Course Hero has millions of student submitted documents similar to the one

below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

1650 Math Homework Solutions Jason Snyder, PhD.
1.10 2-36 (even), 42 52 (even), 54, 56, 60, 68
Solutions 1 8 Find the slope of the line through P and Q. 2) P(0,0), Q(2,-6) =
2 - 1 2 - 1
=
-6-0 2-0
=
-6 2
= -3.
4) P(1,2), Q(3,3) =
2 - 1 2 - 1
=
3-2 3-1
= .
2
1
6) P(2,-5), Q(-4,3) =
2 - 1 2 - 1
=
3-(-5) -4-2
=
3+5 -6
=
8 -6
=- .
3
4
8) P(-1,-4), Q(6,0) =
2 - 1 2 - 1
=
0-(-4) 6-(-1)
= .
7 1 2
4
10) (a) Sketch lines through (0,0) with slopes 1, 0, , 2, and - 1. (b) Sketch lines through (0,0) with slopes , , - , and 3.
3 2 3 1 1 1
y
y
5
5
x
-8 -6 -4 -2 2 4 6 8
x
-8 -6 -4 -2 2 4 6 8
-5
-5
Page 1 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 11 14 Find an equation for line whose graph is sketched. 12)
The line passes through the points (-2,0) and (0,4), thus its slope is given by = 4-0 4 = = 2. 0 - (-2) 2
The slope-intercept form of the line is therefore given by = 2 + 4.
14)
The line passes through the points (-3,0) and (0,-4), thus its slope is given by = -4 - 0 4 =- . 0 - (-3) 3
The slope-intercept form of the line is therefore given by 4 = - - 4. 3
Page 2 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 15 34 Find an equation of the line that satisfies the given conditions. 16) Through (-2,4); slope -1 - 4 = -1( + 2) 18) Through (-3,-5); slope -
7 2
7 + 5 = - ( + 3) 2 20) Through (-1,-2) and (4,3) = 3 - (-2) 5 = =1 4 - (-1) 5
+ 2 = + 1 22) slope ; y-intercept 4
5 2
= 24) x-intercept -8; y-intercept 6
2 +4 5
This line passes through the points (-8,0) and (0,6) = 6-0 6 3 = = 0 - (-8) 8 4
3 = + 6 4
Page 3 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 26) Through (4,5); parallel to x-axis. Parallel to x-axis means m = 0, so the line is horizontal. = 5
28) y-intercept 6; parallel to the line 2x+3y+4=0 The line 2x + 3y + 4 = 0 written in slope-intercept form becomes 2 4 = - - 3 3 So the slope of any parallel line will be = - .
3 2
2 = - + 6 3
30) Through (2,6); perpendicular to the line y = 1 The line y = 1 is horizontal, so any line perpendicular to it must be vertical. = 2
32) Through (1,7); perpendicular to the line 4x 8y = 1 The line 4x 8y = 1 written in slope-intercept form becomes 1 1 = - - 2 8 So the slope of any perpendicular line will be m = 2. - 7 = 2 - 1
Page 4 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 34) Through (-2,-11); perpendicular to the line passing through (1,1) and (5,-1) The line passing through (1,1) and (5,-1) has slope = -1 - 1 2 1 =- =- . 5-1 4 2
So the slope of any perpendicular line will be m = 2. + 11 = 2( + 2)
36) (a) Sketch the line with slope -2 that passes through the point (4,-1). (b) Find an equation for this line.
y
8
6 4
2
x
-8 -6 -4 -2 -2 2 4 6 8
-4 -6
-8
+ 1 = -2 - 4
41 52 Find slope the and y-intercept of the line and draw its graph 42) 3x 2y = 12 Re-writing in slope-intercept form, we get = - 6
2 3
Slope ; y-intercept -6
2
3
Page 5 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 44) 2x 5y = 0 Re-writing in slope-intercept form, we get 2 = 5 Slope ; y-intercept 0
5 2
46) -3x -5y +30 = 0 Re-writing in slope-intercept form, we get 3 = - + 6 5 Slope - ; y-intercept 6
5 3
48) 4y + 8 = 0 Re-writing in slope-intercept form, we get = -2 Slope 0; y-intercept -2
50) x = -5 Undefined slope; no y-intercept
Page 6 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 52) 4x + 5y = 10 Re-writing in slope intercept form, we get = - + 2
5 4
Slope - ; y-intercept 2
5
4
54) Use slopes to show that A(-3,-1), B(3,3), and C(-9,8) are vertices of a right triangle. The slope of the line passing through A and B is = 3 - -1 4 2 = = 3 - -3 6 3
The slope of the line passing through B and C is = 8-3 5 =- -9 - 3 12
The slope of the line passing through C and A is = 8 - (-1) 9 3 =- =- -9 - (-3) 6 2
Since = -1, we conclude that that the lines AB and CA are perpendicular. Thus the points A, B, and C are the vertices of a right triangle.
Page 7 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 60) (a) Find an equation for the line tangent to the circle x2 + y2 = 25 at the point (3,-4). (b) At what other point on the circle will the tangent line be parallel to the tangent line in part (a)?
The line passing through the origin and the point (3,-4) has slope = - 4 3
3 4
Any line perpendicular to this line will have slope = . (a) + 4 = ( - 3)
4 3
(b) (-3,4)
Page 8 of 9
Math 1650 Homework Solutions Jason Snyder, PhD. 68) Depreciation A small business buys a computer for $4000. After 4 years the value of the computer is expected to be $200. For accounting purposes, the business uses linear depreciation to assess the value of the computer at a given time. This means that if V is the value of the computer at time t, then a linear equation is used to relate V and t. (a) Find a linear equation that relates V and t. (b) Sketch a graph of this linear equation. (c) What do the slope and V-intercept of the graph represent? (d) Find the depreciated value of the computer 3 years from the date of purchase.
(a) We know that the line representing the depreciated value of the computer will pass through the points (0,4000) and (4,200). Thus the slope of this line is = 200 - 4000 = -950. 4
So the equation of the line, in slope-intercept form is = -950 + 4000.
(b) Sketch of graph not given here (c) the slope m = -950 means that the computer's value is decreasing at a rate of $950 per year. The V-intercept represents purchase price of the computer. (d) When t = 3, we have = -950 3 + 4000 = -2850 + 4000 = $1150
Page 9 of 9

**Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.**

Below is a small sample set of documents:

Ohio State - MATH - math 150

Math 1650 Homework SolutionsJason Snyder, PhD. 1.112 22 (even), 24, 30, 36, 40, 42Solutions1 12 Write an equation the expresses the statement2) P is directly proportional to w. = 4) w is jointly proportional to m and n. = 6) P varies inversely a

Ohio State - MATH - math 150

Math 1650 Homework SolutionsJason Snyder, PhD. 2.12 8 (even), 14 28 (even), 32, 34, 36, 44, 50, 52, 58, 62, 66, 70Solutions1 4 Express the rule in function notation2) Divide by 7, then subtract 4 =474) Take the square root, add 8, then multiply

Ohio State - MATH - math 150

Math 1650 Homework SolutionsJason Snyder, PhD. 2.22 24 (even), 38 50 (even), 56, 62 72 (even)Solutions1 22 Sketch the graph of the function by first making a table of values.2) = 3-3-2-10123 ()-3-3-3-3-3-3-3yx-3-2-1123123-

Ohio State - MATH - math 150

Math 1650 Homework SolutionsJason Snyder, PhD. 2.36 12 (even), 18 30 (even)5 12 A function f is given.(a) Use a graphing device to draw the graph of f.(b) State approximately the intervals on which f is increasing and on which f isdecreasing.6) =

