PROJET_ELECTRONIQUE.2
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PROJET_ELECTRONIQUE.2

Course Number: AV 244, Spring 2009

College/University: ECE

Word Count: 1834

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Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 PROJET DELECTRONIQUE 2008 www.mes-sa.com/m19.html Page1sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 Analyseetsynthsed'undiscriminateurdesensde rotation Introduction : Cegroupeestconstitudetroislvesdugroupe3,DianedeBeaudrap,LauredeBrocaetNicolasVernos....

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Electronique Projet Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 PROJET DELECTRONIQUE 2008 www.mes-sa.com/m19.html Page1sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 Analyseetsynthsed'undiscriminateurdesensde rotation Introduction : Cegroupeestconstitudetroislvesdugroupe3,DianedeBeaudrap,LauredeBrocaetNicolasVernos. Afinderaliseraumieuxceprojetnousavonscommencpareffectuerungrandnombrederecherchessur internetpourcomprendrelesdiffrentstermesdusujetetpourchercherlematrielutiliserdemaniretablir leschmadundiscriminateur. Nousavonstoutdabordeffectulasynthseetlasimulationetcepourchaquefonctionsecondaire.Lapremire estlafonctionhorlogesynchroneaveclechangementd'tatdesvariablesd'entreX1etX2,lasecondequand ellecorrespondlammorisationdestatsantrieurs,etpourfinirunefonctiondedtectiondusensderotation. Nouspourronstudierensuitelafonctioncompltedudiscriminateur. Conclusion Ceprojetnousapermisdemettreenpratiquecequonnousaenseigncetteanneetlandernier.Deplus, nousavonseffectudenombreusesrecherchessurInternetaudbutdenotreprojet.Cellescinousontpermis demieuxcomprendrelesujetetainsitreplusefficacedanssaralisation. Page2sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 Afinderaliseraumieuxceprojetnousnoussommesrpartislesdiffrentestchesauseindelquipe.Tout dabordnousavonscherchdesinformationssurlesujetsurInternet,puisunepersonnearalisleschma fonctionneldudiscriminateuretlesdeuxautresonteffectulesphasesdetest(synthseplussimulation). Ilnenousapastfacilederaliserlessimulationssurlesordinateursdelcole,Pspicenyfonctionnantpas correctementauniveaudelaphasedesimulation.NousavonsdoncinstallPspicesurnosordinateursportables etainsipulesraliser. Onobtientlasortieducodeurangulairelessignauxsuivants. X1 X2 t t X1 X2 t t SelonlesensderotationX1estenretardouenavancesurX2. Onsouhaitedtecterlechangementdesenschaquechangementd'tatdesvariablesd'entresX1etX2.Pour celalasolutionretenueutiliselesfonctionssecondairessuivantes: FS1:Horlogesynchroneaveclechangementd'tatdesvariablesd'entreX1etX2; FS2:Mmorisationdestatsantrieurs; FS3:Dtectiondusens. Page3sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 FS1:Horlogesynchroneaveclechangementd'tatdes variablesd'entreX1etX2 Fonction:Multiplicateurdefrquence. Type:Squentielle. Organisationfonctionnelle: X1 X2 =1 FS11 Retard FS12 ? FS13 Horloge Unesolutionconsistemultiplierparquatrelafrquencedessignauxd'entreX1ouX2pourgnrerunfront actifsurchaquechangementd'tatdecesvariables. EtudedeFS11 Page4sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 OnremarquequelafonctionFS11estuneportelogiqueOUexclusive,XOR. LechronogrammecidessuspermetdedirequelaporteXORmultipliepardeuxlafrquence. EtudedeFS12 NouscherchonscrerunehorlogequivafaireuneimpulsionsiX1ouX2changedtat. 