in-a-box" would 1 place wavelength in the box so that the wavelength of the lowest solution would be 200 pm. 2 3 The first overtone would have one complete wavelength; the 2nd overtone, wavelengths, and 2 the third overtone would have two complete wavelengths in 100 pm. If there are two complete wavelengths in 100 pm, one wavelength corresponds to 50 pm. 56 (a) must be smaller than n and no smaller than m ; that leaves only = 2. (b) As above; the only constraint here is that n must be larger than , so n = 3, 4, . . .. 1 (c) ms is always ; either choice is allowed. 2 1 (d) n = 1, 2, 3, 4, . . .; m = 0; ms = 2 62 The Li2+ ion is a hydrogen-like atom; so we can use the hydrogenic orbitals as our solutions 2Zr 1 Z . If with Z = 3. Page 307 (Table 8.1) says that R(2s) = ( )1.5 (2 - )e-/2 for = na0 2 2 a0 we wish to find the radial node, we need to find where the first zero of this function is; there are lots of ways to do that, but the easiest is to recognize that 2 = is such a solution; or 2Zr (2 3)r 3r 2= = = in our case. Solving for r, we find that the radial node is found at na0 2a0 a0 2 r = a0 . 3 74 Count the number of nodes in the contour map; if I look in the x-y plane I see three planar nodes corresponding to the y-axis, and the two dotted lines which are at 30 with respect to the x-axis. There also is a single radial node; that is observed in both the x-y plane, and the in the cross-section which shows the z-probability distribution. So there are a total of 4 nodes in this wave function; there is essentially no probability along z, and one radial node. The number of nodes is one less than the principal quantum number, n; so I would call this an orbital from n = 5; the number of angular nodes is equal to , so this corresponds to = 3, or is an f orbital. 84 (a) This would appear to be Si, or silicon; but in an excited state. The lowest energy state would have the two 3p electrons in separate orbitals, with parallel spin. (b) This configuration looks like P, or phosphorous; and in an excited state, as the lowest energy state would have electrons in each of the three orbitals with parallel spin. Our last electron is antiparallel to the two others in unfilled orbitals. (c) This configuration looks like S, in its ground state. (d) S again, but in an excited state. 104 What is the de Broglie wavelength of the electron? Well, for matter waves we have = h mu 3 h or mu = . for h Planck's constant, m the mass of the matter particle and u its velocity. The angular momentum is murn for rn the radius of the nth Bohr orbit; and we require that the angular momentum satisfy the quantization condition murn = nh 2 allowing us to subsitute from our expression above, to find h nh rn = 2 nh Let's eliminate the fractions; that leads to 2rn = = n. But the left-hand side of this h expression is simply the circumference of the nth Bohr orbit; and these circumferences are apparently integer multiples of the electron matter wavelength. 4
Find millions of documents here - Study Guides, Homework Solutions, Papers, Exam Answer Keys and more.
Course Hero has millions of course related materials that will enable you to learn better, faster and get an A in all your courses.
Below is a small sample set of documents:
prefinal_solutions
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Prefinal for AMS310 SOLUTIONS Z /2 I-1 E 2 n 2.58 2 * 15 0.086 I-2 E I-3 (a) I-4 (d) I-5 E I-6 (b) I-7 (a) I-8 (d) I-9 Y Z /2 n 2.58 * 60 10 15 .48 t s /2 n 5.841 * 1.44 2 4.2 2 X 2 *10 20 I-10 (a) I-11 P( X I-12 P( X 3) F (3)...
preQUIZ1
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310.01 Practice quiz 1 1. If there are 10 people in a class and 8 will pass. How many sets of 8 people are there? 2. P(A) = 0.8 , P(B) = 0.4 , P(A B)= 0.3. P(A B) =_. 3. Suppose we toss a single die and the result is the number of dots observed. T...
preQUIZ2
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310.01 PREQUIZ 2 Practice questions for quiz 2. _ 1. P(A B)= 0.2 P(A)=0.5 P(B)= 0.6, P(B|A)= _2. P(B|A) =0.5 P(A)=0.6 P(B)=0.8 P(A B)= _ _ 3. Given S= {1,2,3,4,5,6} the outcomes of the toss of 1 die. Let A={we get less than 5 dots} and let B={we ...
