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### HW_7

Course: PGE 312, Spring 2009
School: University of Texas
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Word Count: 326

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312 PGE Physical and Chemical Behavior of Petroleum Fluids I Homework 7, Spring 2008 Problem 8-2 o API = 141.5 o - 131.5 = 141.5 - 131.5 = 30.2 0.875 Problem 8-4 o API = 141.5 o o - 131.5 = 35.2 o = 141.5 141.5 = = 0.8488 API + 131.5 35.2 + 131.5 Problem 8-7 Volume of Oil + dissolved gas leaving reservoir at Reservoir Conditions Volume of Oil in Stock Tank at Standard Conditions 227.0 res cc res bbl...

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312 PGE Physical and Chemical Behavior of Petroleum Fluids I Homework 7, Spring 2008 Problem 8-2 o API = 141.5 o - 131.5 = 141.5 - 131.5 = 30.2 0.875 Problem 8-4 o API = 141.5 o o - 131.5 = 35.2 o = 141.5 141.5 = = 0.8488 API + 131.5 35.2 + 131.5 Problem 8-7 Volume of Oil + dissolved gas leaving reservoir at Reservoir Conditions Volume of Oil in Stock Tank at Standard Conditions 227.0 res cc res bbl = = 1.356 STB 167.4 ST cc To calculate Bo Bo = To calculate Rs Rs = Volume of Gas Produced at surface at Standard Conditions Volume of Oil entering Stock Tank at Standard Conditions 0.537 scf + 0.059 scf scf = = 566.1 -6 167.4 ST cc 6.2898 10 bbl / cc STB Problem 8-9 To calculate Bo Volume of Oil + dissolved gas leaving reservoir at Reservoir Conditions Volume of Oil in Stock Tank at Standard Conditions 86.3 res bbl / d Bo = = 1.49 res bbl / STB 57.9 STB / d Bo = To calculate Rs Volume of Gas Produced at surface at Standard Conditions Volume of Oil entering Stock Tank at Standard Conditions (43150 + 7240) scf Rs = = 870.3scf / STB 57.9STB Rs = As reservoir pressure is decreased from initial pressure to bubble-point pressure, Bo is increased but Rs is constant. Therefore, applies Rs at the bubble point. Problem 8-10 Bo 1.60 1.50 Bo, res bbl/STB 1.40 1.30 1.20 1.10 1.00 0 1000 2000 3000 4000 Reservoir Pressure, psig 5000 6000 Rs 1000 900 800 700 Rs, scf/STB 600 500 400 300 200 100 0 0 1000 2000 3000 4000 Reservoir Pressure, psig 5000 6000 Problem 8-11 Bt = Bo + Bg ( Rsb - Rs ) Bt = 1.441 + 0.001090 (941 - 732) Bt = 1.669 res bbl / STB Problem 8-12 P=3500 psig > Pb=3054 psig Therefore, Bt = Bo = 1.527 res bbl/STB Problem 8-16 For between 3500 and 4000 psig above the bubble point pressure Pb=3054 psig, co = - 1 Bo Bo P T From the graphs of B0 and Rs in Exercise 8-10, Bo 1.517 - 1.527 = = -2 10-5 P 4000 - 3500 Bo = 1.522 res bbl / STB co = - 1 -2 10-5 = 13.14 10-6 psi -1 1.522 Increases Increases Constant Decreases Increases Problem 8-18 Formation volume factor of oil Total formation volume factor Solution gas-oil ratio Oil viscosity Coefficient of isothermal compressibility of oil Problem 8-19 Formation volume factor of oil Total formation volume factor Solution gas-oil ratio Oil viscosity Coefficient of isothermal compressibility of oil Formation volume factor of free gas Decreases Increases Decreases Increases Increases Increases
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University of Texas - PGE - 312
PGE 312 Physical and Chemical Behavior of Petroleum Fluids IHomework 8, Spring 2008Problem 10-4 Calculations are as follows: Gas-oil ratio (1) at separator (T = 200oF) and stock-tank (T = 0oF) conditions: Volume of gas removed from the separator Seperat
University of Texas - PGE - 312
PGE 312 Physical and Chemical Behavior of Petroleum Fluids IHomework 9, Spring 2008 Problem 9-1 The given data is plotted and then a line of best fit is drawn through the pressure and GOR data. This is shown in the figure below:From the figure, Bubble P
University of Texas - PGE - 312
PHYSICAL AND CHEMICAL BEHAVIOUR OF PETROLEUM FLUIDS I HOMEWORK 1Problem 1-2. i) cyclopentaneii)2,2 dimethyl butaneiii)2,3 dimethyl butaneiv)2 methylpentanev)3 methylpentanevi)n hexanevii)methylcyclopentaneviii)2,2 and 2,4 dimethylpentanean
University of Texas - PGE - 312
Problem 2-21From the above Fig.2-37, lines are drawn through 300psia, 600psia and 900psia to draw the Isobars shown below. This is done by reading the compositions at the corresponding temperatures as they cross the Bubble Point and the Dew Point Curves.