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Math 1650 Homework SolutionsJason Snyder, PhD. 2.56 44 (even)5 18 A quadratic Function is Given.(a) Express the quadratic function in standard form.(b) Find its vertex and its x- and y-intercept(s).(c) Sketch its graph.6) = 2 + 8() = 2 + 8= 2 +

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

section notes for OSU Math 150 based off the book. VERY USEFUL for missed classesStewart, Redlin, and WatsonPrecalculus 5th edition

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

class notes

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - MATH - math 150

Ohio State - CSE - 201

import java.util.Scanner; public class EggBasket cfw_ public static void main(String[] args) cfw_ int numberOfBaskets, eggsPerBasket, totalEggs; Scanner keyboard = new Scanner(System.in); System.out.print( "Enter the number of eggs in each basket: "); egg

Ohio State - CSE - 201

Ohio State - CSE - 201

Ohio State - CSE - 201

Ohio State - CSE - 201

Ohio State - CSE - 201

Ohio State - CSE - 201

Flow of ControlThe order in which statements in a program are executed is called the flow of control So far we have only seen sequential execution: statements execute one after the other in the order in which they appear in the programBoolean Expression

Ohio State - CSE - 201

Sending Output to a (Text) FileFile I/O Exception Handlingimport java.util.Scanner; import java.io.*; public class TextFileOutputDemo1 cfw_ public static void main(String[] args) throws IOException cfw_ Scanner in = new Scanner(System.in); System.out.pr

Ohio State - CSE - 201

Ohio State - CSE - 201

Its Your Turn!Now lets put it all together: Write a Java program called ComputeArea, which asks the user for the width and height of a rectangle and computes and prints the area of the rectangle.Step 1: Program Skeleton/ do we need any libraries? publi

Ohio State - CSE - 201

CSE 201 PRIMITIVE TYPES; STRINGS; BASIC I/O Variables o What is a variable? What is a literal? o How are variables declared? o What are valid variable names? Primitive Types o int, char, boolean, double Why are they considered primitive types? Know when

Ohio State - CSE - 201

If: Syntaxif( test ) cfw_ if_block See Also Section 3.1Flow of Control: Part ISelectionCSE 201 Elementary Computer Programming1CSE 201 Elementary Computer Programming2If: Syntaxif( test ) cfw_ if_block boolean expressionIf: Syntaxif( test ) c

Ohio State - CSE - 201

Ohio State - CSE - 201

Your Turn, Again!Write a Java program called BreakName, which asks the user for his/her name in the form First M. Last, and outputs First, M., and Last on three different lines. In other words, after the name is read from input, the program needs to brea

Ohio State - CSE - 201

An ExampleGiven an integer i, write a piece of code that outputs even or odd depending on whether the value of i is even or odd.An ExampleGiven an integer i, write a piece of code that outputs even or odd depending on whether the value of i is even or

Ohio State - CSE - 201

Another ExampleGiven two integers i and j, write a piece of code that sets integer variable max to the value of the larger of the two.Another ExampleGiven two integers i and j, write a piece of code that sets integer variable max to the value of the la

Ohio State - CSE - 201

if ( cfw_)Max Of Threeif (i > j) cfw_Max Of Three else cfw_ else / i <= j cfw_CSE 201 Elementary Computer Programming 32CSE 201 Elementary Computer Programming 33Were going to start with our generic if-else statement.Now, we need to eliminate

Ohio State - CSE - 201

Grade Conversionchar letterGrade;Grade ConversionCSE 201 Elementary Computer Programming56CSE 201 Elementary Computer Programming57In this, we must take an integer named grade and convert it into a character corresponding to the appropriate letter

Ohio State - CSE - 201

Your Turn, One More TimeGiven a String, s, which is meant to hold a date in the mm/dd/yyyy format, check that it is in the correct format and print an error message if it is not. boolean Character.isDigit(char ch) allows you to check if a given character

Ohio State - CSE - 201

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468

Linfield - BUSN - 468