preQUIZ4
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: preQuiz 4 AMS310 Quiz will be on Monday October 13 _1. Suppose f(x) = 1/6 for 0< X<6 and f(x) = 0 otherwise. Find the mean value of x. Suppose that Z has standard normal density (Z~N(0,1). The p.d.f. of Z is 2 1 e x / 2 for x f(z) = . 2 Use Table ...
preQUIZ6
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Practice questions for Quiz 6 to be given on October 27 _1. Suppose that X has mean deviation of Y equals_ =5 and =10 and Y= 6- 4X. The standard _2. Suppose that X1, X2 and X3 have mean =5 and 2= 4 and Cov(Xj, Xk) =0 for j k . Then the variance of...
preQUIZ7
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Prequiz 7. PRACTICE QUESTIONS FOR QUIZ TODAY . NOVEMBER 2, 2003 1-2 A box of \"1 lb.\" weights must have a mean weight of 1 lb. with a standard deviation of 0.04 lb. _1. We take a sample of n=100 weights and calculate the average of these. We let X den...
prequiz8
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Prequiz 8 1-2 We are interested in estimating the mean score on the test, we sample n=36 individuals and compute an average of 80.1 and a sample estimate of variance equal to 1.44 i.e., n=36, x = 80.1 and s2 = 1.44 so s=1.2. _1.Compute a point estima...
PRETEST1
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310 PRETEST 1 practice questions for Test 1 I. SHORT ANSWER/MULTIPLE CHOICE QUESTIONS. 1. ALL QUIZ QUESTIONS Given f(x)= 0.1x for x=1,2,3, 4. 2 (a) What is the value of x? (b) What is the value of x? 3. Given X has Poisson probability distribution...
PRETEST1solution
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310 PRETEST 1 practice questions for Test 1 I. SHORT ANSWER/MULTIPLE CHOICE QUESTIONS. 1. ALL QUIZ QUESTIONS Given f(x)= 0.1x for x=1,2,3, 4. 2 (a) What is the value of x? (b) What is the value of x? 3. Given X has Poisson probability distribution...
pretest2
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Pretest 2 Pretest 2 Practice questions for Test 2. [I. Short answer questions. All questions on Quiz 1,2,3 , 4 and 4a. (mainly Quiz 3 , Quiz 4 and QUIZ 4a).] 1. Suppose a discrete variable, D has approximately normal distribution. In order to determ...
pretest3
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: PRETEST 3 for Test 3. Test 3 will be on Monday April 28. Questions and answers. Solutions will be posted with corresponding homework solutions. I. Multiple choice/short answer questions: Study all Prequiz questions (with emphasis on Prequizzes 5 and ...
Pretest3_II3
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Pretest 3 II-3 II-3. Prove: If we accept Ho: = o at the level then o is on the (1)100% confidence interval for . (P247) Ans) 1. (1-)100% confidence interval for (given on p228) is : x t / 2 s s x t / 2 n n (a) 2. 1) Critical region of the...
pretest3_solutions
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Solutions to PRETEST 3. TEST 3 will be given on Wednesday December 3 I-1. We decrease the width of the confidence interval by (1) increasing sample size(2) decreasing the confidence value and (3) decreasing the standard deviation of the variable. So ...
quiz2 with soln
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310.01 QUIZ 2 September 17 PRINT YOUR NAME HERE_ USE ALL UPPER CASE LETTERS. UNDERLINE YOUR LAST NAME STUDENT ID NUMBER_ _ 1. P(A B)= 0.15 P(A)=0.5 P(B)= 0.2, P(B|A)= _2. P(B|A) =0.8 P(A)=0.2 P(B)=0.6 P(A B)= _ _ 3. Given S= {1,2,3,4,5,6} the o...
QUIZ4 with solution
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Quiz 4 AMS310.01 Monday October 13 Print your name here_ _1. Suppose f(x) = 3 for 0< X<1/3 and f(x) = 0 otherwise. Find the mean value of x. Hint = 3xdx = 3x2/2. Suppose that Z has standard normal density (Z~N(0,1). The p.d.f. of Z is 2 1 e x / ...
quiz5 with soln
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: QUIZ 5 AMS310.01 Monday, October 20, 2003 Print your name here_ _1. Suppose that X has mean Y equals_ =10 and =50 and Y= (X-10)/50. The mean of _2. Suppose that X is a binomial variable with n=81 and p=0.5. 81 x0.5 x0.5 = 4.5. Then =np= 40.5 and =...
