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Final_461_F06-SOMESOLUTIONS

Course: ECE 461, Fall 2009
School: Toledo
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of University Toronto Faculty of Applied Science and Engineering Final Exam, December 2006 ECE 461: Internetworking Examiner: J. Liebeherr Exam Type: D Permitted aid: The only aid permitted is the binary-decimal conversion table stapled to this quiz. All problems have equal weight (10 marks each). Max Points 1 2 3 4 5 6 7 8 Total 5 5 5 10 5 10 10 5 55 STAPLE EXTRA SHEETS WITH YOUR SOLUTIONS TO THIS SHEET...

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of University Toronto Faculty of Applied Science and Engineering Final Exam, December 2006 ECE 461: Internetworking Examiner: J. Liebeherr Exam Type: D Permitted aid: The only aid permitted is the binary-decimal conversion table stapled to this quiz. All problems have equal weight (10 marks each). Max Points 1 2 3 4 5 6 7 8 Total 5 5 5 10 5 10 10 5 55 STAPLE EXTRA SHEETS WITH YOUR SOLUTIONS TO THIS SHEET BEFORE TURNING IN ! Name: ___________________ Email: ___________________ 1 Problem 1. Assume that you have been assigned the 200.35.1.0/24 network block. a) Define an extended-network-prefix that allows the creation of 20 hosts on each subnet. A minimum of five bits are required to define 20 hosts so the extended-network- prefix is a /27 (27 = 32-5). b) What is the maximum number of hosts that can be assigned to each subnet? The maximum number of hosts on each subnet is 2 5 -2, or 30. c) What is the maximum number of subnets that can be defined? The maximum number of subnets is 2 3 , or 8. d) 4. Specify the subnets of 200.35.1.0/24 in binary format and dotted decimal notation. Subnet #0: 11001000.00100011.00000001. 000 00000 = 200.35.1.0/27 Subnet #1: 11001000.00100011.00000001. 001 00000 = 200.35.1.32/27 Subnet #2: 11001000.00100011.00000001. 010 00000 = 200.35.1.64/27 Subnet #3: 11001000.00100011.00000001. 011 00000 = 200.35.1.96/27 Subnet #4: 11001000.00100011.00000001. 100 00000 = 200.35.1.128/27 Subnet #5: 11001000.00100011.00000001. 101 00000 = 200.35.1.160/27 Subnet #6: 11001000.00100011.00000001. 110 00000 = 200.35.1.192/27 Subnet #7: 11001000.00100011.00000001. 111 00000 = 200.35.1.224/27 e) List range of host addresses that can be assigned to Subnet #6 (200.35.1.192/27) Subnet #6: 11001000.00100011.00000001. 110 00000 = 200.35.1.192/27 Host #1: 11001000.00100011.00000001.110 00001 = 200.35.1.193/27 Host #2: 11001000.00100011.00000001.110 00010 = 200.35.1.194/27 Host #3: 11001000.00100011.00000001.110 00011 = 200.35.1.195/27 : Host #29: 11001000.00100011.00000001.110 11101 = 200.35.1.221/27 Host #30: 11001000.00100011.00000001.110 11110 = 200.35.1.222/27 f) What is the broadcast address for subnet 200.35.1.192/27? 11001000.00100011.00000001.110 11111 = 200.35.1.223 Problem 2. (5 points) 5. Aggregate the following set of (64) IP /24 network addresses to the highest degree possible. 202.1.96.0/24 202.1.97.0/24 202.1.98.0/24 : 202.1.126.0/24 202.1.127.0/24 202.1.128.0/24 202.1.129.0/24 : 202.1.158.0/24 202.1.159.0/24 Solution: 2 . The CIDR aggregation is: 202.1.96.0/19 202.1.128.0/19 Similar to the previous example, if two /19s are to be aggregated into a /18, the /19s must fall within a single /18 block! Since each of these two /19s is a member of a different /18 block, they cannot be aggregated into a single /18. They could be aggregated into 202.1/16, but this aggregation would include 192 network numbers that were not part of the original allocation. Thus, the smallest possible aggregate is two /19s. 3 Problem 3. (20 Points) Bridges / LAN switches Figure 1 (next page) shows a network of bridges (LAN switches) and LANs. The bridges run the IEEE 802.1d spanning tree protocol (STP). The Bridge IDs are given in the figure. Assume that all bridges send out their BPDU's once per second, and assume that all bridges send their BPDUs at the same time. Assume that all bridges are turned on simultaneously at time T=0 sec. (10 points) Use the following table to write the BPDUs which are sent by the bridges. For each cell, include: the BPDU (For each BPDU, only provide the <root, cost, bridge> fields) the ports on which the BPDUs is transmitted (write "none" if the BPDU is not sent on any of the ports). Bridge 1 T=0sec Bridge 2 Bridge 3 Bridge 4 Bridge 5 Bridge 6 T=1sec T=2sec (10 points) After the spanning tree algorithm has converged, provide the following information for each