# Register now to access 7 million high quality study materials (What's Course Hero?) Course Hero is the premier provider of high quality online educational resources. With millions of study documents, online tutors, digital flashcards and free courseware, Course Hero is helping students learn more efficiently and effectively. Whether you're interested in exploring new subjects or mastering key topics for your next exam, Course Hero has the tools you need to achieve your goals.

5 Pages

### a5solution

Course: CEE 320, Fall 2008
School: Washington
Rating:

Word Count: 877

#### Document Preview

320 CEE Spring Quarter 2009 Instructor: Yinhai Wang CEE 320 Assignment #5 Solution Problems from Textbook 7.2 An approach to a pretimed signal has 30 seconds of effective red, and D/D/1 queuing holds. The total delay at the approach is 83.3 veh-s/cycle and the saturation flow rate is 1000 veh/h. If the capacity of the approach equals the number of arrivals per cycle, determine the approach flow rate and cycle...

Register Now

#### Unformatted Document Excerpt

Coursehero >> Washington >> Washington >> CEE 320

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
320 CEE Spring Quarter 2009 Instructor: Yinhai Wang CEE 320 Assignment #5 Solution Problems from Textbook 7.2 An approach to a pretimed signal has 30 seconds of effective red, and D/D/1 queuing holds. The total delay at the approach is 83.3 veh-s/cycle and the saturation flow rate is 1000 veh/h. If the capacity of the approach equals the number of arrivals per cycle, determine the approach flow rate and cycle length. [15 points] Solution Given r = 30, Dt = 83.33, = 1000/3600 = 0.278 determine cycle length Since the capacity of the approach equals the number of arrivals in C, we have tc = g from the area of a triangle r * * (r + t c ) r * * (r + g ) r * * C Dt = = = 2 2 2 and *g * C = * g or = C and g = C r use equation(7.5) substituting * (C - r ) *r = =- C C r * ( * C - * r ) Dt = 2 solving for C yields C = 50 sec determine approach flow *r =- = 0.111 *3600 = 400 veh/hr C Approach flow rate is 400 veh/hr. 7.12 Vehicles arrive at an approach to a pretimed signalized intersection. The arrival rate over the cycle is given by the function (t) = 0.22 + 0.012*t [(t) is in veh/s and t is in seconds]. There are no vehicles in the queue when the cycle (effective red) begins. The cycle length is 60 seconds and the saturation flow rate is 3600 veh/h. Determine the effective green and red times that will allow the queue to clear exactly at the end of the cycle (the end of the effective green), and determine the total vehicle delay over the cycle (assuming D/D/1 queuing). [10 points] CEE 320 Spring Quarter 2009 Solution Given C = 60 sec (t ) = 0.22 + 0.012 * t Arrivals(t) = (t )dt 0.22 * t + 6.00*10-3 * t2 Arrivals(C) = 34.8 veh To clear at the end of the cycle Arrivals(C ) = * g 3600 = = 1 veh/s (given) 3600 Arrival(C ) = 34.8 sec g= Instructor: Yinhai Wang r = C g = 25.2 sec use equation(7.5) determine total delay 60 1 Delay = Arrival(t )dt - * g * ( * g ) = 222.5 veh-sec 0 2 7.17 An intersection has a four-phase signal with the movements allowed in each phase, and corresponding analysis and saturation flow rates shown in Table 7.9 (Data for Problem 7.17). Calculate the sum of the flow ratios for the critical lane groups. [10 points] Solution Phase 1 EBL = 245/1750 = 0.14 WBL = 230/1725 = 0.133 Phase 2 EBTR = 975/3350 = 0.291 WBTR = 1030/3400 = 0.303 Phase 3 SBL = 255/1725 = 0.148 SBTR = 235/1750 = 0.134 Phase 4 NBL = 225/1700 = 0.132 NBTR = 215/1750 = 0.123 Yc=v/s = EBL + WBTR + SBL + NBL = 0.723 CEE 320 Spring Quarter 2009 Instructor: Yinhai Wang 7.28 For Problem 7.17, calculate the minimum cycle length and the effective green time for each phase (balancing v/c for the critical movements). Assume lost time is 4 seconds per phase and a critical intersection v/c of 0.95 is desired. [15 points] Solution From 7.17 solution, Yc=v/s = 0.723 L = 4 * 4 = 16 seconds Xc = 0.95 is given Using Equation (7.20) L X c 16 0.95 C min = = = 66.96 Sec 4 v 0.95 - 0.723 X c - ( ) ci i =1 s Rounding up to the nearest 5 seconds, Cmin = 70 sec This corresponds to Y C min 0.723 70 = 0.937 = Xc = c 70 - 16 C min - L Equation Using (7.22), the effective green times for the three phases can be calculated as v C 70 C g1 = ( ) c1 ( ) = EBL = 0.14 = 10.46 sec -> 10 sec s X1 0.937 Xc v C 70 C g 2 = ( ) c 2 ( ) = WBTR = 0.303 = 22.64 sec -> 23 sec s X2 0.937 Xc v C C 70 g 3 = ( ) c 3 ( ) = SBL = 0.148 = 11.06 sec -> 11 sec s X3 Xc 0.937 v C C 70 g 4 = ( ) c 4 ( ) = NBL = 0.132 = 9.86 sec -> 10 sec s X4 Xc 0.937 Check: g1 + g2 + g3 + g4 + L = 70 sec Other Problem 1. An isolated intersection is controlled by a two-phase pre-timed signal with the movements allowed in each phases, and corresponding analysis and saturation flow rates shown in Table 1-1. Assume the startup loss time is 2 seconds per phase and the clearance loss time is 3 seconds per phase. The traffic flow accounts for the peak 15min period and that there is no initial queue at the start of analysis period. Progression adjustment factor PF=1.0; Upstream filtering/metering adjustment factor I = 1.0. Please answer the following questions: (1) What are the optimal cycle length (round up to nearest 5 seconds) using Webster's optimum cycle length formula and effective green times (based on lane group v/c equalization)? [10 points] CEE 320 Spring Quarter 2009 Instructor: Yinhai Wang (2) What is the northbound approach delay and level of service? [10 points] Table 1-1 Phase and Flow Data for the Intersection Phase 1 Allowed movements NB T/R/L, SB T/R/L Analysis flow rate 800, 820 Saturation flow rate 2800, 2900 Solution: (1) Calculate flow ratios: Phase 1: Northbound: 800 / 2800 = 0.286 Southbound: 820 / 2900 = 0.283 Northbound is critical. Phase 2: Eastbound: 1120 / 3000 = 0.373 Westbound: 960 / 3200 = 0.300 Eastbound is critical. Yc = 0.286 + 0.373 = 0.659 L = (2+3)*2 = 10 sec Xc = 0.90 is given. Using Equation (7.21), we get 1.5L + 5 1.5 10 + 5 = = 58....