Quiz6 with soln
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Quiz 6 October 27 Print your name here: _ ID #_ (use all UPPER CASE letters) _1. Suppose that X has mean deviation of Y equals_ =2 and =1 and Y= 3- 2X. The standard _2. Suppose that X1 and X2 have mean =5 and 2= 4 and Cov(Xj, Xk) =0 for j k . Then...
Quiz7 with soln
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Quiz 7. NOVEMBER 2, 2003 PRINT YOUR NAME HERE_ STUDENT ID _ 1-2 We are told that the mean diameter of the \"1mm\" bolts produced by the ABC Bolt Factory equals 1mm and the standard deviation equals 0.1 mm., i.e., = 1mm =0.1mm. _C__1. We take a sample o...
Syllabus
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: Syllabus There are slight changes in schedule (December) in PINK SURVEY OF PROBABILITY AND STATISTICS FALL SEMESTER, 2003 FIRST DAY PACKET for AMS 310.01 MONDAY AND WEDNESDAY 5:20 PM to 6:40 PM Harriman 112 All information for this class, can be do...
Table1_Binomial
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table2_Poisson Distribution function
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table3_std Normal distribution execution
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table4_T
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table5_Chi square distribution
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table6_F distribution function
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Table8_operating charac curves for tests abt means
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
Test1_makeup_sols
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310.03 TEST 1-A FORM Fall 2003 1. PRINT YOUR NAME HERE_ USE ONLY UPPER CASE LETTERS. UNDERLINE YOUR LAST NAME TWICE. 2. STUDENT ID NUMBER 3. CHECK TO MAKE SURE THAT YOUR TEST HAS 7 PAGES INCLUDING THIS ONE. 4. SHOW YOUR WORK FOR ALL QUESTIONS I...
test2A_sol
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310 TEST 2 Fall 2003 FORM A 1. PRINT YOUR NAME HERE_ USE ONLY UPPER CASE LETTERS. UNDERLINE YOUR LAST NAME TWICE. 2. Write your student ID number here_ 3. CHECK TO MAKE SURE THAT YOUR TEST HAS 8 PAGES INCLUDING THIS ONE. 4. SHOW YOUR WORK FO...
test2B_sol
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: AMS310 TEST 2 Fall 2003 FORM B 1. PRINT YOUR NAME HERE_ USE ONLY UPPER CASE LETTERS. UNDERLINE YOUR LAST NAME TWICE. 2. Write your student ID number here_ 3. CHECK TO MAKE SURE THAT YOUR TEST HAS 8 PAGES INCLUDING THIS ONE. 4. SHOW YOUR WORK F...
test3_sol
Path: SUNY Stony Brook >> AMS >> 310.01 Fall, 2003
Description: ...
anshw330407
Path: Sonoma >> ECON >> 304 Fall, 2007
Description: Econ 304 Sonoma State University Fall 2007 Dr. Robert Eyler Suggested Answers to Homework #3 Please answer the questions fully and draw graphs or use equations when needed. Show all your work and remember that these are practice for the midterm quest...
ans2 301 f06
Path: Cornell >> ECON >> 3010 Fall, 2007
Description: Econ 301 F06 ANSWERS PROBLEM SET 2 Wissink 1. Critically evaluate the following statements and explain why or in what way are they true, false, or uncertain. a. Over the set of people in New York, the binary relation \"is the half-brother of\" is tran...
Chapter 11
Path: Cal Poly Pomona >> ME >> 214 Fall, 2006
Description: ...
2,01 piecewiseCubic example
Path: UBC >> CPSC >> 303 Winter, 2007
Description: Numerical Approximation and Discretization CPSC 303, Term 2, Winter 20072008 Piecewise Cubic Example Consider interpolating the points i xi hi yi 0 0.00 0.10 1.0000 1 0.10 0.15 0.2857 2 0.25 0.25 0.1379 3 0.50 0.50 0.0741 4 1.00 0.0385 Table 1: Da...