111111111111111111111111111 LafonctionFS12doitdonccrerunretard,cestdireFS12estundtecteur. NousavonsdoncrecherchsurGoogleunesolution,maislesseulessolutionstrouvessontavecquatreportes NANDencascadeetcelanecrepasunretardsuffisant(seulement17nFchacune).Nousavonsdonc considruneautresolutionquiseraitdutiliseruncircuitRC.Unretardestainsicausparlachargeetdcharge ducondensateur. Nousvoulonstoujoursunehorloge,parconsquent,lesfrontsmontantsetdescendantsnousintressent.La figure1doittreundtecteurdefrontmontantetdefrontdescendant. Page5sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 Figure1 OnsaitquelaportelogiqueNOTcestdireinverseurpermetdemettreunniveau0unniveau1etviceversa. Deplus,onsaitque: Onconstatequilutiliseleretarddesdeuxportesinversespourcrerunretardateurmaisceretardnestpas assezgrand. EtudedeFS13 FS13estuneportelogiqueXOR.CettedeuximeporteXORnouspermetdemultiplierlafrquencedentrepar deux.Finalement,nousobtenonsunefrquencequiestmultipliparquatre.Nouspouvonsainsignrerunfront actifchaquefoisqueX1etX2changerontdtat. Noussommesenmesuredeproposeruneautresolutionpourpaliercetropfaibleretard: 2222222222 OnadfinitdeuxpointsAetBpourpouvoirdterminerleretardquiestcrerparlecondensateurdansce montage. Daprslacourbedechargeducondensateur,duchronogrammeenAetenB,onconstatequunretardat creetquilestpeuprsd.Deplus,silonregardelechronogrammedelhorlogeHcemomentl,on 444444 observeuneimpulsionaufrontmontant. Eneffet,yaunfrontmontant,lhorlogeadoncdtectlesfrontsmontantsetabiencruneimpulsion. Ilnousrestedterminerdequellefaonlhorlogepourraitaussidtecterlesfrontsdescendants. Pourcela,onregardeleschronogrammesaumomentdeladchargeducondensateur. 5555555 Page6sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 Onobservequeunretarddestcrepourunfrontdescendant.Parconsquent,pourunfrontdescendant,on arussicreruneimpulsionfrontmontant. Onobserveaussiquenousobtenonsuneimpulsionpourchaquefront.Deplus,cesimpulsionsonttoujoursla mmeamplitudequiestgaleVcc. OnadonccrunehorlogesynchronequicreuneimpulsionpourchaquechangementdtatdeX1etdeX2. 6666666 Cependant,notrebutultimeconsisteaussidiffrenciersiX1enretardlediscriminateurtournedansunsenset siX1estenavancealorsiltournedanslautresens. 7777777 NousobtenonsalorscommeschmafinalpourFS1: Daprslechronogrammedecettefonction,unretardde0,25msatcre. Page7sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 FS2Mmorisationdestatsantrieurs Fonction:GracedesbasculesD,l'tatprsentetl'tatantrieurauchangementd'tatdesvariablesd'entres sontmmorises. Type:Squentielle Entres: X1etX2,variablesreprsentativesdelavitesse,dusensderotationetdelapositionrelativeducodeur. Horlogetraduisantlechangementd'tatdesvariablesX1etX2parunfrontactif. Sorties: X1MetX2M,tatprsentdesvariablesd'entresX1etX2mmorisparlefrontactifdusignalhorloge. X1M2etX2M2,tatantrieurdesvariablesd'entresX1etX2mmorisparlefrontactifdusignalhorloge. Oncherchemmoriserchaquechangementdtatpourpouvoirdfinirsionestenavanceoupas.Eneffet, poursavoirltatactueletdfinirsiX1estenavanceouenretardparrapportX2nousdevonsmmoriserltat antrieur. PourconnatreexactementFS2,ilnousfauttudieruncodeurangulaire.Cecodeurnouspermettradtudier touteslesvaleurspossiblesdeX1parrapportX2.OnchoisitdegarderX2stableetdtudiersiX1esten avanceouenretardsurX2. Page8sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 10 5 11100010 0001 1 1110000000 8 6 4 2 1101 3 1011 01110100 7 01 Alaidedececodeurangulaire,nouspouvonstabliruntableaudeKarnaughetmettreainsienvidenceles valeurspossiblesdeX1etX2. X1. X2 0.0 moment 0.1 2.0 2.0 7.1 7.1 7.1 2.0 1.1 3.0 3.0 6.1 6.1 6.1 3.0 1.0 5.1 4.0 4.0 5.1 4.0 5.1 1 2 3 4 5 6 7 8 1.0 8.1 1.0 1.0 8,1 8,1 Page9sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 EtudedelafonctiondelabasculeD(lasortieQrecopieDaufrontmontantdelhorloge): Page10sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 OnchoisitdutiliserdeuxbasculesD,unereliX1etuneautrerelieX2,touteslesdeuxrelieslhorloge. OnadfinitX1MensortiedeX1commetatprsentdeX1etX2MensortiedeX2commetatprsentdeX2. Ondcidederagiraufrontdescendantpouravoirdesrsultatsoptimauxetsurs. 