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

Washington - IE - 315
IND E 315Final Exam Solutions (Version A)June 5, 2006[5 points] On the bubble sheet please indicate that you have: Exam Version ASection A. Multiple choice problems. [5 points each] (correct answers in boldface type)1. EPA studies of fuel con
Washington - ENVH - 471
ENV H 471: EH REGULATION Progress Assessment ExercisesEXTENDED DEGREE PRPGRAM Lesson 13PROGRESS ASSESSMENT EXERCISES Lesson 13. Judicial Remedies CivilAnswer the questions on the following pages. Your responses should be brief, yet contain suf
Laurentian - CHEM - 4000
Phosphines:PR3 - very important ligands - -donors - -acceptors For years, it was assumed that -backdonation occurred from the metal into empty dorbitals on phosphorus. Actually: -backdonation occurs into MOs formed by combination of two dorbitals
Laurentian - CHEM - 4000
Typical Ligands (Alkyl ligands)[ZrCl4] + 4 PhCH2MgCl Na[Mn(CO)5] + MeI [Zr(CH2Ph)4] + 4 MgCl2 [MnMe(CO)5] + NaIBassi, JACS, 1971, 3787- Not that many homoleptic TM alkyl complexes.[WMe6] = melts 30 oC [TiMe4] = decomposes -40 oC [TiBn4] = stable
Laurentian - CHEM - 4000
Typical Ligands (CYCLIC -systems)2planar or the cycloheptatrienyl ligand is the least susceptible to nucleophilic attack (therefore best considered anionic, not cationic). or not planar 2-- Different hapticities possible (see ligands handout)vs
Laurentian - CHEM - 4000
Crystallographically Characterized Alkane -Complex K. Meyer et al., J. Am. Chem. Soc., 2003, 125, 15734
Laurentian - CHEM - 4000
Laurentian - CHEM - 4000
Typical Ligands (Carbides)C. C. Cummins et al., Chem. Commun., 1997, 1995
Laurentian - CHEM - 4000
Mechanism for Olefin Polymerization Chain Propagation: Cossee-Arlman Mechanism = good basic mechanism.Cossee et al., J. Catal., 1964, 3, 80 &amp; 99.1,2-insertionalkene coordinationR [M]R [M] [M]R CH2 C H2 [M] RGreen-Rooney Mechanism involving
Laurentian - CHEM - 4000
COCarbonyl: -donor, strong -acceptor. Terminal (1850-2100 cm-1), 2-bridging (1700-1850 cm-1) or 3-bridging (1600-1700 cm-1). For free CO, (CO) = 2143 cm-1. Thiocarbonyl: better -donor and better -acceptor than CO. Terminal (1160-1410 cm-1), 2-br
Minnesota - CSCI - 8551
ALPHABRAVOX A B 1,1CHARLIEY 0,0 A B1,0 -1,1X 0,0 1,1DELTAY 1,1 0,0X A B 0,0 0,0Y 0,0 1,1ECHOX A B X A B 1,0 0,1 Y 0,1 1,0 0,0 0,1Y 1,0 1,1FOXTROTR R P S 0,0 1,-1PS-1,1 1,-1 0,0 -1,1 0,0-1,1 1,-1
Moravian - PUBLIC - 200670
SHORT COURSE IN THEORY MUS 101 Spring, 2007 TR 12:50-2:00pm Dr. Debra Torok Hours by Appointment Office/Studio 119; 610- 861-1624Goal Through MU101, students will acquire a knowledge of basic theoretical concepts. These include fluency in the readi
Georgia Tech - CS - 4001
CS4001D Computers &amp; Society - Class Participation &amp; Attendance Rating Sheet Date _Instructions:Evaluator_1. Do not evaluate yourself if you are the evaluator. TA will evaluate you based on the quality of your evaluations. 2. Circle a rating for
Minnesota - CLA - 5251
CNES 5251: ARCHAEOLOGY OF HERODIAN ISRAELQuestion Set 3: Building the Kingdom (25 4 B.C.E.)Write an 8-10 page answer to the questions below. Support your statements with full and accurate citations (author, title, publisher, date, page number; UR
Delaware County CC - SPE - 100
CHAPTER 8Communication and Relational DynamicsCopyright 2002 Thomson Learning, Inc.Communication and Relational Dynamics Why We Form Relationships Models of Relational Development and Maintenance Self-Disclosure in Relationships Alternativ
Delaware County CC - SPE - 100