University of Texas - PGE - 312
HOMEWORK# 3 SOLUTION KEY5-1.The initial and final reservoir conditions and the separatoe conditions are plotted on figure 2-37 (shown above).a. The reservoir fluid would be classified as dry gas. No liquid will be formed either in the reservoir or on t
University of Texas - PGE - 312
HOMEWORK# 4 SOLUTION KEY 12-6. Mass of 2,2 dimethylbutane = 3 lbs mass of 2,2,4 trimethylpentane = 2lbs pressure = 5 psia temperature = 100F Component Mass, lbs, mi 3 2 Molecular wt, lb/lbmol, Mi 86 114 Number of moles, ni (=m/M) 0.0349 0.0175 Mole fracti
University of Texas - PGE - 312
Problem 3.2 The formula of the molecule is C3H6 Because the pressure is low (14.7 psia) the Ideal Gas Law can be used. Thus, calculate the molecular weight as follows. P V = nR T m m PV = RT M = RT = RT M V 0 .10 3lb ps i 3 (10 0 + 460 ) o R ft M = RT = 1
University of Texas - PGE - 312
HOMEWORK # 6 SOLUTION KEY 6-1. Assuming ideal gas, PV = nRT, nRT V= P 100 x10.732 x (60 + 459.7) = scf 14.65 = 38071.13 scf 6-8. Given, Area H SW z= 640 acres = 27878400 sq. ft. = 21 ft = 0.18 = 33%= 0.951, from example 3-10.Bg = 0.0282zT P 0.0282 x0.
University of Texas - PGE - 312
SOLUTION KEY HOMEWORK# 7 8-3. Specific gravity,o =o =o w46.4lb / cuft 62.37lb / cuft= 0.744 8-5. API =So,141.5o141.5- 131.535.2 =o- 131.5o = 0.84883 density, o = o w = 52.41x(5.615 cu ft/ bbl) lb/ bbl = 297.25 lb/bbl 297.25 pounds in a barr
University of Texas - PGE - 312
HOMEWORK# 8 SOLUTION KEY 10-4. First calculate gas oil ratio at separator and stock-tank conditions. 0.51383 scf Separator gas-oil ratio = (150.833)(6.29 x10-6 bbl/cc) = 541.6 scf/ SP bbl 0.15186 scf Stock-tank gas-oil ratio = (136.591)(6.29 x10-6 bbl/cc)
University of Texas - PGE - 312
SOLUTION KEY HOMEWORK# 9 11-1. API = 40.3 Specific gravity = 0.756 Rs = 1000scf/ STB From figure 11-1, bubble point pressure at 205 F, Pb = 3500 psia (approx.) 11-3. For pressure below the bubble point, the solution gas oil ratios (Rs) can be estimated fr
University of Texas - PGE - 312
HOMEWORK# 10 SOLUTION KEY 13-8. Molecular weight Mj 16.043 30.07 44.097 58.123 58.123 72.15 72.15 86.177 218Compostition of separator, zj Methane 0.2648 Ethane 0.0951 Propane 0.0961 i-Butane 0.0173 n-Butane 0.0501 i-Pentane 0.0188 n-Pentane 0.0281 Hexane
University of Texas - PGE - 312
PGE 312 - FALL 2007Physical and Chemical Behavior of Petroleum Fluids I Test #1, 50 Minutes Closed Book Note: It will be in your best interest to attempt all the questions. Please budget your time accordingly. Problem 1 (25 points) Name the following hyd
University of Texas - PGE - 312
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University of Texas - PGE - 312
1PGE 312 - FALL 2006Physical and Chemical Behavior of Petroleum Fluids I Final Examination, 3 Hours Closed Book &amp; Notes It will be in your best interest to attempt all the questions. Please budget your time accordingly. Problem 1 (10 points) Five hundre
University of Texas - PGE - 312