8888888 Eneffet: Daprslasimulation,onremarqueX1McorrespondX1etX2McorrespondX2.Nousavonsdoncconfirm quelabasculeDpermetdegarderenmmoire.LepremierbutdelafonctionFS2estdoncacquis. NousdevonsmaintenantnouscontenterdemmoriserlestatsantrieursdeX1MetX2Mquicorrespondent respectivementaumomentprsentdeX1etX2. OnchoisitdappelerX1M1etX1M2lestatsantrieursdeX1MetX2M.Nousallonsdoncutiliserquatrebascules Dquiaurontleurshorlogesconnectes.X1M2seralasortiedeX1M,ellemmeensortiedeX1etselonle mmeprincipe,X2M2sortiedeX2MquiestellemmelasortiedeX2. 9999999 NotreschmafinalsouspspicequimodliselafonctionFS2estlesuivant: Page11sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 OnytrouvebienlesquatrebasculesDreliesentreelleetcomprenonsbienquelpointcorrespondent respectivementX1M,X2M,X1M1etX2M2. LechronogrammedesimulationsouspspicequicorrespondnotrefonctionFS2est: Cela confirmecequiatexpliqucidessus. Page12sur13 Projet Electronique Diane de Beaudrap, Laure de Broca, Nicolas Vernos ING 2 groupe 3 FS3Dtectiondusens Fonction:fonctionquidterminelesensderotation Type:Combinatoire. Entres: X1MetX2M,tatprsentdesvariablesd'entresX1etX2. X1M2etX2M2tatantrieurdesvariablesd'entresX1etX2. Sortie: SENS,tatlogiquereprsentatifdusensderotation. Aprslessimulations,onremarquequelorsqueX1estenavancesurX2,onaX2M=X1M2.Paropposition,siX1 enretardsurX2,onaX1M=X2M2. Schma Page13sur13

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ECE - AV - 244
Sheet1 25; 1;La Defense;9.82;27.51;1;0 2;Esplanade de La Defense;11.40;29.31;1;0 3;Pont de Neuilly;13.54;31.12;1;0 4;Les sablons;15.46;32.92;1;0 5;Porte Maillot;18.85;36.41;1;0 6;Argentine;20.88;38.67;1;0 7;Charles de Gaulle-Etoile;23.48;41.15;1;1 8;Georg
ECE - AV - 244
#include <string> # #include "Ancre.h" u using namespace std; Ancre:Ancre() cfw_ actuelle = NULL; voisins = NULL; depart = NULL; arrivee = NULL; pred = NULL; / tous ses attributs NULL car pointeursvoid Ancre:setActuelle(Station *nouv) cfw_ actuelle = no
ECE - AV - 244
#ifndef ANCRE_H_INCLUDED # #define ANCRE_H_INCLUDED # #include "ListeVoisin.h" / CHAQUE STATION EST UNE ANCRE AVEC UNE STATION ACTUELLE, SON ANCRE PRECEDENT ET SES VOISIN / class Ancre cfw_ public: Ancre(); Station *getActuelle(); ListeVoisin *getVoisins(
ECE - AV - 244
#include #include #include #include #include #include #include # #include"Fenetre.h" <string> <iostream> <stdlib.h> <fstream> <vector> <sstream> <time.h>u using namespace std;/ *DESSINER UN RECTANGLE* / void Fenetre:dessiner_rect_station(QPaintDevice *
ECE - AV - 244
#ifndef FENETRE_H_INCLUDED # #define FENETRE_H_INCLUDED #include <QtGui> #include "Map.h" # #include "FMOD/fmod.h"class Fenetre : public QWidget cfw_ Q_OBJECT;public: Fenetre(int x, int y); taille) / le constructeur de la fenetre (x et y pour la/ les g
ECE - AV - 244
#include <string> # #include "ListeVoisin.h" u using namespace std; ListeVoisin:ListeVoisin() cfw_ tete = NULL; taille = 0; marque = false; int ListeVoisin:getTaille() cfw_ return taille; Voisin *ListeVoisin:getTete() cfw_ return tete; bool ListeVoisin
ECE - AV - 244
#ifndef LISTENOEUD_H_INCLUDED # #define LISTENOEUD_H_INCLUDED # #include "Voisin.h" / / UNE LISTE VOISIN EST UNE LISTE DE TOUS LES VOISIN D'UNE STATION DONNEE / class ListeVoisin cfw_ public: ListeVoisin(); int getTaille(); Voisin *getTete(); bool getMarq
ECE - AV - 244