Improving Communication ClimatesCHAPTER 9Copyright 2002 Thomson Learning, Inc.Improving Communication Climates Communication Climate:The Key to Positive Relationships Defensiveness: Causes and Remedies Responding Non-defensively to Critic
Delaware County CC - SPE - 111
BIBLIOGRAPHY FORMATSA bibliography should cite all the sources used in preparing a speech-including Internet documents, personal interviews, and television programs, as well as print materials such as books, newspaper and magazine articles, referenc
UCSD - EDS - 115
Why is science important?1. We're bad at distinguishing real from illusory correlationstend to ascribe causality to correlates2. Any question about reality can be approached by (1) intuition; (2) religion; (3) science &quot;nave beliefs&quot; hard to
New Mexico - PHYS - 330
UPenn - MATH - 241
Section 19.4 Zeros and PolesMath 241 RimmerClassification of isolated singularitiesLaurent series: f ( z ) =n =-an ( z - z0 ) = an ( z - z0 ) + n n n=0 n =1a- n( z - z0 )n_f (z ) = a- 2 a 2 + + -1 + a + a (z - z0 ) + a2 (
UPenn - MATH - 241
Section 19.4 Zeros and PolesMath 241 RimmerClassification of isolated singularitiesLaurent series: f ( z ) =n =-an ( z - z0 ) = an ( z - z0 ) + n n n=0 n =1a- n( z - z0 )nprincipal partf (z ) = a- 2 a 2 + + -1 + a + a (z
Pittsburgh - SUPER - 0211
VM 544 Preventive Veterinary Medicine Paul C. Bartlett, M.P.H., D.V.M., Ph.D.Food Hygiene: Summary, Philosophy and PoliticsI. General Introduction to the Meat Packing IndustryVeterinarians should know something about the meat packing industry whi
Cal Poly Pomona - BIO - 110
COURSE SCHEDULE DATE TOPIC READINGS* Ch. 1 p. 21 - 30 p. 31 - 43 Ch. 5; p. 57 - 60 Ch. 3, 6, 7Fall 2001Sept 20 Introduction/Scientific Method Sept 25 Ingredients of Life Sept 27 The Big Four Oct 2 Oct 4 Oct 9 Cells: Life's Building Blocks The Fir
Caltech - CNS - 286
Proc. Natl. Acad. Sci. USA Vol. 95, pp. 869875, February 1998 Colloquium PaperThis paper was presented at a colloquium entitled `Neuroimaging of Human Brain Function,' organized by Michael Posner and Marcus E. Raichle, held May 2931, 1997, sponsore
Caltech - CNS - 286
Audiovisual gating and the time course of speech perceptionK. G. MunhallDepartment of Psychology, Queen's University, Kingston, Ontario K7L 3N6, CanadaY. TohkuraATR Human Information Processing Research Laboratories, Kyoto, JapanReceived 4 Mar
Caltech - CNS - 286
The use of visible speech cues for improving auditory detection of spoken sentencesKen W. Granta) and Philip-Franz Seitzb)Walter Reed Army Medical Center, Army Audiology and Speech Center, Washington, D.C. 20307-5001Received 29 June 1999; revised
Caltech - CNS - 286
letters to natureheight using software available from Sontek. From each time series we calculated mean near-bed velocity independent of ow direction. Mean near-bed velocity was compared between treatments using a non-parametric MannWhitney U-test be
Caltech - CNS - 286
David J. LewkowiczNew York State Institute for Basic Research in Developmental Disabilities Staten Island, NY 10314Infants' Response to the Audible and Visible Properties of the Human Face: II. Discrimination of Differences between Singing and Adu
Caltech - CNS - 286
REPORTSActivation of Auditory Cortex During Silent LipreadingGemma A. Calvert,* Edward T. Bullmore, Michael J. Brammer, Ruth Campbell, Steven C. R. Williams, Philip K. McGuire, Peter W. R. Woodruff, Susan D. Iversen, Anthony S. DavidWatching a sp
Caltech - CNS - 286