1.09 the definition of numerical analysis
Path: UBC >> CPSC >> 303 Winter, 2007
Description: The following essay appeared in the November, 1992 issue of SIAM News and the March, 1993 issue of the Bulletin of the Institute for Mathematics and Applications.] THE DEFINITION OF NUMERICAL ANALYSIS Lloyd N. Trefethen Dept. of Computer Science Cor...
Chapter 12
Path: Cal Poly Pomona >> ME >> 214 Fall, 2006
Description: ...
Chapter 13
Path: Cal Poly Pomona >> ME >> 214 Fall, 2006
Description: ...
Solutions Manual - Engineering Mechanics Statics 10E (Hibbeler)
Path: UMKC >> ME >> 275 Spring, 2008
Description: ...
Vector Mechanics for engineers Statics 7th - Cap 05
Path: UMKC >> ME >> 275 Spring, 2008
Description: PROBLEM 5.1 Locate the centroid of the plane area shown. SOLUTION A, in 2 x , in. y , in. xA, in 3 yA, in 3 1 2 8 6 = 48 16 12 = 192 -4 9 6 -192 432 1152 1584 8 1536 1344 240 xA 1344 in 3 = A 240 in 2 yA 1584 in 3 = A 240 in 2 Th...
comm actuate outline
Path: Cornell >> COMM >> 2010 Fall, 2007
Description: Maya Grinberg Comm 201 Actuate Outline Title: Take a CHILL PILL! General Subject: Leisure time Specific Subject: College Students Need to Manage their Stress and Can do so by Engaging in More Leisure Activities. Purpose: To entice my audience into pl...
Thrift Protocol (Facebook)
Path: Stanford >> CS >> 145 Fall, 2007
Description: Thrift: Scalable Cross-Language Services Implementation Mark Slee, Aditya Agarwal and Marc Kwiatkowski Facebook, 156 University Ave, Palo Alto, CA {mcslee,aditya,marc}@facebook.com Abstract Thrift is a software library and set of code-generation too...
exam2
Path: Allegheny >> ECON >> 300 Spring, 2008
Description: ECONOMICS 300 EXAM 2 SPRING 2004 PLEDGE:_ NAME:_ Use this information to answer questions 1-4. Suppose that the supply curve for news stories concerning Michael Jackson is perfectly elastic at the price of $10. The demand curve is downward sloping an...
exam3
Path: Allegheny >> ECON >> 300 Spring, 2008
Description: ECONOMICS 300 FINAL EXAM SPRING 2004 PLEDGE: _ NAME: _ 1. (3) In a model of oligopoly: a. There are many firms that are price takers. b. There are many firms that offer heterogeneous product. c. One firm that is a price setter. d. Several firms that...
Intermediate macroeconomics exam1
Path: Allegheny >> ECON >> 300 Spring, 2008
Description: ECONOMICS 300 FIRST MIDTERM SPRING 2004 PLEDGE:_ NAME:_ Multiple Choice (3 points each) (48 points total) 1. When a consumer is consuming a bundle on her budget constraint then a. She must be maximizing her utility. b. She must be exhausting her inco...
midterm2version1s07
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Econ 101 Principles of Microeconomics Korinna K. Hansen Student Name: Section #: TA Name: Second Midterm Examination Spring 2007 Version 1 DO NOT BEGIN WORKING UNTIL THE INSTRUCTOR TELLS YOU TO DO SO. READ THESE INSTRUCTIONS FIRST. You have 50 m...
midterm 2 review questions
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Review Questions for Midterm 2 Econ 101, Lecture 4, Spring 2007 Professor Korinna K. Hansen TAs: Jonathan Thornhill, Kyoung Jin Choi, Woo Jin Choi and Jim Lin 1) In a world of two goods X and Y with prices P X and PY, an increase in both prices PX a...
final review key
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Econ 101, Final Review Key Spring 2007 1) c 2) a 3) c 4) d 5) b, this is assuming that fixed cost is included in the marginal cost of the first unit. 6) b 7) a 8) d 9) b 10) c 11) b 12) d 13) b 14) c 15) c 16) d 17) a 18) a 19) c 20) b 21) c 22) d 23...
final review problems
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Review Questions for the Final Exam Econ 101, Lecture 4, Spring 2007 Professor Korinna K. Hansen TAs: Jonathan Thornhill, Kyoung Jin Choi, Woo Jin Choi and Jim Lin Use this graph for the next question. 1) Points A, B, and C in the above Figure indic...
finalexamreviewtopics
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Additional Topics for Final Exam Econ 101, Lecture 4, Spring 2007 Professor Korinna K. Hansen In addition to all topics you prepared for Midterms 1 & 2, please prepare the following topics: Monopoly Barriers to entry Revenue curves for the Monopolist...