#include #include #include # #include"Fenetre.h" <string> <QApplication> <iostream>#define ECRAN_X 1200 # #define ECRAN_Y 900 int main(int argc, char* argv[]) cfw_ QApplication app(argc, argv); / franais QString locale = QLocale:system().name(); QTransl
ECE - AV - 244
#include #include #include #include #include # #include<string> "Map.h" <math.h> <vector> <stdlib.h> <fstream>u using namespace std; int getDist(Station *s1, Station *v2) cfw_ / racine(x1-x2)+(y1-y2) int x; x = (int) ( sqrt(v2->getX() - s1->getX()*(v2->
ECE - AV - 244
#ifndef MAP_H_INCLUDED # #define MAP_H_INCLUDED #include "Ancre.h" # #include <iostream> # # # # define define define define NB_STATION 376 TAILLE_X 886 TAILLE_Y 887 INFINI 99999/ /LA MAP EST UN TABLEAU D'ANCRES (DU NB DE STATIONS) /class Map cfw_ publ
ECE - AV - 244
#include <string> # #include "Station.h" u using namespace std; Station:Station() cfw_ nom = "; x = 0; y = 0; ligne = 0; id = 0; multi = 100; void Station:setX(int nouv) cfw_ x = nouv; void Station:setY(int nouv) cfw_ y = nouv; void Station:setLigne(in
ECE - AV - 244
#ifndef STATION_H_INCLUDED # #define STATION_H_INCLUDED # #include <string> / / CONTIENT TOUTES LES INFO DE BASE SUR CHAQUE STATION / class Station cfw_ public: Station(); / constructeur / poru changer les paramtre void setX(int nouv); void setY(int nouv)
ECE - AV - 244
#include<string> #include<math.h> #include"Voisin.h" usingnamespacestd; Voisin:Voisin() cfw_ st=newStation(); next=NULL; dist=9999; Voisin:Voisin(Station*nouv) cfw_ st=nouv; next=NULL; Voisin*Voisin:getNext() cfw_ returnnext; voidVoisin:setNext(Voisin*
ECE - AV - 244
#ifndef NOEUD_H_INCLUDED # #define NOEUD_H_INCLUDED #include "Station.h" # #include <malloc.h> / / CHAQUE OBJET VOISIN EST UN VOISIN D'UNE STATION / class Voisin cfw_ public: Voisin(); Voisin(Station *nouv); void setNext(Voisin* nouv); Voisin* getNext();
ECE - AV - 244
#include <iomanip> #include "minimax.h"/-/ Entree : / Sortie / Effet de bord : Message d'accueil /-void accueil() cfw_ cout < endl < endl < endl; cout < " *"<endl; cout < " BIENVENUE AU JEU DU MORPION " <endl; cout < " *"<endl <endl; /-/ Entree : / Sort
ECE - AV - 244
#include <iostream> #include <fstream> #include <list> using namespace std; /= /Valeurs retournees par h: const int moins_infini = -10000; / si config perdante const int zero = 0; / si match nul const int plus_infini = 10000; / si config gagnante /= /Un t
ECE - AV - 244
#include "jeu.h" /-/ Permet de / - commencer une nouvelle partie / - quitter le jeu /-bool nouvelle_partie() cfw_ char rep; cout < endl < endl < endl < endl; cout <" *"< cout <" * Une nouvelle partie ? *"< cout <" *"< cout <" * Oui.* O *"< cout <" * Non.*
ECE - AV - 244
#include "minimax.h" /-/ Entree : deux entiers a et b / Sortie : le plus grand entier entre a et b /-int max(int a,int b) cfw_ if (a > b) return a; else return b; /-/ Entree : deux entiers a et b / Sortie : le plus petit entier entre a et b /-int min(int
ECE - AV - 244
#include "jeu.h" int max(int , int); int min(int , int); int minimax(config); config meilleur_coup(config);
ECE - AV - 244
( caseO , caseVide , caseVide , caseVide , caseX , caseVide , caseVide , caseVide , caseVide , false , X , 4 , 2 , 1 )
ECE - AV - 244
#include <iostream> u using namespace std; / / Function to return the pgcd of two numbers int pgcd(int n1, int n2) cfw_ if(n2=0) return n1; return pgcd(n2, n102); / Function to reduce and output several fractions void ConvertToLowestTerms(int Numerator,
ECE - AV - 244
#include <iostream> # #include <sstream> u using namespace std; / Function to update to boardgame void updating_game(string c[]) cfw_ system("cls"); cout < "New Game ? type 10" < endl < endl; cout < c[0] < c[1] < c[2] < endl < c[3] < c[4] < c[5] < endl <