bridge: Which is the root port? Which, if any, are designated ports of a bridge? Which, if any, are blocked ports. Bridge 1 Root Port Designated Ports Blocked ports Bridge 2 Bridge 3 Bridge 4 Bridge 5 Bridge 6 4 Bridge ID 1 Bridge ID 3 Bridge ID 5 LAN port A port B LAN port A port B LAN port A port B LAN Bridge ID 6 port A port B Bridge ID 4 Bridge ID 2 port B LAN port A port B LAN port A Figure 1. Problem 4. Consider a TCP connection that is transmitting over a 1 Gbps (Gigabit per second) with an average roundtrip time of 10 milliseconds. What is the maximum throughput of the TCP connection? How does the throughput change if the roundtrip time increases to 40 milliseconds? g) What is approximately the maximum possible throughput of the TCP connection? Explain your answer. h) How does the answer change when the average roundtrip time is increased to ms. Solution: Since the capacity of the network is unlimited, the transmission delay of the data and the ACKs is zero. The figure shows a "round of transmission". During one roundtrip time (20msec), the sender can transmit 64 KB) of data. We obtain: Throughput = 64 KB/20 msec = 3.2MByte/sec = 25.6 Mbit/sec When the propagation is doubled, the throughput is cut in half. 5 Problem 5. Assume a TCP flow has samples of RTT: (1, 3, 2) expressed in units of What is seconds. the Smoothed RTT (srtt), rounttrip time variance (rttvar), and the value of the timeout calculated by TCP when it receives all these samples? (Assume that the current value are srtt = 3 sec, rttvar = = 0 sec. The gains in both the srtt and rttvar calculation are both set to 1/2.) Problem 6. (10 points) Assume that we have a TCP connection between A and B. Assume that A uses slow start and congestion avoidance with the following initial values: Congestion window (at time=0): cwnd=12 segment. Slow-start threshold: ssthresh=5 segments. For the purposes of this problem, assume that MSS= 100 Bytes. Assume that the following events occur at A: Time t = 0: A sends segment with 100 bytes to B, starting with SeqNo=0. Time t = 1: A receives an ACK with AckNo=100 Time t = 2: A sends segment with 100 bytes to B, starting with SeqNo=100. Time t = 3: A sends segment with 100 bytes to B, starting with SeqNo=200. Time t = 4: A receives an ACK with AckNo=100. Time t = 5: A sends segment with 100 bytes to B, starting with SeqNo=300. Time t = 6: A receives an ACK with AckNo=100. Time t = 7: A sends segment with 100 bytes to B, starting with SeqNo=400. Time t = 8: A receives an ACK with AckNo=100. a. (4 points) Describe the actions performed by TCP Tahoe at time t=8, and describe the values of cwnd and ssthresh after the actions are performed. b. (3 points) Describe the actions performed by TCP Reno at time t=8, and describe the values of cwnd and ssthresh after the actions are performed. c. (3 points) For both TCP Tahoe and TCP Reno, describe the actions performed when a timeout occurs between times t=5 and t=6. Problem 7. (10 points) In the figure below, Host1 is a DHCP client, Host 2 is a DHCP server. Router 1 is an IP router (i.e., IP forwarding is enabled), that is also configured as DHCP relay server. 6 DHCP server DHCP relay eth 0 no ip address eth0 10.0.2.1/24 eth1 10.0.3.1/24 eth1 10.0.3.21/24 Router1 Host 1 Ethernet Hub Ethernet Hub Host 2 10.0.2.0/24 Network 10.0.3.0/24 Network d. (4 Points) Explain why Router1 needs to be configured as a DHCP relay server. e. (3 Points) Describe how the relay server processes and directs a DHCP Request from Host 1 and the DHCP Reply to Host 1. Does the DHCP relay server modify the IP headers of the DHCP packets? f. (3 Points) List the IP source and destination addresses in the DHCP Request and the DHCP Response. If the addresses are changed at Router1, show the original and the modified addresses. Problem 8. (10 Points) Most broadband (Cable/DSL) IP routers for home use perform the following functions: DHCP client DHCP server NAT (IP masquerading) IP forwarding g. (5 Points) Explain how these functions are used to provide Internet access to multiple computers on a home network. h. (5 Points) Consider a home network where multiple such `home routers' are connected in series, as shown in the figure below. The home routers form multiple private IP networks, and only one of these networks is connected to the Internet. Suppose that host H1 is connected as shown in the figure. Under which conditions will H1 be able to access the...

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