Income and Substition Effects
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Y Income and Substitution Effects: Px increases E\' E2 E1 New budget line Hypothetical budget line Original budget line X Income effect Substitution effect Y Income and Substitution Effects: Px decreases E1 E\' Original budget line E2 Hypothetic...
LearningGuide1
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: University of Wisconsin Department of Economics Economics 101: Principles of Microeconomics Korinna K. Hansen Learning Guide 1 Due Date: Week of Monday, Jan. 29th, 2007 Reading Assignment: Case & Fair Chapter 2 and Lecture Material. Problem Assignm...
LGuide2
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: University of Wisconsin Department of Economics Economics 101: Principles of Microeconomics Korinna K. Hansen Learning Guide 2 Due Date: Week of Monday, February 5th, 2007 Reading Assignment: Case & Fair Chapter 3 up to page 59 and Lecture Materia...
LGuide3
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: University of Wisconsin Department of Economics Economics 101: Principles of Microeconomics Korinna K. Hansen Learning Guide 3 Due Date: Week of Monday, February 12th, 2007 Reading Assignment: Case & Fair Chapter 3 (mostly beyond page 59) and all ...
LGuide4
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: University of Wisconsin Department of Economics Economics 101: Principles of Microeconomics Korinna K. Hansen Learning Guide 4 Due Date: Week of Monday, February 26th, 2007 Reading Assignment: Case & Fair Chapter 6 up to the middle of page 126. Pl...
midterm1reviewtopics
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Review Topics for Midterm 1 Econ 101, Lecture 4, Spring 2007 Professor Korinna K. Hansen Opportunity Cost Absolute Advantage Comparative Advantage Production Possibility Frontier Marginal Rate of Transformation Law of Increasing Opportunity Cost Law ...
Long-run Producer Theory & Input Market Graphs
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: ...
midterm1 review questions
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Review Questions for Midterm 1 Econ 101, Lecture 4, Spring 2007 Professor Korinna K. Hansen TAs: Jonathan Thornhill, Kyoung Jin Choi, Woo Jin Choi and Jim Lin Use the graph below to answer the following question. 1) In the above Figure, which of th...
Midterm1reviewkey
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Econ 101: Principles of Microeconomics - Lecture 4 - Spring 2007 Key to the Review problems for First Midterm 1) d 2) d 3) b 4) b 5) a 6) d 7) a 8) b 9) a 10) c 11) d 12) c 13) a 14) c 15) c 16) d 17) c 18) b 19) a 20) b 21) d 22) b 23) b 24) b 25) c...
midterm2version1key
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Version 1 1) b 2) b 3) a 4) a 5) b 6) b 7) b 8) b 9) a 10) a 11) b 12) d 13) c 14) d 15) a 16) c 17) a 18) d 19) c 20) b 21) b 22) a 23) b 24) d 25) c 26) d 27) b 28) c 29) d 30) b ...
midterm1version1key
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Version 1 1) a 2) b 3) a 4) a 5) a 6) b 7) b 8) a 9) b 10) b 11) b 12) c 13) a 14) d 15) c 16) c 17) b 18) c 19) a 20) b 21) a 22) d 23) d 24) a 25) c 26) b 27) d 28) d 29) b 30) d ...
midterm1version1s07
Path: Wisconsin >> ECON >> 101 Spring, 2007
Description: Econ 101 Principles of Microeconomics Korinna K. Hansen Student Name: Section #: TA Name: First Midterm Examination Spring 2007 Version 1 DO NOT BEGIN WORKING UNTIL THE INSTRUCTOR TELLS YOU TO DO SO. READ THESE INSTRUCTIONS FIRST. You have 50 mi...