ECE - AV - 244
#include <iostream> #include <string> u using namespace std; string reverse(string str) cfw_ int lg = str.size(); int head, tail; head = 0; tail = lg-1; / string:iterator head, tail; / head = str.begin(); const char* tabstr = str.c_str(); / / / / / / / /
ECE - AV - 244
#include <iostream> # #include <sstream> using namespace std; bool is_number(char str) cfw_ if(str>='0' & str<='9') return true; else return false; int find_next_numb(int place, string exp, int *nbnext) cfw_ int numb; string strnumb; for(int i=1;i<exp.le
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SOLUTIONS BUSI1001 Sample FINAL EXAM1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 b d c b c d b b d c a a c c a c c b d d d c b a d a b c c d c a c aQuestion 2 Solution (10 marks) (a) Bad Debts Expense ($4,
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Sabancı University - PHYS - 229
November 26, 2008 THE PREVAILENT THEMES AND STORIES DURING THE TIME OF TERROR The French revolution is the birth of a new era an era that leads humanity to the birth of modernity. To have full understanding of this transition, one had to go deeper to the
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Homework 1 Due March 101. Calculate the angular diameter of a prestellar nebula of radius 300 A.U lying 50 pc away from earth. Compare this with the apparent diameter of Andromeda, 6o. 2. How close would the nebula in the previous question have to be in
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Homework 2, due Thursday 10th1. a. Based on the graph above, find the approximate mass inside of the orbit of a star 12 kpc away from the sun towards the edge of the galaxy. b. Do the same calculation as (a), assuming no dark matter exists. 2. A density
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Homework 11. Calculate the angular diameter of a prestellar nebula of radius 300 A.U lying 50 pc away from earth. Compare this with the apparent diameter of Andromeda, 6o. Can be solved in two ways: a. Definition of parsec: The distance for baseline of 1
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Homework 2, due Thursday 15th1. a. Based on the graph above, find the approximate mass inside of the orbit of a star 12 kpc away from the sun towards the edge of the galaxy. b. Do the same calculation as (a), assuming no dark matter exists. Solution: a.
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NS 209 What is there in the universe, beyond the Milky Way Final Exam -A11 June 2007 - 16:00-18:00Instructor: Emrah Kalemci Surname: Name: Student No:Problems (62 pts) Short answer (10 pts) Multiple choice (48 pts) Total (120 pts):Instructions: 32 mult
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NS 209 What is there in the universe, beyond the Milky Way Midterm Exam 10 April 2007 - 14:40-15:30Instructor: Emrah Kalemci Surname: Name: Student No:Problem (54 pts) Multiple choice (56 pts) Total (110 pts):Instructions: 28 points multiple choice que
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Problem Set 2 Solutions Astronomy 202 Chapter 5: Review and Discussion: 2, 4, 6 2. List three advantages of reflecting telescopes over refracting telescopes.The largest telescopes are reflecting telescopes, primarily because of 3 distinct disadvantages o
Sabancı University - PHYS - 229
Problem Set 4 Solutions Astronomy 202 Assigned: 20 March 2006 Due: 03 April 2006 Chapter 20 Review and Discussion: 1, 3, 11, 16, 20 1. Why dont stars live forever? Which types of stars live the longest?Stars burn hydrogen into helium. When the hydrogen i