Psychophysiology, 37 ~2000!, 697705. Cambridge University Press. Printed in the USA. Copyright 2000 Society for Psychophysiological ResearchAn event-related brain potential study of cross-modal links in spatial attention between vision and touch
UPenn - ESE - 570
1ESE 570 SEMICONDUCTOR MEMORIESKenneth R. Laker, University of Pennsylvania2Semiconductor MemoriesRead-only Memory (ROM)Read/Write (R/W) Memory or Random Access Memory (ROM)1. Mask programmed 2. Programmable ROM (PROM) b. Fuse ROM a. Er
Santa Clara - ENGR - 300
Neil Quinn - Fwd: presentation (fwd)Page 1From: To: Date: Subject:Chris Kitts &lt;ckitts@me.scu.edu&gt; &lt;nquinn@scu.edu&gt; 09-Feb-02 11:49:30 Fwd: presentation (fwd)I've tried attaching the presentation. In addition, here are some possible items of i
Santa Clara - ENGR - 300
vti_encoding:SR|utf8-nl vti_author:SR|CSESERV\NQUINN vti_modifiedby:SR|CSESERV\nquinn vti_timecreated:TR|26 Feb 2002 17:59:31 -0000 vti_timelastmodified:TR|26 Feb 2002 17:59:31 -0000 vti_filesize:IR|472064 vti_title:SR|Agronomic Benefits vti_extender
Santa Clara - ENGR - 300
vti_encoding:SR|utf8-nl vti_author:SR|CSESERV\NQUINN vti_modifiedby:SR|CSESERV\nquinn vti_timecreated:TR|18 Jan 2002 19:03:53 -0000 vti_timelastmodified:TR|18 Jan 2002 19:03:53 -0000 vti_filesize:IR|69632 vti_title:SR|No Slide Title vti_assignedto:SR
Santa Clara - ENGR - 300
vti_encoding:SR|utf8-nl vti_author:SR|CSESERV\NQUINN vti_timecreated:TR|04 Mar 2002 22:45:14 -0000 vti_timelastmodified:TR|05 Mar 2002 18:10:13 -0000 vti_filesize:IR|3178496 vti_title:SR|Wireless Communication vti_extenderversion:SR|4.0.2.4426 vti_ba
Santa Clara - ENGR - 300
vti_encoding:SR|utf8-nl vti_timelastmodified:TR|12 Mar 2002 21:49:48 -0000 vti_extenderversion:SR|4.0.2.4426 vti_cacheddtm:TX|12 Mar 2002 21:49:48 -0000 vti_filesize:IR|283136 vti_cachedlinkinfo:VX| vti_cachedsvcrellinks:VX| vti_cachedtitle:SR|Smart
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 3 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts (a) Uniform probability on finite space
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 8 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts If X and Y are discrete,then the condit
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 9 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts If X is discrete, then E(X) =xxP (X
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 10 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts The variance of a random variable X me
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 11 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts Let X and Y be discrete random variabl
Wisconsin - STAT - 3092006
STAT309 DISCUSSION 12 TA: Min Niu E-mail: niu@stat.wisc.edu Office Hour: 1:00pm-2:00pm Tuesday &amp; 5:30pm-6:30pm Thursday Location:Room B248 MSC Homepage:http:/www.stat.wisc.edu/ niu/stat309.html 1. Basic Concepts A sampling distribution is the distrib
Wisconsin - STAT - 3092006
STAT309 SOLUTION 6 2.6.2 Let h(x) = cx+d. Then Y = h(X) and h is strictly decreasing, so fY (y) = fX (h-1 (y)/|h (h-1 (y)| = fX (y - d)/c)/|c|, which equals 1/(R - L)|c| = 1/(cL - cR) for L (y - d)/c R, i.e., cR + d y cL + d, otherwise equals 0.
Wisconsin - STAT - 3092006
STAT309 SOLUTION 9 3.3.2 (a) E(X)=(5)(1/7)+(5)(1/7)+(5)(1/7)+(8)(3/7)+(8)(1/7)=47/7. Also, E(Y )=(0)(1/7)+(3)(1/7)+(4)(1/7)+(0)(3/7)+(4)(1/7)=11/7. (b) E(XY )=(5)(0)(1/7)+(5)(3)(1/7)+(5)(4)(1/7)+(8)(0)(3/7)+(8)(4)(1/7)=67/7. Then Cov(X, Y ) = E(XY )
Wisconsin - STAT - 3092006
STAT309 SOLUTION 11 4.1.1 P (Y3 = 1)=(1/2)(1/2)(1/2)=1/8 P (Y3 = 2)=(1/4)(1/4)(1/4)=1/64 P (Y3 = 3)=(1/4)(1/4)(1/4)=1/64 P (Y3 = 21/3 )=(1/2)(1/2)(1/4)+(1/2)(1/4)(1/2)+(1/4)(1/2)(1/2)=3/16 P (Y3 = 31/3 )=(1/2)(1/2)(1/4)+(1/2)(1/4)(1/2)+(1/4)(1/2)(1/2