1PGE 312 - FALL 2007Physical and Chemical Behavior of Petroleum Fluids I Final Examination, 3 Hours Closed Book &amp; Notes It will be in your best interest to attempt all the questions. Please budget your time accordingly. Problem 1 (16 points) Fifty gms (
University of Texas - EM - 306
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University of Texas - EM - 306
University of Texas - EM - 306
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University of Texas - EM - 306
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University of Texas - EM - 306
WJ 12v\cw@)[ Cr\AP\(.~S~-5JAA.JCD[&quot;T~E.s@:1FI..1.-Fo,.-+~ptew .hu1wd~I~.ttl1oJ;~ 'DrQWcfw_OrYIpA'tocnd. .,j-+~e &quot;~&quot;'OCAJ&quot;1 .~DH:tCIot~poilol4.\$ ~C. 0POChlol-U&quot;J.,I&quot;)i~ DdeY&quot;Y'I&quot;\;rle -+l.le ()(~l'.e J~V'(,t,~I&quot;/'Ibtrr bT
University of Texas - MAN - 320
Chapter 1 Introduction to Management and Organizations TRUE/FALSE QUESTIONS A MANAGER'S DILEMMA1. 2.Today's managers are just as likely to be women as they are men. (True; moderate; p. 4) Management affects employee morale but not a company's financial
University of Texas - MAN - 320
Chapter 2 Management Yesterday and Today TRUE/FALSE QUESTIONSHISTORICAL BACKGROUND OF MANAGEMENT 1. 2. 3. According to Adam Smith, division of labor was an important concept. (True; easy; p. 26) In the Industrial Revolution, machine power began substitut
University of Texas - MAN - 320
Chapter 3 Organizational Culture and Environment: The ConstraintsTRUE/FALSE QUESTIONSTHE MANAGER: OMNIPOTENT OR SYMBOLIC?1. In the symbolic view of management, managers are seen as directly responsible for an organization's success or failure. (False;
University of Texas - MAN - 320
Chapter 4 Managing in a Global EnvironmentTRUE/FALSE QUESTIONSWHAT'S YOUR GLOBAL PERSPECTIVE?1. Americans tend to suffer from parochialism. (True; moderate; p. 91; AACSB: Globalizations) 2. A drawback of the geocentric perspective is that it is inflexi
University of Texas - MAN - 320
Chapter 5 Social Responsibility and Managerial EthicsTRUE/FALSE QUESTIONSWHAT IS SOCIAL RESPONSIBILITY?1. The classical view of organizational social responsibility is that management's only social responsibility is to maximize profits. (True; moderate
University of Texas - MAN - 320
Chapter 7 Foundations of PlanningTRUE/FALSE QUESTIONSWHAT IS PLANNING?1. Planning is concerned with how objectives are to be accomplished, not what is to be accomplished. (False; easy; p. 184) 2. If a manager refuses to write anything down or share his
University of Texas - MAN - 320
Chapter 10 Organizational Structure and DesignTRUE/FALSE QUESTIONSDEFINING ORGANIZATIONAL STRUCTURE1. Organizational design is the organization's formal framework by which job tasks are divided, grouped, and coordinated. (False; difficult; p. 266) 2. O
University of Texas - MAN - 320
Homework #6 (due Thursdat March 12, 2009) PLEASE FILL OUT THE COURSE SURVEY AT https:/web.austin.utexas.edu/diia/oca/. Your feedback is very important to me.1. Solve the non-linear equation f(x)=-0.9x2+1.7x+2.5 using 3 iterations each of the following me
University of Texas - MAN - 320
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