Wisconsin - STAT - 3092006
STAT309 SOLUTION 13 4.4.1 Here limn P (Xn = i) = 1/3 = P (X = i) for i=1,2,3, so limn P (Xn x) = P (X x) for all x, so Xn X in distribution. 4.4.4 For 0 &lt; w &lt; 1, P (Wn w) = 0 (1 + x/n)/(1 + 1/2n)dx = (w + w2 /2n)/(1 + 1/2n) w as n . Also, P (W
Wisconsin - ECE - 554
SPARTA Special Purpose Asynchronous Receiver/Trans mitterIntroductionIn this miniproject you are to implement a Special Purpose Asynchronous Receiver/Transmitter (SPART). The SPART can be integrated into the processor of your final project to ser
Cal Poly - CS - 238
Cs238 Lecture 2 Computer System StructuresDr. Alan R. DavisComputer-System OperationBootstrap Program When a computer is powered up it starts a simple initial program, called a bootstrap program. This initializes all aspects of the system: CPU
Cal Poly - CS - 238
Cs238 Lecture 3 Operating System StructuresDr. Alan R. DavisSystem Components Process Management Main-Memory Management File Management I/O System Management Secondary-Storage Management Networking Protection System Command-Interpreter Sys
Cal Poly - CS - 238
CS238 Lecture 4 ProcessesDr. Alan R. DavisProcess Management Processes Chap 4 Threads Chap 5 CPU Scheduling Chap 6 Process Synchronization Chap 7 Deadlocks Chap 8Processes A process can be considered a program in execution. It is a basic u
Cal Poly - CS - 238
Cal Poly - CS - 238
Cs238 CPU SchedulingDr. Alan R. DavisCPU Scheduling The objective of multiprogramming is to have some process running at all times, to maximize CPU utilization. A process is executed until it must wait, usually for completion of some I/O request
Cal Poly - CS - 238
CS238 Group 7 Oksana ZirkiyevaDavid ElfassyOksana BorukhovaKing Ling YeungMilton LopezFile Management Vadim RoginskiyAlgorithms Creating a File Find space in file system Entry of file made in directory and saved information on the file
Cal Poly - CS - 238
CS238Team #1Command Interpreter2/7/2001To test our module1) compile all .java files2) run appletviewer CommandInterpreter.java (has embedded applet tags)3) run appletviewer CommandMenuBar.java (another applet)
St. Mary MD - SEMINARS - 0405
McMASTER UNIVERSITYGRADUATE PROGRAM IN STATISTICSSTATISTICS SEMINARSpeaker: Dr. Xiaowen Zhou, Department of Mathematics andStatistics, Concordia UniversityTitle: Day: Time: Place:&quot;Risk Model With a Constant Dividend Barrier&quot;Tuesday October
New Mexico - ENG - 306
Dr. ObermeierEngl. 306Term Paper Content: Write a concise, detailed, and insightful 8-10-page essay (plus a works cited page) on one of the following topics: 1. Pick an Arthurian character and analyze his or her development in two or more texts (
Berkeley - SECURE - 11561
* DavServlet.javaFri Jan 27 18:10:55 2006- DavServlet.java.newFri Jan 27 18:17:35 2006** 1996,2001 *- 1996,2003 - return; } + / send a &quot;201 Created&quot; not &quot;200 OK&quot;+ resp.setStatus(HttpServletResponse.SC_CREATED); / Removing an
UNC - SOCI - 111
SUNY Stony Brook - ISE - 112
}PY j&quot;4i)!3 I 7 8 U A @ I X I 5 A I I U 8 ' r Y B B A @ 7 h B 5gA~SP4XI5PsFV193V!~wg VSl&amp;34V! 8 7 5 5 I E I @ 7 h # A I X d A \$ # y x v s4P4Po8j (4V)&amp;&quot;VSPV3nP'0C l)(wu PYf g k40iI A 7 8
SUNY Stony Brook - ISE - 112
xk T u d u hg c rc ic p rc e h k r d e d d d d lc ifuffVEsX5xd T} | u hg c rc ic 5T&quot;fiusxfVp rfwuhyiwiuffVdfwhyffsisc | c e h k r u hg c rc ic p rc p e w u hg c rc ic p rc l } u hg c rc ic T&quot;fiusxfVp rfwuhyiwiuff